Undergraduate MCQ & Objective Questions
The undergraduate level is a crucial phase in a student's academic journey, especially for those preparing for school and competitive exams. Mastering this stage can significantly enhance your understanding and retention of key concepts. Practicing MCQs and objective questions is essential, as it not only helps in reinforcing knowledge but also boosts your confidence in tackling important questions during exams.
What You Will Practise Here
Fundamental concepts in Mathematics and Science
Key definitions and theories across various subjects
Important formulas and their applications
Diagrams and graphical representations
Critical thinking and problem-solving techniques
Subject-specific MCQs designed for competitive exams
Revision of essential topics for better retention
Exam Relevance
Undergraduate topics are integral to various examinations such as CBSE, State Boards, NEET, and JEE. These subjects often feature a mix of conceptual and application-based questions. Common patterns include multiple-choice questions that assess both theoretical knowledge and practical application, making it vital for students to be well-versed in undergraduate concepts.
Common Mistakes Students Make
Overlooking the importance of understanding concepts rather than rote memorization
Misinterpreting questions due to lack of careful reading
Neglecting to practice numerical problems that require application of formulas
Failing to review mistakes made in previous practice tests
FAQs
Question: What are some effective strategies for solving undergraduate MCQ questions?Answer: Focus on understanding the concepts, practice regularly, and review your answers to learn from mistakes.
Question: How can I improve my speed in answering objective questions?Answer: Time yourself while practicing and gradually increase the number of questions you attempt in a set time.
Start your journey towards mastering undergraduate subjects today! Solve practice MCQs and test your understanding to ensure you are well-prepared for your exams. Your success is just a question away!
Q. What is the general formula for aldehydes? (2023)
A.
C_nH_(2n)
B.
C_nH_(2n+1)CHO
C.
C_nH_(2n+2)
D.
C_nH_(2n-1)CHO
Show solution
Solution
The general formula for aldehydes is C_nH_(2n+1)CHO, where n is the number of carbon atoms.
Correct Answer:
B
— C_nH_(2n+1)CHO
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Q. What is the general formula for secondary amines? (2021) 2021
A.
RNH2
B.
R2NH
C.
R3N
D.
RNH
Show solution
Solution
The general formula for secondary amines is R2NH, where R represents an alkyl or aryl group.
Correct Answer:
B
— R2NH
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Q. What is the general formula for secondary amines? (2023)
A.
RNH2
B.
R2NH
C.
R3N
D.
RNH
Show solution
Solution
The general formula for secondary amines is R2NH, where R represents an alkyl group.
Correct Answer:
B
— R2NH
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Q. What is the general solution of the equation y' + 4y = 0?
A.
y = Ce^(-4x)
B.
y = Ce^(4x)
C.
y = 4x + C
D.
y = Cx^4
Show solution
Solution
This is a separable equation, and integrating gives y = Ce^(-4x).
Correct Answer:
A
— y = Ce^(-4x)
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Q. What is the general solution of the equation y' = 4y + 3?
A.
y = Ce^(4x) - 3/4
B.
y = Ce^(4x) + 3/4
C.
y = 3e^(4x)
D.
y = Ce^(3x) + 4
Show solution
Solution
The integrating factor is e^(-4x). The solution is y = Ce^(4x) + 3/4.
Correct Answer:
B
— y = Ce^(4x) + 3/4
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Q. What is the general solution of the equation y'' - 3y' + 2y = 0?
A.
y = C1 e^(x) + C2 e^(2x)
B.
y = C1 e^(2x) + C2 e^(x)
C.
y = C1 e^(3x) + C2 e^(0)
D.
y = C1 e^(0) + C2 e^(3x)
Show solution
Solution
The characteristic equation is r^2 - 3r + 2 = 0, which factors to (r - 1)(r - 2) = 0. Thus, the general solution is y = C1 e^(2x) + C2 e^(x).
Correct Answer:
B
— y = C1 e^(2x) + C2 e^(x)
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Q. What is the general solution of the equation y'' - 4y' + 4y = 0?
A.
y = (C1 + C2x)e^(2x)
B.
y = C1 e^(2x) + C2 e^(-2x)
C.
y = C1 e^(4x) + C2 e^(-4x)
D.
y = C1 cos(2x) + C2 sin(2x)
Show solution
Solution
The characteristic equation has a repeated root r = 2. The general solution is y = (C1 + C2x)e^(2x).
