Electrostatics & Circuits MCQ & Objective Questions
Understanding "Electrostatics & Circuits" is crucial for students preparing for school and competitive exams in India. This topic not only forms a significant part of the syllabus but also features prominently in various objective questions and MCQs. By practicing these questions, students can enhance their grasp of concepts and improve their chances of scoring better in exams.
What You Will Practise Here
Fundamental concepts of electrostatics, including charge, electric field, and potential.
Key formulas related to Coulomb's law and electric field strength.
Understanding of capacitors, their types, and applications in circuits.
Basic circuit theory, including Ohm's law and Kirchhoff's laws.
Analysis of series and parallel circuits with practical examples.
Diagrams illustrating electric field lines and circuit schematics.
Problem-solving strategies for common electrostatics and circuit-related questions.
Exam Relevance
The topics of Electrostatics and Circuits are integral to the curriculum of CBSE, State Boards, NEET, and JEE. Students can expect questions that test their understanding of theoretical concepts as well as practical applications. Common question patterns include numerical problems, conceptual MCQs, and diagram-based questions that require a clear understanding of the subject matter.
Common Mistakes Students Make
Confusing the concepts of electric field and electric potential.
Misapplying Ohm's law in complex circuits.
Overlooking the significance of units in calculations.
Failing to interpret circuit diagrams accurately.
Neglecting to review the properties of capacitors and their behavior in circuits.
FAQs
Question: What are the key formulas I should remember for Electrostatics?Answer: Important formulas include Coulomb's law (F = k * |q1 * q2| / r²) and the formula for electric field (E = F/q).
Question: How can I improve my performance in circuit-related MCQs?Answer: Practice solving circuit problems regularly and familiarize yourself with different circuit configurations.
Question: Are there any specific topics I should focus on for competitive exams?Answer: Focus on understanding capacitors, circuit laws, and the relationship between voltage, current, and resistance.
Now is the time to boost your exam preparation! Dive into our practice MCQs on Electrostatics & Circuits and test your understanding to achieve your academic goals.
Q. What is the equivalent capacitance of two capacitors, 4 µF and 6 µF, connected in series?
A.
2.4 µF
B.
10 µF
C.
1.5 µF
D.
3.6 µF
Show solution
Solution
1/C_eq = 1/C1 + 1/C2 = 1/4 + 1/6 => C_eq = 2.4 µF.
Correct Answer:
A
— 2.4 µF
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Q. What is the equivalent capacitance of two capacitors, 4 µF and 6 µF, in series?
A.
2.4 µF
B.
10 µF
C.
1.5 µF
D.
3.6 µF
Show solution
Solution
1/C_total = 1/C1 + 1/C2 = 1/4 + 1/6 = 5/12, thus C_total = 12/5 = 2.4 µF.
Correct Answer:
A
— 2.4 µF
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Q. What is the equivalent capacitance of two capacitors, C1 = 4μF and C2 = 6μF, connected in series?
A.
2.4μF
B.
3.6μF
C.
10μF
D.
24μF
Show solution
Solution
For capacitors in series, 1/C_eq = 1/C1 + 1/C2 => C_eq = 2.4μF.
Correct Answer:
A
— 2.4μF
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Q. What is the equivalent resistance (R_eq) of two resistors (R1 and R2) in series?
A.
R_eq = R1 + R2
B.
R_eq = R1 * R2
C.
R_eq = R1 / R2
D.
R_eq = R1 - R2
Show solution
Solution
The equivalent resistance of two resistors in series is R_eq = R1 + R2.
Correct Answer:
A
— R_eq = R1 + R2
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Q. What is the equivalent resistance (R_eq) of two resistors R1 and R2 in parallel?
A.
1/R_eq = 1/R1 + 1/R2
B.
R_eq = R1 + R2
C.
R_eq = R1 * R2
D.
R_eq = R1 - R2
Show solution
Solution
For resistors in parallel, the equivalent resistance is given by 1/R_eq = 1/R1 + 1/R2.
Correct Answer:
A
— 1/R_eq = 1/R1 + 1/R2
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Q. What is the equivalent resistance of three 4 Ω resistors in series?
A.
12 Ω
B.
8 Ω
C.
16 Ω
D.
4 Ω
Show solution
Solution
R_eq = R1 + R2 + R3 = 4 Ω + 4 Ω + 4 Ω = 12 Ω.
Correct Answer:
A
— 12 Ω
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Q. What is the equivalent resistance of three resistors of 2 Ω, 3 Ω, and 5 Ω connected in series?
A.
10 Ω
B.
5 Ω
C.
8 Ω
D.
12 Ω
Show solution
Solution
R_total = R1 + R2 + R3 = 2 Ω + 3 Ω + 5 Ω = 10 Ω.
