Major Competitive Exams

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Major Competitive Exams

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Major Competitive Exams MCQ & Objective Questions

Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.

What You Will Practise Here

Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams

Exam Relevance

The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.

Common Mistakes Students Make

Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam

FAQs

Question: How can I improve my performance in Major Competitive Exams?
Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.

Question: What types of questions should I focus on for these exams?
Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.

Question: Are there specific strategies for tackling objective questions?
Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.

Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!

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Q. What is the name of the reaction where benzene is converted to phenol?

A. Hydrogenation
B. Nitration
C. Sulfonation
D. Hydroxylation

Solution

The conversion of benzene to phenol is known as hydroxylation, typically involving the addition of a hydroxyl group (-OH) to the aromatic ring.

Correct Answer: D — Hydroxylation

Q. What is the nature of the image formed by a concave lens when the object is placed at infinity?

A. Real and inverted
B. Virtual and upright
C. Real and upright
D. Virtual and inverted

Solution

A concave lens always produces a virtual and upright image regardless of the object's position.

Correct Answer: B — Virtual and upright

Q. What is the nature of the image formed by a concave lens?

A. Real and inverted
B. Real and upright
C. Virtual and upright
D. Virtual and inverted

Solution

A concave lens always forms a virtual and upright image.

Correct Answer: C — Virtual and upright

Q. What is the nature of the image formed by a concave mirror when the object is placed beyond the center of curvature?

A. Real and inverted
B. Virtual and upright
C. Real and upright
D. Virtual and inverted

Solution

When the object is beyond the center of curvature, the image formed is real and inverted.

Correct Answer: A — Real and inverted

Q. What is the nature of the image formed by a concave mirror when the object is placed between the focal point and the mirror? (2021)

A. Real and inverted
B. Virtual and erect
C. Real and erect
D. Virtual and inverted

Solution

When the object is placed between the focal point and the mirror, the image formed is virtual and erect.

Correct Answer: B — Virtual and erect

Q. What is the nature of the image formed by a convex lens when the object is placed at a distance greater than twice the focal length?

A. Real and inverted
B. Virtual and upright
C. Real and upright
D. Virtual and inverted

Solution

When the object is placed beyond 2f, the image formed by a convex lens is real and inverted.

Correct Answer: A — Real and inverted

Q. What is the nature of the image formed by a convex lens when the object is placed beyond the focal point?

A. Virtual and upright
B. Real and inverted
C. Real and upright
D. Virtual and inverted

Solution

When the object is beyond the focal point, the image formed by a convex lens is real and inverted.

Correct Answer: B — Real and inverted

Q. What is the nature of the image formed by a convex lens when the object is placed at infinity?

A. Real and inverted
B. Virtual and upright
C. Real and upright
D. Virtual and inverted

Solution

When the object is at infinity, the rays converge at the focal point, forming a real and inverted image.

Correct Answer: A — Real and inverted

Q. What is the nature of the image formed by a convex lens when the object is placed beyond the focal length?

A. Virtual and erect
B. Real and inverted
C. Real and erect
D. Virtual and inverted

Solution

When an object is placed beyond the focal length of a convex lens, the image formed is real and inverted.

Correct Answer: B — Real and inverted

Q. What is the nature of the image formed by a convex lens when the object is placed at twice the focal length?

A. Real and inverted
B. Virtual and erect
C. Real and erect
D. Virtual and inverted

Solution

When the object is at 2f, the image is formed at 2f on the opposite side, making it real and inverted.

Correct Answer: A — Real and inverted

Q. What is the nature of the image formed by a convex lens when the object is placed beyond the 2F point? (2019)

A. Real and inverted
B. Virtual and erect
C. Real and erect
D. Virtual and inverted

Solution

When the object is placed beyond 2F, the image formed by a convex lens is real, inverted, and diminished.

Correct Answer: A — Real and inverted

Q. What is the nature of the image formed by a convex mirror?

A. Real and inverted
B. Virtual and upright
C. Real and upright
D. Virtual and inverted

Solution

A convex mirror always forms a virtual image that is upright and smaller than the object.

Correct Answer: B — Virtual and upright

Q. What is the nature of the image formed by a plane mirror?

A. Real and inverted
B. Virtual and erect
C. Real and erect
D. Virtual and inverted

Solution

A plane mirror always forms a virtual and erect image, as the image appears behind the mirror at the same distance as the object.

Correct Answer: B — Virtual and erect

Q. What is the nature of the roots of the equation x² + 2x + 5 = 0? (2023)

A. Real and distinct
B. Real and equal
C. Complex
D. None of the above

Solution

The discriminant D = 2² - 4*1*5 = 4 - 20 = -16, which indicates complex roots.