Correct Answer:
A
— y = (C1 + C2x)e^(2x)
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Q. What is the genetic material in most living organisms? (2023)
A.
RNA
B.
DNA
C.
Protein
D.
Carbohydrate
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Solution
DNA (deoxyribonucleic acid) is the genetic material that carries the instructions for life.
Correct Answer:
B
— DNA
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Q. What is the geometry of a molecule with four bonding pairs and no lone pairs around the central atom? (2023)
A.
Linear
B.
Trigonal planar
C.
Tetrahedral
D.
Octahedral
Show solution
Solution
The geometry is tetrahedral when there are four bonding pairs and no lone pairs around the central atom.
Correct Answer:
C
— Tetrahedral
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Q. What is the geometry of a molecule with four bonding pairs and no lone pairs? (2023)
A.
Linear
B.
Trigonal planar
C.
Tetrahedral
D.
Octahedral
Show solution
Solution
A molecule with four bonding pairs and no lone pairs has a tetrahedral geometry.
Correct Answer:
C
— Tetrahedral
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Q. What is the geometry of a molecule with two bonding pairs and no lone pairs on the central atom? (2023)
A.
Linear
B.
Trigonal planar
C.
Tetrahedral
D.
Bent
Show solution
Solution
The geometry is linear when there are two bonding pairs and no lone pairs on the central atom.
Correct Answer:
A
— Linear
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Q. What is the geometry of the complex ion [Ag(NH3)2]+? (2019) 2019
A.
Tetrahedral
B.
Square planar
C.
Octahedral
D.
Linear
Show solution
Solution
The complex [Ag(NH3)2]+ has a linear geometry due to the presence of two ligands around the silver ion.
Correct Answer:
D
— Linear
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Q. What is the gravitational field strength (g) at a distance r from the center of a planet of mass M? (2023)
A.
GM/r^2
B.
GM/r
C.
GMr^2
D.
G/Mr^2
Show solution
Solution
The gravitational field strength at a distance r from the center of a planet is given by g = GM/r^2.
Correct Answer:
A
— GM/r^2
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Q. What is the gravitational field strength at a distance of 10 m from a mass of 100 kg? (G = 6.67 × 10^-11 N m²/kg²)
A.
6.67 × 10^-10 N/kg
B.
6.67 × 10^-9 N/kg
C.
6.67 × 10^-8 N/kg
D.
6.67 × 10^-7 N/kg
Show solution
Solution
g = G * M / r² = (6.67 × 10^-11) * (100) / (10²) = 6.67 × 10^-10 N/kg
Correct Answer:
A
— 6.67 × 10^-10 N/kg
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Q. What is the gravitational field strength at a distance of 3R from the center of the Earth? (R = radius of the Earth) (2022)
A.
g/3
B.
g/9
C.
g/6
D.
g/12
Show solution
Solution
Gravitational field strength decreases with the square of the distance. At 3R, it is g/9.
Correct Answer:
B
— g/9
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Q. What is the gravitational field strength at a distance r from a mass M? (2022)
A.
GM/r
B.
GM/r^2
C.
Gm/r^2
D.
Gm/r
Show solution
Solution
The gravitational field strength (g) at a distance r from a mass M is given by g = GM/r^2.
Correct Answer:
B
— GM/r^2
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Q. What is the gravitational force acting on a 50 kg object at the surface of the Earth?
A.
490 N
B.
500 N
C.
510 N
D.
520 N
Show solution
Solution
Weight = mass * g = 50 kg * 9.8 m/s² = 490 N
Correct Answer:
A
— 490 N
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Q. What is the gravitational force acting on a 50 kg object on the surface of the Earth?
A.
490 N
B.
50 N
C.
5 N
D.
500 N
Show solution
Solution
Weight W = m * g = 50 kg * 9.8 m/s² = 490 N.
Correct Answer:
A
— 490 N
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Q. What is the gravitational force between two 1 kg masses placed 1 meter apart? (G = 6.67 × 10^-11 N m²/kg²)
A.
6.67 × 10^-11 N
B.
1.67 × 10^-10 N
C.
6.67 × 10^-10 N
D.
0 N
Show solution
Solution
F = G * (m1 * m2) / r² = (6.67 × 10^-11) * (1 * 1) / (1²) = 6.67 × 10^-11 N
Correct Answer:
A
— 6.67 × 10^-11 N
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Q. What is the gravitational force between two 10 kg masses separated by a distance of 2 m?
