JEE Main MCQ & Objective Questions
The JEE Main exam is a crucial step for students aspiring to enter prestigious engineering colleges in India. It tests not only knowledge but also the ability to apply concepts effectively. Practicing MCQs and objective questions is essential for scoring better, as it helps in familiarizing students with the exam pattern and enhances their problem-solving skills. Engaging with practice questions allows students to identify important questions and strengthen their exam preparation.
What You Will Practise Here
Fundamental concepts of Physics, Chemistry, and Mathematics
Key formulas and their applications in problem-solving
Important definitions and theories relevant to JEE Main
Diagrams and graphical representations for better understanding
Numerical problems and their step-by-step solutions
Previous years' JEE Main questions for real exam experience
Time management strategies while solving MCQs
Exam Relevance
The topics covered in JEE Main are not only significant for the JEE exam but also appear in various CBSE and State Board examinations. Many concepts are shared with the NEET syllabus, making them relevant across multiple competitive exams. Common question patterns include conceptual applications, numerical problems, and theoretical questions that assess a student's understanding of core subjects.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers
Neglecting units in numerical problems, which can change the outcome
Overlooking negative marking and not managing time effectively
Relying too heavily on rote memorization instead of understanding concepts
Failing to review and analyze mistakes from practice tests
FAQs
Question: How can I improve my speed in solving JEE Main MCQ questions?Answer: Regular practice with timed quizzes and focusing on shortcuts can significantly enhance your speed.
Question: Are the JEE Main objective questions similar to previous years' papers?Answer: Yes, many questions are based on previous years' patterns, so practicing them can be beneficial.
Question: What is the best way to approach JEE Main practice questions?Answer: Start with understanding the concepts, then attempt practice questions, and finally review your answers to learn from mistakes.
Now is the time to take charge of your preparation! Dive into solving JEE Main MCQs and practice questions to test your understanding and boost your confidence for the exam.
Q. For a given mass, which of the following configurations will have the smallest moment of inertia?
A.
All mass at the center
B.
Mass distributed evenly
C.
Mass at the edge
D.
Mass concentrated at one end
Show solution
Solution
The moment of inertia is smallest when all mass is concentrated at the center, as it minimizes the distance from the axis of rotation.
Correct Answer:
A
— All mass at the center
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Q. For a hollow sphere of mass M and radius R, what is the moment of inertia about an axis through its center?
A.
2/5 MR^2
B.
3/5 MR^2
C.
2/3 MR^2
D.
MR^2
Show solution
Solution
The moment of inertia of a hollow sphere about an axis through its center is I = 2/5 MR^2.
Correct Answer:
B
— 3/5 MR^2
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Q. For a monoatomic ideal gas, the RMS speed is given by which of the following expressions?
A.
sqrt((3kT)/m)
B.
sqrt((3RT)/M)
C.
Both of the above
D.
None of the above
Show solution
Solution
Both expressions are valid for calculating the RMS speed of a monoatomic ideal gas.
Correct Answer:
C
— Both of the above
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Q. For a point charge, the electric field varies with distance r as?
A.
1/r
B.
1/r²
C.
1/r³
D.
1/r⁴
Show solution
Solution
The electric field due to a point charge varies as E = kQ/r², where k is a constant.
Correct Answer:
B
— 1/r²
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Q. For a process to be reversible, it must be:
A.
Fast
B.
Quasi-static
C.
Adiabatic
D.
Isochoric
Show solution
Solution
A reversible process must be quasi-static, meaning it occurs infinitely slowly.
Correct Answer:
B
— Quasi-static
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Q. For a process with ΔH = 200 kJ and ΔS = 0.5 kJ/K, what is ΔG at 400 K?
A.
200 kJ
B.
180 kJ
C.
220 kJ
D.
160 kJ
Show solution
Solution
ΔG = ΔH - TΔS = 200 kJ - 400 K * 0.5 kJ/K = 200 kJ - 200 kJ = 0 kJ.
Correct Answer:
B
— 180 kJ
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Q. For a reaction A → B, if the rate of formation of B is 0.5 mol/L/s, what is the rate of disappearance of A?
A.
0.5 mol/L/s
B.
1.0 mol/L/s
C.
0.25 mol/L/s
D.
2.0 mol/L/s
Show solution
Solution
The rate of disappearance of A is equal to the rate of formation of B, multiplied by the stoichiometric coefficients. Here, it is 1.0 mol/L/s.
Correct Answer:
B
— 1.0 mol/L/s
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Q. For a reaction A → B, if the rate of reaction doubles when the concentration of A is doubled, what is the order of the reaction with respect to A?
A.
Zero order
B.
First order
C.
Second order
D.
