Q. In a heat engine, the work done is equal to:
A.
Heat absorbed from the hot reservoir
B.
Heat rejected to the cold reservoir
C.
Heat absorbed minus heat rejected
D.
Heat absorbed plus heat rejected
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Solution
The work done by a heat engine is equal to the heat absorbed from the hot reservoir minus the heat rejected to the cold reservoir.
Correct Answer:
C
— Heat absorbed minus heat rejected
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Q. In a hydraulic lift, if the input power is 2000 W and the output power is 1800 W, what is the efficiency of the lift?
A.
90%
B.
80%
C.
70%
D.
75%
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Solution
Efficiency is calculated as (Output Power / Input Power) * 100%. Here, efficiency = (1800 W / 2000 W) * 100% = 90%.
Correct Answer:
B
— 80%
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Q. In a hydraulic lift, if the input power is 500 W and the efficiency is 80%, what is the output power?
A.
400 W
B.
500 W
C.
600 W
D.
700 W
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Solution
Output power can be calculated using the formula: Output Power = Efficiency * Input Power. Here, Output Power = 0.8 * 500 W = 400 W.
Correct Answer:
A
— 400 W
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Q. In a hydrogen atom, the energy levels are quantized. What is the formula for the energy of the nth level?
A.
E_n = -13.6/n^2 eV
B.
E_n = -13.6n^2 eV
C.
E_n = -13.6/n eV
D.
E_n = -13.6n eV
Show solution
Solution
The energy levels of a hydrogen atom are given by E_n = -13.6/n^2 eV, where n is the principal quantum number.
Correct Answer:
A
— E_n = -13.6/n^2 eV
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Q. In a hydrogen atom, what is the energy of the electron in the ground state?
A.
-13.6 eV
B.
-3.4 eV
C.
-1.51 eV
D.
0 eV
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Solution
The energy of the electron in the ground state of a hydrogen atom is -13.6 eV.
Correct Answer:
A
— -13.6 eV
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Q. In a hydrogen atom, what is the energy of the electron in the n=2 state?
A.
-3.4 eV
B.
-13.6 eV
C.
-1.51 eV
D.
-0.85 eV
Show solution
Solution
The energy of an electron in a hydrogen atom in the n=2 state is given by E_n = -13.6/n^2 = -13.6/4 = -3.4 eV.
Correct Answer:
A
— -3.4 eV
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Q. In a hydrogen atom, what is the wavelength of the emitted photon when an electron transitions from n=3 to n=2?
A.
656 nm
B.
486 nm
C.
434 nm
D.
410 nm
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Solution
Using the Rydberg formula, the wavelength for the transition from n=3 to n=2 is approximately 486 nm.
Correct Answer:
B
— 486 nm
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Q. In a hydrogen atom, which transition emits the photon with the highest energy?
A.
n=2 to n=1
B.
n=3 to n=2
C.
n=4 to n=3
D.
n=5 to n=4
Show solution
Solution
The energy of the emitted photon is highest for the transition from n=2 to n=1, as it involves the largest energy difference.
Correct Answer:
A
— n=2 to n=1
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Q. In a hydrogen atom, which transition would emit the highest energy photon?
A.
n=2 to n=1
B.
n=3 to n=2
C.
n=4 to n=3
D.
n=5 to n=4
Show solution
Solution
The energy of the photon emitted is highest for the transition from n=2 to n=1, as it involves the largest energy difference.
Correct Answer:
A
— n=2 to n=1
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Q. In a hydrogen atom, which transition would emit the photon with the highest energy?
A.
n=2 to n=1
B.
n=3 to n=2
C.
n=4 to n=3
D.
n=5 to n=4
Show solution
Solution
The energy of the emitted photon is highest for the transition from n=2 to n=1, as it involves the largest energy difference.
Correct Answer:
A
— n=2 to n=1
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Q. In a lab experiment, the density of a liquid is measured as 1.2 g/cm³ with an uncertainty of ±0.05 g/cm³. What is the relative error?
A.
4.17%
B.
3.33%
C.
5.00%
D.
2.50%
Show solution
Solution
Relative error = (Uncertainty / Measured value) * 100 = (0.05 / 1.2) * 100 = 4.17%.
Correct Answer:
A
— 4.17%
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Q. In a lab experiment, the speed of sound is measured as 340 m/s with an uncertainty of ±2 m/s. What is the total uncertainty if the speed is used in a calculation involving division by 2?
A.
±1 m/s
B.
±2 m/s
C.
±0.5 m/s
D.
±0.25 m/s
Show solution
Solution
Total uncertainty = (2 m/s) / 2 = ±1 m/s.
