Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.
What You Will Practise Here
Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams
Exam Relevance
The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.
Common Mistakes Students Make
Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam
FAQs
Question: How can I improve my performance in Major Competitive Exams? Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.
Question: What types of questions should I focus on for these exams? Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.
Question: Are there specific strategies for tackling objective questions? Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.
Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!
Q. A person is 40 meters away from a building and sees the top of the building at an angle of elevation of 30 degrees. What is the height of the building?
A.
20√3 meters
B.
30 meters
C.
40 meters
D.
10√3 meters
Solution
Using tan(30°) = height / distance, we have height = distance * tan(30°) = 40 * (1/√3) = 40/√3 = 20√3 meters.
Q. A person is on a diet that consists of 50% carbohydrates, 30% fats, and 20% proteins. If they consume 1800 calories, how many calories are from carbohydrates?
A.
600 calories
B.
700 calories
C.
800 calories
D.
900 calories
Solution
50% of 1800 calories = 0.50 * 1800 = 900 calories from carbohydrates.
Q. A person is running at 3 m/s on a moving escalator that moves at 2 m/s in the same direction. What is the speed of the person relative to a stationary observer?
A.
1 m/s
B.
3 m/s
C.
5 m/s
D.
2 m/s
Solution
Speed of person relative to observer = Speed of escalator + Speed of person = 2 m/s + 3 m/s = 5 m/s.
Q. A person is running at a speed of 10 m/s. If he is running towards a train moving at 20 m/s in the opposite direction, what is the relative speed of the train with respect to the person?
A.
10 m/s
B.
20 m/s
C.
30 m/s
D.
40 m/s
Solution
Relative speed = speed of train + speed of person = 20 + 10 = 30 m/s.
Q. A person is standing 100 meters away from a building. If the angle of elevation to the top of the building is 45 degrees, what is the height of the building?
A.
100 m
B.
50 m
C.
75 m
D.
25 m
Solution
Using tan(45°) = height/distance, we have height = distance * tan(45°) = 100 * 1 = 100 m.
Q. A person is standing 20 m away from a building and sees the top of the building at an angle of elevation of 45 degrees. What is the height of the building? (2019)
Q. A person is standing 20 meters away from a flagpole. If the angle of elevation to the top of the flagpole is 30 degrees, what is the height of the flagpole?
Q. A person is standing 20 meters away from a vertical cliff. If the angle of elevation to the top of the cliff is 60 degrees, what is the height of the cliff?
A.
10√3 m
B.
20√3 m
C.
30√3 m
D.
40√3 m
Solution
Using tan(60°) = height/20, we have √3 = height/20. Therefore, height = 20√3 m.
Q. A person is standing 20 meters away from a vertical pole. If the angle of elevation to the top of the pole is 60 degrees, what is the height of the pole? (2022)
Q. A person is standing 25 meters away from a building and measures the angle of elevation to the top of the building as 36.87 degrees. What is the height of the building?
A.
15 meters
B.
20 meters
C.
10 meters
D.
25 meters
Solution
Let h be the height of the building. tan(36.87°) = h/25. Therefore, h = 25 * tan(36.87°) = 25 * 0.75 = 18.75 meters.
Q. A person is standing 25 meters away from a building and sees the top of the building at an angle of elevation of 60 degrees. What is the height of the building?
A.
25√3 meters
B.
15 meters
C.
20 meters
D.
30 meters
Solution
Using tan(60°) = height / distance, we have height = distance * tan(60°) = 25 * √3 = 25√3 meters.
Q. A person is standing 25 meters away from a building and sees the top of the building at an angle of elevation of 30 degrees. What is the height of the building?
Q. A person is standing 25 meters away from a building. If the angle of elevation to the top of the building is 36.87 degrees, what is the height of the building?
Q. A person is standing 25 meters away from a cliff and sees the top of the cliff at an angle of elevation of 60 degrees. What is the height of the cliff?
Q. A person is standing 25 meters away from a cliff and sees the top of the cliff at an angle of elevation of 75 degrees. What is the height of the cliff?
Q. A person is standing 25 meters away from a vertical cliff. If the angle of elevation to the top of the cliff is 60 degrees, what is the height of the cliff?
A.
10 m
B.
15 m
C.
20 m
D.
25 m
Solution
Using tan(60°) = height/25, we have √3 = height/25. Therefore, height = 25√3 ≈ 43.3 m.
Q. A person is standing 25 meters away from a vertical pole. If the angle of elevation to the top of the pole is 36.87 degrees, what is the height of the pole?
A.
15 m
B.
20 m
C.
25 m
D.
30 m
Solution
Using tan(36.87°) = height/distance, we have height = distance * tan(36.87°) = 25 * 0.75 = 15 m.
Q. A person is standing 30 m away from a tree and observes the top of the tree at an angle of elevation of 60 degrees. What is the height of the tree? (2022)
Q. A person is standing 30 m away from the base of a tree. If the angle of elevation to the top of the tree is 60 degrees, what is the height of the tree?
A.
15 m
B.
20 m
C.
25 m
D.
30 m
Solution
Using tan(60°) = height/30, we have √3 = height/30. Therefore, height = 30√3 = 25 m.
Q. A person is standing 30 m away from the foot of a tree. If the angle of elevation to the top of the tree is 60 degrees, what is the height of the tree?
A.
15 m
B.
20 m
C.
25 m
D.
30 m
Solution
Using tan(60°) = height/30, we have √3 = height/30. Therefore, height = 30√3 = 25 m.
Q. A person is standing 30 meters away from a building. If the angle of elevation to the top of the building is 60 degrees, what is the height of the building? (2022)
A.
15 m
B.
30 m
C.
25 m
D.
20 m
Solution
Height = Distance * tan(angle) = 30 * tan(60) = 30 * √3 ≈ 51.96 m, which rounds to 30 m.
