Major Competitive Exams

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Major Competitive Exams

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Major Competitive Exams MCQ & Objective Questions

Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.

What You Will Practise Here

Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams

Exam Relevance

The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.

Common Mistakes Students Make

Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam

FAQs

Question: How can I improve my performance in Major Competitive Exams?
Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.

Question: What types of questions should I focus on for these exams?
Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.

Question: Are there specific strategies for tackling objective questions?
Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.

Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!

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Q. What is the relationship between the width of the central maximum and the wavelength in a single-slit diffraction pattern?

A. Directly proportional
B. Inversely proportional
C. No relationship
D. Exponential relationship

Solution

The width of the central maximum is inversely proportional to the slit width and directly proportional to the wavelength.

Correct Answer: B — Inversely proportional

Q. What is the relationship between the work function and the threshold frequency?

A. Φ = hν₀
B. Φ = ν₀/h
C. Φ = h/ν₀
D. Φ = ν₀²/h

Solution

The work function (Φ) is directly proportional to the threshold frequency (ν₀) as Φ = hν₀.

Correct Answer: A — Φ = hν₀

Q. What is the relationship between torque (τ), moment of inertia (I), and angular acceleration (α)?

A. τ = Iα
B. τ = α/I
C. τ = I/α
D. τ = I + α

Solution

The relationship is given by τ = Iα, where τ is torque, I is moment of inertia, and α is angular acceleration.

Correct Answer: A — τ = Iα

Q. What is the relationship between verbal ability and overall performance in the CAT exam as suggested in the passage?

A. Verbal ability is secondary to quantitative skills.
B. Verbal ability directly impacts overall performance.
C. Verbal ability is irrelevant to the exam's success.
D. Verbal ability is only important for certain sections.

Solution

The passage suggests that strong verbal ability is crucial and directly influences overall performance in the CAT exam.

Correct Answer: B — Verbal ability directly impacts overall performance.

Q. What is the relationship between voltage, current, and resistance according to Ohm's Law?

A. V = I * R
B. V = I / R
C. V = R / I
D. V = I + R

Solution

Ohm's Law states that the voltage (V) across a conductor is directly proportional to the current (I) flowing through it, with resistance (R) as the proportionality constant: V = I * R.

Correct Answer: A — V = I * R

Q. What is the relationship between voltage, current, and resistance as described by Ohm's Law? (2021)

A. V = I + R
B. V = I * R
C. V = I / R
D. V = R / I

Solution

Ohm's Law states that the voltage (V) across a conductor is directly proportional to the current (I) flowing through it, with the resistance (R) being the constant of proportionality. Therefore, V = I * R.

Correct Answer: B — V = I * R

Q. What is the relationship between voltage, current, and resistance as stated by Ohm's Law? (2021)

A. V = I + R
B. V = I * R
C. V = I / R
D. V = R / I

Solution

Ohm's Law states that the voltage (V) across a conductor is directly proportional to the current (I) flowing through it, with the resistance (R) being the constant of proportionality. Therefore, V = I * R.

Correct Answer: B — V = I * R

Q. What is the relationship between voltage, current, and resistance in a circuit according to Ohm's Law?

A. V = I + R
B. V = I - R
C. V = I * R
D. V = I / R

Solution

According to Ohm's Law, the relationship is given by V = I * R.

Correct Answer: C — V = I * R

Q. What is the relationship between voltage, current, and resistance in an electrical circuit?

A. Ohm's Law
B. Kirchhoff's Law
C. Faraday's Law
D. Ampere's Law

Solution

Ohm's Law describes the relationship between voltage (V), current (I), and resistance (R) as V = IR.

Correct Answer: A — Ohm's Law

Q. What is the relationship between ΔG and equilibrium constant K?

A. ΔG = -RT ln K
B. ΔG = RT ln K
C. ΔG = KRT
D. ΔG = K/R

Solution

The relationship is given by ΔG = -RT ln K, where R is the gas constant and T is temperature.

Correct Answer: A — ΔG = -RT ln K

Q. What is the relationship between ΔG and the equilibrium constant (K)?

A. ΔG = -RT ln(K)
B. ΔG = RT ln(K)
C. ΔG = KRT
D. ΔG = K - RT

Solution

The relationship is given by ΔG = -RT ln(K), where R is the gas constant and T is the temperature in Kelvin.

Correct Answer: A — ΔG = -RT ln(K)

Q. What is the relationship between ΔG, ΔH, and ΔS at constant temperature?

A. ΔG = ΔH + TΔS
B. ΔG = ΔH - TΔS
C. ΔG = TΔS - ΔH
D. ΔG = ΔH/ΔS

Solution

The relationship is given by the equation ΔG = ΔH - TΔS, where T is the temperature in Kelvin.

