Engineering & Architecture Admissions MCQ & Objective Questions
Engineering & Architecture Admissions play a crucial role in shaping the future of aspiring students in India. With the increasing competition in entrance exams, mastering MCQs and objective questions is essential for effective exam preparation. Practicing these types of questions not only enhances concept clarity but also boosts confidence, helping students score better in their exams.
What You Will Practise Here
Key concepts in Engineering Mathematics
Fundamentals of Physics relevant to architecture and engineering
Important definitions and terminologies in engineering disciplines
Essential formulas for solving objective questions
Diagrams and illustrations for better understanding
Conceptual theories related to structural engineering
Analysis of previous years' important questions
Exam Relevance
The topics covered under Engineering & Architecture Admissions are highly relevant for various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter MCQs that test their understanding of core concepts, application of formulas, and analytical skills. Common question patterns include multiple-choice questions that require selecting the correct answer from given options, as well as assertion-reason type questions that assess deeper comprehension.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers.
Overlooking units in numerical problems, which can change the outcome.
Confusing similar concepts or terms, especially in definitions.
Neglecting to review diagrams, which are often crucial for solving problems.
Rushing through practice questions without understanding the underlying concepts.
FAQs
Question: What are the best ways to prepare for Engineering & Architecture Admissions MCQs?Answer: Regular practice of objective questions, reviewing key concepts, and taking mock tests can significantly enhance your preparation.
Question: How can I improve my accuracy in solving MCQs?Answer: Focus on understanding the concepts thoroughly, practice regularly, and learn to eliminate incorrect options to improve accuracy.
Start your journey towards success by solving practice MCQs today! Test your understanding and strengthen your knowledge in Engineering & Architecture Admissions to excel in your exams.
Q. A 5 kg object is at rest on a surface. If a horizontal force of 15 N is applied, what is the object's acceleration? (Assume friction is negligible)
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Using F = ma, a = F/m = 15 N / 5 kg = 3 m/s².
Correct Answer:
B
— 3 m/s²
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Q. A 5 kg object is dropped from a height of 10 m. What is the total mechanical energy just before it hits the ground?
A.
0 J
B.
50 J
C.
100 J
D.
200 J
Show solution
Solution
Total mechanical energy is conserved. At height, PE = mgh = 5 * 9.8 * 10 = 490 J. Just before hitting the ground, total energy = 490 J.
Correct Answer:
C
— 100 J
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Q. A 5 kg object is dropped from a height of 20 m. What is the potential energy at the top? (g = 9.8 m/s²)
A.
980 J
B.
490 J
C.
196 J
D.
9800 J
Show solution
Solution
Potential energy is given by PE = mgh. Here, PE = 5 * 9.8 * 20 = 980 J.
Correct Answer:
A
— 980 J
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Q. A 5 kg object is dropped from a height of 20 m. What is the total mechanical energy just before it hits the ground?
A.
0 J
B.
100 J
C.
200 J
D.
500 J
Show solution
Solution
Total mechanical energy is conserved. At height, PE = mgh = 5 * 9.8 * 20 = 980 J. Just before hitting the ground, total energy = 980 J.
Correct Answer:
C
— 200 J
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Q. A 5 kg object is dropped from a height. What is the force acting on it just before it hits the ground?
A.
5 N
B.
10 N
C.
15 N
D.
20 N
Show solution
Solution
The only force acting on it is its weight, W = mg = 5 kg * 10 m/s² = 50 N.
Correct Answer:
B
— 10 N
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Q. A 5 kg object is dropped from a height. What is the force acting on it just before it hits the ground? (Assume g = 9.8 m/s²)
A.
5 N
B.
9.8 N
C.
49 N
D.
0 N
Show solution
Solution
The force acting on the object is its weight, F = mg = 5 kg * 9.8 m/s² = 49 N.
Correct Answer:
C
— 49 N
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Q. A 5 kg object is lifted to a height of 10 m. What is the gravitational potential energy gained?
A.
50 J
B.
