Quantitative Aptitude & Reasoning MCQ & Objective Questions
Quantitative Aptitude & Reasoning is a crucial component of many school and competitive exams in India. Mastering this subject not only enhances your problem-solving skills but also boosts your confidence during exams. Practicing MCQs and objective questions helps you familiarize yourself with the exam format and improves your ability to tackle important questions efficiently. Regular practice is key to achieving higher scores in your exam preparation.
What You Will Practise Here
Basic Arithmetic Operations and their applications
Number Series and Patterns
Percentage, Ratio, and Proportion
Time, Speed, and Distance problems
Data Interpretation and Analysis
Logical Reasoning and Puzzles
Algebraic Expressions and Equations
Exam Relevance
Quantitative Aptitude & Reasoning is a significant part of various examinations, including CBSE, State Boards, NEET, and JEE. In these exams, you can expect questions that test your analytical skills and numerical ability. Common question patterns include multiple-choice questions that require quick calculations and logical deductions, making it essential to practice regularly to excel.
Common Mistakes Students Make
Misinterpreting the question requirements, leading to incorrect answers.
Overlooking the importance of units in measurement problems.
Failing to apply the correct formulas in different scenarios.
Rushing through calculations, resulting in careless mistakes.
FAQs
Question: What are the best strategies for solving Quantitative Aptitude MCQs?Answer: Focus on understanding the concepts, practice regularly, and learn to manage your time effectively during exams.
Question: How can I improve my reasoning skills for competitive exams?Answer: Engage in regular practice with a variety of reasoning questions and puzzles to enhance your logical thinking.
Start your journey towards mastering Quantitative Aptitude & Reasoning today! Solve practice MCQs and test your understanding to ensure you are well-prepared for your exams. Your success is just a question away!
Q. If a number is even, which of the following must also be even?
A.
Its square
B.
Its cube
C.
The sum of it and 2
D.
All of the above
Show solution
Solution
All options result in even numbers when an even number is used.
Correct Answer:
D
— All of the above
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Q. If a number is even, which of the following must be true?
A.
It is divisible by 2
B.
It is divisible by 3
C.
It is odd
D.
It is prime
Show solution
Solution
An even number is defined as being divisible by 2.
Correct Answer:
A
— It is divisible by 2
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Q. If a number n is odd, what can we say about n^2?
A.
n^2 is even
B.
n^2 is odd
C.
n^2 is prime
D.
n^2 is composite
Show solution
Solution
The square of an odd number is always odd.
Correct Answer:
B
— n^2 is odd
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Q. If a person borrows $5000 at a rate of 8% per annum compounded annually, what will be the amount after 2 years?
A.
$5832
B.
$6000
C.
$5200
D.
$5400
Show solution
Solution
Amount = Principal * (1 + Rate)^Time = 5000 * (1 + 0.08)^2 = 5000 * 1.1664 = $5832.
Correct Answer:
A
— $5832
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Q. If a person buys a watch for $120 and sells it for $150, what is the percentage profit?
A.
20%
B.
25%
C.
30%
D.
35%
Show solution
Solution
Profit = Selling Price - Cost Price = 150 - 120 = $30. Percentage Profit = (Profit/Cost Price) × 100 = (30/120) × 100 = 25%.
Correct Answer:
B
— 25%
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Q. If a person earns $5000 and spends $3500, what percentage of his income does he save?
A.
20%
B.
30%
C.
40%
D.
50%
Show solution
Solution
Savings = Income - Expenditure = 5000 - 3500 = 1500. Savings Percentage = (1500/5000) * 100 = 30%.
Correct Answer:
C
— 40%
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Q. If a person incurs a loss of 15% on selling a book for $85, what was the cost price?
A.
$100
B.
$90
C.
$95
D.
$80
Show solution
Solution
Let Cost Price = x. Selling Price = x - 15% of x = 0.85x. 0.85x = 85. x = 85/0.85 = 100.
Correct Answer:
A
— $100
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Q. If a person invests $1000 at a compound interest rate of 8% per annum, what will be the amount after 1 year?
A.
$1080
B.
$1000
C.
$1100
D.
$1200
Show solution
Solution
Amount = 1000 * (1 + 0.08)^1 = 1000 * 1.08 = $1080.
Correct Answer:
A
— $1080
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Q. If a person invests $1000 at a rate of 5% per annum for 3 years, what will be the total amount at the end of the period using simple interest?
A.
$1150
B.
$1200
C.
$1100
D.
$1250
Show solution
Solution
Simple Interest = Principal * Rate * Time = 1000 * 0.05 * 3 = $150. Total Amount = Principal + Interest = 1000 + 150 = $1150.
Correct Answer:
A
— $1150
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Q. If a person invests $1000 at a simple interest rate of 5% per annum for 3 years, what will be the total amount at the end?
A.
$1150
B.
$1200
C.
$1100
D.
$1250
Show solution
Solution
Simple Interest = Principal * Rate * Time = 1000 * 5/100 * 3 = 150. Total Amount = Principal + Interest = 1000 + 150 = 1150.
Correct Answer:
A
— $1150
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Q. If a person invests $1000 at an interest rate of 5% per annum, what will be the total amount after 3 years using simple interest?
A.
$1150
B.
$1200
C.
$1100
D.
$1050
Show solution
Solution
Simple Interest = Principal * Rate * Time = 1000 * 0.05 * 3 = 150. Total Amount = Principal + Interest = 1000 + 150 = 1150.
Correct Answer:
A
— $1150
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Q. If a person invests $2000 at a simple interest rate of 5% per annum, how much interest will he earn in 3 years?
A.
$300
B.
$200
C.
$150
D.
