Major Competitive Exams MCQ & Objective Questions
Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.
What You Will Practise Here
Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams
Exam Relevance
The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.
Common Mistakes Students Make
Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam
FAQs
Question: How can I improve my performance in Major Competitive Exams?Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.
Question: What types of questions should I focus on for these exams?Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.
Question: Are there specific strategies for tackling objective questions?Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.
Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!
Q. What is the work done by a gas during expansion against a constant external pressure?
Show solution
Solution
The work done by a gas during expansion against a constant external pressure is given by W = PΔV, where P is the pressure and ΔV is the change in volume.
Correct Answer:
A
— PΔV
Learn More →
Q. What is the work done by a gas during expansion at constant pressure?
Show solution
Solution
The work done by a gas during expansion at constant pressure is given by W = PΔV.
Correct Answer:
A
— PΔV
Learn More →
Q. What is the work done by a gas during isothermal expansion?
A.
Zero
B.
Depends on the temperature
C.
Is equal to the heat absorbed
D.
Is equal to the change in internal energy
Show solution
Solution
During isothermal expansion, the work done by the gas is equal to the heat absorbed, as the internal energy remains constant.
Correct Answer:
C
— Is equal to the heat absorbed
Learn More →
Q. What is the work done by an ideal gas during an isobaric expansion if it expands from 2 L to 5 L at a pressure of 3 atm? (2022)
A.
9 J
B.
12 J
C.
15 J
D.
18 J
Show solution
Solution
Work done (W) = P * ΔV = 3 atm * (5 L - 2 L) = 3 atm * 3 L = 9 atm·L = 15 J (1 atm·L = 101.325 J)
Correct Answer:
C
— 15 J
Learn More →
Q. What is the work done by an ideal gas during an isobaric expansion if the pressure is 5 atm and the volume changes from 2 L to 5 L? (2019)
A.
15 L·atm
B.
10 L·atm
C.
5 L·atm
D.
20 L·atm
Show solution
Solution
Work done (W) = PΔV = P(V_final - V_initial) = 5 atm * (5 L - 2 L) = 15 L·atm.
Correct Answer:
A
— 15 L·atm
Learn More →
Q. What is the work done by an ideal gas during an isobaric expansion? (2019)
Show solution
Solution
The work done by an ideal gas during an isobaric (constant pressure) expansion is given by W = PΔV.
Correct Answer:
A
— PΔV
Learn More →
Q. What is the work done by an ideal gas during an isobaric process?
A.
PΔV
B.
nRT
C.
0
D.
nRΔT
Show solution
Solution
The work done by an ideal gas during an isobaric process is given by W = PΔV.
Correct Answer:
A
— PΔV
Learn More →
Q. What is the work done by an ideal gas during an isothermal expansion from volume Vi to Vf?
A.
nRT ln(Vf/Vi)
B.
nR(Tf - Ti)
C.
Zero
D.
nRT
Show solution
Solution
The work done by an ideal gas during an isothermal expansion is W = nRT ln(Vf/Vi).
Correct Answer:
A
— nRT ln(Vf/Vi)
Learn More →
Q. What is the work done by an ideal gas during an isothermal expansion from volume V1 to V2 at temperature T? (2021)
A.
nRT ln(V2/V1)
B.
nRT (V2 - V1)
C.
PV
D.
0
Show solution
Solution
The work done during an isothermal expansion is given by W = nRT ln(V2/V1).
Correct Answer:
A
— nRT ln(V2/V1)
Learn More →
Q. What is the work done by an ideal gas during an isothermal expansion?
A.
Zero
B.
nRT ln(Vf/Vi)
C.
nRT (Vf - Vi)
D.
nR (Tf - Ti)
Show solution
Solution
The work done by an ideal gas during an isothermal expansion is given by W = nRT ln(Vf/Vi).