A.
0.25 N
B.
5 N
C.
10 N
D.
20 N
Show solution
Solution
Using Newton's law of gravitation: F = G(m1*m2)/r² = (6.674 × 10⁻¹¹)(10*10)/(2²) = 0.25 N.
Correct Answer:
A
— 0.25 N
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Q. What is the gravitational force between two objects of mass 5 kg and 10 kg separated by a distance of 2 m? (G = 6.67 × 10^-11 N m²/kg²)
A.
1.67 × 10^-10 N
B.
1.25 × 10^-10 N
C.
1.00 × 10^-10 N
D.
2.00 × 10^-10 N
Show solution
Solution
Using the formula F = G * (m1 * m2) / r², we have F = (6.67 × 10^-11) * (5 * 10) / (2²) = 1.67 × 10^-10 N.
Correct Answer:
A
— 1.67 × 10^-10 N
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Q. What is the gravitational force between two objects of mass m1 and m2 separated by a distance r? (2021)
A.
G * (m1 * m2) / r^2
B.
G * (m1 + m2) / r^2
C.
G * (m1 - m2) / r^2
D.
G * (m1 * m2) * r^2
Show solution
Solution
The gravitational force is given by Newton's law of gravitation: F = G * (m1 * m2) / r^2.
Correct Answer:
A
— G * (m1 * m2) / r^2
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Q. What is the gravitational potential energy of a 10 kg mass at a height of 10 m?
A.
100 J
B.
200 J
C.
500 J
D.
1000 J
Show solution
Solution
Gravitational potential energy (PE) is given by PE = mgh. Here, PE = 10 kg * 9.81 m/s² * 10 m = 981 J.
Correct Answer:
D
— 1000 J
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Q. What is the gravitational potential energy of a 10 kg mass at a height of 5 m? (2019)
A.
50 J
B.
100 J
C.
150 J
D.
200 J
Show solution
Solution
Gravitational potential energy (PE) = m * g * h = 10 kg * 9.81 m/s² * 5 m = 490.5 J.
Correct Answer:
B
— 100 J
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Q. What is the gravitational potential energy of a 10 kg object at a height of 10 m?
A.
100 J
B.
200 J
C.
500 J
D.
1000 J
Show solution
Solution
Gravitational potential energy (PE) is given by the formula PE = mgh. Here, PE = 10 kg * 9.8 m/s² * 10 m = 980 J, which rounds to approximately 1000 J.
Correct Answer:
B
— 200 J
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Q. What is the gravitational potential energy of a 10 kg object at a height of 5 m? (g = 9.8 m/s²)
A.
49 J
B.
98 J
C.
245 J
D.
490 J
Show solution
Solution
Gravitational potential energy (PE) is given by PE = mgh. Here, m = 10 kg, g = 9.8 m/s², and h = 5 m. PE = 10 * 9.8 * 5 = 490 J.
Correct Answer:
B
— 98 J
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Q. What is the gravitational potential energy of a 2 kg mass at a height of 10 m above the ground? (Take g = 9.8 m/s²) (2023)
A.
196 J
B.
98 J
C.
20 J
D.
78 J
Show solution
Solution
Gravitational potential energy (U) = mgh = 2 kg * 9.8 m/s² * 10 m = 196 J.
Correct Answer:
A
— 196 J
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Q. What is the gravitational potential energy of a 2 kg object at a height of 10 m? (2023)
A.
20 J
B.
15 J
C.
10 J
D.
25 J
Show solution
Solution
Gravitational potential energy (PE) = mgh = 2 kg × 9.8 m/s² × 10 m = 196 J.
Correct Answer:
A
— 20 J
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Q. What is the gravitational potential energy of a 5 kg object at a height of 10 m?
A.
50 J
B.
100 J
C.
150 J
D.
200 J
Show solution
Solution
Gravitational potential energy (PE) = m * g * h = 5 kg * 9.8 m/s² * 10 m = 490 J.
Correct Answer:
B
— 100 J
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Q. What is the ground state electron configuration of an oxygen atom? (2023)
A.
1s² 2s² 2p⁴
B.
1s² 2s² 2p²
C.
1s² 2s² 2p⁶
D.
1s² 2s¹ 2p⁵
Show solution
Solution
Oxygen has 8 electrons, and its ground state electron configuration is 1s² 2s² 2p⁴.
Correct Answer:
A
— 1s² 2s² 2p⁴
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