The electric field strength E ∝ 1/r², so if distance is tripled, the field strength becomes 1/9 of the original.

The electric potential decreases as you move away from a positive charge.

When a charge moves against an electric field, its electric potential energy increases.

The electric potential energy of a system of charges decreases when they are brought closer together, especially if they are of opposite signs.

The electric potential energy increases as like charges repel each other.

The energy stored in a capacitor is given by U = 1/2 C V². If the voltage is doubled, the energy increases by a factor of four.

When a capacitor is fully charged, the potential difference across its plates becomes maximum and remains constant until it is discharged.

When a capacitor is fully charged, the voltage across it equals the supply voltage.

C = ε₀ * ε_r * A / d = (8.85 × 10^-12 F/m) * 5 * (0.01 m²) / (0.001 m) = 4.425 × 10^-10 F.

Capacitance C = ε₀ * A / d = (8.85 × 10^-12 F/m) * (0.1 m²) / (0.01 m) = 8.85 × 10^-10 F.

The capacitance C of a parallel plate capacitor is given by the formula C = ε₀ * A / d, where ε₀ is the permittivity of free space.

The capacitance C of a parallel plate capacitor is given by the formula C = ε₀A/d, where ε₀ is the permittivity of free space.

The electric field due to a negative charge points towards the charge.

The electric field due to a positive charge points away from the charge.

The electric field lines point away from a positive charge.

Inserting a dielectric material between the plates of a capacitor decreases the electric field due to polarization.

Inserting a dielectric material into a capacitor decreases the electric field inside the capacitor due to polarization.

The presence of a dielectric material increases the capacitance of a capacitor.

The presence of a dielectric material increases the capacitance of a capacitor.

Increasing the permittivity of the medium decreases the electric field due to a point charge, as E = Q/(4πε₀r²).

Increasing the plate area A of a capacitor increases its capacitance, as C is directly proportional to A.

Increasing the plate area A of a parallel plate capacitor increases its capacitance, as C = ε₀ * A / d.

The electric field due to a point charge decreases with distance, but the total flux remains constant as the charge is fixed.

The electric field due to a charged plane sheet is directly proportional to the surface charge density; increasing σ increases E.

Inserting a dielectric material increases the capacitance of the capacitor by a factor equal to the dielectric constant of the material.

The effect of temperature on capacitance depends on the dielectric material used in the capacitor.

The electric field due to an infinitely long charged wire is given by E = λ/(2πε₀d).

Electric field E = k * q / r^2 = (9 × 10^9) * (1 × 10^-6) / (1)^2 = 9 × 10^3 N/C.

The electric field at a distance r from a uniformly charged disk is given by E = σ/(2ε₀) * (1 - r/√(R² + r²)).

For r > R, the electric field behaves as if all the charge were concentrated at the center, thus E = Q/(4πε₀r²).