Major Competitive Exams

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Major Competitive Exams

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Major Competitive Exams MCQ & Objective Questions

Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.

What You Will Practise Here

Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams

Exam Relevance

The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.

Common Mistakes Students Make

Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam

FAQs

Question: How can I improve my performance in Major Competitive Exams?
Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.

Question: What types of questions should I focus on for these exams?
Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.

Question: Are there specific strategies for tackling objective questions?
Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.

Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!

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Q. What is the oxidation state of nitrogen in NO3^-?

A. +3
B. +5
C. 0
D. -1

Solution

In NO3^-, nitrogen has an oxidation state of +5.

Correct Answer: B — +5

Q. What is the oxidation state of phosphorus in H3PO4?

A. +5
B. +3
C. 0
D. -3

Solution

In H3PO4, phosphorus has an oxidation state of +5.

Correct Answer: A — +5

Q. What is the oxidation state of phosphorus in phosphoric acid (H3PO4)?

A. +3
B. +5
C. 0
D. -3

Solution

In phosphoric acid, phosphorus has an oxidation state of +5.

Correct Answer: B — +5

Q. What is the oxidation state of phosphorus in phosphoric acid (H3PO4)? (2020) 2020

A. +3
B. +5
C. 0
D. -3

Solution

In H3PO4, phosphorus has an oxidation state of +5.

Correct Answer: B — +5

Q. What is the oxidation state of sulfur in H2SO4?

A. 0
B. +4
C. +6
D. -2

Solution

In H2SO4, the oxidation state of sulfur is +6.

Correct Answer: C — +6

Q. What is the oxidation state of sulfur in H2SO4? (2021) 2021

A. +6
B. +4
C. +2
D. 0

Solution

In H2SO4, the oxidation state of sulfur is +6. Each hydrogen is +1 and each oxygen is -2, leading to the equation: 2(+1) + x + 4(-2) = 0, solving gives x = +6.

Correct Answer: A — +6

Q. What is the oxidation state of sulfur in H2SO4? (2023) 2023

A. +2
B. +4
C. +6
D. 0

Solution

In H2SO4, the oxidation state of sulfur is +6.

Correct Answer: C — +6

Q. What is the oxidation state of Uranium in Uranium Hexafluoride (UF6)?

A. +4
B. +6
C. +5
D. 0

Solution

In UF6, Uranium is in the +6 oxidation state as it forms six bonds with fluorine.

Correct Answer: B — +6

Q. What is the packing efficiency of a body-centered cubic (BCC) structure? (2020)

A. 52%
B. 68%
C. 74%
D. 100%

Solution

The packing efficiency of a body-centered cubic (BCC) structure is approximately 68%.

Correct Answer: B — 68%

Q. What is the particular solution of dy/dx = 4x with the initial condition y(0) = 1?

A. y = 2x^2 + 1
B. y = 4x^2 + 1
C. y = 2x^2
D. y = 4x^2 + C

Solution

Integrating gives y = 2x^2 + C. Using the initial condition, C = 1.

Correct Answer: A — y = 2x^2 + 1

Q. What is the particular solution of dy/dx = 4y with the initial condition y(0) = 2?

A. y = 2e^(4x)
B. y = e^(4x)
C. y = 4e^(4x)
D. y = 2e^(x)

Solution

The general solution is y = Ce^(4x). Using the initial condition y(0) = 2, we find C = 2, thus y = 2e^(4x).

Correct Answer: A — y = 2e^(4x)

Q. What is the particular solution of the equation dy/dx = 2y with the initial condition y(0) = 1?

A. y = e^(2x)
B. y = e^(2x) + 1
C. y = 1 + e^(2x)
D. y = 1 + 2x

Solution

The general solution is y = Ce^(2x). Using the initial condition y(0) = 1, we find C = 1.

Correct Answer: A — y = e^(2x)

Q. What is the particular solution of the equation dy/dx = 2y with y(0) = 5?

A. y = 5e^(2x)
B. y = 2e^(2x)
C. y = 5e^(-2x)
D. y = 5 + 2x

Solution

The general solution is y = Ce^(2x). Using y(0) = 5 gives C = 5.

Correct Answer: A — y = 5e^(2x)

Q. What is the passive voice of 'They are painting the house'?

A. The house is painted by them.
B. The house was painted by them.
C. The house is being painted by them.
D. The house has been painted by them.

Solution

In passive voice, the focus is on the action being done to the subject. 'The house' is the subject receiving the action.

Correct Answer: C — The house is being painted by them.

Q. What is the past tense of 'run'? (2021)

A. Runed
B. Ran
C. Runned
D. Running

Solution

The past tense of 'run' is 'ran'.