Correct Answer:
A
— 10 Ω
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Q. What is the equivalent resistance of three resistors of 2 Ω, 3 Ω, and 5 Ω in series?
A.
10 Ω
B.
8 Ω
C.
5 Ω
D.
3 Ω
Show solution
Solution
R_eq = R1 + R2 + R3 = 2 Ω + 3 Ω + 5 Ω = 10 Ω.
Correct Answer:
A
— 10 Ω
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Q. What is the equivalent resistance of three resistors of 2 Ω, 3 Ω, and 6 Ω in series?
A.
11 Ω
B.
10 Ω
C.
9 Ω
D.
8 Ω
Show solution
Solution
R_eq = R1 + R2 + R3 = 2 Ω + 3 Ω + 6 Ω = 11 Ω.
Correct Answer:
A
— 11 Ω
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Q. What is the equivalent resistance of three resistors of 4 ohms, 6 ohms, and 12 ohms connected in series?
A.
22 ohms
B.
12 ohms
C.
10 ohms
D.
8 ohms
Show solution
Solution
In series, R_eq = R1 + R2 + R3 = 4Ω + 6Ω + 12Ω = 22Ω.
Correct Answer:
A
— 22 ohms
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Q. What is the equivalent resistance of three resistors of 4 Ω, 6 Ω, and 12 Ω connected in series?
A.
22 Ω
B.
18 Ω
C.
16 Ω
D.
14 Ω
Show solution
Solution
Equivalent resistance R_eq = R₁ + R₂ + R₃ = 4 Ω + 6 Ω + 12 Ω = 22 Ω.
Correct Answer:
A
— 22 Ω
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Q. What is the equivalent resistance of three resistors of 4 Ω, 6 Ω, and 12 Ω in series?
A.
22 Ω
B.
18 Ω
C.
16 Ω
D.
12 Ω
Show solution
Solution
In series, R_eq = R1 + R2 + R3 = 4 Ω + 6 Ω + 12 Ω = 22 Ω.
Correct Answer:
A
— 22 Ω
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Q. What is the equivalent resistance of three resistors, 2Ω, 3Ω, and 6Ω, connected in parallel?
A.
1Ω
B.
0.5Ω
C.
1.5Ω
D.
2.5Ω
Show solution
Solution
1/R_total = 1/R1 + 1/R2 + 1/R3 = 1/2 + 1/3 + 1/6. R_total = 1.5Ω.
Correct Answer:
C
— 1.5Ω
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Q. What is the equivalent resistance of two resistors, 4 Ω and 6 Ω, connected in parallel?
A.
2.4 Ω
B.
10 Ω
C.
24 Ω
D.
1.5 Ω
Show solution
Solution
1/R_total = 1/R1 + 1/R2 = 1/4 + 1/6 = 5/12, thus R_total = 12/5 Ω = 2.4 Ω.
Correct Answer:
A
— 2.4 Ω
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Q. What is the equivalent resistance of two resistors, R1 = 6Ω and R2 = 3Ω, connected in parallel?
A.
2Ω
B.
9Ω
C.
18Ω
D.
1.5Ω
Show solution
Solution
In parallel, the equivalent resistance is given by 1/R_eq = 1/R1 + 1/R2, so 1/R_eq = 1/6 + 1/3 = 1/2, thus R_eq = 2Ω.
Correct Answer:
A
— 2Ω
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Q. What is the equivalent resistance of two resistors, R1 = 6Ω and R2 = 3Ω, connected in series?
Show solution
Solution
In series, the equivalent resistance is R_eq = R1 + R2 = 6Ω + 3Ω = 9Ω.
Correct Answer:
C
— 9Ω
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Q. What is the expression for the capacitive reactance (Xc) in terms of frequency (f) and capacitance (C)?
A.
Xc = 1/(2πfC)
B.
Xc = 2πfC
C.
Xc = 1/(fC)
D.
Xc = 2πf/C
Show solution
Solution
The capacitive reactance is given by Xc = 1/(2πfC), where f is the frequency and C is the capacitance.
Correct Answer:
A
— Xc = 1/(2πfC)
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Q. What is the expression for the total current (I) in a parallel circuit with two resistors (R1 and R2)?
A.
I = I1 + I2
B.
I = I1 * I2
C.
I = I1 / I2
D.
I = I1 - I2
Show solution
Solution
In a parallel circuit, the total current is the sum of the currents through each resistor: I = I1 + I2.
Correct Answer:
A
— I = I1 + I2
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Q. What is the expression for the total energy stored in a capacitor (U) in terms of capacitance (C) and voltage (V)?
A.
U = 1/2 * C * V^2
B.
U = C * V^2
C.
