Q. If the mass of the Earth is 6 × 10^24 kg and its radius is 6.4 × 10^6 m, what is the acceleration due to gravity at its surface?
A.
9.8 m/s²
B.
10 m/s²
C.
9.81 m/s²
D.
8.9 m/s²
Show solution
Solution
g = G * M / R² = (6.67 × 10^-11) * (6 × 10^24) / (6.4 × 10^6)² = 9.81 m/s²
Correct Answer:
C
— 9.81 m/s²
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Q. If the mass of the Earth is M and its radius is R, what is the gravitational acceleration at the surface of the Earth?
A.
g = GM/R^2
B.
g = GMR^2
C.
g = G/MR^2
D.
g = MR/G
Show solution
Solution
The gravitational acceleration at the surface of the Earth is given by g = GM/R^2.
Correct Answer:
A
— g = GM/R^2
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Q. If the mass of the Earth is M and the radius is R, what is the gravitational acceleration at the surface of the Earth?
A.
g = GM/R^2
B.
g = GMR^2
C.
g = G/R
D.
g = M/R^2
Show solution
Solution
The gravitational acceleration at the surface of the Earth is given by g = GM/R^2.
Correct Answer:
A
— g = GM/R^2
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Q. If the mass of the Earth is M and the radius is R, what is the gravitational force acting on a satellite of mass m at a height h?
A.
GmM/R^2
B.
GmM/(R+h)^2
C.
GmM/(R-h)^2
D.
GmM/h^2
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Solution
The gravitational force F acting on a satellite at height h is given by F = GmM/(R+h)^2, where G is the gravitational constant.
Correct Answer:
B
— GmM/(R+h)^2
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Q. If the mass of the Earth were to double while its radius remained the same, what would happen to the gravitational acceleration at its surface?
A.
It would double
B.
It would remain the same
C.
It would halve
D.
It would increase by a factor of four
Show solution
Solution
Gravitational acceleration is directly proportional to mass, so if the mass doubles, g also doubles.
Correct Answer:
A
— It would double
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Q. If the mass of the Earth were to double while its radius remains the same, what would happen to the gravitational acceleration at its surface?
A.
It would double
B.
It would remain the same
C.
It would halve
D.
It would increase by a factor of four
Show solution
Solution
Gravitational acceleration is directly proportional to mass; thus, if the mass doubles, g also doubles.
Correct Answer:
A
— It would double
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Q. If the mass of the Earth were to double while the radius remains the same, what would happen to the weight of an object on its surface?
A.
It would double
B.
It would remain the same
C.
It would increase by a factor of four
D.
It would decrease by half
Show solution
Solution
Weight is proportional to mass; thus, if the Earth's mass doubles, the weight of an object on its surface also doubles.
Correct Answer:
A
— It would double
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Q. If the mass of the Earth were to double, what would happen to the gravitational force between two objects on its surface?
A.
It would double
B.
It would remain the same
C.
It would be halved
D.
It would quadruple
Show solution
Solution
F = G * (m1 * m2) / r², doubling the mass of Earth doubles the force.
Correct Answer:
A
— It would double
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Q. If the mass of the Earth were to double, what would happen to the gravitational force it exerts on an object at its surface?
A.
It would double
B.
It would remain the same
C.
It would increase by a factor of four
D.
It would decrease by half
Show solution
Solution
If the mass of the Earth doubles, the gravitational force on an object at its surface would also double.
Correct Answer:
A
— It would double
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Q. If the mass of the Earth were to double, what would happen to the gravitational force between the Earth and an object on its surface?
A.
It would double
B.
It would remain the same
C.
It would halve
D.
It would quadruple
Show solution
Solution
F ∝ M; if M doubles, F also doubles.
Correct Answer:
A
— It would double
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Q. If the mass of the Earth were to double, what would happen to the weight of an object on its surface?
A.
It would double
B.
It would remain the same
C.
It would be halved
D.
It would be quartered
Show solution
Solution
Weight is directly proportional to mass. If the Earth's mass doubles, the weight of the object also doubles.
Correct Answer:
A
— It would double
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Q. If the mass of the Earth were to increase while the radius remains constant, what would happen to the gravitational force experienced by an object on its surface?
A.
It would decrease
B.
It would increase
C.
It would remain the same
D.