Correct Answer:
A
— ±1 m/s
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Q. In a lab experiment, the speed of sound is measured as 340 m/s with an uncertainty of ±5 m/s. What is the percentage uncertainty in this measurement?
A.
1.47%
B.
1.5%
C.
2%
D.
0.5%
Show solution
Solution
Percentage uncertainty = (absolute uncertainty / measured value) * 100 = (5 / 340) * 100 ≈ 1.47%.
Correct Answer:
B
— 1.5%
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Q. In a liquid drop, the shape is spherical due to which property?
A.
Viscosity
B.
Surface tension
C.
Density
D.
Pressure
Show solution
Solution
The spherical shape of a liquid drop minimizes the surface area, which is a result of surface tension acting to reduce the energy of the surface.
Correct Answer:
B
— Surface tension
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Q. In a magnetic field, the force on a charged particle is maximum when the particle's velocity is:
A.
Parallel to the field
B.
Perpendicular to the field
C.
At an angle of 45 degrees
D.
At an angle of 90 degrees
Show solution
Solution
The magnetic force on a charged particle is given by F = qvB sin(θ), which is maximum when θ = 90 degrees (perpendicular).
Correct Answer:
B
— Perpendicular to the field
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Q. In a magnetic field, the force on a charged particle is zero when it moves:
A.
Perpendicular to the field
B.
Parallel to the field
C.
At an angle of 30 degrees
D.
At an angle of 90 degrees
Show solution
Solution
The magnetic force on a charged particle is zero when it moves parallel to the magnetic field, as the angle θ = 0° results in sin(θ) = 0.
Correct Answer:
B
— Parallel to the field
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Q. In a material with a resistivity of 2 x 10^-8 Ω·m, what is the resistance of a 10 m long wire with a cross-sectional area of 1 mm²?
A.
0.02 Ω
B.
0.2 Ω
C.
2 Ω
D.
20 Ω
Show solution
Solution
Resistance R = ρ(L/A) = 2 x 10^-8 * (10 / (1 x 10^-6)) = 0.2 Ω.
Correct Answer:
B
— 0.2 Ω
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Q. In a material with a resistivity of 2 x 10^-8 Ω·m, what is the resistance of a 3 m long wire with a cross-sectional area of 1 mm²?
A.
0.006 Ω
B.
0.018 Ω
C.
0.024 Ω
D.
0.036 Ω
Show solution
Solution
Resistance R = ρ(L/A) = 2 x 10^-8 * (3 / (1 x 10^-6)) = 0.024 Ω.
Correct Answer:
C
— 0.024 Ω
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Q. In a material, if the strain energy density is given by U, what is the expression for the total strain energy stored in a volume V of the material?
A.
U * V
B.
U / V
C.
U + V
D.
U - V
Show solution
Solution
The total strain energy stored in a volume V is given by the product of strain energy density U and volume V, i.e., Total Energy = U * V.
Correct Answer:
A
— U * V
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Q. In a material, if the strain is 0.01 and the Young's modulus is 200 GPa, what is the stress in the material?
A.
2 MPa
B.
20 MPa
C.
200 MPa
D.
2000 MPa
Show solution
Solution
Stress = Young's modulus * strain = 200 GPa * 0.01 = 2 GPa = 2000 MPa.
Correct Answer:
C
— 200 MPa
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Q. In a Michelson interferometer, what happens to the interference pattern if one of the mirrors is moved slightly?
A.
The pattern remains unchanged
B.
The pattern shifts
C.
The pattern disappears
D.
The pattern becomes brighter
Show solution
Solution
Moving one of the mirrors changes the path length for one of the beams, causing a shift in the interference pattern.
Correct Answer:
B
— The pattern shifts
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Q. In a Michelson interferometer, what happens to the interference pattern if one of the mirrors is moved?
A.
The pattern disappears
B.
The pattern shifts
C.
The pattern becomes brighter
D.
The pattern becomes dimmer
Show solution
Solution
Moving one of the mirrors changes the path length of one beam, causing a shift in the interference pattern.
Correct Answer:
B
— The pattern shifts
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Q. In a Michelson interferometer, what happens to the interference pattern if one of the mirrors is moved away from the beam splitter?
A.
Fringes move closer
B.
Fringes move apart
C.
Fringes disappear
D.
No change in pattern
Show solution
Solution
Moving one mirror changes the path length of one beam, causing the fringes to move apart or closer depending on the direction of movement.
Correct Answer:
B
— Fringes move apart
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Q. In a Michelson interferometer, what happens when one of the mirrors is moved slightly?
A.
No change in interference pattern
B.
Fringes shift
C.
Fringes disappear
D.
