Physics Syllabus (JEE Main)
Q. In a single-slit diffraction pattern, where is the first minimum located?
A.
At θ = 0
B.
At θ = λ/a
C.
At θ = a/λ
D.
At θ = 2λ/a
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Solution
The first minimum in a single-slit diffraction pattern occurs at θ = λ/a, where a is the width of the slit.
Correct Answer: B — At θ = λ/a
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Q. In a situation where two parallel wires carry currents in the same direction, what is the nature of the force between them?
A.
Attractive
B.
Repulsive
C.
No force
D.
Depends on the distance
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Solution
Two parallel wires carrying currents in the same direction experience an attractive force between them.
Correct Answer: A — Attractive
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Q. In a solenoid carrying current, what is the direction of the magnetic field inside the solenoid?
A.
Perpendicular to the axis of the solenoid
B.
Along the axis of the solenoid
C.
Radially outward from the solenoid
D.
Zero inside the solenoid
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Solution
The magnetic field inside a solenoid is uniform and directed along the axis of the solenoid.
Correct Answer: B — Along the axis of the solenoid
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Q. In a solenoid carrying current, what is the direction of the magnetic field inside the solenoid according to Ampere's Law?
A.
From south to north
B.
From north to south
C.
Perpendicular to the axis
D.
Radially outward
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Solution
The magnetic field inside a solenoid is directed from the north pole to the south pole of the solenoid.
Correct Answer: B — From north to south
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Q. In a solenoid carrying current, what is the magnetic field inside the solenoid?
A.
Zero
B.
μ₀nI
C.
μ₀I
D.
μ₀I/(2n)
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Solution
The magnetic field inside a solenoid carrying current is given by B = μ₀nI, where n is the number of turns per unit length.
Correct Answer: B — μ₀nI
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Q. In a solenoid, if the number of turns per unit length is doubled, what happens to the magnetic field inside the solenoid?
A.
It doubles
B.
It remains the same
C.
It halves
D.
It quadruples
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Solution
The magnetic field inside a solenoid is directly proportional to the number of turns per unit length, so it doubles.
Correct Answer: A — It doubles
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Q. In a solenoid, what factor does NOT affect the strength of the magnetic field inside it?
A.
Number of turns per unit length
B.
Current through the solenoid
C.
Length of the solenoid
D.
Permeability of the core material
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Solution
The length of the solenoid does not affect the strength of the magnetic field inside it; it is determined by the number of turns per unit length, the current, and the permeability of the core material.
Correct Answer: C — Length of the solenoid
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Q. In a solenoid, what is the effect of increasing the number of turns per unit length on the magnetic field strength?
A.
Increases
B.
Decreases
C.
Remains the same
D.
Becomes zero
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Solution
Increasing the number of turns per unit length in a solenoid increases the magnetic field strength.
Correct Answer: A — Increases
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Q. In a solenoid, what is the expression for the magnetic field inside it when it carries a current I?
A.
B = μ₀nI
B.
B = μ₀I/2πr
C.
B = μ₀I/4πr²
D.
B = μ₀I/n
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Solution
Inside a long solenoid, the magnetic field is given by B = μ₀nI, where n is the number of turns per unit length.
Correct Answer: A — B = μ₀nI
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Q. In a standing wave, the points of maximum displacement are called:
A.
Nodes
B.
Antinodes
C.
Crests
D.
Troughs
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Solution
In a standing wave, the points of maximum displacement are called antinodes, while nodes are points of zero displacement.
Correct Answer: B — Antinodes
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Q. In a standing wave, what is the distance between two consecutive nodes?
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Solution
The distance between two consecutive nodes in a standing wave is λ/2.
Correct Answer: A — λ/2
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Q. In a standing wave, what is the point called where there is no displacement?
A.
Node
B.
Antinode
C.
Crest
D.
Trough
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Solution
A node is a point in a standing wave where the displacement is always zero.
Correct Answer: A — Node
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Q. In a standing wave, what is the position of the nodes?
A.
Points of maximum amplitude
B.
Points of minimum amplitude
C.
Points of zero displacement
D.
Points of maximum energy
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Solution
Nodes in a standing wave are points where there is no displacement, meaning they are points of minimum amplitude.
Correct Answer: C — Points of zero displacement
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Q. In a standing wave, what is the relationship between the nodes and antinodes?
A.
Nodes are points of maximum amplitude
B.
Antinodes are points of zero amplitude
C.
Nodes are points of zero amplitude
D.
Antinodes are points of minimum amplitude
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Solution
In a standing wave, nodes are points of zero amplitude, while antinodes are points of maximum amplitude.
Correct Answer: C — Nodes are points of zero amplitude
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Q. In a system of two particles, if one particle has an angular momentum of L1 and the other has L2, what is the total angular momentum of the system?
A.
L1 + L2
B.
L1 - L2
C.
L1 * L2
D.
L1 / L2
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Solution
Total angular momentum of the system is the vector sum of individual angular momenta: L_total = L1 + L2.
Correct Answer: A — L1 + L2
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Q. In a system of two rotating bodies, if one body has twice the moment of inertia of the other, how does their angular momentum compare if they rotate with the same angular velocity?
