The sum of the roots of a quadratic equation ax^2 + bx + c is given by -b/a. Here, -(-4)/1 = 4.

The sum of the roots of a quadratic equation ax^2 + bx + c is given by -b/a. Here, -(-5)/1 = 5.

Step 1: Use the formula -b/a. Here, b = 4 and a = 2. Step 2: Sum of roots = -4/2 = -2.

The sum of the roots of a quadratic equation ax^2 + bx + c = 0 is given by -b/a. Here, b = 3 and a = 1, so the sum is -3/1 = -3.

The sum of the roots is given by -b/a = -4/1 = -4.

Step 1: Use the formula -b/a. Here, b = 6 and a = 1. Step 2: The sum of the roots is -6/1 = -6.

Step 1: Use the sum of roots formula -b/a. Here, b = -6, a = 1. Step 2: Sum = 6.

According to the order of operations, we first multiply 5 by 2 to get 10, then add 7 to get 17.

9² = 81 and 4² = 16. Therefore, 81 - 16 = 65.

cos(45°) = √2/2.

For one solution, the discriminant must be zero: k^2 - 4(2)(3) = 0. Thus, k^2 = 24, so k = ±√24 = ±2√6. The integer value is -4.

For one real solution, the discriminant must be zero: k^2 - 4(1)(16) = 0. Thus, k^2 = 64, so k = ±8.

Using Vieta's formulas, the sum of the roots (4 + (-4)) = 0, so k = 0.

Using the fact that the sum of the roots is -k, we have 4 + 4 = -k, so k = -8.

Using Vieta's formulas, the sum of the roots (3 + (-3)) = -k, so k = 0. The product of the roots (3 * -3) = 9, which is consistent. Thus, k = 0.

Using Vieta's formulas, the sum of the roots is -k = 4 + (-4) = 0, so k = 0.

Using the sum of roots, 3 + 4 = k, we find k = 7.

sec(θ) = 1/cos(θ) = 1/0.5 = 2.

The value of sin(π/6) is 1/2.

Step 1: Divide both sides by 2: x + 5 = 10. Step 2: Subtract 5 from both sides: x = 5.

Step 1: Divide both sides by 2: x - 3 = 4. Step 2: Add 3 to both sides: x = 7.

Using the quadratic formula x = (-b ± √(b² - 4ac)) / 2a. Here, a = 2, b = -4, c = -6. Discriminant = (-4)² - 4(2)(-6) = 16 + 48 = 64. x = (4 ± √64) / 4 = (4 ± 8) / 4. Thus, x = 3 or x = -1.

First, add 8 to both sides: 2x^2 = 8. Then divide by 2: x^2 = 4. Taking the square root gives x = ±2. The positive solution is x = 2.

Step 1: Distribute: 3x + 6 = 2x + 10. Step 2: Subtract 2x from both sides: x + 6 = 10. Step 3: Subtract 6 from both sides: x = 4.

Divide both sides by 3: x + 2 = 7. Then subtract 2: x = 5.

Step 1: Distribute: 3x - 3 = 2x + 4. Step 2: Subtract 2x from both sides: x - 3 = 4. Step 3: Add 3 to both sides: x = 7.

Step 1: Distribute: 3x - 3 = 2x + 4. Step 2: Subtract 2x from both sides: x - 3 = 4. Step 3: Add 3 to both sides: x = 7.

Divide both sides by 3: x - 2 = 4. Then add 2: x = 6.

Subtract 2 from both sides: 3x = 9. Then divide by 3: x = 3.

To solve 3x + 4 = 10, subtract 4 from both sides: 3x = 6. Then divide by 3: x = 2.