Q. If the resistances in a Wheatstone bridge are 5Ω, 15Ω, 10Ω, and R, what is the value of R for the bridge to be balanced?
A.
7.5Ω
B.
10Ω
C.
12.5Ω
D.
15Ω
Show solution
Solution
Using the balance condition R1/R2 = R3/R4, we find R = (R2 * R3) / R1 = (15 * 10) / 5 = 30Ω.
Correct Answer:
C
— 12.5Ω
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Q. If the resistances in a Wheatstone bridge are equal, what is the current through the galvanometer?
A.
Zero
B.
Maximum
C.
Minimum
D.
Depends on the voltage
Show solution
Solution
If all resistances are equal, the bridge is balanced and the current through the galvanometer is zero.
Correct Answer:
A
— Zero
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Q. If the resistances in a Wheatstone bridge are equal, what is the potential difference across the galvanometer?
A.
Zero
B.
Equal to the supply voltage
C.
Half of the supply voltage
D.
Depends on the resistances
Show solution
Solution
If the resistances are equal, the potential difference across the galvanometer is zero.
Correct Answer:
A
— Zero
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Q. If the resistances in a Wheatstone bridge are P = 10Ω, Q = 15Ω, R = 5Ω, and S = xΩ, what is the value of x for the bridge to be balanced?
A.
7.5Ω
B.
10Ω
C.
12.5Ω
D.
15Ω
Show solution
Solution
For balance, P/Q = R/S => 10/15 = 5/x => x = 7.5Ω.
Correct Answer:
C
— 12.5Ω
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Q. If the resistances in a Wheatstone bridge are P = 3Ω, Q = 6Ω, R = 1.5Ω, and S = 3Ω, is the bridge balanced?
A.
Yes
B.
No
C.
Cannot be determined
D.
Only if P = R
Show solution
Solution
The bridge is not balanced because P/Q ≠ R/S.
Correct Answer:
B
— No
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Q. If the resistances in a Wheatstone bridge are R1 = 10Ω, R2 = 15Ω, R3 = 5Ω, and R4 = xΩ, what value of x will balance the bridge?
A.
7.5Ω
B.
10Ω
C.
12.5Ω
D.
15Ω
Show solution
Solution
Using the balance condition R1/R2 = R3/R4, we have 10/15 = 5/x, solving gives x = 7.5Ω.
Correct Answer:
A
— 7.5Ω
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Q. If the resistances in a Wheatstone bridge are R1 = 10Ω, R2 = 15Ω, R3 = 5Ω, and R4 = 7.5Ω, is the bridge balanced?
A.
Yes
B.
No
C.
Depends on the voltage
D.
Not enough information
Show solution
Solution
The bridge is balanced if R1/R2 = R3/R4. Here, 10/15 = 5/7.5, which simplifies to 2/3 = 2/3, confirming the bridge is balanced.
Correct Answer:
A
— Yes
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Q. If the resistances in a Wheatstone bridge are R1 = 10Ω, R2 = 15Ω, R3 = 5Ω, what should R4 be for the bridge to be balanced?
A.
7.5Ω
B.
10Ω
C.
12.5Ω
D.
15Ω
Show solution
Solution
Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (15 * 5) / 10 = 7.5Ω.
Correct Answer:
C
— 12.5Ω
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Q. If the resistances in a Wheatstone bridge are R1 = 10Ω, R2 = 15Ω, R3 = 5Ω, what is the value of R4 for the bridge to be balanced?
A.
7.5Ω
B.
10Ω
C.
12.5Ω
D.
15Ω
Show solution
Solution
Using the balance condition R1/R2 = R3/R4, we have 10/15 = 5/R4. Solving gives R4 = 7.5Ω.
Correct Answer:
C
— 12.5Ω
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Q. If the resistances in a Wheatstone bridge are R1 = 10Ω, R2 = 20Ω, R3 = 15Ω, what should R4 be for the bridge to be balanced?
A.
30Ω
B.
15Ω
C.
20Ω
D.
10Ω
Show solution
Solution
Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (20 * 15) / 10 = 30Ω.
Correct Answer:
B
— 15Ω
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Q. If the resistances in a Wheatstone bridge are R1 = 10Ω, R2 = 20Ω, R3 = 15Ω, what is the value of R4 for the bridge to be balanced?
A.
30Ω
B.
20Ω
C.
15Ω
D.
10Ω
Show solution
Solution
Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (20 * 15) / 10 = 30Ω.
Correct Answer:
B
— 20Ω
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Q. If the resistances in a Wheatstone bridge are R1 = 20Ω, R2 = 30Ω, and R3 = 10Ω, what is the value of R4 for the bridge to be balanced?
A.
15Ω
B.
20Ω
C.
25Ω
D.