Third order
Show solution
Solution
If doubling the concentration of A doubles the rate, the reaction is first order with respect to A.
Correct Answer:
B
— First order
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Q. For a reaction at constant temperature and pressure, which of the following is true?
A.
ΔG = ΔH + TΔS
B.
ΔG = ΔH - TΔS
C.
ΔG = TΔS - ΔH
D.
ΔG = ΔS - ΔH
Show solution
Solution
The correct relationship at constant temperature and pressure is ΔG = ΔH - TΔS.
Correct Answer:
B
— ΔG = ΔH - TΔS
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Q. For a reaction at equilibrium, if the concentration of products increases, what will happen to the equilibrium position?
A.
Shift to the left
B.
Shift to the right
C.
No change
D.
Depends on temperature
Show solution
Solution
According to Le Chatelier's principle, if the concentration of products increases, the equilibrium will shift to the left.
Correct Answer:
A
— Shift to the left
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Q. For a reaction at equilibrium, the change in Gibbs free energy (ΔG) is equal to:
A.
ΔH - TΔS
B.
0
C.
ΔS - TΔH
D.
ΔH + TΔS
Show solution
Solution
At equilibrium, the change in Gibbs free energy (ΔG) is zero, indicating that the system is at maximum entropy.
Correct Answer:
B
— 0
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Q. For a reaction at standard conditions, if ΔG° is negative, what can be said about the equilibrium constant (K)?
A.
K < 1
B.
K = 1
C.
K > 1
D.
K is undefined
Show solution
Solution
If ΔG° is negative, the equilibrium constant K is greater than 1.
Correct Answer:
C
— K > 1
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Q. For a reaction at standard conditions, if ΔG° is positive, what can be said about the reaction?
A.
The reaction is spontaneous in the forward direction.
B.
The reaction is spontaneous in the reverse direction.
C.
The reaction is at equilibrium.
D.
The reaction is impossible.
Show solution
Solution
A positive ΔG° indicates that the reaction is non-spontaneous in the forward direction, thus spontaneous in the reverse.
Correct Answer:
B
— The reaction is spontaneous in the reverse direction.
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Q. For a reaction at standard conditions, if ΔG° is positive, what does it imply?
A.
The reaction is spontaneous in the forward direction.
B.
The reaction is at equilibrium.
C.
The reaction is non-spontaneous in the forward direction.
D.
The reaction will proceed rapidly.
Show solution
Solution
A positive ΔG° indicates that the reaction is non-spontaneous in the forward direction under standard conditions.
Correct Answer:
C
— The reaction is non-spontaneous in the forward direction.
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Q. For a reaction at standard conditions, if ΔG° is positive, what does it indicate?
A.
The reaction is spontaneous in the forward direction.
B.
The reaction is non-spontaneous in the forward direction.
C.
The reaction is at equilibrium.
D.
The reaction is spontaneous in the reverse direction.
Show solution
Solution
A positive ΔG° indicates that the reaction is non-spontaneous in the forward direction.
Correct Answer:
B
— The reaction is non-spontaneous in the forward direction.
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Q. For a reaction with a rate constant k, what is the relationship between the rate of reaction and the concentration of reactants for a first-order reaction?
A.
Rate = k[A]^2
B.
Rate = k[A]
C.
Rate = k[A]^3
D.
Rate = k[A]^0
Show solution
Solution
For a first-order reaction, the rate of reaction is directly proportional to the concentration of the reactant, given by Rate = k[A].
Correct Answer:
B
— Rate = k[A]
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Q. For a reaction with ΔH = 100 kJ and ΔS = 200 J/K, at what temperature will the reaction become spontaneous?
A.
500 K
B.
250 K
C.
200 K
D.
100 K
Show solution
Solution
To find the temperature at which the reaction becomes spontaneous, set ΔG = 0: 0 = ΔH - TΔS. Thus, T = ΔH/ΔS = (100,000 J)/(200 J/K) = 500 K.
Correct Answer:
A
— 500 K
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Q. For a reaction with ΔH = 100 kJ/mol and ΔS = 200 J/mol·K, at what temperature will the reaction become spontaneous?
A.
500 K
B.
250 K
C.
200 K
D.
100 K
Show solution
Solution
To find the temperature at which the reaction becomes spontaneous, set ΔG = 0: 0 = ΔH - TΔS, thus T = ΔH/ΔS = 100,000 J / 200 J/K = 500 K.
Correct Answer:
A
— 500 K
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Q. For a reaction with ΔH = 50 kJ/mol and ΔS = 100 J/mol·K, at what temperature will the reaction become spontaneous?
A.
500 K
B.
250 K
C.
1000 K
D.
