Q. In a circuit with a 12V battery and two resistors in series (4Ω and 8Ω), what is the current flowing through the circuit?
A.
0.5A
B.
1A
C.
1.5A
D.
2A
Show solution
Solution
Total resistance R = R1 + R2 = 4Ω + 8Ω = 12Ω. Using Ohm's law, I = V/R = 12V / 12Ω = 1A.
Correct Answer:
B
— 1A
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Q. In a circuit with a 12V battery and two resistors in series (R1 = 4Ω, R2 = 8Ω), what is the current flowing through the circuit?
A.
0.5A
B.
1A
C.
1.5A
D.
2A
Show solution
Solution
Total resistance R_total = R1 + R2 = 4Ω + 8Ω = 12Ω. Current I = V/R_total = 12V/12Ω = 1A.
Correct Answer:
B
— 1A
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Q. In a circuit with a 12V battery and two resistors in series (R1 = 4Ω, R2 = 8Ω), what is the voltage across R2?
Show solution
Solution
The total resistance is R_total = R1 + R2 = 4Ω + 8Ω = 12Ω. The current is I = V/R_total = 12V / 12Ω = 1A. The voltage across R2 is V_R2 = I * R2 = 1A * 8Ω = 8V.
Correct Answer:
C
— 8V
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Q. In a circuit with a 12V battery and two resistors of 4 ohms and 8 ohms in series, what is the voltage drop across the 8 ohm resistor?
Show solution
Solution
Total resistance R_total = 4 + 8 = 12 ohms. Current I = V/R_total = 12V/12 ohms = 1A. Voltage drop across 8 ohm resistor = I * R = 1A * 8 ohms = 8V.
Correct Answer:
B
— 6V
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Q. In a circuit with a 12V battery and two resistors of 4Ω and 8Ω in series, what is the voltage across the 8Ω resistor?
Show solution
Solution
Using the voltage divider rule, V = (R2 / (R1 + R2)) * Vtotal = (8 / (4 + 8)) * 12 = 8V.
Correct Answer:
C
— 8V
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Q. In a circuit with a 12V battery and two resistors of 4Ω and 8Ω in series, what is the current flowing through the circuit?
A.
0.5A
B.
1A
C.
1.5A
D.
2A
Show solution
Solution
Total resistance R = R1 + R2 = 4Ω + 8Ω = 12Ω. Current I = V/R = 12V / 12Ω = 1A.
Correct Answer:
B
— 1A
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Q. In a circuit with a 15V battery and three resistors (5Ω, 10Ω, and 15Ω) in parallel, what is the equivalent resistance?
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Solution
1/R_eq = 1/5 + 1/10 + 1/15 = 0.1 + 0.0667 + 0.0667 = 0.2334. Therefore, R_eq = 4.29Ω.
Correct Answer:
B
— 3Ω
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Q. In a circuit with a 15V battery and two resistors in series (5Ω and 10Ω), what is the voltage drop across the 10Ω resistor?
A.
5V
B.
10V
C.
15V
D.
20V
Show solution
Solution
Using the voltage divider rule, V2 = (R2 / (R1 + R2)) * Vtotal = (10 / (5 + 10)) * 15 = 10V.
Correct Answer:
B
— 10V
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Q. In a circuit with a 15V battery and two resistors in series (R1 = 5Ω, R2 = 10Ω), what is the voltage across R2?
A.
10V
B.
5V
C.
15V
D.
0V
Show solution
Solution
Voltage across R2 = (R2 / (R1 + R2)) * V = (10Ω / (5Ω + 10Ω)) * 15V = 10V.
Correct Answer:
A
— 10V
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Q. In a circuit with a 20V battery and two resistors (4Ω and 8Ω) in parallel, what is the total current supplied by the battery?
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Solution
Total resistance in parallel, 1/Req = 1/R1 + 1/R2 = 1/4 + 1/8 = 3/8. Therefore, Req = 8/3Ω. Total current I = V/Req = 20V / (8/3) = 7.5A.
Correct Answer:
C
— 4A
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Q. In a circuit with a 24 V battery and a 6 ohm resistor, what is the current flowing through the resistor?
A.
2 A
B.
4 A
C.
6 A
D.
8 A
Show solution
Solution
Using Ohm's law, I = V/R = 24 V / 6 ohms = 4 A.
Correct Answer:
B
— 4 A
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Q. In a circuit with a 24 V battery and a total resistance of 6 ohms, what is the total current flowing through the circuit?
A.
2 A
B.
4 A
C.
6 A
D.
8 A
Show solution
Solution
Using Ohm's law, I = V/R = 24 V / 6 ohms = 4 A.
