The number of ways to choose 3 letters from 11 distinct letters is 11C3 = 165.

Treat the 3 men as one unit. So, we have 3 units (MMM, W, W). Arrangements = 4! * 3! = 24 * 6 = 144.

The arrangements = 5! / (3! * 2!) = 10.

The arrangements = 6! / (3! * 2! * 1!) = 60.

The total arrangements = 6! / (3! * 2! * 1!) = 60.

The number of ways to choose 4 books from 10 is C(10, 4) = 210.

The number of arrangements is 4! = 24.

Each ball can go into any of the 3 boxes, so the total ways = 3^4 = 81.

The number of ways to choose 4 fruits from 10 is given by 10C4 = 210.

The number of ways to choose 4 letters from 11 distinct letters is 11C4 = 330.

The number of ways to choose 4 letters from 11 distinct letters is 11C4 = 330.

The number of ways to award 4 different prizes to 3 students is 3^4 = 81.

Each prize can go to any of the 3 students, so the total ways = 3^4 = 81.

The number of ways is C(10, 4) = 210.

The number of arrangements of 5 different books is 5! = 120.

The number of ways is C(10, 5) = 252.

Treat the two specific letters as one unit. Then, we have 4 units to arrange: 4! = 24. The two letters can be arranged in 2! = 2 ways. Total = 24 * 2 = 48.

Total arrangements = 5! = 120. Arrangements with the two letters together = 4! * 2! = 48. So, arrangements where they are not together = 120 - 48 = 72.

The number of ways to choose 5 letters from 26 is C(26, 5) = 65780.

The number of ways to award 5 different prizes to 3 students is 3^5 = 243.

Treat the 2 specific books as one unit. Then we have 5 units to arrange: 5! * 2! = 240.

The number of arrangements in a circle is (n-1)! = (6-1)! = 5! = 120.

The number of ways to divide 6 people into 2 groups of 3 is (6! / (3!3!)) / 2 = 20.

The number of ways to choose 3 from 5 is C(5,3) = 10.

The number of arrangements = 4! = 24.

The word 'BANANA' has 6 letters with 'A' repeating 3 times and 'N' repeating 2 times. The arrangements are 6!/(3!2!) = 60.

The number of ways to choose 3 fruits from 5 is given by 5C3 = 10.

The number of ways to form a committee of 3 from 10 is given by 10C3 = 120.

The number of ways to choose 2 from 5 is given by 5C2 = 10.

The number of ways to select 2 students from 8 is given by 8C2 = 28.