Major Competitive Exams MCQ & Objective Questions
Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.
What You Will Practise Here
Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams
Exam Relevance
The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.
Common Mistakes Students Make
Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam
FAQs
Question: How can I improve my performance in Major Competitive Exams?Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.
Question: What types of questions should I focus on for these exams?Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.
Question: Are there specific strategies for tackling objective questions?Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.
Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!
Q. A 3 kg object is dropped from a height of 10 m. What is its potential energy at the top? (g = 9.8 m/s²)
A.
294 J
B.
30 J
C.
39.2 J
D.
19.6 J
Show solution
Solution
Potential Energy (PE) = m × g × h = 3 kg × 9.8 m/s² × 10 m = 294 J.
Correct Answer:
A
— 294 J
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Q. A 3 kg object is dropped from a height of 10 m. What is the potential energy at the top? (2022)
A.
30 J
B.
60 J
C.
90 J
D.
120 J
Show solution
Solution
Potential Energy = mass × g × height = 3 kg × 10 m/s² × 10 m = 300 J
Correct Answer:
C
— 90 J
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Q. A 3 kg object is dropped from a height of 12 m. What is its speed just before it hits the ground? (g = 10 m/s²) (2023)
A.
15 m/s
B.
10 m/s
C.
12 m/s
D.
20 m/s
Show solution
Solution
Using conservation of energy, PE = KE: mgh = 1/2 mv²; v = sqrt(2gh) = sqrt(2 * 10 m/s² * 12 m) = 15.49 m/s
Correct Answer:
A
— 15 m/s
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Q. A 3 kg object is dropped from a height of 12 m. What is the potential energy at the top?
A.
30 J
B.
36 J
C.
60 J
D.
120 J
Show solution
Solution
Potential energy = mgh = 3 kg × 9.8 m/s² × 12 m = 352.8 J.
Correct Answer:
D
— 120 J
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Q. A 3 kg object is dropped from a height of 15 m. What is its potential energy at the top? (g = 9.8 m/s²)
A.
441 J
B.
294 J
C.
147 J
D.
0 J
Show solution
Solution
Potential Energy (PE) = m * g * h = 3 kg * 9.8 m/s² * 15 m = 441 J
Correct Answer:
B
— 294 J
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Q. A 3 kg object is dropped from a height of 15 m. What is the potential energy at the top?
A.
30 J
B.
45 J
C.
60 J
D.
75 J
Show solution
Solution
Potential energy = mass × g × height = 3 kg × 9.8 m/s² × 15 m = 441 J.
Correct Answer:
D
— 75 J
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Q. A 3 kg object is dropped from a height of 5 m. What is the potential energy at the height?
A.
15 J
B.
30 J
C.
45 J
D.
60 J
Show solution
Solution
Potential energy = mass × g × height = 3 kg × 9.8 m/s² × 5 m = 147 J.
Correct Answer:
B
— 30 J
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Q. A 3 kg object is dropped from a height of 5 m. What is the potential energy at the top? (g = 9.8 m/s²)
A.
14.7 J
B.
29.4 J
C.
39.2 J
D.
49.05 J
Show solution
Solution
PE = mgh = 3 kg × 9.8 m/s² × 5 m = 147 J.
Correct Answer:
C
— 39.2 J
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Q. A 3 kg object is in free fall. What is the force acting on it due to gravity?
A.
3 N
B.
9 N
C.
30 N
D.
0 N
Show solution
Solution
The force due to gravity is F = mg = 3 kg * 9.8 m/s² = 29.4 N, approximately 30 N.
Correct Answer:
B
— 9 N
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Q. A 3 kg object is lifted to a height of 4 m. What is the gravitational potential energy gained? (2023)
A.
120 J
B.
60 J
C.
30 J
D.