Correct Answer:
B
— 4 A
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Q. In a circuit with a 24V battery and a 6 ohm resistor, what is the voltage drop across the resistor?
A.
4 V
B.
12 V
C.
24 V
D.
6 V
Show solution
Solution
Using Ohm's law, V = I * R. First, find the current I = V/R = 24V / 6 ohms = 4 A. Then, V_drop = I * R = 4 A * 6 ohms = 24 V.
Correct Answer:
B
— 12 V
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Q. In a circuit with a 24V battery and a total resistance of 8 ohms, what is the total current flowing in the circuit?
A.
3 A
B.
2 A
C.
4 A
D.
6 A
Show solution
Solution
Using Ohm's law, I = V/R = 24V / 8Ω = 3 A.
Correct Answer:
C
— 4 A
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Q. In a circuit with a 24V battery and three resistors (R1 = 4Ω, R2 = 4Ω, R3 = 4Ω) in parallel, what is the total current supplied by the battery?
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Solution
Equivalent resistance R_eq = 1/(1/R1 + 1/R2 + 1/R3) = 1/(1/4 + 1/4 + 1/4) = 1.33Ω. Total current I = V/R_eq = 24V/1.33Ω = 18A.
Correct Answer:
D
— 6A
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Q. In a circuit with a 24V battery and three resistors in parallel (4Ω, 6Ω, and 12Ω), what is the total current supplied by the battery?
Show solution
Solution
1/R_eq = 1/4 + 1/6 + 1/12 = 1. Therefore, R_eq = 2Ω. Total current I = V/R_eq = 24V/2Ω = 12A.
Correct Answer:
C
— 4A
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Q. In a circuit with a 24V battery and three resistors in series (R1 = 2Ω, R2 = 3Ω, R3 = 5Ω), what is the voltage drop across R2?
A.
6V
B.
8V
C.
12V
D.
10V
Show solution
Solution
Total resistance R_total = R1 + R2 + R3 = 2Ω + 3Ω + 5Ω = 10Ω. Current I = V/R_total = 24V / 10Ω = 2.4A. Voltage drop across R2 = I * R2 = 2.4A * 3Ω = 7.2V.
Correct Answer:
B
— 8V
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Q. In a circuit with a 24V battery and three resistors of 2 ohms, 4 ohms, and 6 ohms in series, what is the total current flowing through the circuit?
A.
2 A
B.
3 A
C.
4 A
D.
1 A
Show solution
Solution
Total resistance R = 2 + 4 + 6 = 12 ohms. Using Ohm's law, I = V/R = 24V / 12 ohms = 2 A.
Correct Answer:
B
— 3 A
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Q. In a circuit with a 24V battery and three resistors of 4Ω, 4Ω, and 8Ω in series, what is the voltage drop across the 8Ω resistor?
A.
8V
B.
12V
C.
16V
D.
24V
Show solution
Solution
Total resistance R = 4Ω + 4Ω + 8Ω = 16Ω. Current I = V/R = 24V/16Ω = 1.5A. Voltage drop across 8Ω = I * R = 1.5A * 8Ω = 12V.
Correct Answer:
B
— 12V
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Q. In a circuit with a 24V battery and two 12 ohm resistors in series, what is the current flowing through the circuit?
A.
1 A
B.
2 A
C.
3 A
D.
4 A
Show solution
Solution
Total resistance R_total = 12 + 12 = 24 ohms. Current I = V/R_total = 24V / 24Ω = 1 A.
Correct Answer:
B
— 2 A
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Q. In a circuit with a 24V battery and two 12Ω resistors in parallel, what is the total current supplied by the battery?
Show solution
Solution
Total resistance R = 1/(1/12 + 1/12) = 6Ω; Total current I = V/R = 24V / 6Ω = 4A.
Correct Answer:
D
— 4A
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Q. In a circuit with a 24V battery and two 12Ω resistors in series, what is the current flowing through the circuit?
Show solution
Solution
Total resistance R_total = 12Ω + 12Ω = 24Ω. Current I = V/R_total = 24V / 24Ω = 1A.
Correct Answer:
B
— 2A
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Q. In a circuit with a 24V battery and two resistors in series (4Ω and 8Ω), what is the voltage across the 8Ω resistor?
A.
8V
B.
12V
C.
16V
D.
20V
Show solution
Solution
Voltage across 8Ω resistor = (R2 / (R1 + R2)) * Vtotal = (8 / (4 + 8)) * 24 = 16V.
Correct Answer:
B
— 12V
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Q. In a circuit with a 24V battery and two resistors in series (6Ω and 3Ω), what is the voltage across the 3Ω resistor?
A.
8V
B.
12V
C.
16V
D.
