Engineering & Architecture Admissions MCQ & Objective Questions
Engineering & Architecture Admissions play a crucial role in shaping the future of aspiring students in India. With the increasing competition in entrance exams, mastering MCQs and objective questions is essential for effective exam preparation. Practicing these types of questions not only enhances concept clarity but also boosts confidence, helping students score better in their exams.
What You Will Practise Here
Key concepts in Engineering Mathematics
Fundamentals of Physics relevant to architecture and engineering
Important definitions and terminologies in engineering disciplines
Essential formulas for solving objective questions
Diagrams and illustrations for better understanding
Conceptual theories related to structural engineering
Analysis of previous years' important questions
Exam Relevance
The topics covered under Engineering & Architecture Admissions are highly relevant for various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter MCQs that test their understanding of core concepts, application of formulas, and analytical skills. Common question patterns include multiple-choice questions that require selecting the correct answer from given options, as well as assertion-reason type questions that assess deeper comprehension.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers.
Overlooking units in numerical problems, which can change the outcome.
Confusing similar concepts or terms, especially in definitions.
Neglecting to review diagrams, which are often crucial for solving problems.
Rushing through practice questions without understanding the underlying concepts.
FAQs
Question: What are the best ways to prepare for Engineering & Architecture Admissions MCQs?Answer: Regular practice of objective questions, reviewing key concepts, and taking mock tests can significantly enhance your preparation.
Question: How can I improve my accuracy in solving MCQs?Answer: Focus on understanding the concepts thoroughly, practice regularly, and learn to eliminate incorrect options to improve accuracy.
Start your journey towards success by solving practice MCQs today! Test your understanding and strengthen your knowledge in Engineering & Architecture Admissions to excel in your exams.
Q. Given vectors P = (4, 1, 0) and Q = (1, 2, 3), find the scalar product P · Q.
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Solution
P · Q = 4*1 + 1*2 + 0*3 = 4 + 2 + 0 = 6.
Correct Answer:
B
— 11
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Q. How does the addition of a surfactant affect the surface tension of water?
A.
Increases surface tension
B.
Decreases surface tension
C.
No effect on surface tension
D.
Surface tension becomes negative
Show solution
Solution
Surfactants lower the surface tension of water by disrupting the cohesive forces between water molecules.
Correct Answer:
B
— Decreases surface tension
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Q. How does the addition of salt to water affect its surface tension?
A.
Increases surface tension
B.
Decreases surface tension
C.
No effect on surface tension
D.
Salt has no effect on water
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Solution
The addition of salt to water can increase the surface tension due to the ionic interactions that enhance the cohesive forces among water molecules.
Correct Answer:
A
— Increases surface tension
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Q. How does the addition of soap to water affect its surface tension?
A.
Increases surface tension
B.
Decreases surface tension
C.
No effect on surface tension
D.
Changes surface tension unpredictably
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Solution
The addition of soap decreases the surface tension of water by disrupting the cohesive forces between water molecules.
Correct Answer:
B
— Decreases surface tension
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Q. How does the gravitational field strength vary with distance from a point mass?
A.
It increases linearly.
B.
It decreases with the square of the distance.
C.
It remains constant.
D.
It decreases linearly.
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Solution
The gravitational field strength decreases with the square of the distance from the point mass.
Correct Answer:
B
— It decreases with the square of the distance.
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Q. How does the gravitational force between two objects change if both masses are doubled?
A.
It becomes four times stronger
B.
It becomes twice as strong
C.
It remains the same
D.
It becomes half as strong
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Solution
Doubling both masses results in a fourfold increase in gravitational force, as it is directly proportional to the product of the masses.
Correct Answer:
A
— It becomes four times stronger
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Q. How does the gravitational force between two objects change if the distance between them is halved?
A.
It doubles
B.
It quadruples
C.
It remains the same
D.
It halves
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Solution
According to Newton's law of gravitation, if the distance is halved, the force increases by a factor of 4 (F ∝ 1/r²).
Correct Answer:
B
— It quadruples
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Q. How does the gravitational force between two objects change if the mass of one object is tripled?
A.
It triples
B.
It doubles
C.
It remains the same
D.
It increases by a factor of nine
Show solution
Solution
Gravitational force is directly proportional to the product of the masses. Tripling one mass triples the force.
Correct Answer:
A
— It triples
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Q. How does the gravitational potential change as you move away from a planet?
A.
It increases.
B.
It decreases.
C.
It remains constant.
D.
It oscillates.
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Solution
The gravitational potential decreases as you move away from a planet.
Correct Answer:
B
— It decreases.
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Q. How does the gravitational potential energy of a system of two masses change as they move closer together?
A.
It increases.
B.
It decreases.
C.
It remains constant.
D.
It becomes zero.
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Solution
The gravitational potential energy decreases as the two masses move closer together.
Correct Answer:
B
— It decreases.
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Q. How does the gravitational potential energy of an object change when it is lifted to a height 'h' above the ground?
A.
It decreases.
B.
It increases.
C.
It remains the same.
D.
It becomes zero.
Show solution
Solution
The gravitational potential energy increases as the object is lifted to a height 'h' above the ground.
Correct Answer:
B
— It increases.
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Q. How does the presence of a +M group affect the stability of a carbocation?
A.
Increases stability
B.
Decreases stability
C.
No effect
D.
Depends on the solvent
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Solution
A +M group increases the stability of a carbocation by donating electron density through resonance.
Correct Answer:
A
— Increases stability
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Q. How does the presence of a -I group affect the stability of a carbocation?
A.
Increases stability
B.
Decreases stability
C.
No effect
D.
Depends on the size of the group
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Solution
A -I group decreases the stability of a carbocation by withdrawing electron density.
