Major Competitive Exams MCQ & Objective Questions
Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.
What You Will Practise Here
Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams
Exam Relevance
The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.
Common Mistakes Students Make
Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam
FAQs
Question: How can I improve my performance in Major Competitive Exams?Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.
Question: What types of questions should I focus on for these exams?Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.
Question: Are there specific strategies for tackling objective questions?Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.
Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!
Q. What is the vertex of the parabola given by the equation y = -2(x - 1)^2 + 4?
A.
(1, 4)
B.
(1, -4)
C.
(4, 1)
D.
(-1, 4)
Show solution
Solution
The vertex form of a parabola is y = a(x - h)^2 + k. Here, h = 1 and k = 4, so the vertex is (1, 4).
Correct Answer:
A
— (1, 4)
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Q. What is the vertex of the parabola given by the equation y = 2x^2 - 4x + 1?
A.
(1, -1)
B.
(1, 0)
C.
(2, 1)
D.
(0, 1)
Show solution
Solution
To find the vertex, use the formula x = -b/(2a). Here, a = 2, b = -4, so x = 1. Substitute x = 1 into the equation to find y = -1.
Correct Answer:
A
— (1, -1)
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Q. What is the vertex of the parabola represented by the equation y = -2(x - 1)^2 + 4?
A.
(1, 4)
B.
(1, -4)
C.
(-1, 4)
D.
(-1, -4)
Show solution
Solution
The vertex form of a parabola is y = a(x - h)^2 + k. Here, h = 1 and k = 4, so the vertex is (1, 4).
Correct Answer:
A
— (1, 4)
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Q. What is the vertex of the parabola represented by the equation y = 2x^2 - 8x + 5?
A.
(2, -3)
B.
(2, -7)
C.
(4, -3)
D.
(4, -7)
Show solution
Solution
The vertex can be found using x = -b/(2a) = 4. Substituting x = 4 into the equation gives y = -3.
Correct Answer:
A
— (2, -3)
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Q. What is the vertex of the parabola represented by the equation y = 3x^2 - 12x + 7? (2023)
A.
(2, -5)
B.
(2, -1)
C.
(2, 1)
D.
(2, 5)
Show solution
Solution
The vertex can be found using x = -b/(2a). Here, x = 12/(2*3) = 2. Substituting x = 2 into the equation gives y = 3(2)^2 - 12(2) + 7 = -5.
Correct Answer:
A
— (2, -5)
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Q. What is the vertex of the parabola represented by the equation y = x² - 4x + 3? (2022)
A.
(2, -1)
B.
(2, 1)
C.
(1, 2)
D.
(3, 0)
Show solution
Solution
The vertex can be found using the formula x = -b/2a. Here, x = 2, and substituting back gives y = -1.
Correct Answer:
A
— (2, -1)
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Q. What is the vertex of the parabola represented by the equation y = x² - 6x + 8? (2023)
A.
(3, -1)
B.
(3, -5)
C.
(2, -4)
D.
(2, -2)
Show solution
Solution
The vertex can be found using the formula x = -b/2a = 6/2 = 3. Substituting x = 3 into the equation gives y = -1.
Correct Answer:
A
— (3, -1)
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Q. What is the vertex of the quadratic function f(x) = 2x^2 - 8x + 5? (2021)
A.
(2, -3)
B.
(2, -7)
C.
(4, -3)
D.
(4, -7)
Show solution
Solution
The vertex can be found using x = -b/(2a). Here, x = 8/(2*2) = 2. Substituting x = 2 into f(x) gives f(2) = -3, so the vertex is (2, -3).
Correct Answer:
A
— (2, -3)
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Q. What is the vertex of the quadratic function f(x) = 2x^2 - 8x + 6?
A.
(2, -2)
B.
(2, 2)
C.
(4, -2)
D.
(4, 2)
Show solution
Solution
The vertex can be found using the formula x = -b/(2a), which gives x = 2. Substituting x back into the function gives the y-coordinate.
Correct Answer:
A
— (2, -2)
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Q. What is the viscosity of water at 20°C?
A.
0.001 Pa·s
B.
0.01 Pa·s
C.
0.1 Pa·s
D.
1 Pa·s
Show solution
Solution
The viscosity of water at 20°C is approximately 0.001 Pa·s.
Correct Answer:
A
— 0.001 Pa·s
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Q. What is the voltage across a 10 ohm resistor carrying a current of 0.5 A?
A.
5 V
B.
10 V
C.
15 V
D.
20 V
Show solution
Solution
Using Ohm's law, V = I * R = 0.5 A * 10 Ω = 5 V.
Correct Answer:
A
— 5 V
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Q. What is the voltage across a 10Ω resistor carrying a current of 2A? (2022)
A.
5V
B.
10V
C.
15V
D.
20V
Show solution
Solution
Using Ohm's law, V = I * R = 2A * 10Ω = 20V.
Correct Answer:
B
— 10V
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Q. What is the voltage across a 10Ω resistor carrying a current of 3A? (2022)
A.
30V
B.
20V
C.
10V
D.
15V
Show solution
Solution
Using Ohm's law, V = IR = 3A * 10Ω = 30V.
Correct Answer:
A
— 30V
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Q. What is the voltage across a 12Ω resistor carrying a current of 1.5A? (2023)
A.
