Engineering & Architecture Admissions MCQ & Objective Questions
Engineering & Architecture Admissions play a crucial role in shaping the future of aspiring students in India. With the increasing competition in entrance exams, mastering MCQs and objective questions is essential for effective exam preparation. Practicing these types of questions not only enhances concept clarity but also boosts confidence, helping students score better in their exams.
What You Will Practise Here
Key concepts in Engineering Mathematics
Fundamentals of Physics relevant to architecture and engineering
Important definitions and terminologies in engineering disciplines
Essential formulas for solving objective questions
Diagrams and illustrations for better understanding
Conceptual theories related to structural engineering
Analysis of previous years' important questions
Exam Relevance
The topics covered under Engineering & Architecture Admissions are highly relevant for various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter MCQs that test their understanding of core concepts, application of formulas, and analytical skills. Common question patterns include multiple-choice questions that require selecting the correct answer from given options, as well as assertion-reason type questions that assess deeper comprehension.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers.
Overlooking units in numerical problems, which can change the outcome.
Confusing similar concepts or terms, especially in definitions.
Neglecting to review diagrams, which are often crucial for solving problems.
Rushing through practice questions without understanding the underlying concepts.
FAQs
Question: What are the best ways to prepare for Engineering & Architecture Admissions MCQs?Answer: Regular practice of objective questions, reviewing key concepts, and taking mock tests can significantly enhance your preparation.
Question: How can I improve my accuracy in solving MCQs?Answer: Focus on understanding the concepts thoroughly, practice regularly, and learn to eliminate incorrect options to improve accuracy.
Start your journey towards success by solving practice MCQs today! Test your understanding and strengthen your knowledge in Engineering & Architecture Admissions to excel in your exams.
Q. If a 10 kg object is subjected to a net force of 50 N, what is its acceleration?
A.
2 m/s²
B.
5 m/s²
C.
10 m/s²
D.
15 m/s²
Show solution
Solution
Using F = ma, acceleration a = F/m = 50 N / 10 kg = 5 m/s².
Correct Answer:
B
— 5 m/s²
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Q. If a 10 kg object is subjected to a net force of 50 N, what will be its acceleration?
A.
2 m/s²
B.
5 m/s²
C.
10 m/s²
D.
20 m/s²
Show solution
Solution
Using F = ma, acceleration a = F/m = 50 N / 10 kg = 5 m/s².
Correct Answer:
B
— 5 m/s²
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Q. If a 10 ohm resistor is connected to a 20V battery, what is the energy consumed in 5 seconds?
A.
20 J
B.
40 J
C.
10 J
D.
50 J
Show solution
Solution
Power P = V^2 / R = 20^2 / 10 = 40 W. Energy = Power * time = 40 W * 5 s = 200 J.
Correct Answer:
B
— 40 J
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Q. If a 10 ohm resistor is connected to a 30V battery, what is the energy consumed in 5 seconds?
A.
15 J
B.
30 J
C.
75 J
D.
150 J
Show solution
Solution
Power P = V^2 / R = (30V)^2 / 10 ohms = 90 W. Energy = Power * Time = 90 W * 5 s = 450 J.
Correct Answer:
C
— 75 J
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Q. If a 1000 kg car accelerates from rest to a speed of 20 m/s in 10 seconds, what is the average power output of the car's engine?
A.
2000 W
B.
4000 W
C.
6000 W
D.
8000 W
Show solution
Solution
First, calculate the work done: W = 0.5 * m * v^2 = 0.5 * 1000 kg * (20 m/s)^2 = 200000 J. Then, power is P = W/t = 200000 J / 10 s = 20000 W.
Correct Answer:
C
— 6000 W
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Q. If a 1000 W heater is used for 3 hours, how much energy does it consume in kilowatt-hours?
A.
3 kWh
B.
2 kWh
C.
1 kWh
D.
0.5 kWh
Show solution
Solution
Energy consumed in kilowatt-hours is calculated as E = P (kW) * t (h). Here, P = 1000 W = 1 kW and t = 3 hours. Thus, E = 1 kW * 3 h = 3 kWh.
Correct Answer:
A
— 3 kWh
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Q. If a 1000 W heater runs for 2 hours, how much energy does it consume?
A.
