If all resistances are equal, the bridge is always balanced regardless of the values.

Doubling all resistance values does not affect the balance condition, as the ratios remain the same.

Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (15 * 5) / 10 = 7.5Ω.

Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (20 * 15) / 10 = 30Ω.

Using the formula R1/R2 = R3/R4, we find that R4 = (R2 * R3) / R1 = (20 * 30) / 10 = 60Ω.

Using the balance condition R1/R2 = R3/R4, we find R = (R2 * R3) / R1 = (8 * 12) / 4 = 24Ω.

Using the balance condition R1/R2 = R3/R4, we find R = (R2 * R3) / R1 = (15 * 10) / 5 = 30Ω.

If all resistances are equal, the bridge is balanced and the current through the galvanometer is zero.

If the resistances are equal, the potential difference across the galvanometer is zero.

For balance, P/Q = R/S => 10/15 = 5/x => x = 7.5Ω.

The bridge is not balanced because P/Q ≠ R/S.

The bridge is balanced if R1/R2 = R3/R4. Here, 10/15 = 5/7.5, which simplifies to 2/3 = 2/3, confirming the bridge is balanced.

Using the balance condition R1/R2 = R3/R4, we have 10/15 = 5/x, solving gives x = 7.5Ω.

Using the balance condition R1/R2 = R3/R4, we have 10/15 = 5/R4. Solving gives R4 = 7.5Ω.

Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (15 * 5) / 10 = 7.5Ω.

Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (20 * 15) / 10 = 30Ω.

Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (20 * 15) / 10 = 30Ω.

Using the balance condition R1/R2 = R3/R4, we have 20/30 = 10/x, solving gives x = 20Ω.

The condition for balance in a Wheatstone bridge is R1/R2 = R3/R4.

Resistance R = ρ(L/A) = (1.5 x 10^-8)(3)/(0.5 x 10^-6) = 0.09 Ω.

Resistance R = ρ * (L / A) = 2 x 10^-8 * (3 / 0.5 x 10^-6) = 0.12 Ω.

Resistance R is directly proportional to resistivity ρ, so if ρ is doubled, R also doubles.

Resistance R is directly proportional to resistivity; if resistivity doubles, resistance also doubles.

Resistance is directly proportional to resistivity; halving resistivity halves the resistance.

Resistance is directly proportional to resistivity; halving resistivity halves the resistance.

Resistance is directly proportional to resistivity; halving resistivity halves the resistance.

A superconductor has zero resistivity, which means it has zero resistance.

Resistance R = ρ * (L / A) = 1.68 x 10^-8 * (100 / (π * (0.5 x 10^-3)²)) = 0.168 Ω.

Increasing the supply voltage does not affect the balance condition; it remains dependent on the resistance ratios.

For most conductors, resistivity increases with temperature due to increased atomic vibrations.