100 J
C.
200 J
D.
500 J
Show solution
Solution
Potential Energy (PE) = m * g * h = 5 kg * 10 m/s^2 * 10 m = 500 J
Correct Answer:
B
— 100 J
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Q. A 5 kg object is lifted to a height of 10 m. What is the potential energy gained?
A.
50 J
B.
100 J
C.
200 J
D.
500 J
Show solution
Solution
Potential Energy (PE) = m * g * h = 5 kg * 9.8 m/s^2 * 10 m = 490 J (approx. 500 J)
Correct Answer:
B
— 100 J
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Q. A 5 kg object is lifted to a height of 10 m. What is the potential energy gained by the object?
A.
50 J
B.
100 J
C.
150 J
D.
200 J
Show solution
Solution
Potential energy (PE) = mgh = 5 kg * 9.8 m/s² * 10 m = 490 J.
Correct Answer:
B
— 100 J
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Q. A 5 kg object is lifted to a height of 10 m. What is the work done against gravity?
A.
50 J
B.
100 J
C.
150 J
D.
200 J
Show solution
Solution
Work done against gravity is W = mgh = 5 * 9.8 * 10 = 490 J.
Correct Answer:
D
— 200 J
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Q. A 5 kg object is lifted to a height of 3 m. What is the work done against gravity?
A.
15 J
B.
30 J
C.
45 J
D.
60 J
Show solution
Solution
Work done against gravity is W = mgh = 5 * 9.8 * 3 = 147 J.
Correct Answer:
B
— 30 J
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Q. A 5 kg object is moving with a velocity of 10 m/s. What is its kinetic energy?
A.
25 J
B.
50 J
C.
100 J
D.
250 J
Show solution
Solution
Kinetic energy (KE) = 0.5 * mass * velocity² = 0.5 * 5 * (10)² = 250 J.
Correct Answer:
C
— 100 J
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Q. A 5 kg object is moving with a velocity of 3 m/s. What is its kinetic energy?
A.
22.5 J
B.
30 J
C.
45 J
D.
60 J
Show solution
Solution
Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 5 kg × (3 m/s)² = 22.5 J.
Correct Answer:
A
— 22.5 J
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Q. A 5 kg object is pulled with a force of 25 N. What is the acceleration of the object?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Using F = ma, acceleration a = F/m = 25 N / 5 kg = 5 m/s².
Correct Answer:
C
— 4 m/s²
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Q. A 5 kg object is pushed with a force of 15 N. If the frictional force is 5 N, what is the acceleration of the object?
A.
1 m/s²
B.
2 m/s²
C.
3 m/s²
D.
4 m/s²
Show solution
Solution
Net force = applied force - friction = 15 N - 5 N = 10 N. Acceleration = F/m = 10 N / 5 kg = 2 m/s².
Correct Answer:
B
— 2 m/s²
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Q. A 5 kg object is subjected to a net force of 15 N. What is its acceleration?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Using F = ma, a = F/m = 15 N / 5 kg = 3 m/s².
Correct Answer:
B
— 3 m/s²
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Q. A 5 kg object is subjected to a net force of 15 N. What is the object's acceleration?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Using F = ma, a = F/m = 15 N / 5 kg = 3 m/s².
Correct Answer:
B
— 3 m/s²
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Q. A 5 kg object is subjected to a net force of 25 N. What is its acceleration?
A.
2 m/s²
B.
5 m/s²
C.
10 m/s²
D.
15 m/s²
Show solution
Solution
Using F = ma, a = F/m = 25 N / 5 kg = 5 m/s².
Correct Answer:
C
— 10 m/s²
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Q. A 5 kg object is thrown vertically upward with a speed of 20 m/s. What is the maximum height reached by the object? (g = 10 m/s²)
A.
20 m
B.
30 m
C.
40 m
D.
50 m
Show solution
Solution
Using the formula h = v²/(2g) = (20 m/s)² / (2 * 10 m/s²) = 20 m.