90 J
Show solution
Solution
Potential Energy (PE) = m * g * h = 3 kg * 9.8 m/s^2 * 4 m = 117.6 J (approximately 120 J)
Correct Answer:
A
— 120 J
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Q. A 3 kg object is lifted to a height of 4 m. What is the work done against gravity?
A.
12 J
B.
24 J
C.
36 J
D.
48 J
Show solution
Solution
Work done = mgh = 3 * 9.8 * 4 = 117.6 J.
Correct Answer:
B
— 24 J
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Q. A 3 kg object is lifted to a height of 4 m. What is the work done against gravity? (g = 9.8 m/s²)
A.
117.6 J
B.
29.4 J
C.
39.2 J
D.
78.4 J
Show solution
Solution
Work done (W) = mgh = 3 kg × 9.8 m/s² × 4 m = 117.6 J.
Correct Answer:
A
— 117.6 J
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Q. A 3 kg object is lifted to a height of 5 m. What is the work done against gravity? (g = 9.8 m/s²)
A.
147 J
B.
294 J
C.
441 J
D.
588 J
Show solution
Solution
Work done = mgh = 3 kg × 9.8 m/s² × 5 m = 147 J.
Correct Answer:
B
— 294 J
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Q. A 3 kg object is moving in a circular path of radius 2 m with a speed of 4 m/s. What is the centripetal force acting on it?
A.
6 N
B.
12 N
C.
24 N
D.
36 N
Show solution
Solution
Centripetal force F = mv²/r = 3 kg * (4 m/s)² / 2 m = 24 N.
Correct Answer:
B
— 12 N
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Q. A 3 kg object is moving in a straight line with a constant velocity of 5 m/s. What is the net force acting on the object?
A.
0 N
B.
3 N
C.
15 N
D.
5 N
Show solution
Solution
Since the object is moving with constant velocity, the net force acting on it is 0 N.
Correct Answer:
A
— 0 N
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Q. A 3 kg object is moving with a speed of 10 m/s. What is its kinetic energy?
A.
150 J
B.
300 J
C.
450 J
D.
600 J
Show solution
Solution
Kinetic energy = 0.5mv² = 0.5 * 3 * (10)² = 150 J.
Correct Answer:
B
— 300 J
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Q. A 3 kg object is moving with a speed of 10 m/s. What is its total mechanical energy?
A.
150 J
B.
300 J
C.
450 J
D.
600 J
Show solution
Solution
Total mechanical energy = KE + PE. Assuming PE = 0, KE = 0.5mv² = 0.5 * 3 * (10)² = 150 J.
Correct Answer:
B
— 300 J
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Q. A 3 kg object is moving with a speed of 4 m/s. If a net work of 24 J is done on the object, what will be its final speed?
A.
4 m/s
B.
6 m/s
C.
8 m/s
D.
10 m/s
Show solution
Solution
Initial kinetic energy = 0.5 × m × v^2 = 0.5 × 3 kg × (4 m/s)^2 = 24 J. Final kinetic energy = Initial + Work done = 24 J + 24 J = 48 J. Final speed = √(2 × KE/m) = √(2 × 48 J / 3 kg) = 6.93 m/s.
Correct Answer:
C
— 8 m/s
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Q. A 3 kg object is moving with a speed of 4 m/s. What is its kinetic energy?
A.
12 J
B.
24 J
C.
36 J
D.
48 J
Show solution
Solution
Kinetic energy = 0.5mv² = 0.5 * 3 * (4)² = 24 J.
Correct Answer:
B
— 24 J
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Q. A 3 kg object is moving with a speed of 4 m/s. What is its total mechanical energy?
A.
24 J
B.
32 J
C.
48 J
D.
60 J
Show solution
Solution
Total mechanical energy = KE + PE. Assuming it is at ground level, PE = 0. KE = 0.5mv² = 0.5 * 3 * (4)² = 24 J.
Correct Answer:
B
— 32 J
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Q. A 3 kg object is moving with a speed of 5 m/s. What is its kinetic energy?
