Current Electricity Study Materials for Competitive Exams

Current Electricity

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Q. In a circuit with a 10V battery and two resistors of 5 ohms each in series, what is the current flowing through the circuit?

A. 1 A
B. 2 A
C. 0.5 A
D. 5 A

Solution

Total resistance R_total = 5 + 5 = 10 ohms. Current I = V/R_total = 10V / 10 ohms = 1 A.

Correct Answer: B — 2 A

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Q. In a circuit with a 10V battery and two resistors of 5Ω each in series, what is the voltage across the second resistor?

A. 5V
B. 10V
C. 2.5V
D. 0V

Solution

In series, the voltage is divided equally: V2 = (R2 / (R1 + R2)) * Vtotal = (5 / (5 + 5)) * 10 = 5V.

Correct Answer: A — 5V

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Q. In a circuit with a 12 V battery and two resistors in series (4 ohms and 8 ohms), what is the voltage drop across the 8 ohm resistor?

A. 4 V
B. 8 V
C. 6 V
D. 12 V

Solution

The total resistance is 4 + 8 = 12 ohms. The current I = V / R = 12 V / 12 ohms = 1 A. The voltage drop across the 8 ohm resistor is V = I * R = 1 A * 8 ohms = 8 V.

Correct Answer: B — 8 V

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Q. In a circuit with a 12V battery and two resistors in parallel (4 ohms and 6 ohms), what is the total current supplied by the battery?

A. 3 A
B. 2 A
C. 1 A
D. 4 A

Solution

First, find the equivalent resistance: 1/R_eq = 1/4 + 1/6 = 5/12, so R_eq = 12/5 = 2.4 ohms. Then, using Ohm's law, I = V/R, we have I = 12V / 2.4 ohms = 5 A.

Correct Answer: A — 3 A

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Q. In a circuit with a 12V battery and two resistors in series (3 ohms and 6 ohms), what is the voltage drop across the 6 ohm resistor?

A. 8 V
B. 4 V
C. 6 V
D. 12 V

Solution

The total resistance is 9 ohms. The current is I = V/R = 12V / 9 ohms = 4/3 A. The voltage drop across the 6 ohm resistor is V = I * R = (4/3 A) * 6 ohms = 8 V.

Correct Answer: A — 8 V

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Q. In a circuit with a 12V battery and two resistors in series (4Ω and 8Ω), what is the current flowing through the circuit?

A. 0.5A
B. 1A
C. 1.5A
D. 2A

Solution

Total resistance R = R1 + R2 = 4Ω + 8Ω = 12Ω. Using Ohm's law, I = V/R = 12V / 12Ω = 1A.

Correct Answer: B — 1A

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Q. In a circuit with a 12V battery and two resistors in series (R1 = 4Ω, R2 = 8Ω), what is the current flowing through the circuit?

A. 0.5A
B. 1A
C. 1.5A
D. 2A

Solution

Total resistance R_total = R1 + R2 = 4Ω + 8Ω = 12Ω. Current I = V/R_total = 12V/12Ω = 1A.

Correct Answer: B — 1A

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Q. In a circuit with a 12V battery and two resistors in series (R1 = 4Ω, R2 = 8Ω), what is the voltage across R2?

A. 4V
B. 6V
C. 8V
D. 12V

Solution

The total resistance is R_total = R1 + R2 = 4Ω + 8Ω = 12Ω. The current is I = V/R_total = 12V / 12Ω = 1A. The voltage across R2 is V_R2 = I * R2 = 1A * 8Ω = 8V.

Correct Answer: C — 8V

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Q. In a circuit with a 12V battery and two resistors of 4 ohms and 8 ohms in series, what is the voltage drop across the 8 ohm resistor?

A. 4V
B. 6V
C. 8V
D. 12V

Solution

Total resistance R_total = 4 + 8 = 12 ohms. Current I = V/R_total = 12V/12 ohms = 1A. Voltage drop across 8 ohm resistor = I * R = 1A * 8 ohms = 8V.

Correct Answer: B — 6V

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Q. In a circuit with a 12V battery and two resistors of 4Ω and 8Ω in series, what is the voltage across the 8Ω resistor?