A.
The same
B.
Twice as much
C.
Half as much
D.
Four times as much
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Solution
Angular momentum L = Iω; if one has twice the moment of inertia, it will have twice the angular momentum at the same angular velocity.
Correct Answer: B — Twice as much
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Q. In a system of two rotating disks, if disk A has twice the moment of inertia of disk B and they are both rotating with the same angular velocity, what can be said about their angular momentum?
A.
LA = LB
B.
LA = 2LB
C.
LA = 4LB
D.
LA = 1/2 LB
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Solution
Angular momentum L = Iω; since IA = 2IB and ωA = ωB, LA = 2LB.
Correct Answer: B — LA = 2LB
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Q. In a temperature-resistivity graph, what does the slope represent for a metallic conductor?
A.
Resistivity
B.
Temperature coefficient of resistivity
C.
Resistance
D.
Conductivity
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Solution
The slope of the temperature-resistivity graph represents the temperature coefficient of resistivity.
Correct Answer: B — Temperature coefficient of resistivity
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Q. In a tensile test, if a material exhibits a linear stress-strain relationship, what type of deformation is it undergoing?
A.
Elastic deformation
B.
Plastic deformation
C.
Brittle fracture
D.
Ductile fracture
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Solution
A linear stress-strain relationship indicates that the material is undergoing elastic deformation.
Correct Answer: A — Elastic deformation
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Q. In a tensile test, if a material shows a linear relationship between stress and strain up to a certain point, this point is known as:
A.
Yield point
B.
Ultimate tensile strength
C.
Elastic limit
D.
Fracture point
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Solution
The elastic limit is the maximum stress that a material can withstand while still returning to its original shape.
Correct Answer: C — Elastic limit
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Q. In a tensile test, if a material shows a linear relationship between stress and strain, it is said to be in which region?
A.
Plastic region
B.
Elastic region
C.
Yield point
D.
Fracture point
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Solution
The linear relationship between stress and strain indicates that the material is in the elastic region.
Correct Answer: B — Elastic region
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Q. In a tensile test, if the stress-strain curve shows a linear relationship, what does this indicate about the material?
A.
It is inelastic
B.
It is elastic
C.
It has reached its yield point
D.
It will break immediately
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Solution
A linear relationship in the stress-strain curve indicates that the material behaves elastically within that range.
Correct Answer: B — It is elastic
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Q. In a thermodynamic cycle, if the net work done by the system is 200 J and the heat absorbed is 300 J, what is the change in internal energy?
A.
100 J
B.
200 J
C.
300 J
D.
500 J
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Solution
According to the First Law of Thermodynamics, ΔU = Q - W. Here, ΔU = 300 J - 200 J = 100 J.
Correct Answer: A — 100 J
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Q. In a thermodynamic cycle, the net work done is equal to the:
A.
Net heat added to the system
B.
Net heat removed from the system
C.
Change in internal energy
D.
Change in entropy
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Solution
In a thermodynamic cycle, the net work done is equal to the net heat added to the system, according to the first law of thermodynamics.
Correct Answer: A — Net heat added to the system
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Q. In a thermodynamic cycle, the net work done is equal to:
A.
Net heat added to the system
B.
Net change in internal energy
C.
Net heat removed from the system
D.
None of the above
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Solution
In a thermodynamic cycle, the net work done is equal to the net heat added to the system, as the internal energy change is zero.
Correct Answer: A — Net heat added to the system
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Q. In a thermodynamic process, if the internal energy of a system increases, which of the following could be true?
A.
Heat is added to the system
B.
Work is done by the system
C.
Both heat is added and work is done by the system
D.
Work is done on the system
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Solution
The internal energy of a system increases if heat is added to the system or work is done on the system.
Correct Answer: A — Heat is added to the system
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Q. In a thermodynamic process, if the pressure of a gas is held constant and the volume decreases, what happens to the temperature?
A.
It increases
B.
It decreases
C.
It remains constant
D.
It becomes negative
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Solution
According to Gay-Lussac's Law, if the volume decreases at constant pressure, the temperature must increase.
Correct Answer: B — It decreases
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Q. In a thermodynamic process, if the volume of a gas is doubled while keeping the temperature constant, what happens to the pressure?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
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Solution
According to Boyle's Law, for a constant temperature, pressure is inversely proportional to volume. If volume doubles, pressure halves.
Correct Answer: B — It halves
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Q. In a thin film interference pattern, what happens to the colors observed as the angle of incidence increases?
A.
Colors become more vivid
B.
Colors disappear
C.
Colors shift
D.
Colors remain unchanged
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Solution
As the angle of incidence increases, the effective path difference changes, causing a shift in the observed colors.
Correct Answer: C — Colors shift
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Q. In a thin film interference, if the film is denser than the medium it is placed in, what happens to the phase of the reflected wave?
A.
No phase change
B.
Phase change of π
C.
Phase change of 2π
D.
Phase change of π/2
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Solution
When light reflects off a denser medium, it undergoes a phase change of π (180 degrees).
Correct Answer: B — Phase change of π
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