Engineering Entrance MCQ & Objective Questions
Preparing for Engineering Entrance exams is crucial for aspiring engineers in India. Mastering MCQs and objective questions not only enhances your understanding of key concepts but also boosts your confidence during exams. Regular practice with these questions helps identify important topics and improves your overall exam preparation.
What You Will Practise Here
Fundamental concepts of Physics and Mathematics
Key formulas and their applications in problem-solving
Important definitions and theorems relevant to engineering
Diagrams and graphical representations for better understanding
Conceptual questions that challenge your critical thinking
Previous years' question papers and their analysis
Time management strategies while solving MCQs
Exam Relevance
The Engineering Entrance syllabus is integral to various examinations like CBSE, State Boards, NEET, and JEE. Questions often focus on core subjects such as Physics, Chemistry, and Mathematics, with formats varying from direct MCQs to application-based problems. Understanding the common question patterns can significantly enhance your performance and help you tackle the exams with ease.
Common Mistakes Students Make
Overlooking the importance of units and dimensions in calculations
Misinterpreting questions due to lack of careful reading
Neglecting to review basic concepts before attempting advanced problems
Rushing through practice questions without thorough understanding
FAQs
Question: What are the best ways to prepare for Engineering Entrance MCQs?Answer: Focus on understanding concepts, practice regularly with objective questions, and review previous years' papers.
Question: How can I improve my speed in solving MCQs?Answer: Regular practice, time-bound mock tests, and familiarizing yourself with common question types can help improve your speed.
Start your journey towards success by solving Engineering Entrance MCQ questions today! Test your understanding and build a strong foundation for your exams.
Q. What is the volume of a cube with side length 3 units? (2023)
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Solution
Volume = side³ = 3³ = 27 cubic units.
Correct Answer:
B
— 27
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Q. What is the volume of a cube with side length 4 units? (2020)
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Solution
Volume = side³ = 4³ = 64 cubic units.
Correct Answer:
B
— 64
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Q. What is the volume of a cylinder with radius 2 and height 5? (2023)
A.
20π
B.
10π
C.
15π
D.
25π
Show solution
Solution
Volume = πr²h = π(2²)(5) = 20π cubic units.
Correct Answer:
A
— 20π
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Q. What is the volume of a cylinder with radius 3 units and height 5 units? (2021)
A.
45π
B.
30π
C.
15π
D.
9π
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Solution
Volume = πr²h = π(3²)(5) = 45π cubic units.
Correct Answer:
A
— 45π
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Q. What is the volume of a sphere with radius 5 units? (2021)
A.
500/3π
B.
125/3π
C.
100/3π
D.
200/3π
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Solution
Volume = (4/3)πr³ = (4/3)π(5)³ = (4/3)π(125) = 500/3π cubic units.
Correct Answer:
A
— 500/3π
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Q. What is the work done by a force of 15 N acting at an angle of 60° while moving an object 4 m? (2021)
A.
30 J
B.
60 J
C.
45 J
D.
90 J
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Solution
Work = F × d × cos(θ) = 15 N × 4 m × cos(60°) = 15 × 4 × 0.5 = 30 J.
Correct Answer:
C
— 45 J
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Q. What is the work done by an ideal gas during an isobaric expansion if it expands from 2 L to 5 L at a pressure of 3 atm? (2022)
A.
9 J
B.
12 J
C.
15 J
D.
18 J
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Solution
Work done (W) = P * ΔV = 3 atm * (5 L - 2 L) = 3 atm * 3 L = 9 atm·L = 15 J (1 atm·L = 101.325 J)
Correct Answer:
C
— 15 J
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Q. What is the work done by an ideal gas during an isobaric expansion if the pressure is 5 atm and the volume changes from 2 L to 5 L? (2019)
A.
15 L·atm
B.
10 L·atm
C.
5 L·atm
D.
20 L·atm
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Solution
Work done (W) = PΔV = P(V_final - V_initial) = 5 atm * (5 L - 2 L) = 15 L·atm.
Correct Answer:
A
— 15 L·atm
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Q. What is the work done by an ideal gas during an isothermal expansion from volume V1 to V2 at temperature T? (2021)
A.
nRT ln(V2/V1)
B.
nRT (V2 - V1)
C.
PV
D.
0
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Solution
The work done during an isothermal expansion is given by W = nRT ln(V2/V1).
Correct Answer:
A
— nRT ln(V2/V1)
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Q. What is the work done by an ideal gas during isothermal expansion? (2021)
A.
0
B.
nRT ln(Vf/Vi)
C.
nRT (Vf - Vi)
D.
nR (Tf - Ti)
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Solution
For an ideal gas undergoing isothermal expansion, the work done is given by W = nRT ln(Vf/Vi).
Correct Answer:
B
— nRT ln(Vf/Vi)
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Q. What is the work done on a gas when it is compressed from 4 L to 2 L at a constant pressure of 2 atm?
A.
4 L·atm
B.
2 L·atm
C.
8 L·atm
D.
0 L·atm
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Solution
Work done (W) = P * ΔV = 2 atm * (2 L - 4 L) = 2 atm * (-2 L) = -4 L·atm (work done on the gas is positive).
Correct Answer:
A
— 4 L·atm
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Q. What is the work done on a gas when it is compressed from 5 L to 2 L at a constant pressure of 200 kPa? (2022)
A.
