The structural formula of propane is C3H8, indicating three carbon atoms.

A nucleotide consists of a sugar, a phosphate group, and a nitrogenous base.

DNA is described as a double helix, consisting of two strands that wind around each other.

DNA is composed of nucleotides, which include a sugar, phosphate, and nitrogenous base.

DNA has a double helix structure, consisting of two strands that coil around each other.

The factors of 24 are 1, 2, 3, 4, 6, 8, 12, 24. Their sum is 60.

The sum of the angles in a triangle is always 180 degrees.

The sum of the coefficients is (2 + 3)^4 = 5^4 = 625.

The sum of the coefficients is found by substituting x = 1: (2 + 3*1)^4 = 5^4 = 625.

To find the sum of the coefficients, substitute x = 1: (2*1 - 3)^4 = (-1)^4 = 1. The sum of coefficients is 81.

To find the sum of the coefficients, substitute x = 1. Thus, (3(1) - 2)^4 = (3 - 2)^4 = 1^4 = 1.

The sum of the coefficients in the expansion of (x + 1)^4 is (1 + 1)^4 = 2^4 = 16.

The sum of the coefficients is found by substituting x = 1, so (1 + 1)^5 = 2^5 = 32.

The sum of the coefficients is found by substituting x = 1, giving (1 + 1)^7 = 2^7 = 128.

The sum of the coefficients in the expansion of (x + 1)^n is given by (1 + 1)^n = 2^n. Here, n=8, so the sum is 2^8 = 256.

The sum of the coefficients is found by substituting x=1. So, (1 + 2)^5 = 3^5 = 243.

(1 + 2i) + (3 - 4i) = (1 + 3) + (2 - 4)i = 4 - 2i.

The sum is (2 + 4) + (3 - 5)i = 6 - 2i.

(3 + 2i) + (1 - 4i) = (3 + 1) + (2 - 4)i = 4 - 2i.

To find the sum, we add the real parts and the imaginary parts: (2 + 3) + (2 - 4)i = 5 - 2i.

The sum of two complex numbers z1 + z2 = (2 + 3i) + (4 - 2i) = (2 + 4) + (3 - 2)i = 6 + i.

'101' is 5 and '110' is 6 in decimal. Their sum is 5 + 6 = 11.

The sum of the digits in '1011' is 1 + 0 + 1 + 1 = 3.

The digits are 1, 2, and 3. Their sum is 1 + 2 + 3 = 6.

The first 10 prime numbers are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29. Their sum is 129.

The sum of the first n terms S_n = n/2 * (2a + (n-1)d). Here, S_15 = 15/2 * (2*2 + 14*4) = 15/2 * (4 + 56) = 15/2 * 60 = 450.

The sum of the first n terms S_n = n/2 * (2a + (n-1)d). Here, S_15 = 15/2 * (2*10 + 14*2) = 15/2 * (20 + 28) = 15/2 * 48 = 360.

Sum = 1 + 2 + 3 + 4 + 5 = 15.

The sum of the first n terms of a GP is given by S_n = a(1 - r^n) / (1 - r). Here, S_5 = 2(1 - 3^5) / (1 - 3) = 2(1 - 243) / (-2) = 242.

S_5 = 1 + 1/2 + 1/4 + 1/8 + 1/16 = 1.5.