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Q. A square has a perimeter of 40 cm. What is the area of the square?

A. 100 cm²
B. 200 cm²
C. 150 cm²
D. 250 cm²

Solution

Perimeter of a square = 4 × side. Thus, 40 = 4 × side, giving side = 10 cm. Area = side² = 10² = 100 cm².

Correct Answer: A — 100 cm²

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Q. A square has a perimeter of 48 cm. What is the area of the square?

A. 144 cm²
B. 64 cm²
C. 36 cm²
D. 100 cm²

Solution

Perimeter of a square = 4 × side. Thus, 48 = 4 × side, giving side = 12 cm. Area = side² = 12² = 144 cm².

Correct Answer: A — 144 cm²

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Q. A square has a perimeter of 64 cm. What is the length of one side of the square?

A. 16 cm
B. 12 cm
C. 14 cm
D. 8 cm

Solution

The perimeter of a square is given by P = 4s, where s is the length of one side. Therefore, 4s = 64 cm, leading to s = 16 cm.

Correct Answer: A — 16 cm

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Q. A stock price increased from $80 to $100. What is the percentage increase in the stock price? (2023)

A. 20%
B. 25%
C. 30%
D. 15%

Solution

Percentage Increase = ((New Price - Old Price) / Old Price) * 100 = ((100 - 80) / 80) * 100 = 25%.

Correct Answer: B — 25%

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Q. A stone is dropped from a height of 20 m. How long does it take to reach the ground?

A. 2 s
B. 1 s
C. 3 s
D. 4 s

Solution

Using h = (1/2)gt², where h = 20 m and g = 9.8 m/s², we have 20 = (1/2)*9.8*t². Solving gives t² = 4.08, so t ≈ 2 s.

Correct Answer: A — 2 s

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Q. A stone is dropped from a height of 20 m. How long will it take to reach the ground?

A. 2 s
B. 1 s
C. 3 s
D. 4 s

Solution

Using h = (1/2)gt², where h = 20 m and g = 9.8 m/s², we have 20 = (1/2)*9.8*t². Solving gives t² = 4.08, so t ≈ 2 s.

Correct Answer: A — 2 s

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Q. A stone is dropped from a height of 45 m. How far will it have fallen after 2 seconds?

A. 10 m
B. 20 m
C. 30 m
D. 40 m

Solution

Distance fallen (s) = (1/2)gt² = (1/2)(9.8)(2²) = 19.6 m.

Correct Answer: C — 30 m

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Q. A stone is dropped from a height of 45 m. How far will it have fallen after 3 seconds?

A. 10.5 m
B. 20 m
C. 30 m
D. 40.5 m

Solution

Distance fallen (s) = (1/2)gt² = (1/2)(9.8)(3²) = 44.1 m.

Correct Answer: D — 40.5 m

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Q. A stone is dropped from a height of 45 m. How far will it travel horizontally if it is projected horizontally with a speed of 10 m/s?

A. 20 m
B. 30 m
C. 40 m
D. 50 m

Solution

Time to fall t = √(2h/g) = √(90/9.8) ≈ 4.27 s; horizontal distance = 10 * 4.27 ≈ 42.7 m.

Correct Answer: C — 40 m

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Q. A stone is dropped from a height of 45 m. How far will it travel horizontally if it is thrown horizontally with a speed of 10 m/s?

A. 20 m
B. 30 m
C. 40 m
D. 50 m

Solution

Time to fall (t) = √(2h/g) = √(2*45/9.8) ≈ 3 s; horizontal distance = v*t = 10*3 = 30 m.

Correct Answer: B — 30 m

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Q. A stone is dropped from a height of 45 m. How long does it take to reach the ground?

A. 3 s
B. 4 s
C. 5 s
D. 6 s

Solution

Using h = (1/2)gt², we have 45 = (1/2)(9.8)t², solving gives t ≈ 4.3 s.

Correct Answer: B — 4 s

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Q. A stone is dropped from a height of 80 m. How long does it take to hit the ground?

A. 4 s
B. 5 s
C. 6 s
D. 8 s

Solution

Time (t) = √(2h/g) = √(2*80/9.8) = 4.04 s.

Correct Answer: A — 4 s

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Q. A stone is dropped from a height of 80 m. How long will it take to reach the ground?

A. 2 s
B. 4 s
C. 6 s
D. 8 s

Solution

Using h = (1/2)gt², we get t = √(2h/g) = √(2*80/9.8) = 4.04 s.

Correct Answer: B — 4 s

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Q. A stone is thrown downward with an initial velocity of 5 m/s from a height of 45 m. How long will it take to hit the ground? (Assume g = 10 m/s²)

A. 3 s
B. 4 s
C. 5 s
D. 6 s

Solution

Using the equation of motion: h = ut + 0.5gt². 45 = 5t + 0.5 * 10 * t². Solving the quadratic gives t = 3 s.

Correct Answer: B — 4 s

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Q. A stone is thrown downward with an initial velocity of 5 m/s from a height of 45 m. How long will it take to hit the ground? (2020)

A. 3 s
B. 4 s
C. 5 s
D. 6 s

Solution

Using the equation of motion: h = ut + 0.5gt². Solving for t gives t ≈ 4 seconds.

Correct Answer: B — 4 s

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Q. A stone is thrown horizontally from a height of 45 m. How long will it take to hit the ground? (Take g = 10 m/s²) (2023)

A. 3 s
B. 4.5 s
C. 5 s
D. 6 s

Solution

Using h = 0.5 * g * t^2, we have 45 = 0.5 * 10 * t^2. Solving gives t^2 = 9, so t = 3 s.