Correct Answer:
B
— Decreases stability
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Q. How many atoms are in 2 moles of oxygen gas (O2)?
A.
6.022 x 10^23
B.
1.2044 x 10^24
C.
3.011 x 10^23
D.
12.044 x 10^23
Show solution
Solution
Each O2 molecule has 2 oxygen atoms. Number of atoms = moles x Avogadro's number x 2 = 2 moles x 6.022 x 10^23 molecules/mole x 2 = 1.2044 x 10^24 atoms.
Correct Answer:
B
— 1.2044 x 10^24
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Q. How many centimeters are there in a meter?
A.
10
B.
100
C.
1000
D.
10000
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Solution
There are 100 centimeters in a meter.
Correct Answer:
B
— 100
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Q. How many different ways can 3 red, 2 blue, and 1 green balls be arranged in a line?
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Solution
The total arrangements = 6! / (3! * 2! * 1!) = 60.
Correct Answer:
B
— 120
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Q. How many different ways can 4 people be seated at a round table?
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Solution
The number of arrangements of n people at a round table is (n-1)!. For 4 people, it is 3! = 6.
Correct Answer:
B
— 12
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Q. How many different ways can 4 students be selected from a group of 10?
A.
210
B.
120
C.
100
D.
90
Show solution
Solution
The number of ways to choose 4 from 10 is given by 10C4 = 210.
Correct Answer:
A
— 210
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Q. How many different ways can 6 people be seated at a round table?
A.
720
B.
120
C.
600
D.
480
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Solution
The number of arrangements of 6 people at a round table is (6-1)! = 5! = 120.
Correct Answer:
A
— 720
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Q. How many elements are in the power set of the empty set?
A.
0
B.
1
C.
2
D.
Infinite
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Solution
The power set of the empty set contains only one subset, which is the empty set itself. Thus, it has 1 element.
Correct Answer:
B
— 1
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Q. How many grams are in 0.25 moles of glucose (C6H12O6)?
A.
30 g
B.
45 g
C.
75 g
D.
90 g
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Solution
Molar mass of C6H12O6 = 6*12 + 12*1 + 6*16 = 180 g/mol. Mass = 0.25 moles x 180 g/mol = 45 g.
Correct Answer:
D
— 90 g
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Q. How many grams are in 0.25 moles of KCl?
A.
35 g
B.
70 g
C.
17.5 g
D.
140 g
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Solution
Molar mass of KCl = 39 + 35.5 = 74.5 g/mol. Mass = moles x molar mass = 0.25 moles x 74.5 g/mol = 18.625 g.
Correct Answer:
B
— 70 g
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Q. How many grams are in 0.25 moles of sulfuric acid (H2SO4)?
A.
49 g
B.
98 g
C.
24.5 g
D.
12.25 g
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Solution
Molar mass of H2SO4 = 98 g/mol. Mass = moles x molar mass = 0.25 moles x 98 g/mol = 24.5 g.
Correct Answer:
A
— 49 g
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Q. How many grams are in 0.5 moles of sodium (Na)?
A.
11 g
B.
22 g
C.
5.5 g
D.
44 g
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Solution
The molar mass of sodium is approximately 23 g/mol. Therefore, 0.5 moles of Na weigh 0.5 x 23 g = 11 g.
Correct Answer:
A
— 11 g
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Q. How many grams are in 2 moles of carbon dioxide (CO2)?
A.
44 g
B.
88 g
C.
22 g
D.
66 g
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Solution
The molar mass of CO2 is 44 g/mol. Thus, 2 moles of CO2 = 2 x 44 g = 88 g.
Correct Answer:
B
— 88 g
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Q. How many grams are in 3 moles of glucose (C6H12O6)?
A.
180 g
B.
360 g
C.
540 g
D.
90 g
Show solution
Solution
Molar mass of glucose = 6*12 + 12*1 + 6*16 = 180 g/mol. Mass = moles x molar mass = 3 moles x 180 g/mol = 540 g.
Correct Answer:
B
— 360 g
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Q. How many grams of CO2 are produced from the complete combustion of 1 mole of C3H8?
A.
44 g
B.
88 g
C.
132 g
D.
22 g
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Solution
C3H8 + 5O2 → 3CO2 + 4H2O. 1 mole of C3H8 produces 3 moles of CO2. Mass = 3 * 44 g = 132 g.
Correct Answer:
B
— 88 g
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Q. How many grams of KCl are needed to prepare 0.5 moles of KCl solution?
A.
37.5 g
B.
74.5 g
C.
50 g
D.
100 g
Show solution
Solution
The molar mass of KCl is 39 g/mol (K) + 35.5 g/mol (Cl) = 74.5 g/mol. Therefore, 0.5 moles of KCl will weigh 0.5 x 74.5 g = 37.25 g.
Correct Answer:
B
— 74.5 g
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Q. How many grams of KCl are needed to prepare 0.5 moles of KCl solution? (Molar mass of KCl = 74.5 g/mol)
A.
37.25 g
B.
74.5 g
C.
148.5 g
D.
18.5 g
Show solution
Solution
To find the mass, use the formula: mass = moles x molar mass. Thus, 0.5 moles x 74.5 g/mol = 37.25 g.
Correct Answer:
A
— 37.25 g
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Q. How many grams of KCl are needed to prepare 0.5 moles of KCl?
A.
37.5 g
B.
45 g
C.
50 g
D.
60 g
Show solution
Solution
The molar mass of KCl is approximately 74.5 g/mol. Therefore, 0.5 moles of KCl will weigh 0.5 x 74.5 g = 37.25 g.
Correct Answer:
B
— 45 g
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