Correct Answer:
B
— nRT ln(Vf/Vi)
Learn More →
Q. What is the work done by an ideal gas during isothermal expansion? (2021)
A.
0
B.
nRT ln(Vf/Vi)
C.
nRT (Vf - Vi)
D.
nR (Tf - Ti)
Show solution
Solution
For an ideal gas undergoing isothermal expansion, the work done is given by W = nRT ln(Vf/Vi).
Correct Answer:
B
— nRT ln(Vf/Vi)
Learn More →
Q. What is the work done by friction when a 5 kg block slides 2 m on a surface with a coefficient of kinetic friction of 0.4?
A.
-4 N·m
B.
-8 N·m
C.
-10 N·m
D.
-20 N·m
Show solution
Solution
Frictional force F_friction = μk * N = 0.4 * 5 kg * 9.8 m/s² = 19.6 N. Work done by friction = -F_friction * distance = -19.6 N * 2 m = -39.2 N·m, approximately -40 N·m.
Correct Answer:
B
— -8 N·m
Learn More →
Q. What is the work done by the system during an isochoric process?
A.
Positive
B.
Negative
C.
Zero
D.
Depends on the temperature
Show solution
Solution
In an isochoric process, the volume remains constant, so no work is done by the system (W = PΔV = 0).
Correct Answer:
C
— Zero
Learn More →
Q. What is the work done by the system in an isochoric process?
A.
Positive
B.
Negative
C.
Zero
D.
Depends on the temperature
Show solution
Solution
In an isochoric process, the volume remains constant, so no work is done by the system (W = PΔV = 0).
Correct Answer:
C
— Zero
Learn More →
Q. What is the work done by the system when it expands against a constant external pressure?
Show solution
Solution
The work done by the system during expansion against a constant external pressure is given by W = PΔV.
Correct Answer:
A
— PΔV
Learn More →
Q. What is the work done in moving a charge of +2μC from a point A to B in a uniform electric field of 500 N/C over a distance of 0.4m?
A.
400 J
B.
200 J
C.
100 J
D.
80 J
Show solution
Solution
Work done W = F * d = q * E * d = (2 × 10^-6 C) * (500 N/C) * (0.4 m) = 0.4 J = 80 J.
Correct Answer:
D
— 80 J
Learn More →
Q. What is the work done in moving a charge of +2μC through a potential difference of 10V?
A.
20 μJ
B.
200 μJ
C.
2 μJ
D.
0.2 μJ
Show solution
Solution
W = q * V = 2 × 10^-6 C * 10 V = 20 × 10^-6 J = 20 μJ.
Correct Answer:
B
— 200 μJ
Learn More →
Q. What is the work done in moving a charge of +2μC through a potential difference of 5V?
A.
10 μJ
B.
5 μJ
C.
2 μJ
D.
1 μJ
Show solution
Solution
Work done W = q * V = (2 × 10^-6 C) * (5 V) = 10 μJ.
Correct Answer:
A
— 10 μJ
Learn More →
Q. What is the work done in moving a charge of 2 μC from a point at 50 V to a point at 100 V?
A.
0.1 mJ
B.
0.2 mJ
C.
0.3 mJ
D.
0.4 mJ
Show solution
Solution
Work done W = q * ΔV = 2 × 10^-6 C * (100 V - 50 V) = 2 × 10^-6 * 50 = 0.1 mJ.
Correct Answer:
B
— 0.2 mJ
Learn More →
Q. What is the work done in moving a charge of 2 μC from a point at 50 V to another at 100 V?
A.
100 μJ
B.
200 μJ
C.
150 μJ
D.
50 μJ
Show solution
Solution
Work done W = q * ΔV = (2 × 10^-6 C) * (100 V - 50 V) = 100 μJ.
Correct Answer:
B
— 200 μJ
Learn More →
Q. What is the work done in moving a mass from a point A to point B in a uniform gravitational field?
A.
Depends on the path taken
B.
Zero
C.