Correct Answer: B — ΔG = ΔH - TΔS

Q. What is the relationship between ΔH and ΔG at equilibrium?

A. ΔG = 0
B. ΔH = 0
C. ΔG = ΔH
D. ΔG = ΔH + TΔS

Solution

At equilibrium, the change in Gibbs free energy (ΔG) is zero.

Correct Answer: A — ΔG = 0

Q. What is the relationship between ΔH and ΔU for a reaction at constant pressure?

A. ΔH = ΔU + PΔV
B. ΔH = ΔU - PΔV
C. ΔH = ΔU
D. ΔH = PΔV

Solution

At constant pressure, the relationship is given by ΔH = ΔU + PΔV.

Correct Answer: A — ΔH = ΔU + PΔV

Q. What is the remainder when 1000 is divided by 6?

A. 4
B. 2
C. 1
D. 0

Solution

1000 divided by 6 gives a quotient of 166 and a remainder of 4.

Correct Answer: A — 4

Q. What is the remainder when 1000 is divided by 9? (2023)

A. 1
B. 2
C. 3
D. 4

Solution

1000 divided by 9 gives a remainder of 1 (1000 = 9*111 + 1).

Correct Answer: B — 2

Q. What is the remainder when 123456 is divided by 10? (2023)

A. 0
B. 1
C. 2
D. 6

Solution

The remainder when a number is divided by 10 is the last digit of the number, which is 6.

Correct Answer: D — 6

Q. What is the remainder when 123456 is divided by 11? (2023)

A. 0
B. 1
C. 2
D. 3

Solution

123456 mod 11 = 0, as 123456 is divisible by 11.

Correct Answer: A — 0

Q. What is the remainder when 144 is divided by 11?

A. 0
B. 1
C. 2
D. 3

Solution

144 divided by 11 gives a remainder of 1.

Correct Answer: A — 0

Q. What is the remainder when 145 is divided by 12?

A. 1
B. 2
C. 3
D. 4

Solution

145 divided by 12 gives a remainder of 1.

Correct Answer: B — 2

Q. What is the remainder when 250 is divided by 7?

A. 1
B. 2
C. 3
D. 4

Solution

250 divided by 7 gives a quotient of 35 and a remainder of 5.

Correct Answer: A — 1

Q. What is the remainder when 256 is divided by 11?

A. 2
B. 3
C. 4
D. 5

Solution

256 divided by 11 gives a quotient of 23 and a remainder of 3.

Correct Answer: A — 2

Q. What is the remainder when 256 is divided by 7?

A. 3
B. 4
C. 5
D. 6

Solution

256 divided by 7 gives a quotient of 36 and a remainder of 4.

Correct Answer: B — 4

Q. What is the remainder when 256 is divided by 9?

A. 1
B. 2
C. 3
D. 4

Solution

256 divided by 9 gives a quotient of 28 and a remainder of 4.

Correct Answer: B — 2

Q. What is the remainder when 987654 is divided by 9?

A. 0
B. 1
C. 2
D. 3

Solution

The sum of the digits of 987654 is 39, which is divisible by 9, hence the remainder is 0.

Correct Answer: A — 0

Q. What is the remainder when 987654321 is divided by 9? (2023)

A. 0
B. 1
C. 2
D. 3

Solution

The remainder when a number is divided by 9 can be found by summing its digits. The sum of the digits of 987654321 is 45, which is divisible by 9, hence the remainder is 0.

Correct Answer: A — 0

Q. What is the repeating unit in polyethylene?

A. -CH2-CH2-
B. -C6H5-
C. -C3H6-
D. -C2H4-

Solution

The repeating unit in polyethylene is -CH2-CH2-, derived from ethylene monomers.

Correct Answer: A — -CH2-CH2-

Q. What is the repeating unit of polystyrene? (2021)

A. -CH2-CH2-
B. -CH=CH2-
C. -C6H5-
D. -C3H6-

Solution

The repeating unit of polystyrene is derived from the monomer styrene, which has the structure -CH=CH2-.

Correct Answer: B — -CH=CH2-

Q. What is the resistance of a circuit if a current of 5A flows through it when a voltage of 25V is applied? (2022)

A. 5Ω
B. 10Ω
C. 15Ω
D. 20Ω

Solution

Using Ohm's law (R = V/I), R = 25V / 5A = 5Ω.

Correct Answer: B — 10Ω

Q. What is the resistance of a wire of length 2 m and cross-sectional area 1 mm² if the resistivity of the material is 1.7 x 10^-8 Ωm?

A. 0.034 Ω
B. 0.017 Ω
C. 0.068 Ω
D. 0.085 Ω

Solution

Resistance R = ρ * (L/A). Here, R = (1.7 x 10^-8 Ωm) * (2 m / (1 x 10^-6 m²)) = 0.034 Ω.

Correct Answer: A — 0.034 Ω

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