First, divide both sides by 2 to get x - 3 = 2, then add 3 to both sides to find x = 5.

Subtracting 4 from both sides gives 2x = 12. Dividing by 2 gives x = 6.

Using the quadratic formula, x = [8 ± sqrt(64 - 48)] / 4 = [8 ± 4] / 4, giving x = 3 or x = 1.

Subtracting 7 from both sides gives 3x = 15. Dividing by 3 gives x = 5.

Solving for x: 3x = 12, thus x = 4.

Adding 7 to both sides gives 3x = 9. Dividing by 3 gives x = 3.

Rearranging gives 3x - 2x = 5 + 7, thus x = 12.

To solve for x, add 9 to both sides and then divide by 3: 3x = 9, thus x = 3.

Dividing both sides by 4 gives x - 1 = 3, thus x = 4.

First, divide both sides by 4: x - 2 = 3, then add 2 to both sides: x = 5.

Expanding both sides gives 4x - 8 = 3x + 3. Subtract 3x from both sides: x - 8 = 3. Adding 8 gives x = 11.

Solving for x gives 4x = 16, thus x = 4.

Add 5 to both sides: 4x = 16. Then divide by 4: x = 4.

Adding 7 to both sides gives 4x = 16. Dividing by 4 gives x = 4.

First, divide both sides by 5: x - 2 = 3. Then add 2 to both sides to find x = 5.

Expanding gives 5x - 10 = 3x + 4. Rearranging gives 2x = 14, thus x = 7.

5x + 2 = 17 => 5x = 15 => x = 3.

Adding 3 to both sides gives 5x = 5. Dividing by 5 gives x = 1.

Rearranging gives 5x - 2x = 12 + 3 => 3x = 15 => x = 5.

Rearranging gives 5x - 2x = 6 + 3 => 3x = 9 => x = 3.

Subtract 3x from both sides: 4x - 4 = 12. Add 4: 4x = 16. Divide by 4: x = 4.

f'(x) = 3x^2 - 3. Setting f'(x) = 0 gives x = ±1. f(1) = -2.

9y - 5 = 22 => 9y = 27 => y = 3.

The solutions to z^2 = -1 are z = i and z = -i.

The determinant is 0 because the first column is repeated.

The determinant is calculated as \( 2*4 - 1*3 = 8 - 3 = 5 \).

By definition, \( \tan(\tan^{-1}(x)) = x \). Therefore, \( \tan(\tan^{-1}(3)) = 3 \).

The determinant is \( 0*0 - 1*1 = 0 - 1 = -1 \).

The determinant of the identity matrix is always 1.

The modulus |z| = √((-1)² + (-1)²) = √(1 + 1) = √2.