Fringes become brighter
Show solution
Solution
Moving one of the mirrors changes the path length, causing a shift in the interference pattern (fringes).
Correct Answer:
B
— Fringes shift
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Q. In a mixture of gases, how does the RMS speed depend on the individual gas components?
A.
It depends only on the lightest gas
B.
It is the weighted average of the RMS speeds of the components
C.
It is the sum of the RMS speeds of the components
D.
It is independent of the gas components
Show solution
Solution
The RMS speed of a mixture of gases is the weighted average of the RMS speeds of the individual components, taking into account their molar masses.
Correct Answer:
B
— It is the weighted average of the RMS speeds of the components
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Q. In a mixture of gases, how is the RMS speed of the mixture calculated?
A.
Using the average molar mass of the mixture
B.
Using the molar mass of the heaviest gas
C.
Using the molar mass of the lightest gas
D.
It cannot be calculated
Show solution
Solution
The RMS speed of a mixture of gases is calculated using the average molar mass of the mixture in the formula v_rms = sqrt((3RT)/M_avg).
Correct Answer:
A
— Using the average molar mass of the mixture
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Q. In a moving coil galvanometer, what is the role of the spring?
A.
To provide a magnetic field
B.
To measure current
C.
To return the coil to its original position
D.
To increase sensitivity
Show solution
Solution
The spring in a moving coil galvanometer provides a restoring torque that returns the coil to its original position when the current is removed.
Correct Answer:
C
— To return the coil to its original position
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Q. In a Newton's rings experiment, if the radius of the ring increases, what can be inferred about the wavelength of light used?
A.
Wavelength is increasing
B.
Wavelength is decreasing
C.
Wavelength remains constant
D.
Wavelength cannot be determined
Show solution
Solution
The radius of the rings is directly proportional to the wavelength of light used. If the radius increases, the wavelength must also be increasing.
Correct Answer:
A
— Wavelength is increasing
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Q. In a nuclear reaction, what is conserved?
A.
Mass only
B.
Charge only
C.
Mass and charge
D.
Energy only
Show solution
Solution
In nuclear reactions, both mass and charge are conserved, according to the law of conservation of mass-energy and charge.
Correct Answer:
C
— Mass and charge
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Q. In a nuclear reaction, what is the term for the energy released when a nucleus is formed from its constituent nucleons?
A.
Binding energy
B.
Kinetic energy
C.
Potential energy
D.
Thermal energy
Show solution
Solution
The energy released when a nucleus is formed from its constituent nucleons is called binding energy.
Correct Answer:
A
— Binding energy
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Showing 2581 to 2610 of 5000 (167 Pages)
Physics Syllabus (JEE Main) MCQ & Objective Questions
The Physics Syllabus for JEE Main is crucial for students aiming to excel in their exams. Understanding this syllabus not only helps in grasping fundamental concepts but also enhances problem-solving skills through practice. Engaging with MCQs and objective questions is essential for effective exam preparation, as it allows students to identify important questions and strengthen their knowledge base.
What You Will Practise Here
Mechanics: Laws of Motion, Work, Energy, and Power
Thermodynamics: Laws of Thermodynamics, Heat Transfer
Waves and Oscillations: Simple Harmonic Motion, Wave Properties
Electromagnetism: Electric Fields, Magnetic Fields, and Circuits
Optics: Reflection, Refraction, and Optical Instruments
Modern Physics: Quantum Theory, Atomic Models, and Nuclear Physics
Fluid Mechanics: Properties of Fluids, Bernoulli's Principle
Exam Relevance
The Physics Syllabus (JEE Main) is integral to various examinations, including CBSE, State Boards, and competitive exams like NEET and JEE. Questions often focus on conceptual understanding and application of theories. Common patterns include numerical problems, conceptual MCQs, and assertion-reason type questions, which test both knowledge and analytical skills.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers.
Neglecting units and dimensions in calculations.
Overlooking the significance of diagrams in understanding concepts.
Confusing similar concepts, such as velocity and acceleration.
Failing to apply formulas correctly in different contexts.
FAQs
Question: What are the key topics in the Physics Syllabus for JEE Main?Answer: Key topics include Mechanics, Thermodynamics, Waves, Electromagnetism, Optics, Modern Physics, and Fluid Mechanics.
Question: How can I improve my performance in Physics MCQs?Answer: Regular practice of MCQs, understanding concepts deeply, and revising important formulas can significantly enhance your performance.
Start solving practice MCQs today to test your understanding of the Physics Syllabus (JEE Main). This will not only boost your confidence but also prepare you effectively for your upcoming exams. Remember, consistent practice is the key to success!
