Mathematics (School) MCQ & Objective Questions
Mathematics is a crucial subject in school education, forming the foundation for various competitive exams. Mastering Mathematics (School) not only enhances problem-solving skills but also boosts confidence during exams. Practicing MCQs and objective questions is essential for effective exam preparation, as it helps students identify important questions and understand concepts clearly.
What You Will Practise Here
Number Systems and their properties
Algebraic Expressions and Equations
Geometry: Angles, Triangles, and Circles
Statistics and Probability concepts
Mensuration: Area, Volume, and Surface Area
Trigonometry basics and applications
Functions and Graphs
Exam Relevance
Mathematics (School) is a significant part of the curriculum for CBSE and State Boards, as well as competitive exams like NEET and JEE. Students can expect a variety of question patterns, including direct application of formulas, conceptual understanding, and problem-solving scenarios. Familiarity with MCQs in this subject can greatly enhance performance in both board and competitive examinations.
Common Mistakes Students Make
Misinterpreting the question, leading to incorrect answers.
Overlooking the importance of units in measurement-related problems.
Confusing similar formulas, especially in Geometry and Algebra.
Neglecting to check calculations, resulting in simple arithmetic errors.
Failing to understand the underlying concepts, which affects problem-solving ability.
FAQs
Question: How can I improve my speed in solving Mathematics (School) MCQs?Answer: Regular practice with timed quizzes and mock tests can significantly enhance your speed and accuracy.
Question: Are there any specific topics I should focus on for competitive exams?Answer: Focus on Algebra, Geometry, and Statistics, as these areas frequently appear in competitive exams.
Start your journey towards mastering Mathematics (School) today! Solve practice MCQs to test your understanding and prepare effectively for your exams. Remember, consistent practice leads to success!
Q. What is the perimeter of an equilateral triangle with a side length of 4 cm?
A.
12 cm
B.
16 cm
C.
10 cm
D.
8 cm
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Solution
Perimeter = 3 * side length = 3 * 4 = 12 cm.
Correct Answer:
A
— 12 cm
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Q. What is the perimeter of an equilateral triangle with a side length of 6 cm?
A.
12 cm
B.
18 cm
C.
24 cm
D.
30 cm
Show solution
Solution
The perimeter of an equilateral triangle is given by P = 3 * side length = 3 * 6 = 18 cm.
Correct Answer:
B
— 18 cm
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Q. What is the perimeter of an equilateral triangle with a side length of 8 cm?
A.
16 cm
B.
24 cm
C.
32 cm
D.
40 cm
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Solution
The perimeter of an equilateral triangle is 3 times the side length. Therefore, perimeter = 3 * 8 = 24 cm.
Correct Answer:
B
— 24 cm
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Q. What is the perimeter of triangle DEF if DE = 7 cm, EF = 5 cm, and DF = 6 cm?
A.
18 cm
B.
20 cm
C.
22 cm
D.
24 cm
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Solution
The perimeter is the sum of all sides: 7 + 5 + 6 = 18 cm.
Correct Answer:
A
— 18 cm
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Q. What is the period of the function y = sin(x)?
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Solution
The period of the sine function is 2π.
Correct Answer:
B
— 2π
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Q. What is the period of the sine function?
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Solution
The period of the sine function is 2π, meaning it repeats every 2π units.
Correct Answer:
B
— 2π
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Q. What is the phase shift of y = 4sin(2x + π)?
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Solution
The phase shift is found by setting 2x + π = 0, leading to a shift of -π/2.
Correct Answer:
A
— -π/2
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Q. What is the product of (x + 1)(x + 4)?
A.
x^2 + 5x + 4
B.
x^2 + 3x + 4
C.
x^2 + 4x + 1
D.
x^2 + 5x + 1
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Solution
Step 1: Use the distributive property: x^2 + 4x + x + 4. Step 2: Combine like terms: x^2 + 5x + 4.
Correct Answer:
A
— x^2 + 5x + 4
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Q. What is the product of the factors (x + 2) and (x - 3)?
A.
x^2 - x - 6
B.
x^2 + x - 6
C.
x^2 - 6
D.
x^2 + 6
Show solution
Solution
Step 1: Use the distributive property: x^2 - 3x + 2x - 6 = x^2 - x - 6.
Correct Answer:
A
— x^2 - x - 6
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Q. What is the product of the roots of the polynomial x^2 + 3x + 2?
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Solution
The product of the roots of a quadratic equation ax^2 + bx + c = 0 is given by c/a. Here, 2/1 = 2.
Correct Answer:
A
— 2
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Q. What is the product of the roots of the polynomial x^2 - 4x + 3?
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Solution
The product of the roots is given by c/a. Here, c = 3, so the product is 3.
Correct Answer:
A
— 3
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Q. What is the product of the roots of the quadratic equation x^2 + 3x + 2 = 0?
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Solution
Step 1: Use the formula c/a. Here, c = 2 and a = 1, so the product is 2/1 = 2.
Correct Answer:
A
— 2
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Q. What is the product of the roots of the quadratic equation x^2 + 5x + 6 = 0?
