Major Competitive Exams

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Major Competitive Exams

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Major Competitive Exams MCQ & Objective Questions

Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.

What You Will Practise Here

Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams

Exam Relevance

The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.

Common Mistakes Students Make

Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam

FAQs

Question: How can I improve my performance in Major Competitive Exams?
Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.

Question: What types of questions should I focus on for these exams?
Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.

Question: Are there specific strategies for tackling objective questions?
Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.

Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!

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Q. A policy aims to reduce carbon emissions by 25% from a baseline of 800,000 tons. What is the target emission level?

A. 600,000 tons
B. 700,000 tons
C. 800,000 tons
D. 500,000 tons

Solution

Target emissions = Baseline - (25% of Baseline) = 800,000 - (0.25 * 800,000) = 600,000 tons.

Correct Answer: A — 600,000 tons

Q. A political party has 150 seats in the parliament. If they lose 20% of their seats in the next election, how many seats will they have left? (2020)

A. 120
B. 130
C. 140
D. 150

Solution

20% of 150 = 0.20 * 150 = 30. Seats left = 150 - 30 = 120.

Correct Answer: A — 120

Q. A political party received 45% of the votes in an election. If 2,000,000 votes were cast, how many votes did the party receive?

A. 900,000
B. 800,000
C. 700,000
D. 1,000,000

Solution

45% of 2,000,000 is calculated as 0.45 * 2,000,000 = 900,000.

Correct Answer: A — 900,000

Q. A political party's membership increased from 50,000 to 75,000 in one year. What is the percentage increase in membership?

A. 50%
B. 25%
C. 30%
D. 40%

Solution

Percentage increase = ((75,000 - 50,000) / 50,000) * 100 = 50%.

Correct Answer: A — 50%

Q. A population of a town decreases by 15% in one year. If the initial population was 2000, what is the population after one year?

A. 1700
B. 1800
C. 1900
D. 2000

Solution

Population after decrease = Initial Population - (15% of Initial Population) = 2000 - (0.15 * 2000) = 2000 - 300 = 1700.

Correct Answer: A — 1700

Q. A population of a town decreases by 15% in one year. If the population was 2000, what is the population after the decrease?

A. 1700
B. 1800
C. 1900
D. 1600

Solution

New Population = Original Population - (15% of Original Population) = 2000 - (0.15 * 2000) = 2000 - 300 = 1700.

Correct Answer: B — 1800

Q. A population of a town increased from 800 to 1000. What is the percentage increase?

A. 25%
B. 20%
C. 15%
D. 30%

Solution

Percentage increase = ((1000 - 800) / 800) * 100 = 25%.

Correct Answer: B — 20%

Q. A population of a town increases by 15% every year. If the current population is 2000, what will be the population after one year?

A. 2300
B. 2200
C. 2150
D. 2100

Solution

Population after one year = Current Population + (15% of Current Population) = 2000 + (0.15 * 2000) = 2000 + 300 = 2300.

Correct Answer: B — 2200

Q. A potentiometer is used to compare two emf sources. If the first source gives a balance length of 60cm and the second gives 90cm, what is the ratio of their emfs?

A. 2:3
B. 3:2
C. 1:1
D. 4:5

Solution

The ratio of emfs is equal to the ratio of the balance lengths, so it is 60cm:90cm = 2:3.

Correct Answer: B — 3:2

Q. A potentiometer is used to compare two EMFs. If the known EMF is 6V and the length of the wire is 120 cm, what is the potential gradient if the length of the wire is used to balance an unknown EMF of 4V?

A. 0.05 V/cm
B. 0.03 V/cm
C. 0.04 V/cm
D. 0.02 V/cm

Solution

The potential gradient is calculated as (6V / 120 cm) = 0.05 V/cm. For the unknown EMF of 4V, the length used would be (4V / 0.05 V/cm) = 80 cm.

Correct Answer: C — 0.04 V/cm

Q. A potentiometer wire has a length of 10 m and a potential difference of 5 V across it. What is the potential gradient?

A. 0.5 V/m
B. 1 V/m
C. 2 V/m
D. 5 V/m

Solution

The potential gradient is calculated as the potential difference divided by the length of the wire: 5 V / 10 m = 0.5 V/m.

Correct Answer: A — 0.5 V/m

Q. A potentiometer wire has a resistance of 10 ohms and is connected to a 5 V battery. What is the current flowing through the wire?

A. 0.5 A
B. 1 A
C. 2 A
D. 5 A

Solution

Using Ohm's law (V = IR), the current can be calculated as I = V/R = 5 V / 10 ohms = 0.5 A.

Correct Answer: B — 1 A

Q. A potentiometer wire has a uniform cross-section and a length of 10 m. If a potential difference of 5 V is applied, what is the potential gradient?

A. 0.5 V/m
B. 1 V/m
C. 2 V/m
D. 5 V/m

Solution

The potential gradient is calculated as V/L = 5 V / 10 m = 0.5 V/m.

Correct Answer: B — 1 V/m

Q. A potentiometer wire has a uniform cross-section and a potential difference of 12V across it. If the length of the wire is 6m, what is the potential gradient?

A. 2 V/m
B. 4 V/m
C. 6 V/m
D. 8 V/m

Solution

Potential gradient = Voltage / Length = 12V / 6m = 2 V/m.

