5 - 2x ≤ 3 => -2x ≤ -2 => x ≥ 1.

6 - 3x ≥ 0 => -3x ≥ -6 => x ≤ 2.

6x + 2 < 14 => 6x < 12 => x < 2.

6x + 2 ≤ 14 => 6x ≤ 12 => x ≤ 2.

6x + 4 < 2x + 20 => 4x < 16 => x < 4.

6x + 4 ≤ 2x + 16 => 4x ≤ 12 => x ≤ 3.

7 - 3x > 1 => -3x > -6 => x < 2.

7 - 3x < 1 => -3x < -6 => x > 2.

7x + 2 > 5 => 7x > 3 => x > 0.5.

7x + 2 > 5x + 6 => 2x > 4 => x > 2.

7x + 2 < 5 => 7x < 3 => x < -1.

7x + 3 > 24 => 7x > 21 => x > 3.

7x + 5 < 2x + 20 => 5x < 15 => x < 3.

7x - 4 < 3x + 8 => 4x < 12 => x < 3.

8 - 2x > 0 => -2x > -8 => x < 4.

x/2 - 1 ≤ 3 => x/2 ≤ 4 => x ≤ 8.

x/3 - 2 ≤ 1 => x/3 ≤ 3 => x ≤ 9.

Mean = 19.5, Variance = 25, Standard Deviation = √25 = 5.

Mean = 19.14, Variance = 20.25, Standard Deviation = √20.25 = 4.5.

Mean = 5.2. Variance = [(4-5.2)² + (8-5.2)² + (6-5.2)² + (5-5.2)² + (3-5.2)²]/5 = 6.56. Standard Deviation = √6.56 ≈ 2.56.

Mean = 3. Standard Deviation = sqrt[((1-3)^2 + (2-3)^2 + (3-3)^2 + (4-3)^2 + (5-3)^2)/5] = sqrt[2] = 1.414.

The standard form of a parabola that opens upwards is given by x^2 = 4ay.

The sum of the coefficients is found by substituting x = 1: (2 + 3*1)^4 = 5^4 = 625.

The sum of the coefficients is found by substituting x = 1, so (1 + 1)^5 = 2^5 = 32.

The sum of the coefficients is found by substituting x = 1, giving (1 + 1)^7 = 2^7 = 128.

The sum is (2 + 4) + (3 - 5)i = 6 - 2i.

Sum = 1 + 2 + 3 + 4 + 5 = 15.

S_5 = 1 + 1/2 + 1/4 + 1/8 + 1/16 = 1.5.

The sum S_n = n/2 * (2a + (n-1)d) = 6/2 * (2*10 + 5*5) = 3 * (20 + 25) = 135.

The first term a = 2, common difference d = 3. The sum of the first n terms S_n = n/2 * (2a + (n-1)d) = n/2 * (2 + (n-1) * 3).