It would become zero
Show solution
Solution
If the mass of the Earth increases, the gravitational force experienced by an object on its surface would increase.
Correct Answer:
B
— It would increase
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Q. If the measured length of a rod is 20 cm with an error of 0.5 cm, what is the relative error in the measurement?
A.
0.025
B.
0.05
C.
0.0025
D.
0.005
Show solution
Solution
Relative error = (Absolute error / Measured value) = 0.5 / 20 = 0.025 or 2.5%
Correct Answer:
B
— 0.05
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Q. If the measured value of a quantity is 100 with a relative error of 0.02, what is the absolute error?
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Solution
Absolute error = Relative error * Measured value = 0.02 * 100 = 2.
Correct Answer:
A
— 2
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Q. If the measured value of a quantity is 75 with a relative error of 0.04, what is the true value?
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Solution
Relative error = Absolute error / True value. Let true value be x. 0.04 = |75 - x| / x. Solving gives x = 78.
Correct Answer:
B
— 78
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Q. If the molar mass of a gas is doubled, how does its RMS speed change?
A.
Increases by sqrt(2)
B.
Decreases by sqrt(2)
C.
Remains the same
D.
Increases by 2
Show solution
Solution
RMS speed is inversely proportional to the square root of molar mass, so if M is doubled, v_rms decreases by sqrt(2).
Correct Answer:
B
— Decreases by sqrt(2)
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Q. If the molar mass of a gas is doubled, how does the RMS speed change?
A.
Increases by sqrt(2)
B.
Decreases by sqrt(2)
C.
Remains the same
D.
Increases by 2
Show solution
Solution
The RMS speed is inversely proportional to the square root of the molar mass. If M is doubled, v_rms decreases by sqrt(2).
Correct Answer:
B
— Decreases by sqrt(2)
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Q. If the molar mass of a gas is halved, what happens to its RMS speed?
A.
Increases by a factor of sqrt(2)
B.
Increases by a factor of 2
C.
Decreases by a factor of sqrt(2)
D.
Remains the same
Show solution
Solution
If the molar mass is halved, the RMS speed increases by a factor of sqrt(2) because RMS speed is inversely proportional to the square root of molar mass.
Correct Answer:
A
— Increases by a factor of sqrt(2)
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Q. If the moment of inertia of a body is 10 kg m², what is the angular momentum when it rotates with an angular velocity of 5 rad/s?
A.
50 kg m²/s
B.
10 kg m²/s
C.
5 kg m²/s
D.
2 kg m²/s
Show solution
Solution
Angular momentum L = Iω = 10 kg m² * 5 rad/s = 50 kg m²/s.
Correct Answer:
A
— 50 kg m²/s
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Q. If the moment of inertia of a body is 10 kg m², what is the rotational kinetic energy when it rotates with an angular velocity of 5 rad/s?
A.
125 J
B.
50 J
C.
100 J
D.
75 J
Show solution
Solution
Rotational kinetic energy is given by KE = 1/2 I ω² = 1/2 * 10 * 5² = 125 J.
Correct Answer:
A
— 125 J
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Q. If the moment of inertia of a body is 10 kg·m² and it is subjected to a torque of 20 N·m, what is the angular acceleration?
A.
2 rad/s²
B.
0.5 rad/s²
C.
5 rad/s²
D.
10 rad/s²
Show solution
Solution
Using τ = Iα, we have α = τ/I = 20 N·m / 10 kg·m² = 2 rad/s².
Correct Answer:
A
— 2 rad/s²
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Q. If the moment of inertia of a body is doubled, what happens to its rotational kinetic energy if the angular velocity remains constant?
A.
Doubles
B.
Halves
C.
Remains the same
D.
Quadruples
Show solution
Solution
Rotational kinetic energy is given by KE = 1/2 I ω^2. If I is doubled and ω remains constant, KE also doubles.
Correct Answer:
A
— Doubles
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Q. If the moment of inertia of a body is doubled, what will be the effect on its angular acceleration if the torque applied remains constant?
A.
Doubles
B.
Halves
C.
Remains the same
D.
Increases by a factor of four
Show solution
Solution
Angular acceleration α = τ/I. If I is doubled and τ remains constant, α is halved.
Correct Answer:
B
— Halves
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Q. If the moment of inertia of a body is doubled, what will happen to its angular momentum if the angular velocity remains constant?
A.
Doubles
B.