30Ω
Show solution
Solution
Using the balance condition R1/R2 = R3/R4, we have 20/30 = 10/x, solving gives x = 20Ω.
Correct Answer:
B
— 20Ω
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Q. If the resistances in a Wheatstone bridge are R1, R2, R3, and R4, what is the condition for balance?
A.
R1/R2 = R3/R4
B.
R1 + R2 = R3 + R4
C.
R1 * R4 = R2 * R3
D.
R1 - R2 = R3 - R4
Show solution
Solution
The condition for balance in a Wheatstone bridge is R1/R2 = R3/R4.
Correct Answer:
A
— R1/R2 = R3/R4
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Q. If the resistivity of a material is 1.5 x 10^-8 Ω·m, what is the resistance of a 3 m long wire with a cross-sectional area of 0.5 mm²?
A.
0.09 Ω
B.
0.18 Ω
C.
0.27 Ω
D.
0.36 Ω
Show solution
Solution
Resistance R = ρ(L/A) = (1.5 x 10^-8)(3)/(0.5 x 10^-6) = 0.09 Ω.
Correct Answer:
B
— 0.18 Ω
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Q. If the resistivity of a material is 2 x 10^-8 Ω·m and the wire has a length of 3 m and a cross-sectional area of 0.5 mm², what is the resistance?
A.
0.12 Ω
B.
0.15 Ω
C.
0.18 Ω
D.
0.20 Ω
Show solution
Solution
Resistance R = ρ * (L / A) = 2 x 10^-8 * (3 / 0.5 x 10^-6) = 0.12 Ω.
Correct Answer:
A
— 0.12 Ω
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Q. If the resistivity of a material is doubled, what happens to the resistance of a wire of constant length and cross-sectional area?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
Show solution
Solution
Resistance R is directly proportional to resistivity ρ, so if ρ is doubled, R also doubles.
Correct Answer:
A
— It doubles
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Q. If the resistivity of a material is doubled, what happens to the resistance of a wire of fixed length and cross-sectional area?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
Show solution
Solution
Resistance R is directly proportional to resistivity; if resistivity doubles, resistance also doubles.
Correct Answer:
A
— It doubles
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Q. If the resistivity of a material is halved, what happens to the resistance of a uniform wire of that material?
A.
Halved
B.
Doubled
C.
Remains the same
D.
Quadrupled
Show solution
Solution
Resistance is directly proportional to resistivity; halving resistivity halves the resistance.
Correct Answer:
A
— Halved
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Q. If the resistivity of a material is halved, what happens to the resistance of a wire of fixed length and cross-sectional area?
A.
Halved
B.
Doubled
C.
Remains the same
D.
Quadrupled
Show solution
Solution
Resistance is directly proportional to resistivity; halving resistivity halves the resistance.
Correct Answer:
A
— Halved
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Q. If the resistivity of a material is halved, what will happen to the resistance of a wire of fixed length and cross-sectional area?
A.
Halved
B.
Doubled
C.
Remains the same
D.
Quadrupled
Show solution
Solution
Resistance is directly proportional to resistivity; halving resistivity halves the resistance.
Correct Answer:
A
— Halved
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Q. If the resistivity of a superconductor is zero, what can be said about its resistance?
A.
Infinite
B.
Zero
C.
Depends on temperature
D.
Undefined
Show solution
Solution
A superconductor has zero resistivity, which means it has zero resistance.
Correct Answer:
B
— Zero
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Q. If the resistivity of copper is 1.68 x 10^-8 Ω·m, what is the resistance of a copper wire of length 100 m and diameter 1 mm?
A.
0.168 Ω
B.
0.168 kΩ
C.
1.68 Ω
D.
1.68 kΩ
Show solution
Solution
Resistance R = ρ * (L / A) = 1.68 x 10^-8 * (100 / (π * (0.5 x 10^-3)²)) = 0.168 Ω.
Correct Answer:
A
— 0.168 Ω
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Q. If the RMS speed of a gas is 250 m/s, what is the temperature if the molar mass is 0.028 kg/mol?
A.
100 K
B.
200 K
C.
300 K
D.
400 K
Show solution
Solution
Using v_rms = sqrt(3RT/M), we can rearrange to find T = (v_rms^2 * M) / (3R) = 300 K.
Correct Answer:
C
— 300 K
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Q. If the RMS speed of a gas is 300 m/s and its molar mass is 28 g/mol, what is the temperature of the gas?
A.
300 K
B.
600 K
C.
900 K
D.
1200 K
Show solution
Solution
Using the formula v_rms = sqrt((3RT)/M), we can rearrange to find T = (v_rms^2 * M)/(3R). Plugging in the values gives T = 600 K.