Equal to the change in gravitational potential energy
D.
Equal to the gravitational force times distance
Show solution
Solution
The work done is equal to the change in gravitational potential energy, which depends on the initial and final positions.
Correct Answer:
C
— Equal to the change in gravitational potential energy
Learn More →
Q. What is the work done in moving an object from a point A to point B in a uniform gravitational field?
A.
Depends on the path taken
B.
Zero
C.
Depends on the mass of the object
D.
Depends on the height difference
Show solution
Solution
The work done in moving an object in a uniform gravitational field depends only on the height difference between points A and B.
Correct Answer:
D
— Depends on the height difference
Learn More →
Q. What is the work done in moving an object from one point to another in a gravitational field?
A.
Depends on the path taken
B.
Is always zero
C.
Depends only on the initial and final positions
D.
Is maximum at the highest point
Show solution
Solution
The work done in moving an object in a gravitational field depends only on the initial and final positions, not the path taken.
Correct Answer:
C
— Depends only on the initial and final positions
Learn More →
Q. What is the work done on a gas during an isochoric process?
A.
Positive
B.
Negative
C.
Zero
D.
Depends on the gas
Show solution
Solution
In an isochoric process, the volume remains constant, which means no work is done on or by the gas. Therefore, the work done is zero.
Correct Answer:
C
— Zero
Learn More →
Q. What is the work done on a gas during an isothermal compression? (2019)
A.
Positive
B.
Negative
C.
Zero
D.
Depends on the volume
Show solution
Solution
The work done on a gas during isothermal compression is positive, as work is done on the gas to compress it.
Correct Answer:
A
— Positive
Learn More →
Q. What is the work done on a gas when it is compressed from 4 L to 2 L at a constant pressure of 2 atm?
A.
4 L·atm
B.
2 L·atm
C.
8 L·atm
D.
0 L·atm
Show solution
Solution
Work done (W) = P * ΔV = 2 atm * (2 L - 4 L) = 2 atm * (-2 L) = -4 L·atm (work done on the gas is positive).
Correct Answer:
A
— 4 L·atm
Learn More →
Q. What is the work done on a gas when it is compressed from 5 L to 2 L at a constant pressure of 200 kPa? (2022)
A.
600 J
B.
800 J
C.
1000 J
D.
1200 J
Show solution
Solution
Work done (W) = P * ΔV = 200 kPa * (2 L - 5 L) = 200 kPa * (-3 L) = -600 J (work done on the gas).
Correct Answer:
C
— 1000 J
Learn More →
Q. What is the work done on a gas when it is compressed isothermally from 4 L to 2 L at a pressure of 1 atm? (2021)
A.
2.0 L·atm
B.
4.0 L·atm
C.
6.0 L·atm
D.
8.0 L·atm
Show solution
Solution
Work done (W) = PΔV = 1 atm * (2 L - 4 L) = 2 L·atm.
Correct Answer:
B
— 4.0 L·atm
Learn More →
Q. What is the work done when 1 mole of an ideal gas expands isothermally from 10 L to 20 L at 300 K? (R = 8.31 J/mol·K) (2023)
A.
0 J
B.
830 J
C.
1660 J
D.
2490 J
Show solution
Solution
Work done = nRT ln(Vf/Vi) = 1 mol × 8.31 J/mol·K × 300 K × ln(20/10) = 1660 J.
Correct Answer:
C
— 1660 J
Learn More →
Q. What is the work done when 1 mole of an ideal gas expands isothermally from 10 L to 20 L at 300 K? (2022)
A.
300 J
B.
600 J
C.
150 J
D.
0 J
Show solution
Solution
Work done W = nRT ln(Vf/Vi) = 1 * 8.314 * 300 * ln(20/10) = 600 J.
Correct Answer:
B
— 600 J
Learn More →
Showing 25321 to 25350 of 31669 (1056 Pages)
