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Q. A 2 kg object is dropped from a height of 5 m. What is the potential energy at the height?

A. 10 J
B. 20 J
C. 30 J
D. 40 J

Solution

Potential energy = mgh = 2 kg × 9.8 m/s² × 5 m = 98 J.

Correct Answer: B — 20 J

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Q. A 2 kg object is dropped from a height of 5 m. What is the potential energy at the top?

A. 10 J
B. 20 J
C. 30 J
D. 40 J

Solution

Potential energy = mgh = 2 kg × 9.8 m/s² × 5 m = 98 J.

Correct Answer: B — 20 J

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Q. A 2 kg object is dropped from a height of 5 m. What is the work done by gravity on the object just before it hits the ground?

A. 10 J
B. 20 J
C. 30 J
D. 40 J

Solution

Work done by gravity = m × g × h = 2 kg × 9.8 m/s² × 5 m = 98 J.

Correct Answer: B — 20 J

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Q. A 2 kg object is dropped from a height. What is the force acting on it just before it hits the ground? (2022)

A. 2 N
B. 9.8 N
C. 19.6 N
D. 29.4 N

Solution

The force acting on the object is its weight, F = mg = 2 kg × 9.8 m/s² = 19.6 N.

Correct Answer: C — 19.6 N

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Q. A 2 kg object is heated from 20°C to 80°C. If the specific heat capacity is 0.5 kJ/kg°C, how much heat is absorbed? (2023)

A. 30 kJ
B. 40 kJ
C. 20 kJ
D. 10 kJ

Solution

Q = mcΔT = 2 kg * 0.5 kJ/kg°C * (80°C - 20°C) = 60 kJ.

Correct Answer: B — 40 kJ

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Q. A 2 kg object is heated from 20°C to 80°C. If the specific heat capacity is 0.5 J/g°C, how much heat is absorbed? (2019)

A. 60 kJ
B. 80 kJ
C. 100 kJ
D. 120 kJ

Solution

Heat absorbed (Q) = mcΔT = (2000 g)(0.5 J/g°C)(60°C) = 60,000 J = 60 kJ.

Correct Answer: B — 80 kJ

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Q. A 2 kg object is in free fall. What is the net force acting on it?

A. 0 N
B. 2 N
C. 20 N
D. 19.6 N

Solution

The net force is equal to the weight of the object: F = mg = 2 kg * 9.8 m/s² = 19.6 N.

Correct Answer: C — 20 N

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Q. A 2 kg object is lifted to a height of 3 m. What is the work done against gravity? (g = 9.8 m/s²) (2023)

A. 58.8 J
B. 19.6 J
C. 29.4 J
D. 39.2 J

Solution

Work Done = mgh = 2 kg * 9.8 m/s² * 3 m = 58.8 J

Correct Answer: A — 58.8 J

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Q. A 2 kg object is lifted to a height of 3 m. What is the work done against gravity? (2020)

A. 60 J
B. 30 J
C. 20 J
D. 10 J

Solution

Work Done (W) = m * g * h = 2 kg * 9.8 m/s^2 * 3 m = 58.8 J (approx. 60 J)

Correct Answer: B — 30 J

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Q. A 2 kg object is lifted to a height of 5 m. What is the potential energy gained by the object? (g = 9.8 m/s²)

A. 98 J
B. 19.6 J
C. 39.2 J
D. 49 J

Solution

Potential Energy = mass × g × height = 2 kg × 9.8 m/s² × 5 m = 98 J

Correct Answer: A — 98 J

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Q. A 2 kg object is lifted to a height of 5 m. What is the potential energy gained by the object? (2022)

A. 10 J
B. 20 J
C. 30 J
D. 40 J

Solution

Potential Energy = mass × g × height = 2 kg × 10 m/s² × 5 m = 100 J

Correct Answer: B — 20 J

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Q. A 2 kg object is moving with a speed of 3 m/s. What is its kinetic energy?

A. 6 J
B. 9 J
C. 12 J
D. 18 J

Solution

Kinetic energy = 0.5 × m × v² = 0.5 × 2 kg × (3 m/s)² = 9 J.

Correct Answer: B — 9 J

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Q. A 2 kg object is moving with a speed of 3 m/s. What is its total mechanical energy?

A. 9 J
B. 12 J
C. 15 J
D. 18 J

Solution

Total mechanical energy = kinetic energy + potential energy. KE = 0.5mv² = 0.5 * 2 * (3)² = 9 J.

Correct Answer: B — 12 J

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Q. A 2 kg object is moving with a velocity of 10 m/s. What is its momentum? (2021)

A. 5 kg·m/s
B. 10 kg·m/s
C. 15 kg·m/s
D. 20 kg·m/s

Solution

Momentum = Mass × Velocity = 2 kg × 10 m/s = 20 kg·m/s.

Correct Answer: D — 20 kg·m/s

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Q. A 2 kg object is moving with a velocity of 3 m/s. What is its momentum?

A. 3 kg·m/s
B. 6 kg·m/s
C. 9 kg·m/s
D. 12 kg·m/s

Solution

Momentum = mass × velocity = 2 kg × 3 m/s = 6 kg·m/s.