A. 4V
B. 6V
C. 8V
D. 12V

Solution

Using the voltage divider rule, V = (R2 / (R1 + R2)) * Vtotal = (8 / (4 + 8)) * 12 = 8V.

Correct Answer: C — 8V

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Q. In a circuit with a 12V battery and two resistors of 4Ω and 8Ω in series, what is the current flowing through the circuit?

A. 0.5A
B. 1A
C. 1.5A
D. 2A

Solution

Total resistance R = R1 + R2 = 4Ω + 8Ω = 12Ω. Current I = V/R = 12V / 12Ω = 1A.

Correct Answer: B — 1A

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Q. In a circuit with a 15V battery and three resistors (5Ω, 10Ω, and 15Ω) in parallel, what is the equivalent resistance?

A. 2Ω
B. 3Ω
C. 5Ω
D. 10Ω

Solution

1/R_eq = 1/5 + 1/10 + 1/15 = 0.1 + 0.0667 + 0.0667 = 0.2334. Therefore, R_eq = 4.29Ω.

Correct Answer: B — 3Ω

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Q. In a circuit with a 15V battery and two resistors in series (5Ω and 10Ω), what is the voltage drop across the 10Ω resistor?

A. 5V
B. 10V
C. 15V
D. 20V

Solution

Using the voltage divider rule, V2 = (R2 / (R1 + R2)) * Vtotal = (10 / (5 + 10)) * 15 = 10V.

Correct Answer: B — 10V

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Q. In a circuit with a 15V battery and two resistors in series (R1 = 5Ω, R2 = 10Ω), what is the voltage across R2?

A. 10V
B. 5V
C. 15V
D. 0V

Solution

Voltage across R2 = (R2 / (R1 + R2)) * V = (10Ω / (5Ω + 10Ω)) * 15V = 10V.

Correct Answer: A — 10V

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Q. In a circuit with a 20V battery and two resistors (4Ω and 8Ω) in parallel, what is the total current supplied by the battery?

A. 2A
B. 3A
C. 4A
D. 5A

Solution

Total resistance in parallel, 1/Req = 1/R1 + 1/R2 = 1/4 + 1/8 = 3/8. Therefore, Req = 8/3Ω. Total current I = V/Req = 20V / (8/3) = 7.5A.

Correct Answer: C — 4A

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Q. In a circuit with a 24 V battery and a 6 ohm resistor, what is the current flowing through the resistor?

A. 2 A
B. 4 A
C. 6 A
D. 8 A

Solution

Using Ohm's law, I = V/R = 24 V / 6 ohms = 4 A.

Correct Answer: B — 4 A

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Q. In a circuit with a 24 V battery and a total resistance of 6 ohms, what is the total current flowing through the circuit?

A. 2 A
B. 4 A
C. 6 A
D. 8 A

Solution

Using Ohm's law, I = V/R = 24 V / 6 ohms = 4 A.

Correct Answer: B — 4 A

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Q. In a circuit with a 24V battery and a 6 ohm resistor, what is the voltage drop across the resistor?

A. 4 V
B. 12 V
C. 24 V
D. 6 V

Solution

Using Ohm's law, V = I * R. First, find the current I = V/R = 24V / 6 ohms = 4 A. Then, V_drop = I * R = 4 A * 6 ohms = 24 V.

Correct Answer: B — 12 V

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Q. In a circuit with a 24V battery and a total resistance of 8 ohms, what is the total current flowing in the circuit?

A. 3 A
B. 2 A
C. 4 A
D. 6 A

Solution

Using Ohm's law, I = V/R = 24V / 8Ω = 3 A.

Correct Answer: C — 4 A

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Q. In a circuit with a 24V battery and three resistors (R1 = 4Ω, R2 = 4Ω, R3 = 4Ω) in parallel, what is the total current supplied by the battery?

A. 2A
B. 3A
C. 4A
D. 6A

Solution

Equivalent resistance R_eq = 1/(1/R1 + 1/R2 + 1/R3) = 1/(1/4 + 1/4 + 1/4) = 1.33Ω. Total current I = V/R_eq = 24V/1.33Ω = 18A.