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Solution
Step 1: Use the product of roots formula c/a. Here, c = 6, a = 1. Step 2: Product = 6/1 = 6.
Correct Answer:
A
— 6
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Q. What is the product of the roots of the quadratic equation x^2 + 6x + 8 = 0?
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Solution
Step 1: Use the formula c/a. Step 2: Here, c = 8 and a = 1. Step 3: Product of roots = 8.
Correct Answer:
A
— 8
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Q. What is the radius of a circle if its area is 100π cm²?
A.
10 cm
B.
5 cm
C.
20 cm
D.
15 cm
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Solution
The area of a circle is A = πr². Setting 100π = πr² gives r² = 100, thus r = 10 cm.
Correct Answer:
A
— 10 cm
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Q. What is the radius of a circle if its area is 36π cm²?
A.
6 cm
B.
12 cm
C.
18 cm
D.
9 cm
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Solution
Area = πr², so r² = 36, thus r = 6 cm.
Correct Answer:
A
— 6 cm
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Q. What is the radius of a circle if its area is 50.24 cm²?
A.
4 cm
B.
5 cm
C.
6 cm
D.
7 cm
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Solution
Area = πr², so r = √(Area/π) = √(50.24/π) ≈ 5 cm.
Correct Answer:
B
— 5 cm
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Q. What is the radius of a circle if its area is 50π square units?
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Solution
Area = πr², so 50π = πr². Dividing both sides by π gives r² = 50, thus r = √50 = 5√2.
Correct Answer:
A
— 5
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Q. What is the radius of a circle if the area is 154 square cm? (Use π = 22/7)
A.
6 cm
B.
7 cm
C.
8 cm
D.
9 cm
Show solution
Solution
Area of a circle = πr². Thus, 154 = (22/7)r². Solving gives r² = 154 * 7 / 22 = 49, so r = 7 cm.
Correct Answer:
B
— 7 cm
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Q. What is the radius of a circle if the area is 50π square units?
A.
5 units
B.
10 units
C.
25 units
D.
50 units
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Solution
Area of a circle = πr². Setting 50π = πr² gives r² = 50, so r = √50 = 5√2, approximately 7.07 units.
Correct Answer:
B
— 10 units
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Q. What is the radius of a circle if the circumference is 31.4 cm?
A.
5 cm
B.
10 cm
C.
15 cm
D.
20 cm
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Solution
The circumference C = 2πr. Thus, r = C/(2π) = 31.4/(2π) ≈ 5 cm.
Correct Answer:
B
— 10 cm
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Q. What is the radius of a circle inscribed in a triangle with sides 7 cm, 8 cm, and 9 cm?
A.
4 cm
B.
3 cm
C.
5 cm
D.
6 cm
Show solution
Solution
Semi-perimeter s = (7 + 8 + 9)/2 = 12 cm. Area = √[s(s-a)(s-b)(s-c)] = √[12(12-7)(12-8)(12-9)] = √[12*5*4*3] = 12√5 cm². Radius = Area/s = 12√5/12 = √5 cm.
Correct Answer:
B
— 3 cm
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Q. What is the radius of a circle whose area is 113.04 cm²?
A.
6 cm
B.
7 cm
C.
8 cm
D.
9 cm
Show solution
Solution
Area = πr², so r = √(Area/π) = √(113.04/π) ≈ 6 cm.
Correct Answer:
B
— 7 cm
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Q. What is the radius of a circle whose area is 50π cm²?
A.
5 cm
B.
10 cm
C.
7.07 cm
D.
12.56 cm
Show solution
Solution
Area = πr², so r² = 50, r = √50 = 7.07 cm.
Correct Answer:
C
— 7.07 cm
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Q. What is the radius of a circle with a circumference of 31.4 units?
A.
5 units
B.
10 units
C.
15 units
D.
20 units
Show solution
Solution
The formula for circumference is C = 2πr. Solving for r gives r = C/(2π) = 31.4/(2π) = 5 units.
Correct Answer:
A
— 5 units
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Q. What is the radius of a circle with the equation (x - 2)² + (y + 3)² = 16?
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Solution
The standard form of a circle is (x - h)² + (y - k)² = r². Here, r² = 16, so r = √16 = 4.
Correct Answer:
A
— 4
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Q. What is the radius of a circle with the equation (x - 2)² + (y + 3)² = 25?
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Solution
Radius = √25 = 5.
Correct Answer:
A
— 5
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Q. What is the radius of a circle with the equation (x - 3)² + (y + 2)² = 25?
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Solution
The standard form of a circle is (x - h)² + (y - k)² = r². Here, r² = 25, so r = √25 = 5.
Correct Answer:
A
— 5
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Q. What is the radius of a circle with the equation (x - 4)² + (y + 2)² = 36?
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Solution
The standard form of a circle is (x - h)² + (y - k)² = r². Here, r² = 36, so r = √36 = 6.
Correct Answer:
A
— 6
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Q. What is the range of the data set: 10, 15, 20, 25, 30?
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Solution
Range = max - min = 30 - 10 = 20
Correct Answer:
A
— 15
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