Correct Answer: B — 6 kg·m/s

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Q. A 2 kg object is moving with a velocity of 4 m/s. What is its kinetic energy? (2023)

A. 16 J
B. 8 J
C. 4 J
D. 32 J

Solution

Kinetic Energy (KE) = 1/2 * m * v^2 = 1/2 * 2 kg * (4 m/s)^2 = 16 J.

Correct Answer: A — 16 J

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Q. A 2 kg object is moving with a velocity of 4 m/s. What is its momentum? (2020)

A. 8 kg m/s
B. 4 kg m/s
C. 2 kg m/s
D. 16 kg m/s

Solution

Momentum (p) = m * v = 2 kg * 4 m/s = 8 kg m/s

Correct Answer: A — 8 kg m/s

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Q. A 2 kg object is moving with a velocity of 5 m/s. If it collides elastically with a stationary object of mass 3 kg, what will be the final velocity of the 2 kg object?

A. 1 m/s
B. 2 m/s
C. 3 m/s
D. 4 m/s

Solution

Using conservation of momentum and kinetic energy, the final velocity of the 2 kg object after an elastic collision is 1 m/s.

Correct Answer: A — 1 m/s

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Q. A 2 kg object is pulled with a force of 8 N. What is the acceleration of the object?

A. 2 m/s²
B. 4 m/s²
C. 6 m/s²
D. 8 m/s²

Solution

Using F = ma, we find a = F/m = 8 N / 2 kg = 4 m/s².

Correct Answer: B — 4 m/s²

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Q. A 2 kg object is pushed with a force of 10 N over a distance of 5 m. What is the work done on the object?

A. 25 J
B. 50 J
C. 75 J
D. 100 J

Solution

Work done = Force * Distance = 10 N * 5 m = 50 J.

Correct Answer: B — 50 J

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Q. A 2 kg object is raised to a height of 5 m. What is the potential energy gained?

A. 10 J
B. 20 J
C. 30 J
D. 40 J

Solution

Potential Energy (PE) = m * g * h = 2 kg * 9.8 m/s^2 * 5 m = 98 J

Correct Answer: B — 20 J

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Q. A 2 kg object is sliding on a frictionless surface with a velocity of 4 m/s. What is the momentum of the object?

A. 8 kg·m/s
B. 2 kg·m/s
C. 4 kg·m/s
D. 16 kg·m/s

Solution

Momentum p = mv = 2 kg * 4 m/s = 8 kg·m/s.

Correct Answer: A — 8 kg·m/s

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Q. A 2 kg object is sliding on a frictionless surface with a velocity of 5 m/s. What is the momentum of the object?

A. 10 kg·m/s
B. 5 kg·m/s
C. 2 kg·m/s
D. 1 kg·m/s

Solution

Momentum p = mv = 2 kg * 5 m/s = 10 kg·m/s.

Correct Answer: A — 10 kg·m/s

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Q. A 2 kg object is subjected to a net force of 8 N. What is its acceleration? (2020)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Using F = ma, a = F/m = 8 N / 2 kg = 4 m/s².

Correct Answer: C — 4 m/s²

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Q. A 2 kg object is thrown upwards with a speed of 10 m/s. What is the maximum height it reaches?

A. 5 m
B. 10 m
C. 15 m
D. 20 m

Solution

Using energy conservation: KE_initial = PE_max; 0.5 × 2 kg × (10 m/s)² = 2 kg × 9.8 m/s² × h; h = 5.1 m.

Correct Answer: A — 5 m

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Q. A 2 kg object is thrown upwards with a velocity of 10 m/s. What is its maximum height? (g = 9.8 m/s²)

A. 5.1 m
B. 10.2 m
C. 20.4 m
D. 15.3 m

Solution

Using the formula v² = u² - 2gh, where v = 0 at max height: 0 = (10)² - 2 * 9.8 * h, h = 5.1 m.

Correct Answer: A — 5.1 m

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Q. A 2 kg object is thrown vertically upwards with a speed of 10 m/s. What is the maximum height it reaches? (g = 10 m/s²)

A. 5 m
B. 10 m
C. 15 m
D. 20 m

Solution

Using energy conservation: KE at bottom = PE at top; 1/2 mv^2 = mgh; h = v^2/(2g) = (10^2)/(2*10) = 5 m

Correct Answer: B — 10 m

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Q. A 2 kg piece of copper (specific heat = 0.385 J/g°C) is heated from 25°C to 75°C. How much heat is absorbed? (2022)

A. 2000 J
B. 3000 J
C. 4000 J
D. 5000 J

Solution

Q = mcΔT = 2000 g * 0.385 J/g°C * (75°C - 25°C) = 38500 J.

Correct Answer: B — 3000 J

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Q. A 2 kg piece of iron at 150°C is placed in 1 kg of water at 20°C. What will be the final temperature of the system? (Specific heat of iron = 0.45 J/g°C, water = 4.18 J/g°C) (2023)

A. 25°C
B. 30°C
C. 35°C
D. 40°C

Solution

Using heat transfer equations, we find the final temperature to be approximately 35°C.

Correct Answer: C — 35°C

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Q. A 20 kg cart is pulled with a force of 80 N. If the frictional force is 20 N, what is the acceleration of the cart? (2020)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Net force = 80 N - 20 N = 60 N. Acceleration a = F/m = 60 N / 20 kg = 3 m/s².

Correct Answer: C — 4 m/s²

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Major Competitive Exams

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