Correct Answer:
B
— 600 K
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Q. If the RMS speed of a gas is 300 m/s at 300 K, what will be its RMS speed at 600 K?
A.
300 m/s
B.
600 m/s
C.
300√2 m/s
D.
600√2 m/s
Show solution
Solution
The RMS speed is proportional to the square root of the temperature. Therefore, at 600 K, the RMS speed will be 300 * sqrt(2) m/s.
Correct Answer:
C
— 300√2 m/s
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Q. If the RMS speed of a gas is 300 m/s at 400 K, what will be the RMS speed at 200 K?
A.
150 m/s
B.
300 m/s
C.
600 m/s
D.
100 m/s
Show solution
Solution
The RMS speed is proportional to the square root of the temperature. Therefore, at 200 K, the RMS speed will be 300 * sqrt(200/400) = 150 m/s.
Correct Answer:
A
— 150 m/s
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Q. If the RMS speed of a gas is 300 m/s at 400 K, what will be the RMS speed at 800 K?
A.
300 m/s
B.
600 m/s
C.
424 m/s
D.
848 m/s
Show solution
Solution
RMS speed is proportional to the square root of temperature. v_rms at 800 K = 300 * sqrt(800/400) = 300 * sqrt(2) = 600 m/s.
Correct Answer:
B
— 600 m/s
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Q. If the RMS speed of a gas is 300 m/s, what is the kinetic energy per molecule?
A.
0.5 * m * (300)^2
B.
0.5 * m * (150)^2
C.
0.5 * m * (600)^2
D.
0.5 * m * (100)^2
Show solution
Solution
The kinetic energy per molecule is given by KE = 0.5 * m * v^2. Substituting v = 300 m/s gives the correct expression.
Correct Answer:
A
— 0.5 * m * (300)^2
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Q. If the RMS speed of a gas is 300 m/s, what is the RMS speed of the same gas at double the temperature?
A.
300 m/s
B.
600 m/s
C.
300√2 m/s
D.
600√2 m/s
Show solution
Solution
The RMS speed is proportional to the square root of the temperature. If the temperature is doubled, the RMS speed increases by a factor of sqrt(2). Therefore, the new RMS speed will be 300 * sqrt(2), which is approximately 600 m/s.
Correct Answer:
B
— 600 m/s
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Q. If the RMS speed of a gas is 400 m/s and its molar mass is 16 g/mol, what is the temperature of the gas?
A.
200 K
B.
400 K
C.
800 K
D.
1600 K
Show solution
Solution
Using the formula v_rms = sqrt((3RT)/M), we can rearrange to find T: T = (M * v_rms^2) / (3R). Substituting M = 0.016 kg/mol and v_rms = 400 m/s gives T = 400 K.
Correct Answer:
B
— 400 K
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Physics Syllabus (JEE Main) MCQ & Objective Questions
The Physics Syllabus for JEE Main is crucial for students aiming to excel in their exams. Understanding this syllabus not only helps in grasping fundamental concepts but also enhances problem-solving skills through practice. Engaging with MCQs and objective questions is essential for effective exam preparation, as it allows students to identify important questions and strengthen their knowledge base.
What You Will Practise Here
Mechanics: Laws of Motion, Work, Energy, and Power
Thermodynamics: Laws of Thermodynamics, Heat Transfer
Waves and Oscillations: Simple Harmonic Motion, Wave Properties
Electromagnetism: Electric Fields, Magnetic Fields, and Circuits
Optics: Reflection, Refraction, and Optical Instruments
Modern Physics: Quantum Theory, Atomic Models, and Nuclear Physics
Fluid Mechanics: Properties of Fluids, Bernoulli's Principle
Exam Relevance
The Physics Syllabus (JEE Main) is integral to various examinations, including CBSE, State Boards, and competitive exams like NEET and JEE. Questions often focus on conceptual understanding and application of theories. Common patterns include numerical problems, conceptual MCQs, and assertion-reason type questions, which test both knowledge and analytical skills.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers.
Neglecting units and dimensions in calculations.
Overlooking the significance of diagrams in understanding concepts.
Confusing similar concepts, such as velocity and acceleration.
Failing to apply formulas correctly in different contexts.
FAQs
Question: What are the key topics in the Physics Syllabus for JEE Main?Answer: Key topics include Mechanics, Thermodynamics, Waves, Electromagnetism, Optics, Modern Physics, and Fluid Mechanics.
Question: How can I improve my performance in Physics MCQs?Answer: Regular practice of MCQs, understanding concepts deeply, and revising important formulas can significantly enhance your performance.
Start solving practice MCQs today to test your understanding of the Physics Syllabus (JEE Main). This will not only boost your confidence but also prepare you effectively for your upcoming exams. Remember, consistent practice is the key to success!