600 J
B.
800 J
C.
1000 J
D.
1200 J
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Solution
Work done (W) = P * ΔV = 200 kPa * (2 L - 5 L) = 200 kPa * (-3 L) = -600 J (work done on the gas).
Correct Answer:
C
— 1000 J
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Q. What is the work done when 1 mole of an ideal gas expands isothermally from 10 L to 20 L at 300 K? (R = 8.31 J/mol·K) (2023)
A.
0 J
B.
830 J
C.
1660 J
D.
2490 J
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Solution
Work done = nRT ln(Vf/Vi) = 1 mol × 8.31 J/mol·K × 300 K × ln(20/10) = 1660 J.
Correct Answer:
C
— 1660 J
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Q. What is the work done when 1 mole of an ideal gas expands isothermally from 10 L to 20 L at a temperature of 300 K? (2020)
A.
1.5 kJ
B.
2.5 kJ
C.
3.5 kJ
D.
4.5 kJ
Show solution
Solution
Work done (W) = nRT ln(Vf/Vi) = 1 mol * 8.314 J/(mol K) * 300 K * ln(20/10) = 2.5 kJ.
Correct Answer:
B
— 2.5 kJ
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Q. What is the work done when 1 mole of an ideal gas expands isothermally from 10 L to 20 L at 300 K? (2022)
A.
300 J
B.
600 J
C.
150 J
D.
0 J
Show solution
Solution
Work done W = nRT ln(Vf/Vi) = 1 * 8.314 * 300 * ln(20/10) = 600 J.
Correct Answer:
B
— 600 J
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Q. What is the work done when a 50 N force moves an object 3 m in the direction of the force?
A.
150 J
B.
100 J
C.
50 J
D.
200 J
Show solution
Solution
Work done (W) = F × d = 50 N × 3 m = 150 J.
Correct Answer:
A
— 150 J
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Q. What is the work done when a force of 10 N moves an object 5 m in the direction of the force? (2016)
A.
50 J
B.
25 J
C.
10 J
D.
5 J
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Solution
Work done (W) = Force × Distance = 10 N × 5 m = 50 J.
Correct Answer:
A
— 50 J
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Q. What is the work done when a force of 15 N moves an object 3 m at an angle of 0 degrees to the direction of motion?
A.
45 J
B.
30 J
C.
60 J
D.
75 J
Show solution
Solution
Work = Force * Distance * cos(θ) = 15 N * 3 m * cos(0°) = 45 J.
Correct Answer:
A
— 45 J
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Q. What is the work done when a force of 15 N moves an object 3 m at an angle of 60° to the direction of the force?
A.
22.5 J
B.
30 J
C.
36.5 J
D.
45 J
Show solution
Solution
W = F × d × cos(θ) = 15 N × 3 m × cos(60°) = 15 × 3 × 0.5 = 22.5 J.
Correct Answer:
A
— 22.5 J
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Q. What is the work done when a force of 15 N moves an object 4 m in the direction of the force?
A.
60 J
B.
30 J
C.
45 J
D.
75 J
Show solution
Solution
Work done = Force × Distance = 15 N × 4 m = 60 J
Correct Answer:
A
— 60 J
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Q. What is the x-intercept of the line 5x + 2y = 10?
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Solution
Setting y = 0 in the equation gives 5x = 10, thus x = 2. The x-intercept is 2.
Correct Answer:
B
— 5
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Q. What is the x-intercept of the line 5x - 2y + 10 = 0?
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Solution
Setting y = 0 in the equation gives 5x + 10 = 0, thus x = -2.
Correct Answer:
B
— 2
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Q. What is the x-intercept of the line 6x - 2y = 12?
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Solution
Setting y = 0 in the equation gives 6x = 12, thus x = 2. The x-intercept is 2.
Correct Answer:
B
— 3
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Q. What is the y-intercept of the line 2x - 3y + 6 = 0? (2023)
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Solution
Rearranging gives y = (2/3)x + 2; y-intercept = 2
Correct Answer:
A
— 2
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Q. What is the y-intercept of the line 2x - 3y = 6? (2022)
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Solution
To find y-intercept, set x = 0: 2(0) - 3y = 6 => -3y = 6 => y = -2
Correct Answer:
B
— 3
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Q. What is the y-intercept of the line 3x - 2y = 6? (2020) 2020
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Solution
Setting x = 0, we get -2y = 6, so y = -3.
Correct Answer:
A
— 3
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Q. What is the y-intercept of the line 3x - 2y = 6? (2022)
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Solution
Set x = 0: -2y = 6 => y = -3, y-intercept is 3.
Correct Answer:
B
— 2
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Q. What is the y-intercept of the line 3x - 4y = 12? (2023)
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Solution
Setting x = 0, we get -4y = 12, so y = -3.
Correct Answer:
A
— 3
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Q. What is the y-intercept of the line 4x + 5y - 20 = 0?
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Solution
Setting x = 0 in the equation gives 5y = 20, thus y = 4. The y-intercept is 4.
Correct Answer:
B
— 5
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Q. What type of adsorption is characterized by the formation of a chemical bond? (2019)
A.
Physisorption
B.
Chemisorption
C.
Desorption
D.
Multilayer adsorption
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Solution
Chemisorption is characterized by the formation of a chemical bond between the adsorbate and the surface.
Correct Answer:
B
— Chemisorption
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