Step 1: Factor the inequality: (x - 2)(x + 4) > 0. Step 2: Critical points are x = -4 and x = 2. Step 3: Test intervals: (-∞, -4), (-4, 2), (2, ∞). The solution is (-∞, -4) ∪ (2, ∞).

Step 1: Rearrange: x^2 + 3x - 10 < 0. Step 2: Factor: (x + 5)(x - 2) < 0. Step 3: The solution is -5 < x < 2.

Step 1: Factor the quadratic: (x + 4)(x - 1) ≤ 0. Step 2: Critical points are x = -4 and x = 1. Step 3: Test intervals: (-∞, -4), (-4, 1), (1, ∞). The solution set is [-4, 1].

Step 1: Rearrange: x^2 + 4x - 5 < 0. Step 2: Factor: (x + 5)(x - 1) < 0. Step 3: Solution is -5 < x < 1.

Step 1: Factor the quadratic: (x - 2)(x - 3) < 0. Step 2: Test intervals: x < 2, 2 < x < 3, x > 3. Solution: 2 < x < 3.

Step 1: Factor: (x - 3)(x + 3) > 0. Step 2: Test intervals: solution is x < -3 or x > 3.

Step 1: Factor the equation: (x + 2)(x + 2) = 0. Step 2: Set the factor to zero: x + 2 = 0. Solution is x = -2.

The equation x^2 + 6x + 9 can be factored as (x + 3)(x + 3) = 0. Thus, the solution is x = -3.

Factor the equation: (x - 2)(x - 3) = 0. Thus, x = 2 or x = 3.

From x - y = 2, we get y = x - 2. Substituting into the first equation gives x = 4, y = 2.

The first term a = 2, common difference d = 3. The sum of the first n terms S_n = n/2 * (2a + (n-1)d). For n = 5, S_5 = 5/2 * (2*2 + 4*3) = 5/2 * (4 + 12) = 5/2 * 16 = 40/2 = 20.

The first term a = 2, common difference d = 3. Sum = n/2 * (2a + (n-1)d) = 5/2 * (4 + 12) = 30.

The first term a = 1, common difference d = 3. The sum of the first n terms S_n = n/2 * (2a + (n-1)d). For n = 6, S_6 = 6/2 * (2*1 + 5*3) = 3 * (2 + 15) = 3 * 17 = 51.

The first term a = 1, and the common ratio r = 3. The sum of the first n terms of a GP is S_n = a(1 - r^n) / (1 - r). For n = 6, S_6 = 1(1 - 3^6) / (1 - 3) = (1 - 729) / -2 = -728 / -2 = 364.

The sum of the interior angles formed by a transversal intersecting two parallel lines is 360 degrees.

The sum of the interior angles formed by two parallel lines and a transversal is 360°.

The sum of the interior angles formed is 360 degrees, as there are four angles created.

The sum of the interior angles of any triangle is always 180 degrees.

The sum of the interior angles of any triangle is always 180 degrees.

The sum of the interior angles of any triangle is always 180 degrees.

The sum of the interior angles of any triangle is always 180 degrees.

The sum of the interior angles of any triangle is always 180 degrees.

The sum of the measures of the interior angles formed is 360°.

The sum of the measures of all interior angles formed by a transversal cutting two parallel lines is 360°.

The sum of the measures of the interior angles of any triangle is always 180 degrees.

Same-side interior angles are supplementary, so their sum is always 180 degrees.

The sum of the roots can be found using -b/a. Here, b = 6 and a = 1, so the sum is -6.

The sum of the roots can be found using -b/a. Here, b = -8 and a = 1. Thus, the sum is 8.

The sum of the roots of a quadratic ax^2 + bx + c is given by -b/a. Here, b = 6 and a = 1, so the sum is -6/1 = -6.

Step 1: The sum of the roots is given by -b/a: -6/1 = -6.