A.
15 J
B.
25 J
C.
35 J
D.
45 J
Show solution
Solution
Kinetic energy is given by KE = 0.5mv² = 0.5 * 3 * (5)² = 37.5 J, approximately 35 J.
Correct Answer:
B
— 25 J
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Q. A 3 kg object is moving with a velocity of 2 m/s. What is its kinetic energy? (2021)
A.
6 J
B.
12 J
C.
3 J
D.
9 J
Show solution
Solution
Kinetic Energy (KE) = 1/2 * m * v^2 = 1/2 * 3 kg * (2 m/s)^2 = 6 J
Correct Answer:
B
— 12 J
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Q. A 3 kg object is moving with a velocity of 4 m/s. If a force of 12 N is applied in the opposite direction, what will be its velocity after 2 seconds?
A.
0 m/s
B.
2 m/s
C.
4 m/s
D.
6 m/s
Show solution
Solution
Acceleration = F/m = -12 N / 3 kg = -4 m/s². Change in velocity = a * t = -4 m/s² * 2 s = -8 m/s. Final velocity = 4 m/s - 8 m/s = -4 m/s (object stops).
Correct Answer:
B
— 2 m/s
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Q. A 3 kg object is moving with a velocity of 4 m/s. If it comes to a stop, what is the work done by the friction force?
A.
-24 J
B.
-48 J
C.
-12 J
D.
-36 J
Show solution
Solution
Work done by friction = - Kinetic Energy = - (0.5 × 3 kg × (4 m/s)²) = -24 J.
Correct Answer:
B
— -48 J
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Q. A 3 kg object is moving with a velocity of 4 m/s. What is its kinetic energy?
A.
12 J
B.
24 J
C.
36 J
D.
48 J
Show solution
Solution
Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 3 kg × (4 m/s)² = 24 J.
Correct Answer:
B
— 24 J
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Q. A 3 kg object is moving with a velocity of 4 m/s. What is its momentum?
A.
6 kg·m/s
B.
12 kg·m/s
C.
9 kg·m/s
D.
15 kg·m/s
Show solution
Solution
Momentum = mass × velocity = 3 kg × 4 m/s = 12 kg·m/s.
Correct Answer:
B
— 12 kg·m/s
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Q. A 3 kg object is moving with a velocity of 6 m/s. What is its kinetic energy?
A.
54 J
B.
36 J
C.
18 J
D.
72 J
Show solution
Solution
Kinetic Energy (KE) = 1/2 * m * v^2 = 1/2 * 3 * (6^2) = 54 J
Correct Answer:
B
— 36 J
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Q. A 3 kg object is moving with a velocity of 6 m/s. What is its momentum? (2021)
A.
18 kg m/s
B.
12 kg m/s
C.
9 kg m/s
D.
6 kg m/s
Show solution
Solution
Momentum (p) = mv = 3 kg * 6 m/s = 18 kg m/s
Correct Answer:
A
— 18 kg m/s
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Q. A 3 kg object is pushed with a force of 12 N over a distance of 4 m. If the object starts from rest, what is its final speed? (Assume no friction)
A.
2 m/s
B.
3 m/s
C.
4 m/s
D.
5 m/s
Show solution
Solution
Work done = Force × Distance = 12 N × 4 m = 48 J. Kinetic energy = 0.5 × mass × v²; 48 J = 0.5 × 3 kg × v²; v² = 32; v = 4 m/s.
Correct Answer:
C
— 4 m/s
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Q. A 3 kg object is pushed with a force of 12 N over a distance of 4 m. What is the net work done if friction does 8 J of work?
A.
28 J
B.
32 J
C.
36 J
D.
40 J
Show solution
Solution
Net work done = Work done by force - Work done against friction = (12 N × 4 m) - 8 J = 48 J - 8 J = 40 J.
Correct Answer:
B
— 32 J
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