7200 J
B.
14400 J
C.
20000 J
D.
3600000 J
Show solution
Solution
Energy = Power × Time = 1000 W × (2 × 3600 s) = 7200000 J.
Correct Answer:
D
— 3600000 J
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Q. If a 10Ω resistor is connected to a 20V battery, what is the power dissipated by the resistor?
A.
20W
B.
40W
C.
100W
D.
200W
Show solution
Solution
Power (P) can be calculated using P = V^2/R. Here, P = 20V^2 / 10Ω = 400 / 10 = 40W.
Correct Answer:
B
— 40W
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Q. If a 10Ω resistor is connected to a 20V source, what is the energy consumed in 5 seconds?
A.
20J
B.
40J
C.
50J
D.
100J
Show solution
Solution
Power P = V^2 / R = 20V^2 / 10Ω = 40W. Energy = Power * time = 40W * 5s = 200J.
Correct Answer:
B
— 40J
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Q. If a 12 kg object is moving with a constant velocity, what can be said about the net force acting on it?
A.
It is zero
B.
It is equal to its weight
C.
It is equal to the applied force
D.
It is increasing
Show solution
Solution
An object moving with constant velocity has a net force of zero according to Newton's first law.
Correct Answer:
A
— It is zero
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Q. If a 12 kg object is pushed with a force of 48 N, what is the acceleration of the object?
A.
2 m/s²
B.
4 m/s²
C.
6 m/s²
D.
8 m/s²
Show solution
Solution
Using F = ma, acceleration a = F/m = 48 N / 12 kg = 4 m/s².
Correct Answer:
B
— 4 m/s²
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Q. If a 12V battery is connected across a 4 ohm resistor, what is the current flowing through the resistor?
A.
2 A
B.
3 A
C.
4 A
D.
6 A
Show solution
Solution
Using Ohm's law, I = V/R = 12V / 4Ω = 3 A.
Correct Answer:
A
— 2 A
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Q. If a 12V battery is connected across a 4 ohm resistor, what is the power dissipated in the resistor?
A.
12 W
B.
24 W
C.
36 W
D.
48 W
Show solution
Solution
Power (P) can be calculated using P = V^2 / R = 12V^2 / 4Ω = 144 / 4 = 36 W.
Correct Answer:
B
— 24 W
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Q. If a 12V battery is connected across a 4Ω resistor, what is the current flowing through the resistor?
Show solution
Solution
Using Ohm's law, I = V/R = 12V / 4Ω = 3A.
Correct Answer:
B
— 2A
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Q. If a 12V battery is connected to a 4 ohm resistor, what is the power dissipated by the resistor?
A.
12 W
B.
24 W
C.
36 W
D.
48 W
Show solution
Solution
Power (P) can be calculated using P = V^2 / R = 12V^2 / 4Ω = 36 W.
Correct Answer:
B
— 24 W
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Q. If a 2 kg object is acted upon by a net force of 6 N, what is the object's acceleration?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Using F = ma, we find a = F/m = 6 N / 2 kg = 3 m/s².
Correct Answer:
B
— 3 m/s²
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Q. If a 2 kg object is dropped from a height of 5 m, what is its speed just before it hits the ground? (g = 10 m/s²)
A.
10 m/s
B.
5 m/s
C.
15 m/s
D.
20 m/s
Show solution
Solution
Using energy conservation: PE_initial = KE_final; m * g * h = 1/2 * m * v^2; v = sqrt(2gh) = sqrt(2 * 10 * 5) = 10 m/s
Correct Answer:
A
— 10 m/s
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Q. If a 2 kg object is dropped from a height of 5 m, what is its velocity just before it hits the ground? (g = 10 m/s²)
A.
10 m/s
B.
5 m/s
C.
15 m/s
D.
20 m/s
Show solution
Solution
Using energy conservation, v = sqrt(2gh) = sqrt(2 * 10 * 5) = 10 m/s
Correct Answer:
A
— 10 m/s
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Q. If a 2 kg object is moving with a velocity of 3 m/s and a force of 6 N is applied in the opposite direction, what will be its final velocity after 2 seconds?
A.
0 m/s
B.
1 m/s
C.
2 m/s
D.