Correct Answer: A — 3 s

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Q. A stone is thrown horizontally from the top of a cliff 45 m high. How long does it take to hit the ground? (Assume g = 10 m/s²)

A. 3 s
B. 4 s
C. 5 s
D. 6 s

Solution

Using h = 0.5 * g * t^2, rearranging gives t = sqrt(2h/g) = sqrt(2 * 45 / 10) = sqrt(9) = 3 s.

Correct Answer: B — 4 s

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Q. A stone is thrown horizontally from the top of a cliff 45 m high. How long does it take to hit the ground? (g = 10 m/s²)

A. 3 s
B. 4 s
C. 5 s
D. 6 s

Solution

Using h = 0.5 * g * t^2, rearranging gives t = sqrt(2h/g) = sqrt(2 * 45 / 10) = sqrt(9) = 3 s.

Correct Answer: B — 4 s

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Q. A stone is thrown horizontally from the top of a cliff 45 m high. How long will it take to hit the ground? (Assume g = 10 m/s²)

A. 3 s
B. 4 s
C. 5 s
D. 6 s

Solution

Using the formula: h = 0.5 * g * t^2. Rearranging gives t = sqrt(2h/g) = sqrt(2 * 45 / 10) = sqrt(9) = 3 s.

Correct Answer: B — 4 s

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Q. A stone is thrown horizontally from the top of a cliff 80 m high. How far from the base of the cliff will it land?

A. 20 m
B. 40 m
C. 60 m
D. 80 m

Solution

Time to fall = √(2h/g) = √(2*80/9.8) ≈ 4.04 s. Horizontal distance = horizontal speed * time. Assuming horizontal speed = 10 m/s, distance = 10 m/s * 4.04 s = 40.4 m.

Correct Answer: B — 40 m

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Q. A stone is thrown horizontally from the top of a cliff 80 m high. How far from the base of the cliff will the stone land if it is thrown with a speed of 10 m/s?

A. 20 m
B. 40 m
C. 60 m
D. 80 m

Solution

Time to fall = √(2h/g) = √(2*80/9.8) ≈ 4.04 s. Horizontal distance = speed * time = 10 m/s * 4.04 s ≈ 40 m.

Correct Answer: B — 40 m

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Q. A stone is thrown horizontally from the top of a cliff 80 m high. How long does it take to hit the ground? (g = 10 m/s²)

A. 4 s
B. 8 s
C. 10 s
D. 12 s

Solution

Using the formula: h = 0.5 * g * t^2. Rearranging gives t = sqrt(2h/g) = sqrt(2 * 80 / 10) = sqrt(16) = 4 s.

Correct Answer: A — 4 s

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Q. A stone is thrown in a circular path with a radius of 3 m. If the stone completes 4 revolutions in 8 seconds, what is the angular speed?

A. π/2 rad/s
B. π rad/s
C. 2π rad/s
D. 4π rad/s

Solution

Angular speed (ω) = Total angle / Time = (4 * 2π) / 8 = π rad/s.

Correct Answer: B — π rad/s

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Q. A stone is thrown vertically upward with a speed of 20 m/s. How high will it rise before coming to rest?

A. 10 m
B. 20 m
C. 30 m
D. 40 m

Solution

Maximum height (H) = (u²)/(2g) = (20²)/(2*9.8) ≈ 20.4 m.

Correct Answer: C — 30 m

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Q. A stone is thrown vertically upward with a speed of 20 m/s. How long will it take to reach the maximum height?

A. 1 s
B. 2 s
C. 3 s
D. 4 s

Solution

Time to reach maximum height = initial velocity / g = 20 / 10 = 2 s.

Correct Answer: B — 2 s

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Q. A stone is thrown vertically upward with a speed of 20 m/s. How long will it take to reach the maximum height? (g = 10 m/s²)

A. 1 s
B. 2 s
C. 3 s
D. 4 s

Solution

Using the formula: v = u - gt. At maximum height, v = 0. So, 0 = 20 - 10t. Solving gives t = 2 s.

Correct Answer: B — 2 s

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Q. A stone is thrown vertically upward with a speed of 20 m/s. How long will it take to reach the maximum height? (Assume g = 10 m/s²)

A. 1 s
B. 2 s
C. 3 s
D. 4 s

Solution

Time to reach maximum height = initial velocity / g = 20 / 10 = 2 s.

Correct Answer: B — 2 s

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Q. A stone is thrown vertically upwards with a speed of 15 m/s. How long will it take to reach the highest point? (Take g = 10 m/s²) (2023)

A. 1.5 s
B. 2 s
C. 3 s
D. 4 s

Solution

Time to reach highest point = u/g = 15/10 = 1.5 s.

Correct Answer: B — 2 s

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Q. A stone is thrown vertically upwards with a speed of 20 m/s. How long will it take to reach the maximum height? (Assume g = 10 m/s²)

A. 1 s
B. 2 s
C. 3 s
D. 4 s

Solution

Using the formula: time = (final velocity - initial velocity) / g. At maximum height, final velocity = 0. Time = (0 - 20) / -10 = 2 s.

Correct Answer: B — 2 s

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Q. A stone is thrown vertically upwards with a speed of 20 m/s. How long will it take to reach the maximum height? (g = 10 m/s²)

A. 1 s
B. 2 s
C. 3 s
D. 4 s

Solution

Using the formula: v = u - gt. At maximum height, v = 0. So, 0 = 20 - 10t. Solving gives t = 2 s.

Correct Answer: B — 2 s

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Major Competitive Exams

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