Physics Syllabus (JEE Main)
Q. In a circuit with a 12V battery and two resistors in series (4Ω and 8Ω), what is the current flowing through the circuit?
A.
0.5A
B.
1A
C.
1.5A
D.
2A
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Solution
Total resistance R = R1 + R2 = 4Ω + 8Ω = 12Ω. Using Ohm's law, I = V/R = 12V / 12Ω = 1A.
Correct Answer: B — 1A
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Q. In a circuit with a 12V battery and two resistors in series (R1 = 4Ω, R2 = 8Ω), what is the current flowing through the circuit?
A.
0.5A
B.
1A
C.
1.5A
D.
2A
Show solution
Solution
Total resistance R_total = R1 + R2 = 4Ω + 8Ω = 12Ω. Current I = V/R_total = 12V/12Ω = 1A.
Correct Answer: B — 1A
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Q. In a circuit with a 12V battery and two resistors in series (R1 = 4Ω, R2 = 8Ω), what is the voltage across R2?
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Solution
The total resistance is R_total = R1 + R2 = 4Ω + 8Ω = 12Ω. The current is I = V/R_total = 12V / 12Ω = 1A. The voltage across R2 is V_R2 = I * R2 = 1A * 8Ω = 8V.
Correct Answer: C — 8V
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Q. In a circuit with a 12V battery and two resistors of 4 ohms and 8 ohms in series, what is the voltage drop across the 8 ohm resistor?
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Solution
Total resistance R_total = 4 + 8 = 12 ohms. Current I = V/R_total = 12V/12 ohms = 1A. Voltage drop across 8 ohm resistor = I * R = 1A * 8 ohms = 8V.
Correct Answer: B — 6V
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Q. In a circuit with a 12V battery and two resistors of 4Ω and 8Ω in series, what is the voltage across the 8Ω resistor?
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Solution
Using the voltage divider rule, V = (R2 / (R1 + R2)) * Vtotal = (8 / (4 + 8)) * 12 = 8V.
Correct Answer: C — 8V
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Q. In a circuit with a 12V battery and two resistors of 4Ω and 8Ω in series, what is the current flowing through the circuit?
A.
0.5A
B.
1A
C.
1.5A
D.
2A
Show solution
Solution
Total resistance R = R1 + R2 = 4Ω + 8Ω = 12Ω. Current I = V/R = 12V / 12Ω = 1A.
Correct Answer: B — 1A
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Q. In a circuit with a 15V battery and three resistors (5Ω, 10Ω, and 15Ω) in parallel, what is the equivalent resistance?
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Solution
1/R_eq = 1/5 + 1/10 + 1/15 = 0.1 + 0.0667 + 0.0667 = 0.2334. Therefore, R_eq = 4.29Ω.
Correct Answer: B — 3Ω
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Q. In a circuit with a 15V battery and two resistors in series (5Ω and 10Ω), what is the voltage drop across the 10Ω resistor?
A.
5V
B.
10V
C.
15V
D.
20V
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Solution
Using the voltage divider rule, V2 = (R2 / (R1 + R2)) * Vtotal = (10 / (5 + 10)) * 15 = 10V.
Correct Answer: B — 10V
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Q. In a circuit with a 15V battery and two resistors in series (R1 = 5Ω, R2 = 10Ω), what is the voltage across R2?
A.
10V
B.
5V
C.
15V
D.
0V
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Solution
Voltage across R2 = (R2 / (R1 + R2)) * V = (10Ω / (5Ω + 10Ω)) * 15V = 10V.
Correct Answer: A — 10V
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Q. In a circuit with a 20V battery and two resistors (4Ω and 8Ω) in parallel, what is the total current supplied by the battery?
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Solution
Total resistance in parallel, 1/Req = 1/R1 + 1/R2 = 1/4 + 1/8 = 3/8. Therefore, Req = 8/3Ω. Total current I = V/Req = 20V / (8/3) = 7.5A.
Correct Answer: C — 4A
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Q. In a circuit with a 24 V battery and a 6 ohm resistor, what is the current flowing through the resistor?
A.
2 A
B.
4 A
C.
6 A
D.
8 A
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Solution
Using Ohm's law, I = V/R = 24 V / 6 ohms = 4 A.
Correct Answer: B — 4 A
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Q. In a circuit with a 24 V battery and a total resistance of 6 ohms, what is the total current flowing through the circuit?
A.
2 A
B.
4 A
C.
6 A
D.
8 A
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Solution
Using Ohm's law, I = V/R = 24 V / 6 ohms = 4 A.
Correct Answer: B — 4 A
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Q. In a circuit with a 24V battery and a 6 ohm resistor, what is the voltage drop across the resistor?
A.
4 V
B.
12 V
C.
24 V
D.
6 V
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Solution
Using Ohm's law, V = I * R. First, find the current I = V/R = 24V / 6 ohms = 4 A. Then, V_drop = I * R = 4 A * 6 ohms = 24 V.
Correct Answer: B — 12 V
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Q. In a circuit with a 24V battery and a total resistance of 8 ohms, what is the total current flowing in the circuit?
A.
3 A
B.
2 A
C.
4 A
D.
6 A
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Solution
Using Ohm's law, I = V/R = 24V / 8Ω = 3 A.
Correct Answer: C — 4 A
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Q. In a circuit with a 24V battery and three resistors (R1 = 4Ω, R2 = 4Ω, R3 = 4Ω) in parallel, what is the total current supplied by the battery?
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Solution
Equivalent resistance R_eq = 1/(1/R1 + 1/R2 + 1/R3) = 1/(1/4 + 1/4 + 1/4) = 1.33Ω. Total current I = V/R_eq = 24V/1.33Ω = 18A.