18V
B.
12V
C.
6V
D.
24V
Show solution
Solution
Using Ohm's law, V = IR = 1.5A * 12Ω = 18V.
Correct Answer:
A
— 18V
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Q. What is the voltage across a 12Ω resistor carrying a current of 3A? (2023)
A.
36V
B.
24V
C.
12V
D.
18V
Show solution
Solution
Using Ohm's law, V = IR = 3A * 12Ω = 36V.
Correct Answer:
A
— 36V
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Q. What is the voltage across a 5Ω resistor carrying a current of 3A? (2023)
A.
15V
B.
10V
C.
5V
D.
20V
Show solution
Solution
Using Ohm's law, V = IR = 3A * 5Ω = 15V.
Correct Answer:
A
— 15V
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Q. What is the voltage across a 5Ω resistor if a current of 3A flows through it? (2020)
A.
15V
B.
10V
C.
5V
D.
20V
Show solution
Solution
Using Ohm's law, V = IR = 3A * 5Ω = 15V.
Correct Answer:
A
— 15V
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Q. What is the voltage drop across a 10Ω resistor carrying a current of 2A? (2019)
A.
5V
B.
10V
C.
15V
D.
20V
Show solution
Solution
Using Ohm's law, V = I * R = 2A * 10Ω = 20V.
Correct Answer:
B
— 10V
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Q. What is the voltage drop across a 3 ohm resistor carrying a current of 2 A?
A.
3 V
B.
6 V
C.
9 V
D.
12 V
Show solution
Solution
Using Ohm's law, V = I * R = 2 A * 3 ohms = 6 V.
Correct Answer:
B
— 6 V
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Q. What is the voltage drop across a 3Ω resistor carrying a current of 4A? (2019)
A.
6V
B.
8V
C.
12V
D.
15V
Show solution
Solution
Using Ohm's law, V = I * R = 4A * 3Ω = 12V.
Correct Answer:
C
— 12V
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Q. What is the voltage drop across a 5 ohm resistor carrying a current of 2 A?
A.
5 V
B.
10 V
C.
15 V
D.
20 V
Show solution
Solution
Using Ohm's law, V = I * R = 2 A * 5 ohms = 10 V.
Correct Answer:
B
— 10 V
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Q. What is the voltage drop across a 5 ohm resistor carrying a current of 3 A?
A.
15 V
B.
10 V
C.
5 V
D.
20 V
Show solution
Solution
Using Ohm's law, V = I * R = 3 A * 5Ω = 15 V.
Correct Answer:
A
— 15 V
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Q. What is the voltage drop across a 5Ω resistor carrying a current of 3A?
A.
5V
B.
10V
C.
15V
D.
20V
Show solution
Solution
Using Ohm's law, V = I * R = 3A * 5Ω = 15V.
Correct Answer:
C
— 15V
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Q. What is the volume occupied by 1 mole of an ideal gas at STP (Standard Temperature and Pressure)?
A.
22.4 L
B.
24.0 L
C.
18.0 L
D.
20.0 L
Show solution
Solution
At STP, 1 mole of an ideal gas occupies 22.4 liters.
Correct Answer:
A
— 22.4 L
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Q. What is the volume occupied by 1 mole of an ideal gas at STP?
A.
22.4 L
B.
24 L
C.
20 L
D.
18 L
Show solution
Solution
At STP, 1 mole of an ideal gas occupies 22.4 liters.
Correct Answer:
A
— 22.4 L
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Q. What is the volume occupied by 4 moles of an ideal gas at STP?
A.
22.4 L
B.
44.8 L
C.
67.2 L
D.
89.6 L
Show solution
Solution
At STP, 1 mole of gas occupies 22.4 L. Therefore, 4 moles occupy 4 x 22.4 L = 89.6 L.
Correct Answer:
B
— 44.8 L
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Q. What is the volume of 0.2 M NaOH required to neutralize 0.1 M HCl in 250 mL? (2020)
A.
125 mL
B.
250 mL
C.
500 mL
D.
100 mL
Show solution
Solution
Using the formula M1V1 = M2V2, (0.1 M)(0.25 L) = (0.2 M)(V2). V2 = 0.125 L = 125 mL.
Correct Answer:
A
— 125 mL
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Q. What is the volume of 1 liter in cubic meters?
A.
0.001
B.
0.01
C.
1
D.
1000
Show solution
Solution
1 liter is equal to 0.001 cubic meters.
Correct Answer:
A
— 0.001
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Q. What is the volume of 1 M HCl solution needed to obtain 0.5 moles of HCl? (2022)
A.
0.5 L
B.
1 L
C.
2 L
D.
0.25 L
Show solution
Solution
Volume = moles / molarity = 0.5 moles / 1 M = 0.5 L.
Correct Answer:
A
— 0.5 L
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Q. What is the volume of 1 M NaOH solution required to obtain 0.5 moles of NaOH?
A.
0.5 L
B.
1 L
C.
2 L
D.
0.25 L
Show solution
Solution
Using the formula M = moles/volume, Volume = moles/M = 0.5 moles / 1 M = 0.5 L.
Correct Answer:
A
— 0.5 L
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