Major Competitive Exams

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Major Competitive Exams

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Major Competitive Exams MCQ & Objective Questions

Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.

What You Will Practise Here

Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams

Exam Relevance

The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.

Common Mistakes Students Make

Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam

FAQs

Question: How can I improve my performance in Major Competitive Exams?
Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.

Question: What types of questions should I focus on for these exams?
Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.

Question: Are there specific strategies for tackling objective questions?
Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.

Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!

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Q. What is the van 't Hoff factor (i) for a solution of glucose (C6H12O6)? (2023)

A. 1
B. 2
C. 3
D. 4

Solution

Glucose does not dissociate in solution, so the van 't Hoff factor (i) = 1.

Correct Answer: A — 1

Q. What is the van 't Hoff factor (i) for a strong electrolyte like Na2SO4 in solution? (2023)

A. 1
B. 2
C. 3
D. 4

Solution

Na2SO4 dissociates into 3 ions (2 Na⁺ and 1 SO4²⁻), so i = 3.

Correct Answer: C — 3

Q. What is the van 't Hoff factor (i) for a strong electrolyte like NaCl in solution?

A. 1
B. 2
C. 3
D. 4

Solution

NaCl dissociates into two ions (Na+ and Cl-), so the van 't Hoff factor (i) is 2.

Correct Answer: B — 2

Q. What is the van 't Hoff factor (i) for a strong electrolyte that completely dissociates into 3 ions?

A. 1
B. 2
C. 3
D. 4

Solution

The van 't Hoff factor (i) is equal to the number of particles the solute dissociates into. For a strong electrolyte that dissociates into 3 ions, i = 3.

Correct Answer: C — 3

Q. What is the van 't Hoff factor (i) for glucose in solution?

A. 1
B. 2
C. 3
D. 0

Solution

The van 't Hoff factor (i) for glucose is 1, as it does not dissociate in solution.

Correct Answer: A — 1

Q. What is the van 't Hoff factor for a non-electrolyte solute?

A. 0
B. 1
C. 2
D. 3

Solution

For a non-electrolyte solute, the van 't Hoff factor (i) is 1, as it does not dissociate into ions.

Correct Answer: B — 1

Q. What is the vapor pressure of a solution containing 0.1 mol of a non-volatile solute in 1 kg of water? (Vapor pressure of pure water = 23.76 mmHg)

A. 22.88 mmHg
B. 21.76 mmHg
C. 20.76 mmHg
D. 19.76 mmHg

Solution

Vapor pressure = P°_solvent * (n_solvent / (n_solvent + n_solute)) = 23.76 * (55.5 / (55.5 + 0.1)) = 22.88 mmHg

Correct Answer: A — 22.88 mmHg

Q. What is the vapor pressure of a solution containing 1 mole of a non-volatile solute in 3 moles of solvent, assuming ideal behavior?

A. 0.25 P0
B. 0.75 P0
C. 1.0 P0
D. 0.5 P0

Solution

Vapor pressure lowering = (moles of solute / total moles) * P0 = (1 / (1 + 3)) * P0 = 0.25 P0, so vapor pressure = P0 - 0.25 P0 = 0.75 P0.

Correct Answer: B — 0.75 P0

Q. What is the vapor pressure of a solution containing 1 mole of a non-volatile solute in 9 moles of solvent, if the vapor pressure of the pure solvent is 100 mmHg?

A. 90 mmHg
B. 100 mmHg
C. 10 mmHg
D. 80 mmHg

Solution

Using Raoult's law, P_solution = X_solvent * P°_solvent = (9/10) * 100 mmHg = 90 mmHg.

Correct Answer: A — 90 mmHg

Q. What is the vapor pressure of a solution containing 1 mole of a non-volatile solute in 10 moles of solvent, assuming ideal behavior?

A. 0.1 P0
B. 0.9 P0
C. 1.0 P0
D. 0.5 P0

Solution

Using Raoult's law, the vapor pressure of the solution = (moles of solvent / total moles) * P0 = (10 / 11) * P0 = 0.909 P0.

Correct Answer: B — 0.9 P0

Q. What is the vapor pressure of a solution containing 1 mole of non-volatile solute in 3 moles of solvent if the vapor pressure of the pure solvent is 100 mmHg?

A. 75 mmHg
B. 100 mmHg
C. 25 mmHg
D. 50 mmHg

Solution

Using Raoult's law, P_solution = X_solvent * P°_solvent. X_solvent = 3/(1+3) = 0.75, so P_solution = 0.75 * 100 mmHg = 75 mmHg.

Correct Answer: A — 75 mmHg

Q. What is the vapor pressure of a solution containing 1 mole of solute in 10 moles of solvent, assuming ideal behavior? (2019)

A. 0.1 P0
B. 0.9 P0
C. 0.5 P0
D. 0.2 P0

Solution

Using Raoult's law, the vapor pressure of the solution = (moles of solvent / total moles) * P0 = (10 / 11) * P0 ≈ 0.909 P0.

Correct Answer: B — 0.9 P0

Q. What is the vapor pressure of a solution containing 1 mole of solute in 3 moles of solvent, assuming ideal behavior?

A. 0.25 P0
B. 0.75 P0
C. 0.5 P0
D. P0

Solution

Using Raoult's law, the vapor pressure of the solution = (moles of solvent / total moles) * P0 = (3 / (3 + 1)) * P0 = 0.75 P0.

Correct Answer: B — 0.75 P0

Q. What is the vapor pressure of a solution containing 1 mole of solute in 9 moles of solvent, assuming ideal behavior? (2019)

A. 0.1 P0
B. 0.9 P0
C. 0.5 P0
D. 0.2 P0

Solution

Using Raoult's law, the vapor pressure of the solution = (moles of solvent / total moles) * P0 = (9 / 10) * P0 = 0.9 P0.

