Q. What is the work done in moving an object from a point A to point B in a uniform gravitational field?
-
A.
Depends on the path taken
-
B.
Zero
-
C.
Depends on the mass of the object
-
D.
Depends on the height difference
Solution
The work done in moving an object in a uniform gravitational field depends only on the height difference between points A and B.
Correct Answer:
D
— Depends on the height difference
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Q. What is the work done in moving an object from one point to another in a gravitational field?
-
A.
Depends on the path taken
-
B.
Is always zero
-
C.
Depends only on the initial and final positions
-
D.
Is maximum at the highest point
Solution
The work done in moving an object in a gravitational field depends only on the initial and final positions, not the path taken.
Correct Answer:
C
— Depends only on the initial and final positions
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Q. What is the work done on a gas during an isochoric process?
-
A.
Positive
-
B.
Negative
-
C.
Zero
-
D.
Depends on the gas
Solution
In an isochoric process, the volume remains constant, which means no work is done on or by the gas. Therefore, the work done is zero.
Correct Answer:
C
— Zero
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Q. What is the work done on a gas during an isothermal compression? (2019)
-
A.
Positive
-
B.
Negative
-
C.
Zero
-
D.
Depends on the volume
Solution
The work done on a gas during isothermal compression is positive, as work is done on the gas to compress it.
Correct Answer:
A
— Positive
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Q. What is the work done on a gas when it is compressed from 4 L to 2 L at a constant pressure of 2 atm?
-
A.
4 L·atm
-
B.
2 L·atm
-
C.
8 L·atm
-
D.
0 L·atm
Solution
Work done (W) = P * ΔV = 2 atm * (2 L - 4 L) = 2 atm * (-2 L) = -4 L·atm (work done on the gas is positive).
Correct Answer:
A
— 4 L·atm
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Q. What is the work done on a gas when it is compressed from 5 L to 2 L at a constant pressure of 200 kPa? (2022)
-
A.
600 J
-
B.
800 J
-
C.
1000 J
-
D.
1200 J
Solution
Work done (W) = P * ΔV = 200 kPa * (2 L - 5 L) = 200 kPa * (-3 L) = -600 J (work done on the gas).
Correct Answer:
C
— 1000 J
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Q. What is the work done on a gas when it is compressed isothermally from 4 L to 2 L at a pressure of 1 atm? (2021)
-
A.
2.0 L·atm
-
B.
4.0 L·atm
-
C.
6.0 L·atm
-
D.
8.0 L·atm
Solution
Work done (W) = PΔV = 1 atm * (2 L - 4 L) = 2 L·atm.
Correct Answer:
B
— 4.0 L·atm
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Q. What is the work done when 1 mole of an ideal gas expands isothermally from 10 L to 20 L at 300 K? (R = 8.31 J/mol·K) (2023)
-
A.
0 J
-
B.
830 J
-
C.
1660 J
-
D.
2490 J
Solution
Work done = nRT ln(Vf/Vi) = 1 mol × 8.31 J/mol·K × 300 K × ln(20/10) = 1660 J.
Correct Answer:
C
— 1660 J
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Q. What is the work done when 1 mole of an ideal gas expands isothermally from 10 L to 20 L at 300 K? (2022)
-
A.
300 J
-
B.
600 J
-
C.
150 J
-
D.
0 J
Solution
Work done W = nRT ln(Vf/Vi) = 1 * 8.314 * 300 * ln(20/10) = 600 J.
Correct Answer:
B
— 600 J
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Q. What is the work done when 1 mole of an ideal gas expands isothermally from 10 L to 20 L at a temperature of 300 K? (2020)
-
A.
1.5 kJ
-
B.
2.5 kJ
-
C.
3.5 kJ
-
D.
4.5 kJ
Solution
Work done (W) = nRT ln(Vf/Vi) = 1 mol * 8.314 J/(mol K) * 300 K * ln(20/10) = 2.5 kJ.
Correct Answer:
B
— 2.5 kJ
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Q. What is the work done when a 50 N force moves an object 3 m in the direction of the force?
-
A.
150 J
-
B.
100 J
-
C.
50 J
-
D.
200 J
Solution
Work done (W) = F × d = 50 N × 3 m = 150 J.
Correct Answer:
A
— 150 J
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Q. What is the work done when a force of 10 N moves an object 5 m in the direction of the force? (2016)
-
A.
50 J
-
B.
25 J
-
C.
10 J
-
D.
5 J
Solution
Work done (W) = Force × Distance = 10 N × 5 m = 50 J.
Correct Answer:
A
— 50 J
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Q. What is the work done when a force of 15 N moves an object 3 m at an angle of 0 degrees to the direction of motion?
-
A.
45 J
-
B.
30 J
-
C.
60 J
-
D.
75 J
Solution
Work = Force * Distance * cos(θ) = 15 N * 3 m * cos(0°) = 45 J.
