The energy of a wave is proportional to the square of its amplitude, so if the amplitude increases, the energy increases with the square of the amplitude.

The energy carried by a wave is proportional to the square of its amplitude, so if the amplitude increases, the energy increases with the square of that increase.

The energy of a wave is proportional to the square of its amplitude. Therefore, if the amplitude increases, the energy increases.

The distance between two consecutive crests in a wave is called the wavelength.

When all resistances are equal, the bridge is balanced regardless of the configuration.

Changing one resistor can either balance or unbalance the bridge depending on the new value relative to the others.

Using the balance condition P/Q = R/S, we find S = 15Ω.

Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (15 * 30) / 10 = 45Ω.

Using the balance condition R1/R2 = R3/R4, we have 10/20 = 30/R4, which gives R4 = 20Ω.

For balance, R1/R2 = R3/R4. Thus, 10/20 = 15/R4, giving R4 = 30Ω.

Using the balance condition R1/R2 = R3/R4, we have 1/2 = 3/R4. Solving gives R4 = 6Ω.

Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (30 * 10) / 20 = 15Ω.

Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (30 * 10) / 20 = 15Ω.

Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (3 * 6) / 2 = 9Ω.

Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (3 * 6) / 2 = 9Ω.

Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (6 * 12) / 4 = 18Ω.

Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (10 * 15) / 5 = 30Ω.

Using the balance condition R1/R2 = R3/R4, we have 5/10 = 15/x, solving gives x = 7.5Ω.

In a balanced Wheatstone bridge, the current through the galvanometer is zero.

With equal resistances, the voltage across the galvanometer is 0V.

The balance condition depends on the ratio of resistances, not the voltage.

In a balanced Wheatstone bridge, the ratio of the resistances in one branch is equal to the ratio in the other branch, hence R1/R2 = R3/R4.

When the Wheatstone bridge is unbalanced, a current flows through the galvanometer, indicating a difference in potential across it.

A current in the galvanometer indicates that the bridge is unbalanced.

If the galvanometer shows a current, it indicates that the bridge is unbalanced.

A deflection in the galvanometer indicates that the bridge is unbalanced, meaning the ratios of the resistances are not equal.

Zero deflection indicates that no current flows through the galvanometer.

Zero deflection in the galvanometer indicates that the bridge is balanced.

For the bridge to be balanced, the ratios must be equal. Thus, 2/3 should equal 4/5, which is not true.

The bridge is unbalanced because the ratios 2:3 and 4:5 are not equal.