4V
Show solution
Solution
Total resistance = 6Ω + 3Ω = 9Ω. Current I = V / R = 24V / 9Ω = 2.67A. Voltage across 3Ω = I * R = 2.67A * 3Ω = 8V.
Correct Answer:
A
— 8V
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Q. In a circuit with a 24V battery and two resistors in series (R1 = 6Ω, R2 = 12Ω), what is the voltage drop across R2?
A.
12V
B.
18V
C.
6V
D.
8V
Show solution
Solution
Voltage drop across R2 = V_R2 = (R2 / (R1 + R2)) * V_total = (12Ω / (6Ω + 12Ω)) * 24V = 12V.
Correct Answer:
A
— 12V
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Q. In a circuit with a 24V battery and two resistors in series (R1 = 8Ω, R2 = 16Ω), what is the voltage across R2?
A.
16V
B.
8V
C.
12V
D.
4V
Show solution
Solution
Using voltage division, V_R2 = V_total * (R2 / (R1 + R2)) = 24V * (16Ω / (8Ω + 16Ω)) = 16V.
Correct Answer:
A
— 16V
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Q. In a circuit with a 24V battery and two resistors in series (R1 = 8Ω, R2 = 16Ω), what is the current flowing through the circuit?
Show solution
Solution
Total resistance R_total = R1 + R2 = 8Ω + 16Ω = 24Ω. The current is I = V/R_total = 24V / 24Ω = 1A.
Correct Answer:
B
— 2A
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Q. In a circuit with a 24V battery and two resistors of 4Ω and 8Ω in series, what is the voltage across the 8Ω resistor?
A.
8V
B.
12V
C.
16V
D.
20V
Show solution
Solution
Voltage across R2 = (R2 / (R1 + R2)) * V = (8 / (4 + 8)) * 24 = 16V.
Correct Answer:
B
— 12V
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Q. In a circuit with a 24V battery and two resistors of 6Ω and 12Ω in series, what is the voltage across the 12Ω resistor?
A.
8V
B.
12V
C.
16V
D.
6V
Show solution
Solution
Voltage across R2 = (R2/(R1+R2)) * V = (12/(6+12)) * 24 = 12V.
Correct Answer:
B
— 12V
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Q. In a circuit with a 24V battery and two resistors of 8 ohms and 16 ohms in series, what is the total current in the circuit?
A.
1 A
B.
2 A
C.
3 A
D.
4 A
Show solution
Solution
Total resistance R_total = 8 + 16 = 24 ohms. Current I = V/R_total = 24V / 24Ω = 1 A.
Correct Answer:
B
— 2 A
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Showing 2401 to 2430 of 5000 (167 Pages)
Physics Syllabus (JEE Main) MCQ & Objective Questions
The Physics Syllabus for JEE Main is crucial for students aiming to excel in their exams. Understanding this syllabus not only helps in grasping fundamental concepts but also enhances problem-solving skills through practice. Engaging with MCQs and objective questions is essential for effective exam preparation, as it allows students to identify important questions and strengthen their knowledge base.
What You Will Practise Here
Mechanics: Laws of Motion, Work, Energy, and Power
Thermodynamics: Laws of Thermodynamics, Heat Transfer
Waves and Oscillations: Simple Harmonic Motion, Wave Properties
Electromagnetism: Electric Fields, Magnetic Fields, and Circuits
Optics: Reflection, Refraction, and Optical Instruments
Modern Physics: Quantum Theory, Atomic Models, and Nuclear Physics
Fluid Mechanics: Properties of Fluids, Bernoulli's Principle
Exam Relevance
The Physics Syllabus (JEE Main) is integral to various examinations, including CBSE, State Boards, and competitive exams like NEET and JEE. Questions often focus on conceptual understanding and application of theories. Common patterns include numerical problems, conceptual MCQs, and assertion-reason type questions, which test both knowledge and analytical skills.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers.
Neglecting units and dimensions in calculations.
Overlooking the significance of diagrams in understanding concepts.
Confusing similar concepts, such as velocity and acceleration.
Failing to apply formulas correctly in different contexts.
FAQs
Question: What are the key topics in the Physics Syllabus for JEE Main?Answer: Key topics include Mechanics, Thermodynamics, Waves, Electromagnetism, Optics, Modern Physics, and Fluid Mechanics.
Question: How can I improve my performance in Physics MCQs?Answer: Regular practice of MCQs, understanding concepts deeply, and revising important formulas can significantly enhance your performance.
Start solving practice MCQs today to test your understanding of the Physics Syllabus (JEE Main). This will not only boost your confidence but also prepare you effectively for your upcoming exams. Remember, consistent practice is the key to success!