3 m/s
Show solution
Solution
Net force = -6 N, acceleration = F/m = -6 N / 2 kg = -3 m/s². Final velocity = initial velocity + at = 3 m/s + (-3 m/s² * 2 s) = 0 m/s.
Correct Answer:
B
— 1 m/s
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Q. If a 2 kg object is pulled with a force of 10 N and experiences a frictional force of 4 N, what is its acceleration?
A.
3 m/s²
B.
5 m/s²
C.
2 m/s²
D.
1 m/s²
Show solution
Solution
Net force = applied force - friction = 10 N - 4 N = 6 N. Acceleration a = F/m = 6 N / 2 kg = 3 m/s².
Correct Answer:
A
— 3 m/s²
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Q. If a 2 kg object is subjected to a net force of 6 N, what is its acceleration?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Using F = ma, we have a = F/m = 6 N / 2 kg = 3 m/s².
Correct Answer:
B
— 3 m/s²
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Q. If a 3 kg object is in free fall, what is the force acting on it due to gravity?
A.
3 N
B.
9 N
C.
30 N
D.
None of the above
Show solution
Solution
Force due to gravity F = mg = 3 kg * 9.8 m/s² = 29.4 N, approximately 9 N for simplification.
Correct Answer:
B
— 9 N
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Q. If a 3 kg object is moving with a speed of 4 m/s and comes to a stop, what is the work done by friction?
A.
-24 J
B.
-48 J
C.
0 J
D.
24 J
Show solution
Solution
Initial kinetic energy = 0.5 × m × v² = 0.5 × 3 kg × (4 m/s)² = 24 J. Work done by friction = -24 J.
Correct Answer:
B
— -48 J
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Q. If a 3 kg object is moving with a speed of 4 m/s and comes to a stop, what is the work done by the friction?
A.
-24 J
B.
-48 J
C.
-12 J
D.
-36 J
Show solution
Solution
Initial kinetic energy = 0.5 × 3 kg × (4 m/s)² = 24 J. Work done by friction = -24 J.
Correct Answer:
B
— -48 J
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Q. If a 3 kg object is moving with a speed of 4 m/s and comes to a stop, what is the work done by the friction force?
A.
-24 J
B.
-48 J
C.
-72 J
D.
-96 J
Show solution
Solution
Initial kinetic energy = 0.5 × 3 kg × (4 m/s)² = 24 J. Work done by friction = -24 J.
Correct Answer:
B
— -48 J
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Q. If a 3 kg object is moving with a speed of 4 m/s, what is the total mechanical energy if it is at a height of 2 m?
A.
30 J
B.
40 J
C.
50 J
D.
60 J
Show solution
Solution
Total mechanical energy = K.E + P.E = 0.5 × 3 kg × (4 m/s)² + 3 kg × 9.8 m/s² × 2 m = 24 J + 58.8 J = 82.8 J.
Correct Answer:
C
— 50 J
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Q. If a 3 kg object is moving with a velocity of 4 m/s, what is its momentum?
A.
12 kg m/s
B.
6 kg m/s
C.
8 kg m/s
D.
10 kg m/s
Show solution
Solution
Momentum (p) = m * v = 3 kg * 4 m/s = 12 kg m/s
Correct Answer:
A
— 12 kg m/s
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Q. If a 4 kg object is acted upon by a net force of 16 N, what is its acceleration?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Using F = ma, we have a = F/m = 16 N / 4 kg = 4 m/s².
Correct Answer:
C
— 4 m/s²
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Q. If a 4 kg object is at rest and a net force of 8 N is applied, what will be its velocity after 2 seconds?
A.
4 m/s
B.
2 m/s
C.
1 m/s
D.
0 m/s
Show solution
Solution
Using F = ma, a = F/m = 8 N / 4 kg = 2 m/s². Velocity after 2 seconds = a * t = 2 m/s² * 2 s = 4 m/s.
Correct Answer:
B
— 2 m/s
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Q. If a 4 kg object is moving with a constant velocity, what can be said about the net force acting on it?
A.
It is zero
B.
It is equal to its weight
C.
It is equal to the applied force
D.
It is maximum
Show solution
Solution
According to Newton's first law, if an object is moving with constant velocity, the net force acting on it is zero.
Correct Answer:
A
— It is zero
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