x = 10 - 3 = 7.

Subtracting 5 from both sides gives x = 7.

Substituting x = 3 gives 2(3^2) - 5 = 18 - 5 = 13.

For 3x + 5 to be even, x must be odd.

The smallest positive integer satisfying x ≡ 3 (mod 5) is 3.

Total parts = 3 + 1 = 4. Water = (1/4) * 40 = 10 liters.

Let the volumes of A and B be 3x and 2x respectively. 3x + 2x = 50, x = 10. Therefore, A = 3 * 10 = 30 liters.

Let the volumes of X and Y be x and 3x. x + 3x + 12 = 48. Solving gives x = 6. New ratio = 6:18 = 1:3.

3x = 15, so x = 5.

Distance = (Speed of A + Speed of B) * Time = (60 km/h + 90 km/h) * 2 h = 150 km.

12 divided by 7 is 1 with a remainder of 5, so 12 mod 7 = 5.

15 divided by 4 equals 3.75.

15 divided by 4 is 3 with a remainder of 3.

15% of 300 is calculated as (15/100) * 300 = 45.

7 divided by 3 gives a remainder of 1.

The nth term is given by 2 + (n-1) * 3. For n=10, it is 2 + 27 = 29.

The common difference is 3. The 5th term is 2 + 4*3 = 14.

The common difference is 3; the 5th term is 2 + 4*3 = 14.

The common difference is 4; thus, the 5th term is 3 + 4*4 = 19.

The nth term is given by a_n = a_1 + (n-1)d. Here, a_5 = 2 + 4*3 = 14.

Compound Interest = P(1 + r/n)^(nt) - P = 1000(1 + 0.05/1)^(1*2) - 1000 = 1000(1.1025) - 1000 = 102.50.

Amount = 2000 * (1 + 0.10)^3 = 2000 * 1.331 = $2662. Compound Interest = Amount - Principal = 2662 - 2000 = $662.

Compound Interest = P(1 + r/n)^(nt) - P = 2000(1 + 0.06)^2 - 2000 = 2000(1.1236) - 2000 = $247.20.

CI = P(1 + r/100)^n - P = 5000(1 + 0.10)^2 - 5000 = 5000(1.21) - 5000 = $1050.

The GCD of 12 and 15 is 3, as it is the largest number that divides both.

The GCD of 36 and 60 is 12.

The GCD of 48 and 180 is 12.

GCD(48, 18) = 6.

The sequence doubles each time, so the next number is 32.

The sequence doubles each time, so the next term is 32.