Correct Answer: C — Complex

Q. What is the Nernst equation for a cell at 298 K with E° = 0.77 V and [Zn²⁺] = 0.01 M?

A. E = 0.77 - 0.0591 log(0.01)
B. E = 0.77 + 0.0591 log(0.01)
C. E = 0.77 - 0.0591 log(100)
D. E = 0.77 + 0.0591 log(100)

Solution

Using the Nernst equation: E = E° - (0.0591/n) log([Zn²⁺]), where n=2.

Correct Answer: A — E = 0.77 - 0.0591 log(0.01)

Q. What is the Nernst equation used for calculating the cell potential at non-standard conditions? (2023)

A. E = E° - (RT/nF)lnQ
B. E = E° + (RT/nF)lnQ
C. E = E° - (nF/RT)lnQ
D. E = E° + (nF/RT)lnQ

Solution

The Nernst equation is E = E° - (RT/nF)lnQ, where E is the cell potential, E° is the standard potential, R is the gas constant, T is the temperature, n is the number of moles of electrons, and F is Faraday's constant.

Correct Answer: A — E = E° - (RT/nF)lnQ

Q. What is the Nernst equation used for?

A. Calculating pH
B. Determining cell potential
C. Finding molarity
D. Measuring temperature

Solution

The Nernst equation is used to determine the cell potential under non-standard conditions.

Correct Answer: B — Determining cell potential

Q. What is the Nernst equation used for? (2023) 2023

A. Calculating pH
B. Determining cell potential
C. Measuring current
D. Finding resistance

Solution

The Nernst equation is used to determine the cell potential under non-standard conditions.

Correct Answer: B — Determining cell potential

Q. What is the net force acting on a 12 kg object moving with a constant velocity? (2023)

A. 0 N
B. 12 N
C. 24 N
D. 36 N

Solution

According to Newton's first law, if the object is moving with constant velocity, the net force is 0 N.

Correct Answer: A — 0 N

Q. What is the net force acting on a 15 kg object moving with a constant velocity? (2021)

A. 0 N
B. 15 N
C. 30 N
D. 45 N

Solution

If the object is moving with constant velocity, net force is 0 N (Newton's first law).

Correct Answer: A — 0 N

Q. What is the net force acting on a 15 kg object that is accelerating at 4 m/s²? (2020)

A. 60 N
B. 30 N
C. 45 N
D. 75 N

Solution

Net force F = m × a = 15 kg × 4 m/s² = 60 N.

Correct Answer: A — 60 N

Q. What is the net force acting on an object at rest?

A. Zero
B. Equal to its weight
C. Equal to its mass
D. Equal to the applied force

Solution

An object at rest has no net force acting on it, according to Newton's first law.

Correct Answer: A — Zero

Q. What is the net gain of ATP from one molecule of glucose during aerobic respiration? (2023)

A. 2 ATP
B. 30-32 ATP
C. 36 ATP
D. 38 ATP

Solution

The net gain of ATP from one molecule of glucose during aerobic respiration is approximately 30-32 ATP, depending on the efficiency of the process.

Correct Answer: B — 30-32 ATP

Q. What is the net gain of ATP molecules from one molecule of glucose during aerobic respiration? (2023)

A. 2
B. 18
C. 30-32
D. 36

Solution

The net gain of ATP molecules from one molecule of glucose during aerobic respiration is approximately 30-32 ATP.

Correct Answer: C — 30-32

Q. What is the next figure in the series? A, B, C, ?

A. D
B. E
C. F
D. G

Solution

The series follows an alphabetical order, so the next figure is D.

Correct Answer: D — G

Q. What is the next letter in the series: A, C, E, G, ?

A. H
B. I
C. J
D. K

Solution

The pattern is that each letter is two places ahead in the alphabet. G + 2 = I.

Correct Answer: A — H

Q. What is the next letter in the series: D, F, H, J, ?

A. K
B. L
C. M
D. N

Solution

The series consists of every second letter in the alphabet: D, F, H, J, L.

Correct Answer: A — K

Q. What is the next letter in the series: Z, Y, X, W, ...?

A. V
B. U
C. T
D. S

Solution

The series goes backward in the alphabet, so the next letter is V.

Correct Answer: A — V

Q. What is the next number in the series: 1, 1, 2, 3, 5, ...? (2023)

A. 6
B. 7
C. 8
D. 9

Solution

The series is the Fibonacci sequence where each number is the sum of the two preceding ones. The next number is 3 + 5 = 8.

Correct Answer: A — 6

Q. What is the next number in the series: 1, 2, 4, 7, 11, ?

A. 14
B. 15
C. 16
D. 17

Solution

The differences are 1, 2, 3, 4, which increase by 1 each time. 11 + 3 = 14.

Correct Answer: A — 14

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