Correct Answer:
B
— 30 m
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Q. A 5 ohm resistor and a 10 ohm resistor are connected in series. What is the total resistance?
A.
15 ohms
B.
5 ohms
C.
10 ohms
D.
2 ohms
Show solution
Solution
In series, the total resistance is R_total = R1 + R2 = 5 + 10 = 15 ohms.
Correct Answer:
A
— 15 ohms
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Q. A 50 kg crate is at rest on a flat surface. What is the normal force acting on the crate?
A.
0 N
B.
50 N
C.
500 N
D.
1000 N
Show solution
Solution
The normal force equals the weight of the crate, which is N = mg = 50 kg * 10 m/s² = 500 N.
Correct Answer:
C
— 500 N
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Q. A 50 kg object is at rest on a surface. What is the normal force acting on it?
A.
0 N
B.
50 N
C.
100 N
D.
500 N
Show solution
Solution
The normal force equals the weight of the object, which is F = mg = 50 kg * 9.8 m/s² = 490 N.
Correct Answer:
C
— 100 N
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Q. A 50 kg object is in free fall. What is the net force acting on it?
A.
50 N
B.
100 N
C.
200 N
D.
500 N
Show solution
Solution
The net force is equal to the weight of the object, F = mg = 50 kg * 9.8 m/s² = 490 N (approximately 500 N).
Correct Answer:
B
— 100 N
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Q. A 50 kg object is moving with a constant velocity. What can be said about the net force acting on it?
A.
It is zero
B.
It is equal to its weight
C.
It is equal to the applied force
D.
It is maximum
Show solution
Solution
If the object is moving with constant velocity, the net force acting on it is zero.
Correct Answer:
A
— It is zero
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Q. A 50 kg object is moving with a velocity of 10 m/s. What is its momentum?
A.
500 kg m/s
B.
1000 kg m/s
C.
1500 kg m/s
D.
2000 kg m/s
Show solution
Solution
Momentum = mass × velocity = 50 kg × 10 m/s = 500 kg m/s.
Correct Answer:
B
— 1000 kg m/s
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Q. A 50 kg object is pulled with a force of 200 N. What is the acceleration of the object?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Using F = ma, we have a = F/m = 200 N / 50 kg = 4 m/s².
Correct Answer:
D
— 5 m/s²
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Q. A 50 kg object is pushed with a force of 200 N over a distance of 10 m. What is the work done? (2000)
A.
2000 J
B.
1000 J
C.
500 J
D.
3000 J
Show solution
Solution
Work Done = Force * Distance = 200 N * 10 m = 2000 J
Correct Answer:
A
— 2000 J
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Q. A 50 kg person jumps off a diving board with a speed of 5 m/s. What is the momentum of the person just before hitting the water?
A.
100 kg·m/s
B.
200 kg·m/s
C.
250 kg·m/s
D.
300 kg·m/s
Show solution
Solution
Momentum p = mv = 50 kg * 5 m/s = 250 kg·m/s.
Correct Answer:
A
— 100 kg·m/s
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Q. A 500 g block of ice at -10°C is heated until it melts completely and the water is at 0°C. How much heat is required? (Specific heat of ice = 2.1 J/g°C, Latent heat of fusion = 334 J/g) (2000)
A.
1050 J
B.
1340 J
C.
1500 J
D.
2000 J
Show solution
Solution
Heat to raise ice to 0°C = 500g * 2.1 J/g°C * 10°C = 10500 J. Heat to melt = 500g * 334 J/g = 167000 J. Total = 1050 J + 167000 J = 1340 J.
Correct Answer:
B
— 1340 J
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Q. A 6 kg object is at rest on a horizontal surface. If a horizontal force of 12 N is applied, what is the acceleration assuming no friction?
A.
1 m/s²
B.
2 m/s²
C.
3 m/s²
D.
4 m/s²
Show solution
Solution
Using F = ma, acceleration a = F/m = 12 N / 6 kg = 2 m/s².
Correct Answer:
B
— 2 m/s²
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