Correct Answer: D — 6A

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Q. In a circuit with a 24V battery and three resistors in parallel (4Ω, 6Ω, and 12Ω), what is the total current supplied by the battery?

A. 2A
B. 3A
C. 4A
D. 6A

Solution

1/R_eq = 1/4 + 1/6 + 1/12 = 1. Therefore, R_eq = 2Ω. Total current I = V/R_eq = 24V/2Ω = 12A.

Correct Answer: C — 4A

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Q. In a circuit with a 24V battery and three resistors in series (R1 = 2Ω, R2 = 3Ω, R3 = 5Ω), what is the voltage drop across R2?

A. 6V
B. 8V
C. 12V
D. 10V

Solution

Total resistance R_total = R1 + R2 + R3 = 2Ω + 3Ω + 5Ω = 10Ω. Current I = V/R_total = 24V / 10Ω = 2.4A. Voltage drop across R2 = I * R2 = 2.4A * 3Ω = 7.2V.

Correct Answer: B — 8V

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Q. In a circuit with a 24V battery and three resistors of 2 ohms, 4 ohms, and 6 ohms in series, what is the total current flowing through the circuit?

A. 2 A
B. 3 A
C. 4 A
D. 1 A

Solution

Total resistance R = 2 + 4 + 6 = 12 ohms. Using Ohm's law, I = V/R = 24V / 12 ohms = 2 A.

Correct Answer: B — 3 A

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Q. In a circuit with a 24V battery and three resistors of 4Ω, 4Ω, and 8Ω in series, what is the voltage drop across the 8Ω resistor?

A. 8V
B. 12V
C. 16V
D. 24V

Solution

Total resistance R = 4Ω + 4Ω + 8Ω = 16Ω. Current I = V/R = 24V/16Ω = 1.5A. Voltage drop across 8Ω = I * R = 1.5A * 8Ω = 12V.

Correct Answer: B — 12V

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Q. In a circuit with a 24V battery and two 12 ohm resistors in series, what is the current flowing through the circuit?

A. 1 A
B. 2 A
C. 3 A
D. 4 A

Solution

Total resistance R_total = 12 + 12 = 24 ohms. Current I = V/R_total = 24V / 24Ω = 1 A.

Correct Answer: B — 2 A

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Q. In a circuit with a 24V battery and two 12Ω resistors in parallel, what is the total current supplied by the battery?

A. 1A
B. 2A
C. 3A
D. 4A

Solution

Total resistance R = 1/(1/12 + 1/12) = 6Ω; Total current I = V/R = 24V / 6Ω = 4A.

Correct Answer: D — 4A

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Q. In a circuit with a 24V battery and two 12Ω resistors in series, what is the current flowing through the circuit?

A. 1A
B. 2A
C. 3A
D. 4A

Solution

Total resistance R_total = 12Ω + 12Ω = 24Ω. Current I = V/R_total = 24V / 24Ω = 1A.

Correct Answer: B — 2A

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Q. In a circuit with a 24V battery and two resistors in series (4Ω and 8Ω), what is the voltage across the 8Ω resistor?

A. 8V
B. 12V
C. 16V
D. 20V

Solution

Voltage across 8Ω resistor = (R2 / (R1 + R2)) * Vtotal = (8 / (4 + 8)) * 24 = 16V.

Correct Answer: B — 12V

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Q. In a circuit with a 24V battery and two resistors in series (6Ω and 3Ω), what is the voltage across the 3Ω resistor?

A. 8V
B. 12V
C. 16V
D. 4V

Solution

Total resistance = 6Ω + 3Ω = 9Ω. Current I = V / R = 24V / 9Ω = 2.67A. Voltage across 3Ω = I * R = 2.67A * 3Ω = 8V.

Correct Answer: A — 8V

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Q. In a circuit with a 24V battery and two resistors in series (R1 = 6Ω, R2 = 12Ω), what is the voltage drop across R2?

A. 12V
B. 18V
C. 6V
D. 8V

Solution

Voltage drop across R2 = V_R2 = (R2 / (R1 + R2)) * V_total = (12Ω / (6Ω + 12Ω)) * 24V = 12V.

Correct Answer: A — 12V

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Current Electricity

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