The slopes of the lines are -2/3 and 4. The angle θ can be found using tan(θ) = |(m1 - m2) / (1 + m1*m2)|.

Using the formula for the angle between two lines, we find that the angle is 90 degrees.

The angle can be calculated using the slopes derived from the equation, leading to 90 degrees.

By completing the square, we can find the slopes of the lines and calculate the angle between them.

The slopes are m1 = 2 and m2 = -0.5. The angle θ is given by tan(θ) = |(m1 - m2) / (1 + m1*m2)| = |(2 + 0.5) / (1 - 1)|, which is undefined, indicating 90 degrees.

The slopes are m1 = 2 and m2 = -1/2. The angle θ = tan^(-1) |(m1 - m2) / (1 + m1*m2)| = tan^(-1)(5/0) = 90 degrees.

The angle between (1, 0) and (0, 1) is 90 degrees.

Cosine of angle θ = (u · v) / (|u| |v|). Calculate to find θ = 60 degrees.

cos(θ) = (a · b) / (|a| |b|). Calculate a · b = 1*2 + 2*0 + 2*2 = 6, |a| = √(1^2 + 2^2 + 2^2) = 3, |b| = √(2^2 + 0^2 + 2^2) = 2√2. Thus, cos(θ) = 6 / (3 * 2√2) = 1/√2, θ = 45 degrees.

The angle between u and v is 90 degrees since they are perpendicular.

The angle θ = cos⁻¹((A . B) / (|A| |B|)) = cos⁻¹(0) = 90 degrees.

The area between the curves is given by ∫(from -2 to 2) (4 - x^2) dx = [4x - x^3/3] from -2 to 2 = (8 - (8/3)) - (-8 + (8/3)) = 16 - (16/3) = 32/3.

The area of a circle is given by A = πr², so A = π(10)² = 100π.

The area of a circle is given by A = πr², so A = π(7)² = 49π.

The area is calculated as (1/2) * base * height = (1/2) * 4 * 3 = 6.

The area of an ellipse is given by A = πab. Here, A = π * 7 * 4 = 28π.

The area of an equilateral triangle is given by the formula (√3/4)a².

Area = 1/2 * base * height = 1/2 * 4 * 3 = 6.

The area is given by the integral from 1 to 2 of 1/x dx. This evaluates to [ln(x)] from 1 to 2 = ln(2) - ln(1) = ln(2).

The area is given by the integral from 0 to π/2 of cos(x) dx. This evaluates to [sin(x)] from 0 to π/2 = 1 - 0 = 1.

The area is given by the integral from 0 to π of sin(x) dx. This evaluates to [-cos(x)] from 0 to π = [1 - (-1)] = 2.

The area is given by the integral ∫_0^3 x^2 dx = [x^3/3]_0^3 = 27/3 = 9.

The area is ∫(1 to 3) x^2 dx = [1/3 * x^3] from 1 to 3 = (27/3 - 1/3) = 26/3.

The area under the curve y = x^3 from x = 1 to x = 2 is given by ∫(from 1 to 2) x^3 dx = [x^4/4] from 1 to 2 = (16/4) - (1/4) = 4 - 0.25 = 3.75.

The area under the curve y = x^4 from x = 0 to x = 1 is given by ∫(from 0 to 1) x^4 dx = [x^5/5] from 0 to 1 = 1/5.

The argument of z = -1 + 0i is arg(z) = π.

The argument of z = -1 - i is θ = tan^(-1)(-1/-1) = -3π/4.

Mean = (2 + 3 + 5 + 7 + 11) / 5 = 28 / 5 = 5.6.

The axis of symmetry for a parabola in the form y^2 = 4px is the x-axis, which is x = 0.

The axis of symmetry for a parabola in the form y = ax^2 + bx + c is given by x = -b/(2a). Here, a = -2, b = 4, so x = -4/(2*-2) = 1.