A geostationary satellite orbits at a height of approximately 36,000 km above the Earth's surface, which is about R (the radius of the Earth) plus the height of the satellite.

The gravitational force acting on the satellite is given by Newton's law of gravitation, which states that F = G * (M * m) / (R + h)^2, where M is the mass of the Earth and m is the mass of the satellite.

At a height R above the Earth's surface, the gravitational acceleration is g/4, derived from the formula g' = g(R/(R+h))^2.

The radius of a geostationary orbit is approximately 3R, where R is the radius of the Earth.

The gravitational force is inversely proportional to the square of the distance. If the radius doubles, the force decreases to one-fourth.

Gravitational acceleration is inversely proportional to the square of the radius, so it would be quartered.

Weight is proportional to 1/r^2; if the radius doubles, the weight becomes four times less.

Gravitational acceleration is inversely proportional to the square of the radius. If the radius doubles, g becomes 1/(2^2) = 1/4 of the original value.

Gravitational acceleration is inversely proportional to the square of the radius. If the radius is halved, g becomes 4 times greater.

The orbital speed v is given by v = √(GM/r). If r is doubled, v decreases by a factor of √2.

Induced EMF (ε) = -L(dI/dt) = -3 H * 2 A/s = -6 V.

Critical angle θc = sin⁻¹(1/1.33) ≈ 48.6°.

The critical angle θc can be calculated as θc = sin^(-1)(n2/n1) = sin^(-1)(1.00/1.33) ≈ 48.6°.

Speed of light in medium = c/n = (3 x 10^8 m/s) / 1.33 ≈ 2.25 x 10^8 m/s.

The critical angle θc is given by sin(θc) = n2/n1 = 1/1.5, which gives θc ≈ 41.8°.

Speed of light in medium = c/n = (3 x 10^8 m/s) / 1.5 = 2 x 10^8 m/s.

The speed of light in a medium is given by v = c/n. Here, c = 3 x 10^8 m/s and n = 1.5, so v = 3 x 10^8 / 1.5 = 2 x 10^8 m/s.

Wavelength in medium = λ/v = λ0/n = 600 nm / 1.5 = 400 nm.

Using the formula sin(θc) = n2/n1, we have sin(θc) = 1.00/2.00, leading to θc ≈ 30°.

Using the formula sin(θc) = n2/n1, where n1 = 2.0 (medium) and n2 = 1.0 (air), we find sin(θc) = 1.0/2.0 = 0.5, leading to θc = 60°.

Using the formula θc = sin^(-1)(1/n), where n = 2.0, we find θc = sin^(-1)(1/2) = 30°.

Critical angle θc = sin⁻¹(n2/n1) = sin⁻¹(1.00/2.00) ≈ 30°; thus, maximum angle of incidence for total internal reflection is 60°.

The speed of light in a medium is given by v = c/n, where n is the refractive index. If n > 1, the speed decreases.

The speed of light in a medium is given by v = c/n, where n is the refractive index. If n > 1, then v < c, meaning the speed decreases.

The speed of light in a medium is less than that in vacuum, given by v = c/n, where n > 1.

The wavelength of light decreases in a medium with a refractive index greater than 1, as λ' = λ/n.

The wavelength of light decreases in a medium with a refractive index greater than 1, as it is given by λ' = λ/n.

When light reflects off a medium with a higher refractive index, it undergoes a phase change of π (180 degrees).

Using the formula sin(θc) = n2/n1, where n1 = 2.42 (diamond) and n2 = 1.00 (air), we find θc ≈ 24.4°.

According to Ohm's Law (I = V/R), if resistance (R) is doubled and voltage (V) remains constant, the current (I) will be halved.