$250
Show solution
Solution
Simple Interest = PRT = 2000 * 5/100 * 3 = $300.
Correct Answer:
A
— $300
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Q. If a person invests $5000 at a compound interest rate of 4% per annum, how much will he have after 3 years?
A.
$5624.64
B.
$6000
C.
$5800
D.
$5500
Show solution
Solution
Amount = P(1 + r)^t = 5000(1 + 0.04)^3 = 5000(1.124864) = $5624.64.
Correct Answer:
A
— $5624.64
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Q. If a person invests $5000 at a compound interest rate of 8% per annum, what will be the total amount after 3 years?
A.
$5920
B.
$6000
C.
$5934
D.
$5800
Show solution
Solution
Amount = 5000 * (1 + 0.08)^3 = 5000 * 1.259712 = $6298.56.
Correct Answer:
C
— $5934
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Q. If a person mixes two types of tea costing $20 and $30 per kg in the ratio 2:3, what is the cost price per kg of the mixture?
A.
$24
B.
$26
C.
$28
D.
$22
Show solution
Solution
Cost = (2*20 + 3*30) / (2 + 3) = (40 + 90) / 5 = 130 / 5 = $26.
Correct Answer:
B
— $26
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Q. If a person sells an article for $1200 at a profit of 20%, what was the cost price?
A.
$1000
B.
$1100
C.
$900
D.
$1200
Show solution
Solution
Cost Price = Selling Price / (1 + Profit%) = 1200 / 1.2 = $1000
Correct Answer:
A
— $1000
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Q. If a person spends 30% of his salary on rent and 20% on food, what percentage of his salary is left?
A.
50%
B.
40%
C.
30%
D.
60%
Show solution
Solution
Total expenditure = 30% + 20% = 50%. Salary left = 100% - 50% = 50%.
Correct Answer:
A
— 50%
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Q. If a person walks 5 km in 1 hour, how far will he walk in 3 hours at the same speed?
A.
10 km
B.
12 km
C.
15 km
D.
18 km
Show solution
Solution
Distance = Speed x Time = 5 km/h x 3 h = 15 km.
Correct Answer:
C
— 15 km
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Q. If a person walks 5 km in 1 hour, how long will it take to walk 20 km?
A.
3 hours
B.
4 hours
C.
5 hours
D.
6 hours
Show solution
Solution
Time = Distance / Speed = 20 km / (5 km/h) = 4 hours
Correct Answer:
C
— 5 hours
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Q. If a person walks at a speed of 4 km/h, how far can he walk in 3 hours?
A.
10 km
B.
12 km
C.
14 km
D.
15 km
Show solution
Solution
Distance = Speed × Time = 4 km/h × 3 h = 12 km.
Correct Answer:
B
— 12 km
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Q. If a person walks at a speed of 5 km/h, how long will it take to walk 15 km?
A.
2 hours
B.
3 hours
C.
4 hours
D.
5 hours
Show solution
Solution
Time = Distance / Speed = 15 km / 5 km/h = 3 hours.
Correct Answer:
B
— 3 hours
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Q. If a person works 8 hours a day and completes a task in 5 days, what is the total work done in hours?
A.
30 hours
B.
35 hours
C.
40 hours
D.
45 hours
Show solution
Solution
Total Work = Hours per Day * Days = 8 * 5 = 40 hours
Correct Answer:
C
— 40 hours
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Q. If a polynomial f(x) = x^2 - 4, what are its roots?
A.
-2, 2
B.
0, 4
C.
1, -1
D.
2, 2
Show solution
Solution
Setting f(x) = 0 gives x^2 - 4 = 0, so x = ±2.
Correct Answer:
A
— -2, 2
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Q. If a polynomial f(x) = x^2 - 4x + 4, what is f(2)?
Show solution
Solution
f(2) = 2^2 - 4*2 + 4 = 0.
Correct Answer:
A
— 0
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Q. If a polynomial f(x) = x^2 - 5x + 6, what are its roots?
A.
1 and 6
B.
2 and 3
C.
3 and 2
D.
5 and 1
Show solution
Solution
Factoring gives (x-2)(x-3) = 0, so roots are 2 and 3.
Correct Answer:
B
— 2 and 3
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Q. If a product is bought for $80 and sold for $100, what is the profit?
A.
$20
B.
$15
C.
$25
D.
$30
Show solution
Solution
Profit = Selling Price - Cost Price = 100 - 80 = $20.
Correct Answer:
A
— $20
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Q. If a product is marked at $150 and sold at a discount of 20%, what is the selling price?
A.
$120
B.
$130
C.
$140
D.
$110
Show solution
Solution
Discount = 20% of 150 = 0.20 * 150 = $30. Selling Price = Marked Price - Discount = 150 - 30 = $120.
Correct Answer:
A
— $120
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Q. If a product is marked at $250 and sold at a discount of 20%, what is the selling price?
A.
$200
B.
$210
C.
$220
D.
$230
Show solution
Solution
Selling Price = Marked Price - Discount = 250 - (20/100 * 250) = 250 - 50 = $200.
Correct Answer:
A
— $200
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Q. If a product is marked at $500 and sold at a discount of 10%, what is the selling price?
A.
$450
B.
$400
C.
$475
D.
$425
Show solution
Solution
Selling Price = Marked Price - Discount = 500 - (10% of 500) = 500 - 50 = $450.
Correct Answer:
C
— $475
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Q. If a product is sold for $120 after a profit of 20%, what was the cost price of the product?
A.
$80
B.
$90
C.
$100
D.
$110
Show solution
Solution
Let Cost Price = x. Then, 120 = x + 0.2x => 120 = 1.2x => x = 120/1.2 = $100.
Correct Answer:
A
— $80
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