Perimeter = 3 * side length = 3 * 4 = 12 cm.

The perimeter of an equilateral triangle is given by P = 3 * side length = 3 * 6 = 18 cm.

The perimeter of an equilateral triangle is 3 times the side length. Therefore, perimeter = 3 * 8 = 24 cm.

The perimeter is the sum of all sides: 7 + 5 + 6 = 18 cm.

The period of the sine function is 2π.

The period of the sine function is 2π, meaning it repeats every 2π units.

The phase shift is found by setting 2x + π = 0, leading to a shift of -π/2.

Step 1: Use the distributive property: x^2 + 4x + x + 4. Step 2: Combine like terms: x^2 + 5x + 4.

Step 1: Use the distributive property: x^2 - 3x + 2x - 6 = x^2 - x - 6.

The product of the roots of a quadratic equation ax^2 + bx + c = 0 is given by c/a. Here, 2/1 = 2.

The product of the roots is given by c/a. Here, c = 3, so the product is 3.

Step 1: Use the formula c/a. Here, c = 2 and a = 1, so the product is 2/1 = 2.

Step 1: Use the product of roots formula c/a. Here, c = 6, a = 1. Step 2: Product = 6/1 = 6.

Step 1: Use the formula c/a. Step 2: Here, c = 8 and a = 1. Step 3: Product of roots = 8.

The area of a circle is A = πr². Setting 100π = πr² gives r² = 100, thus r = 10 cm.

Area = πr², so r² = 36, thus r = 6 cm.

Area = πr², so r = √(Area/π) = √(50.24/π) ≈ 5 cm.

Area = πr², so 50π = πr². Dividing both sides by π gives r² = 50, thus r = √50 = 5√2.

Area of a circle = πr². Thus, 154 = (22/7)r². Solving gives r² = 154 * 7 / 22 = 49, so r = 7 cm.

Area of a circle = πr². Setting 50π = πr² gives r² = 50, so r = √50 = 5√2, approximately 7.07 units.

The circumference C = 2πr. Thus, r = C/(2π) = 31.4/(2π) ≈ 5 cm.

Semi-perimeter s = (7 + 8 + 9)/2 = 12 cm. Area = √[s(s-a)(s-b)(s-c)] = √[12(12-7)(12-8)(12-9)] = √[12*5*4*3] = 12√5 cm². Radius = Area/s = 12√5/12 = √5 cm.

Area = πr², so r = √(Area/π) = √(113.04/π) ≈ 6 cm.

Area = πr², so r² = 50, r = √50 = 7.07 cm.

The formula for circumference is C = 2πr. Solving for r gives r = C/(2π) = 31.4/(2π) = 5 units.

The standard form of a circle is (x - h)² + (y - k)² = r². Here, r² = 16, so r = √16 = 4.

Radius = √25 = 5.

The standard form of a circle is (x - h)² + (y - k)² = r². Here, r² = 25, so r = √25 = 5.

The standard form of a circle is (x - h)² + (y - k)² = r². Here, r² = 36, so r = √36 = 6.

Range = max - min = 30 - 10 = 20