The equivalent capacitance C_eq of capacitors in series is given by 1 / C_eq = 1 / C1 + 1 / C2.

Using Coulomb's law, F = k * |q1 * q2| / r² = (9 × 10^9 N m²/C²) * |(3 × 10^-6 C) * (5 × 10^-6 C)| / (0.3 m)² = 0.45 N.

The electric fields due to both charges at the midpoint cancel each other out, resulting in a net electric field of 0 N/C.

As the charges are brought closer, the potential energy of the system increases due to the repulsive force between like charges.

According to Coulomb's law, force is inversely proportional to the square of the distance. If the distance is doubled, the force becomes one-fourth.

The electric fields due to both charges at the midpoint cancel each other, resulting in a net electric field of 0.

The electric fields due to both charges at the midpoint cancel each other, resulting in a net electric field of 0 N/C.

Potential energy U = k * q1 * q2 / r = (9 × 10^9 N m²/C²) * (q²) / 1m. For q = 1μC, U = 1 J.

The electric potential energy increases as the charges are brought closer together if they are of the same sign.

Capacitance is directly proportional to the plate area A. Increasing A increases capacitance.

The dielectric constant represents the ability of a material to increase the capacitance of a capacitor compared to a vacuum.

The relationship is given by Q = C * V, where Q is the charge, C is the capacitance, and V is the voltage.

The time constant (τ) of an RC circuit is given by τ = R * C.

When a capacitor is fully charged, the voltage across it is equal to the voltage of the source it was connected to.

The total capacitance C_total in parallel is the sum of individual capacitances: C_total = C1 + C2 = 2μF + 3μF = 5μF.

In parallel, the total capacitance is the sum: C_total = C1 + C2 = 3μF + 6μF = 9μF.

For capacitors in parallel, the total capacitance is the sum of the individual capacitances: C_total = C1 + C2 = 4μF + 6μF = 10μF.

In a parallel combination, the total capacitance is simply the sum of the individual capacitances: C_eq = C1 + C2 + C3.

Capacitance is directly proportional to the area of the plates. Doubling the area will double the capacitance.

The electric potential V is directly proportional to the distance d between the plates, so if d is doubled, V also doubles.

Capacitance C = ε₀ * A / d. If d is halved, C doubles.

The electric flux Φ through a surface area A in a uniform electric field E is given by Φ = EA when the surface is perpendicular to the field.

The electric flux is maximum when the angle between the electric field and the normal to the surface is 0°, as Φ = E·A·cos(θ).

A plane is the simplest Gaussian surface for uniform electric fields, as it allows for straightforward calculation of flux.

In a uniform electric field, the electric potential changes linearly with distance.

Equipotential surfaces are always perpendicular to electric field lines.

In a uniform electric field, the equipotential surfaces are parallel planes.

The potential difference is directly proportional to both the distance between the points and the magnitude of the electric field.

In a uniform electric field, the potential difference (V) between two points separated by a distance (d) is given by V = E × d, where E is the electric field strength.

In a uniform electric field, the potential difference (V) between two points is given by V = Ed, where d is the distance between the points.