Correct Answer: B — 0.9 P0

Q. What is the vapor pressure of a solution containing 2 moles of solute and 3 moles of solvent, assuming ideal behavior? (2022)

A. 0.4 P0
B. 0.6 P0
C. 0.2 P0
D. 0.8 P0

Solution

Vapor pressure of solution = (moles of solvent / total moles) * P0 = (3 / (2 + 3)) * P0 = 0.6 P0.

Correct Answer: B — 0.6 P0

Q. What is the vapor pressure of a solution containing 2 moles of solute and 4 moles of solvent, assuming ideal behavior? (2022)

A. 0.33 P0
B. 0.50 P0
C. 0.67 P0
D. 0.75 P0

Solution

Vapor pressure = (moles of solvent / total moles) * P0 = (4 / (2 + 4)) * P0 = (4/6) * P0 = 0.67 P0.

Correct Answer: C — 0.67 P0

Q. What is the vapor pressure of a solution containing 2 moles of solute and 4 moles of solvent compared to pure solvent? (2022)

A. 1/3
B. 1/2
C. 2/3
D. 1/4

Solution

Vapor pressure lowering = (moles of solute / total moles) = 2 / (2 + 4) = 2/6 = 1/3. Thus, vapor pressure is 1/2 of pure solvent.

Correct Answer: B — 1/2

Q. What is the vapor pressure of a solution containing a non-volatile solute compared to the pure solvent?

A. Higher than the pure solvent
B. Lower than the pure solvent
C. Equal to the pure solvent
D. Unpredictable

Solution

The vapor pressure of a solution containing a non-volatile solute is lower than that of the pure solvent due to the presence of solute particles.

Correct Answer: B — Lower than the pure solvent

Q. What is the variance of the data set {4, 8, 6, 5, 3}?

A. 2.5
B. 3
C. 4
D. 5

Solution

Mean = 5.2; Variance = [(4-5.2)² + (8-5.2)² + (6-5.2)² + (5-5.2)² + (3-5.2)²] / 5 = 2.56.

Correct Answer: A — 2.5

Q. What is the variance of the data set: 1, 2, 3, 4, 5?

A. 2
B. 1.5
C. 1
D. 0.5

Solution

Mean = 3. Variance = [(1-3)² + (2-3)² + (3-3)² + (4-3)² + (5-3)²] / 5 = 2.

Correct Answer: B — 1.5

Q. What is the variance of the data set: 2, 4, 4, 4, 5, 5, 7, 9?

A. 2.5
B. 3.5
C. 4.5
D. 5.5

Solution

Mean = 5.0; Variance = [(2-5)^2 + (4-5)^2 + (4-5)^2 + (4-5)^2 + (5-5)^2 + (5-5)^2 + (7-5)^2 + (9-5)^2] / 8 = 2.5.

Correct Answer: A — 2.5

Q. What is the variance of the following data set: {5, 7, 8, 9, 10}?

A. 2
B. 3
C. 4
D. 5

Solution

Mean = 7.8, Variance = [(5-7.8)² + (7-7.8)² + (8-7.8)² + (9-7.8)² + (10-7.8)²] / 5 = 3.

Correct Answer: B — 3

Q. What is the variance of the following numbers: 1, 1, 1, 1, 1?

A. 0
B. 1
C. 2
D. 3

Solution

All values are the same, so variance = 0.

Correct Answer: A — 0

Q. What is the variance of the following numbers: 1, 2, 3, 4, 5, 6? (2022)

A. 2.5
B. 3.5
C. 4.5
D. 5.5

Solution

Mean = (1 + 2 + 3 + 4 + 5 + 6) / 6 = 3.5. Variance = [(1-3.5)² + (2-3.5)² + (3-3.5)² + (4-3.5)² + (5-3.5)² + (6-3.5)²] / 6 = 2.92 (approx 2.5).

Correct Answer: A — 2.5

Q. What is the variance of the following numbers: 2, 4, 4, 4, 5, 5, 7, 9?

A. 4
B. 6
C. 8
D. 10

Solution

Mean = 5. Variance = [(2-5)² + (4-5)² + (4-5)² + (4-5)² + (5-5)² + (5-5)² + (7-5)² + (9-5)²] / 8 = 6.

Correct Answer: B — 6

Q. What is the variance of the following numbers: 5, 5, 5, 5? (2019)

A. 0
B. 1
C. 2
D. 3

Solution

All values are the same, so variance = 0.

Correct Answer: A — 0

Q. What is the variance of the following numbers: 5, 7, 9, 11? (2020)

A. 4
B. 6
C. 8
D. 10

Solution

Mean = (5 + 7 + 9 + 11) / 4 = 8. Variance = [(5-8)² + (7-8)² + (9-8)² + (11-8)²] / 4 = 4.

Correct Answer: A — 4

Q. What is the variance of the numbers: 1, 1, 1, 1, 1? (2023)

A. 0
B. 1
C. 2
D. 3

Solution

All values are the same, so variance = 0.

Correct Answer: A — 0

Q. What is the variance of the numbers: 5, 5, 5, 5? (2023)

A. 0
B. 1
C. 2
D. 3

Solution

All values are the same, so variance = 0.

Correct Answer: A — 0

Q. What is the vertex of the parabola defined by the equation y = -2(x - 1)^2 + 4?

A. (1, 4)
B. (1, -4)
C. (4, 1)
D. (-1, 4)

Solution

The vertex form of a parabola is y = a(x - h)^2 + k. Here, h = 1 and k = 4, so the vertex is (1, 4).

Correct Answer: A — (1, 4)

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