Correct Answer: B — 4 V/m

Q. A potentiometer wire has a uniform cross-section and a total length of 10 m. If a potential difference of 5 V is applied across it, what is the potential gradient?

A. 0.5 V/m
B. 1 V/m
C. 2 V/m
D. 5 V/m

Solution

The potential gradient is calculated as V/L = 5 V / 10 m = 0.5 V/m.

Correct Answer: B — 1 V/m

Q. A potentiometer wire is made of constantan. What is the advantage of using this material?

A. High conductivity
B. Low temperature coefficient
C. High resistance
D. Low cost

Solution

Constantan has a low temperature coefficient, making it stable for accurate measurements.

Correct Answer: B — Low temperature coefficient

Q. A principal amount of $1200 is invested at a rate of 10% per annum for 3 years. What is the total amount after 3 years?

A. $1500
B. $1320
C. $1440
D. $1600

Solution

Total Amount = P + SI = 1200 + (1200 * 0.10 * 3) = 1200 + 360 = $1440

Correct Answer: C — $1440

Q. A principal amount of $8000 is invested at a compound interest rate of 7% per annum. What will be the total amount after 3 years?

A. $9784.00
B. $9000.00
C. $8500.00
D. $9500.00

Solution

Amount = P(1 + r)^n = 8000(1 + 0.07)^3 = 8000(1.225043) = $9800.34.

Correct Answer: A — $9784.00

Q. A principal of $2000 is invested at a compound interest rate of 5% per annum. What will be the total amount after 2 years?

A. $2205.00
B. $2100.00
C. $2150.00
D. $2250.00

Solution

Amount = P(1 + r)^n = 2000(1 + 0.05)^2 = 2000(1.1025) = $2205.00.

Correct Answer: A — $2205.00

Q. A principal of $2000 is invested for 5 years at a simple interest rate of 3%. What is the total amount at the end of 5 years?

A. $2300
B. $2400
C. $2500
D. $2600

Solution

Total Amount = P + Simple Interest = 2000 + (2000 * 0.03 * 5) = 2000 + 300 = 2300.

Correct Answer: B — $2400

Q. A prize of $1200 is to be distributed among three winners in the ratio 2:3:5. How much will the winner with the highest share receive? (2020)

A. $600
B. $500
C. $400
D. $300

Solution

Total parts = 2 + 3 + 5 = 10. Highest share = (5/10) * 1200 = $600.

Correct Answer: A — $600

Q. A prize of $1500 is to be divided among three students in the ratio 2:3:5. How much does the student with the largest share receive?

A. $500
B. $600
C. $750
D. $900

Solution

Total parts = 2 + 3 + 5 = 10. Largest share = (5/10) * 1500 = $750.

Correct Answer: C — $750

Q. A prize of $1500 is to be divided among three students in the ratio 2:3:5. How much will the student with the largest share receive?

A. $500
B. $600
C. $750
D. $900

Solution

Total parts = 2 + 3 + 5 = 10. Largest share = (5/10) * 1500 = $750.

Correct Answer: B — $600

Q. A prize of $3000 is to be divided among 3 winners in the ratio 2:3:5. How much does the second winner receive? (2019)

A. $600
B. $900
C. $1200
D. $1500

Solution

Total parts = 2 + 3 + 5 = 10. Second winner's share = (3/10) * 3000 = $900.

Correct Answer: B — $900

Q. A prize of $3000 is to be divided among 3 winners in the ratio 2:3:5. How much does the winner with the largest share receive? (2019)

A. $600
B. $900
C. $1200
D. $1500

Solution

Total parts = 2 + 3 + 5 = 10. The largest share = (5/10) * 3000 = $1500.

Correct Answer: C — $1200

Q. A product costs $500 today. If the inflation rate is 3% per year, what will be the cost of the product in 5 years?

A. $575
B. $600
C. $615
D. $625

Solution

Cost in 5 years = 500 * (1 + 0.03)^5 = 500 * 1.159274 = $579.64 (approx $625)

Correct Answer: D — $625

Q. A product costs $80 after a 20% discount. What was the original price?

A. $100
B. $90
C. $80
D. $70

Solution

Let the original price be x. Then, x - 0.2x = 80, so 0.8x = 80, thus x = 100.

Correct Answer: A — $100

Q. A product is bought for $120 and sold for $144. What is the profit percentage?

A. 15%
B. 20%
C. 25%
D. 30%

Solution

Profit = Selling Price - Cost Price = 144 - 120 = 24. Profit Percentage = (Profit/Cost Price) * 100 = (24/120) * 100 = 20%.

Correct Answer: B — 20%

Q. A product is bought for $150 and sold for $180. What is the profit in dollars?

A. $20
B. $25
C. $30
D. $35

Solution

Profit = Selling Price - Cost Price = 180 - 150 = $30.

Correct Answer: A — $20

Q. A product is bought for $200 and sold for $240. What is the profit percentage?

A. 15%
B. 20%
C. 25%
D. 30%

Solution

Profit = Selling Price - Cost Price = 240 - 200 = 40. Profit Percentage = (Profit/Cost Price) * 100 = (40/200) * 100 = 20%.

Correct Answer: B — 20%

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