The potential drop is calculated using Ohm's law: V = IR = 0.5 A * 10 ohms = 5 V.

Higher resistivity increases the resistance of the wire, which can lead to a larger voltage drop along the wire, potentially affecting the accuracy of the measurements.

Higher resistivity increases the resistance of the wire, which can decrease the potential gradient for a given voltage.

Higher resistivity increases the resistance of the wire, which can lead to a decrease in current and thus affect the potential gradient.

Increasing the length of the wire increases the accuracy of voltage measurement due to a smaller potential gradient.

The jockey is used to touch the wire and find the null point where the galvanometer shows zero deflection, indicating balance.

The voltage drop per meter is calculated as V/L = 10 V / 20 m = 0.5 V/m.

If the wire has a uniform cross-section, the potential gradient remains uniform along its length.

Higher resistivity increases the resistance of the wire, which decreases the current for a given voltage, thus increasing the potential gradient.

The jockey is used to find the balance point where the potential difference is equal to the reference voltage.

The effect of temperature on resistance measurements in a Wheatstone bridge depends on the material of the resistors, as different materials have different temperature coefficients.

In general, the resistance of conductors increases with temperature due to increased atomic vibrations.

Temperature changes can affect the resistance values of the resistors, thus affecting the balance condition.

Non-ideal resistors can introduce errors in the measurements due to their tolerance and temperature coefficients.

When the angle of incidence equals the angle of emergence, the angle of deviation is equal to the angle of the prism.

The minimum angle of deviation (D) for a prism is given by D = A, where A is the angle of the prism. Therefore, for a 60-degree prism, the minimum angle of deviation is 30 degrees.

Using the first law of thermodynamics, ΔU = Q - W, we have 40 J = 100 J - W, thus W = 100 J - 40 J = 60 J.

Using the first law of thermodynamics, ΔU = Q - W. Rearranging gives W = Q - ΔU. Here, W = 300 J - 100 J = 200 J.

Using the first law of thermodynamics, ΔU = Q - W = 300 J - 100 J = 200 J.

Using the first law of thermodynamics, ΔU = Q - W = 300 J - 100 J = 200 J.

In a refrigerator, work is done on the system to transfer heat from a colder body to a hotter body, which is against the natural flow of heat.

The electric flux Φ through a surface area A in a uniform electric field E is given by Φ = EA when the surface is perpendicular to the field.

The electric flux is maximum when the angle between the electric field and the normal to the surface is 0°, as Φ = E·A·cos(θ).

A plane is the simplest Gaussian surface for uniform electric fields, as it allows for straightforward calculation of flux.

Since L = Iω, if L is doubled and I remains constant, then ω must also double.

Torque (τ) = F × r = 30 N × 1.5 m = 45 Nm.

Torque (τ) = F × r = 30 N × 2 m = 60 Nm.

To balance the seesaw, the other child must exert an equal torque of 30 N·m.

The energy required to move an electron from the valence band to the conduction band is known as the band gap energy.

Total resistance R = 2Ω + 3Ω + 5Ω = 10Ω. Current I = V / R = 12V / 10Ω = 1.2A.