Correct Answer: D — 6A
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Q. In a circuit with a 24V battery and three resistors in parallel (4Ω, 6Ω, and 12Ω), what is the total current supplied by the battery?
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Solution
1/R_eq = 1/4 + 1/6 + 1/12 = 1. Therefore, R_eq = 2Ω. Total current I = V/R_eq = 24V/2Ω = 12A.
Correct Answer: C — 4A
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Q. In a circuit with a 24V battery and three resistors in series (R1 = 2Ω, R2 = 3Ω, R3 = 5Ω), what is the voltage drop across R2?
A.
6V
B.
8V
C.
12V
D.
10V
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Solution
Total resistance R_total = R1 + R2 + R3 = 2Ω + 3Ω + 5Ω = 10Ω. Current I = V/R_total = 24V / 10Ω = 2.4A. Voltage drop across R2 = I * R2 = 2.4A * 3Ω = 7.2V.
Correct Answer: B — 8V
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Q. In a circuit with a 24V battery and three resistors of 2 ohms, 4 ohms, and 6 ohms in series, what is the total current flowing through the circuit?
A.
2 A
B.
3 A
C.
4 A
D.
1 A
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Solution
Total resistance R = 2 + 4 + 6 = 12 ohms. Using Ohm's law, I = V/R = 24V / 12 ohms = 2 A.
Correct Answer: B — 3 A
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Q. In a circuit with a 24V battery and three resistors of 4Ω, 4Ω, and 8Ω in series, what is the voltage drop across the 8Ω resistor?
A.
8V
B.
12V
C.
16V
D.
24V
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Solution
Total resistance R = 4Ω + 4Ω + 8Ω = 16Ω. Current I = V/R = 24V/16Ω = 1.5A. Voltage drop across 8Ω = I * R = 1.5A * 8Ω = 12V.
Correct Answer: B — 12V
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Q. In a circuit with a 24V battery and two 12 ohm resistors in series, what is the current flowing through the circuit?
A.
1 A
B.
2 A
C.
3 A
D.
4 A
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Solution
Total resistance R_total = 12 + 12 = 24 ohms. Current I = V/R_total = 24V / 24Ω = 1 A.
Correct Answer: B — 2 A
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Q. In a circuit with a 24V battery and two 12Ω resistors in parallel, what is the total current supplied by the battery?
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Solution
Total resistance R = 1/(1/12 + 1/12) = 6Ω; Total current I = V/R = 24V / 6Ω = 4A.
Correct Answer: D — 4A
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Q. In a circuit with a 24V battery and two 12Ω resistors in series, what is the current flowing through the circuit?
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Solution
Total resistance R_total = 12Ω + 12Ω = 24Ω. Current I = V/R_total = 24V / 24Ω = 1A.
Correct Answer: B — 2A
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Q. In a circuit with a 24V battery and two resistors in series (4Ω and 8Ω), what is the voltage across the 8Ω resistor?
A.
8V
B.
12V
C.
16V
D.
20V
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Solution
Voltage across 8Ω resistor = (R2 / (R1 + R2)) * Vtotal = (8 / (4 + 8)) * 24 = 16V.
Correct Answer: B — 12V
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Q. In a circuit with a 24V battery and two resistors in series (6Ω and 3Ω), what is the voltage across the 3Ω resistor?
A.
8V
B.
12V
C.
16V
D.
4V
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Solution
Total resistance = 6Ω + 3Ω = 9Ω. Current I = V / R = 24V / 9Ω = 2.67A. Voltage across 3Ω = I * R = 2.67A * 3Ω = 8V.
Correct Answer: A — 8V
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Q. In a circuit with a 24V battery and two resistors in series (R1 = 6Ω, R2 = 12Ω), what is the voltage drop across R2?
A.
12V
B.
18V
C.
6V
D.
8V
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Solution
Voltage drop across R2 = V_R2 = (R2 / (R1 + R2)) * V_total = (12Ω / (6Ω + 12Ω)) * 24V = 12V.
Correct Answer: A — 12V
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Q. In a circuit with a 24V battery and two resistors in series (R1 = 8Ω, R2 = 16Ω), what is the voltage across R2?
A.
16V
B.
8V
C.
12V
D.
4V
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Solution
Using voltage division, V_R2 = V_total * (R2 / (R1 + R2)) = 24V * (16Ω / (8Ω + 16Ω)) = 16V.
Correct Answer: A — 16V
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Q. In a circuit with a 24V battery and two resistors in series (R1 = 8Ω, R2 = 16Ω), what is the current flowing through the circuit?
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Solution
Total resistance R_total = R1 + R2 = 8Ω + 16Ω = 24Ω. The current is I = V/R_total = 24V / 24Ω = 1A.
Correct Answer: B — 2A
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Q. In a circuit with a 24V battery and two resistors of 4Ω and 8Ω in series, what is the voltage across the 8Ω resistor?
A.
8V
B.
12V
C.
16V
D.
20V
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Solution
Voltage across R2 = (R2 / (R1 + R2)) * V = (8 / (4 + 8)) * 24 = 16V.
Correct Answer: B — 12V
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Q. In a circuit with a 24V battery and two resistors of 6Ω and 12Ω in series, what is the voltage across the 12Ω resistor?
A.
8V
B.
12V
C.
16V
D.
6V
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Solution
Voltage across R2 = (R2/(R1+R2)) * V = (12/(6+12)) * 24 = 12V.
Correct Answer: B — 12V
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Q. In a circuit with a 24V battery and two resistors of 8 ohms and 16 ohms in series, what is the current flowing through the circuit?
A.
1 A
B.
2 A
C.
3 A
D.
4 A
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Solution
Total resistance R = 8 + 16 = 24 ohms. Current I = V/R = 24V / 24Ω = 1 A.
Correct Answer: B — 2 A
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