U = V / (2 * C)
D.
U = C * V
Show solution
Solution
The total energy stored in a capacitor is given by U = 1/2 * C * V^2.
Correct Answer:
A
— U = 1/2 * C * V^2
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Q. What is the final charge (Q) on a capacitor in an RC circuit when a voltage (V) is applied?
A.
Q = CV
B.
Q = V/R
C.
Q = V^2/R
D.
Q = I * t
Show solution
Solution
The final charge on a capacitor when a voltage V is applied is given by Q = CV, where C is the capacitance.
Correct Answer:
A
— Q = CV
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Q. What is the final charge on a capacitor (Q) in an RC circuit after a long time if the voltage across it is 5V and the capacitance is 200 microfarads?
A.
0.001 C
B.
0.01 C
C.
0.0001 C
D.
0.1 C
Show solution
Solution
The charge Q is given by Q = C * V = 200 x 10^-6 F * 5 V = 0.001 C.
Correct Answer:
A
— 0.001 C
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Q. What is the final voltage across a capacitor after it has been fully charged in an RC circuit?
A.
0V
B.
V0
C.
V0/2
D.
V0/e
Show solution
Solution
The final voltage across a capacitor after it has been fully charged in an RC circuit is V0, where V0 is the supply voltage.
Correct Answer:
B
— V0
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Q. What is the final voltage across a capacitor in a series RC circuit after a long time?
A.
0V
B.
V0
C.
V0/2
D.
V0/e
Show solution
Solution
The final voltage across a capacitor in a series RC circuit after a long time is V0, where V0 is the supply voltage.
Correct Answer:
B
— V0
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Q. What is the final voltage across the capacitor in a charging RC circuit if the applied voltage is 12V?
A.
0V
B.
6V
C.
12V
D.
24V
Show solution
Solution
The final voltage across the capacitor in a charging RC circuit will equal the applied voltage, which is 12V.
Correct Answer:
C
— 12V
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Q. What is the force between two charges of +1 µC and +1 µC separated by 0.1 m?
A.
0.09 N
B.
0.18 N
C.
0.02 N
D.
0.04 N
Show solution
Solution
F = k * |q1 * q2| / r² = (8.99 x 10^9 N m²/C²) * (1 x 10^-6 C)² / (0.1 m)² = 0.09 N.
Correct Answer:
B
— 0.18 N
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Q. What is the force between two charges of +1 µC and +1 µC separated by 1 m?
A.
8.99 N
B.
0.009 N
C.
0.089 N
D.
0.899 N
Show solution
Solution
F = k * |q1 * q2| / r^2 = (8.99 x 10^9 N m²/C²) * (1 x 10^-6 C)² / (1 m)² = 8.99 N.
Correct Answer:
A
— 8.99 N
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Q. What is the force between two charges of +2 µC and -3 µC separated by a distance of 0.5 m?
A.
-1.08 N
B.
-0.72 N
C.
1.08 N
D.
0.72 N
Show solution
Solution
Using Coulomb's law: F = k * |q1 * q2| / r^2 = (8.99 x 10^9 N m²/C²) * |(2 x 10^-6 C) * (-3 x 10^-6 C)| / (0.5 m)^2 = -1.08 N.
Correct Answer:
A
— -1.08 N
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Q. What is the force between two charges of 1 microcoulomb each, separated by a distance of 0.5 meters?
A.
0.36 N
B.
0.72 N
C.
0.18 N
D.
0.09 N
Show solution
Solution
Using Coulomb's law, F = k * |q1 * q2| / r^2. Here, F = (8.99 x 10^9) * (1 x 10^-6)^2 / (0.5^2) = 0.36 N.
Correct Answer:
A
— 0.36 N
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Q. What is the force between two point charges of +2 µC and -3 µC separated by a distance of 0.5 m in a vacuum?
A.
-1.08 N
B.
-0.72 N
C.
1.08 N
D.
0.72 N
Show solution
Solution
Using Coulomb's law, F = k * |q1 * q2| / r^2 = (8.99 x 10^9 N m²/C²) * |(2 x 10^-6 C) * (-3 x 10^-6 C)| / (0.5 m)^2 = -1.08 N.
Correct Answer:
A
— -1.08 N
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Q. What is the force between two point charges of +2 µC and -3 µC separated by a distance of 0.5 m?
A.
1.2 N
B.
0.24 N
C.
0.48 N
D.
0.96 N
Show solution
Solution
Using Coulomb's law, F = k * |q1 * q2| / r^2 = (8.99 x 10^9 N m²/C²) * |(2 x 10^-6 C) * (-3 x 10^-6 C)| / (0.5 m)^2 = 0.24 N.
Correct Answer:
B
— 0.24 N
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