Halves
C.
Remains the same
D.
Quadruples
Show solution
Solution
Angular momentum L = Iω; if I is doubled and ω remains constant, L also doubles.
Correct Answer:
A
— Doubles
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Q. If the moment of inertia of a body is increased, what happens to its angular acceleration for a constant torque?
A.
Increases
B.
Decreases
C.
Remains the same
D.
Becomes zero
Show solution
Solution
According to Newton's second law for rotation, τ = Iα, if I increases and τ is constant, α must decrease.
Correct Answer:
B
— Decreases
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Q. If the natural frequency of a damped oscillator is 5 rad/s and the damping ratio is 0.2, what is the damped frequency?
A.
4.8 rad/s
B.
5 rad/s
C.
5.2 rad/s
D.
5.5 rad/s
Show solution
Solution
Damped frequency (ω_d) = ω_n√(1-ζ^2) = 5√(1-0.2^2) = 5√(0.96) ≈ 4.8 rad/s.
Correct Answer:
A
— 4.8 rad/s
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Q. If the object distance is equal to the focal length of a convex lens, what is the nature of the image formed?
A.
Real and inverted
B.
Virtual and upright
C.
At infinity
D.
No image formed
Show solution
Solution
When the object distance equals the focal length, the image is formed at infinity.
Correct Answer:
C
— At infinity
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Q. If the object distance is equal to the focal length of a convex lens, what type of image is formed?
A.
Real and inverted
B.
Virtual and upright
C.
At infinity
D.
No image formed
Show solution
Solution
When the object is at the focal length, the image is formed at infinity.
Correct Answer:
C
— At infinity
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Q. If the peak current in an AC circuit is 5 A, what is the average current over one complete cycle?
A.
5 A
B.
2.5 A
C.
0 A
D.
7.07 A
Show solution
Solution
The average current over one complete cycle is I_avg = I_peak/√2 = 5/√2 = 2.5 A.
Correct Answer:
B
— 2.5 A
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Q. If the peak voltage of an AC source is 200 V, what is the RMS voltage?
A.
100 V
B.
141.42 V
C.
200 V
D.
282.84 V
Show solution
Solution
The RMS voltage (V_rms) is given by V_rms = V_peak / √2. Therefore, V_rms = 200 V / √2 = 141.42 V.
Correct Answer:
B
— 141.42 V
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Physics Syllabus (JEE Main) MCQ & Objective Questions
The Physics Syllabus for JEE Main is crucial for students aiming to excel in their exams. Understanding this syllabus not only helps in grasping fundamental concepts but also enhances problem-solving skills through practice. Engaging with MCQs and objective questions is essential for effective exam preparation, as it allows students to identify important questions and strengthen their knowledge base.
What You Will Practise Here
Mechanics: Laws of Motion, Work, Energy, and Power
Thermodynamics: Laws of Thermodynamics, Heat Transfer
Waves and Oscillations: Simple Harmonic Motion, Wave Properties
Electromagnetism: Electric Fields, Magnetic Fields, and Circuits
Optics: Reflection, Refraction, and Optical Instruments
Modern Physics: Quantum Theory, Atomic Models, and Nuclear Physics
Fluid Mechanics: Properties of Fluids, Bernoulli's Principle
Exam Relevance
The Physics Syllabus (JEE Main) is integral to various examinations, including CBSE, State Boards, and competitive exams like NEET and JEE. Questions often focus on conceptual understanding and application of theories. Common patterns include numerical problems, conceptual MCQs, and assertion-reason type questions, which test both knowledge and analytical skills.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers.
Neglecting units and dimensions in calculations.
Overlooking the significance of diagrams in understanding concepts.
Confusing similar concepts, such as velocity and acceleration.
Failing to apply formulas correctly in different contexts.
FAQs
Question: What are the key topics in the Physics Syllabus for JEE Main?Answer: Key topics include Mechanics, Thermodynamics, Waves, Electromagnetism, Optics, Modern Physics, and Fluid Mechanics.
Question: How can I improve my performance in Physics MCQs?Answer: Regular practice of MCQs, understanding concepts deeply, and revising important formulas can significantly enhance your performance.
Start solving practice MCQs today to test your understanding of the Physics Syllabus (JEE Main). This will not only boost your confidence but also prepare you effectively for your upcoming exams. Remember, consistent practice is the key to success!