200 K
Show solution
Solution
To find the temperature at which the reaction becomes spontaneous, set ΔG = 0: 0 = ΔH - TΔS, thus T = ΔH/ΔS = (50,000 J/mol) / (100 J/mol·K) = 500 K.
Correct Answer:
A
— 500 K
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Q. For a rectangular plate of mass M and dimensions a x b, what is the moment of inertia about an axis through its center and parallel to side a?
A.
1/12 Mb^2
B.
1/3 Mb^2
C.
1/4 Mb^2
D.
1/6 Mb^2
Show solution
Solution
The moment of inertia of a rectangular plate about an axis through its center parallel to side a is I = 1/12 Mb^2.
Correct Answer:
A
— 1/12 Mb^2
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Q. For a reversible process, the change in entropy is given by which of the following?
A.
ΔS = Q/T
B.
ΔS = W/T
C.
ΔS = Q + W
D.
ΔS = 0
Show solution
Solution
For a reversible process, the change in entropy is given by ΔS = Q/T, where Q is the heat exchanged and T is the temperature.
Correct Answer:
A
— ΔS = Q/T
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Q. For a reversible process, the change in entropy of the system is equal to the heat absorbed divided by the temperature. What is the formula?
A.
ΔS = Q/T
B.
ΔS = T/Q
C.
ΔS = Q*T
D.
ΔS = Q + T
Show solution
Solution
The change in entropy (ΔS) for a reversible process is given by ΔS = Q/T, where Q is the heat absorbed and T is the temperature.
Correct Answer:
A
— ΔS = Q/T
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Q. For a reversible process, the change in entropy of the system is equal to the heat absorbed divided by the temperature. This is expressed as:
A.
ΔS = Q/T
B.
ΔS = T/Q
C.
ΔS = Q + T
D.
ΔS = Q - T
Show solution
Solution
For a reversible process, the change in entropy (ΔS) is given by ΔS = Q/T, where Q is the heat absorbed and T is the temperature.
Correct Answer:
A
— ΔS = Q/T
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Q. For a reversible process, the change in entropy of the universe is:
A.
Zero
B.
Positive
C.
Negative
D.
Undefined
Show solution
Solution
For a reversible process, the change in entropy of the universe is zero, as the system and surroundings are in equilibrium.
Correct Answer:
A
— Zero
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Q. For a reversible process, the efficiency of a Carnot engine is given by which formula?
A.
1 - (T2/T1)
B.
T1/T2
C.
T2/T1
D.
1 - (T1/T2)
Show solution
Solution
The efficiency of a Carnot engine is given by η = 1 - (T2/T1), where T1 is the temperature of the hot reservoir and T2 is the temperature of the cold reservoir.
Correct Answer:
A
— 1 - (T2/T1)
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Q. For a satellite in a circular orbit, which of the following is true about its kinetic and potential energy?
A.
K.E. = P.E.
B.
K.E. > P.E.
C.
K.E. < P.E.
D.
K.E. = 0
Show solution
Solution
For a satellite in a circular orbit, the kinetic energy is less than the potential energy, as K.E. = -1/2 P.E.
Correct Answer:
C
— K.E. < P.E.
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Q. For a satellite in a low Earth orbit, what is the approximate altitude range? (2000)
A.
200-2000 km
B.
500-10000 km
C.
1000-20000 km
D.
30000-40000 km
Show solution
Solution
Low Earth orbit satellites typically operate at altitudes ranging from about 200 km to 2000 km above the Earth's surface.
Correct Answer:
A
— 200-2000 km
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Q. For a satellite in a stable orbit, what must be true about the centripetal force and gravitational force?
A.
Centripetal force is greater than gravitational force
B.
Centripetal force is less than gravitational force
C.
Centripetal force equals gravitational force
D.
Centripetal force is independent of gravitational force
Show solution
Solution
For a satellite in a stable orbit, the centripetal force required for circular motion equals the gravitational force acting on the satellite.
Correct Answer:
C
— Centripetal force equals gravitational force
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Q. For a single slit of width 'a', what is the angular position of the first minimum?
A.
λ/a
B.
a/λ
C.
sin θ = λ/a
D.
tan θ = λ/a
Show solution
Solution
The angular position of the first minimum is given by sin θ = λ/a.
Correct Answer:
C
— sin θ = λ/a
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Q. For a solenoid of length L and n turns per unit length carrying current I, what is the magnetic field inside the solenoid?
A.
μ₀nI
B.
μ₀I/n
C.
μ₀I/L
D.
μ₀nI/L
Show solution
Solution
The magnetic field inside a solenoid is given by B = μ₀nI.
Correct Answer:
A
— μ₀nI
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