Correct Answer:
A
— 45 J
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Q. What is the work done when a force of 15 N moves an object 3 m at an angle of 60° to the direction of the force?
-
A.
22.5 J
-
B.
30 J
-
C.
36.5 J
-
D.
45 J
Solution
W = F × d × cos(θ) = 15 N × 3 m × cos(60°) = 15 × 3 × 0.5 = 22.5 J.
Correct Answer:
A
— 22.5 J
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Q. What is the work done when a force of 15 N moves an object 3 m in the direction of the force? (2021)
-
A.
45 J
-
B.
30 J
-
C.
15 J
-
D.
60 J
Solution
Work Done (W) = Force * Distance = 15 N * 3 m = 45 J.
Correct Answer:
A
— 45 J
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Q. What is the work done when a force of 15 N moves an object 4 m in the direction of the force?
-
A.
60 J
-
B.
30 J
-
C.
45 J
-
D.
75 J
Solution
Work done = Force × Distance = 15 N × 4 m = 60 J
Correct Answer:
A
— 60 J
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Q. What is the work done when a force of 25 N moves an object 4 m at an angle of 60° to the direction of the force? (2019)
-
A.
50 J
-
B.
100 J
-
C.
75 J
-
D.
25 J
Solution
Work done = Fd cos(θ) = 25 N × 4 m × cos(60°) = 25 N × 4 m × 0.5 = 50 J
Correct Answer:
C
— 75 J
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Q. What is the work done when a force of 25 N moves an object 8 m in the direction of the force? (2023)
-
A.
200 J
-
B.
150 J
-
C.
300 J
-
D.
100 J
Solution
Work done (W) = F × d = 25 N × 8 m = 200 J.
Correct Answer:
A
— 200 J
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Q. What is the work done when a force of 5 N moves an object 3 m in the direction of the force?
-
A.
15 J
-
B.
5 J
-
C.
10 J
-
D.
20 J
Solution
Work done (W) = Force (F) × Distance (d) = 5 N × 3 m = 15 J.
Correct Answer:
A
— 15 J
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Q. What is the work function of a metal if the threshold frequency is 5 x 10^14 Hz?
-
A.
3.1 eV
-
B.
2.5 eV
-
C.
4.1 eV
-
D.
1.6 eV
Solution
The work function φ can be calculated using φ = hf, where h = 6.63 x 10^-34 J.s and f = 5 x 10^14 Hz, giving φ ≈ 3.1 eV.
Correct Answer:
A
— 3.1 eV
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Q. What is the work function of a metal?
-
A.
The energy required to ionize an atom
-
B.
The energy required to remove an electron from the surface of a metal
-
C.
The energy of the emitted electrons
-
D.
The energy of the incident photons
Solution
The work function is the minimum energy required to remove an electron from the surface of a metal.
Correct Answer:
B
— The energy required to remove an electron from the surface of a metal
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Q. What is the work-energy theorem?
-
A.
Work done is equal to change in momentum
-
B.
Work done is equal to change in kinetic energy
-
C.
Work done is equal to change in potential energy
-
D.
Work done is equal to change in total energy
Solution
The work-energy theorem states that the work done on an object is equal to the change in its kinetic energy.
Correct Answer:
B
— Work done is equal to change in kinetic energy
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Q. What is the x-intercept of the line 2x + 3y = 6? (2019)
Solution
To find the x-intercept, set y = 0. Thus, 2x = 6, giving x = 3.
Correct Answer:
A
— 2
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Q. What is the x-intercept of the line 3x + 4y - 12 = 0?
Solution
To find the x-intercept, set y = 0. Thus, 3x - 12 = 0 gives x = 4.
Correct Answer:
B
— 3
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Q. What is the x-intercept of the line 5x + 2y = 10?
Solution
Setting y = 0 in the equation gives 5x = 10, thus x = 2. The x-intercept is 2.
Correct Answer:
B
— 5
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Q. What is the x-intercept of the line 5x - 2y + 10 = 0?
Solution
Setting y = 0 in the equation gives 5x + 10 = 0, thus x = -2.
Correct Answer:
B
— 2
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Q. What is the x-intercept of the line 6x - 2y = 12?
Solution
Setting y = 0 in the equation gives 6x = 12, thus x = 2. The x-intercept is 2.
Correct Answer:
B
— 3
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Q. What is the x-intercept of the line given by the equation 4x + 5y - 20 = 0?
Solution
To find the x-intercept, set y = 0. Thus, 4x = 20, giving x = 5.
Correct Answer:
A
— 4
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Q. What is the x-intercept of the line represented by the equation 5x + 2y = 10?
Solution
To find the x-intercept, set y = 0. The equation becomes 5x = 10, thus x = 2.
Correct Answer:
C
— 5
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Q. What is the y-intercept of the line 2x - 3y + 6 = 0? (2023)
Solution
Rearranging gives y = (2/3)x + 2; y-intercept = 2
Correct Answer:
A
— 2
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