Correct Answer: B — Ran

Q. What is the past tense of 'to lie' (to recline)?

A. lied
B. lay
C. lain
D. layed

Solution

The past tense of 'to lie' (to recline) is 'lay'.

Correct Answer: B — lay

Q. What is the past tense of 'to run'?

A. run
B. running
C. ran
D. runs

Solution

'Ran' is the correct past tense form of the verb 'to run'.

Correct Answer: C — ran

Q. What is the path difference for light waves from two coherent sources at an angle of 45° to the line joining them?

A. λ/2
B. λ
C. √2λ
D. 0

Solution

Path difference = d sin θ = d sin(45°) = d(√2/2). For d = λ, path difference = √2λ.

Correct Answer: C — √2λ

Q. What is the path difference for light waves from two coherent sources at an angle of 45° to the line joining the sources at a distance of 1 m?

A. 0.5 m
B. 0.707 m
C. 1 m
D. 0.25 m

Solution

Path difference = d sin θ = 1 m * sin(45°) = 1 m * √2/2 = 0.707 m.

Correct Answer: B — 0.707 m

Q. What is the path difference for the first minimum in a double-slit experiment?

A. λ/2
B. λ
C. 3λ/2
D. 2λ

Solution

The path difference for the first minimum is λ/2, which leads to destructive interference.

Correct Answer: A — λ/2

Q. What is the path difference for the first minimum in a single-slit diffraction pattern? (2021)

A. λ/2
B. λ
C. 3λ/2
D. λ/4

Solution

The path difference for the first minimum in single-slit diffraction is λ/2.

Correct Answer: A — λ/2

Q. What is the peak voltage of an AC source if its RMS voltage is 220 V? (2021)

A. 311 V
B. 220 V
C. 155 V
D. 440 V

Solution

The peak voltage (V_peak) is related to the RMS voltage (V_rms) by the formula V_peak = V_rms × √2. Therefore, V_peak = 220 V × √2 ≈ 311 V.

Correct Answer: A — 311 V

Q. What is the peak voltage of an AC supply if its RMS voltage is 220 V? (2021)

A. 311 V
B. 220 V
C. 155 V
D. 440 V

Solution

The peak voltage (V_peak) is related to the RMS voltage (V_rms) by the formula V_peak = V_rms × √2. Therefore, V_peak = 220 V × √2 ≈ 311 V.

Correct Answer: A — 311 V

Q. What is the percentage by mass of a solution containing 15 grams of solute in 85 grams of solvent? (2021)

A. 15%
B. 17.65%
C. 20%
D. 25%

Solution

Percentage by mass = (mass of solute / total mass) × 100 = (15 g / (15 g + 85 g)) × 100 = 17.65%.

Correct Answer: B — 17.65%

Q. What is the percentage by mass of a solution containing 20 grams of solute in 180 grams of solution?

A. 10%
B. 20%
C. 15%
D. 25%

Solution

Percentage by mass = (mass of solute / mass of solution) * 100 = (20 g / (20 g + 180 g)) * 100 = 20%.

Correct Answer: B — 20%

Q. What is the percentage by mass of a solution containing 5 g of NaCl in 95 g of water?

A. 5%
B. 10%
C. 15%
D. 20%

Solution

Percentage by mass = (mass of solute / total mass) × 100 = (5 g / (5 g + 95 g)) × 100 = 5%.

Correct Answer: A — 5%

Q. What is the percentage composition of carbon in glucose (C6H12O6)?

A. 40%
B. 50%
C. 60%
D. 30%

Solution

Molar mass of glucose = 6(12) + 12(1) + 6(16) = 180 g. Percentage of carbon = (72/180) x 100 = 40%.

Correct Answer: A — 40%

Q. What is the percentage concentration of a solution containing 15 g of solute in 150 g of solution? (2023)

A. 10%
B. 15%
C. 20%
D. 25%

Solution

Percentage concentration = (mass of solute / mass of solution) × 100 = (15 g / 150 g) × 100 = 10%

Correct Answer: B — 15%

Q. What is the percentage concentration of a solution containing 20 g of solute in 200 g of solution? (2021)

A. 10%
B. 20%
C. 5%
D. 15%

Solution

Percentage concentration = (mass of solute / mass of solution) × 100 = (20 g / 200 g) × 100 = 10%.

Correct Answer: A — 10%

Q. What is the percentage error if the measured value is 10.0 and the true value is 9.5? (2021)

A. 5.26%
B. 4.76%
C. 2.5%
D. 10%

Solution

Percentage error = (|Measured - True| / True) × 100 = (|10.0 - 9.5| / 9.5) × 100 = 5.26%.

Correct Answer: B — 4.76%

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