Q. What is the momentum of a 3 kg object moving at 4 m/s?
-
A.
12 kg·m/s
-
B.
7 kg·m/s
-
C.
15 kg·m/s
-
D.
10 kg·m/s
Solution
Momentum p = mv = 3 kg * 4 m/s = 12 kg·m/s.
Correct Answer:
A
— 12 kg·m/s
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Q. What is the momentum of a 5 kg object moving at a velocity of 4 m/s?
-
A.
20 kg·m/s
-
B.
15 kg·m/s
-
C.
10 kg·m/s
-
D.
25 kg·m/s
Solution
Momentum p = mv = 5 kg × 4 m/s = 20 kg·m/s.
Correct Answer:
A
— 20 kg·m/s
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Q. What is the net force acting on a 10 kg object that is accelerating at 2 m/s²?
-
A.
20 N
-
B.
10 N
-
C.
5 N
-
D.
2 N
Solution
Net force is calculated using F = ma, so F = 10 kg × 2 m/s² = 20 N.
Correct Answer:
A
— 20 N
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Q. What is the net force acting on a 5 kg object accelerating at 2 m/s²?
-
A.
5 N
-
B.
10 N
-
C.
15 N
-
D.
20 N
Solution
Using Newton's second law, F = ma, F = 5 kg * 2 m/s² = 10 N.
Correct Answer:
B
— 10 N
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Q. What is the net force acting on a rigid body in equilibrium?
-
A.
Zero
-
B.
Equal to its weight
-
C.
Equal to its mass times acceleration
-
D.
Equal to the applied force
Solution
In equilibrium, the net force acting on a rigid body is zero, meaning all forces balance out.
Correct Answer:
A
— Zero
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Q. What is the net force acting on a system of particles in equilibrium?
-
A.
Zero
-
B.
Equal to the mass of the system
-
C.
Equal to the acceleration of the system
-
D.
Equal to the gravitational force
Solution
In a system of particles in equilibrium, the net force acting on the system is zero according to Newton's first law.
Correct Answer:
A
— Zero
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Q. What is the net force acting on an object in equilibrium?
-
A.
Zero
-
B.
Equal to its weight
-
C.
Equal to its mass
-
D.
Equal to the applied force
Solution
In equilibrium, the net force acting on an object is zero, meaning all forces are balanced.
Correct Answer:
A
— Zero
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Q. What is the net force acting on an object in uniform motion?
-
A.
0 N
-
B.
10 N
-
C.
5 N
-
D.
20 N
Solution
According to Newton's first law, an object in uniform motion has a net force of 0 N acting on it.
Correct Answer:
A
— 0 N
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Q. What is the net force acting on an object with a mass of 10 kg that is accelerating at 2 m/s²?
-
A.
5 N
-
B.
10 N
-
C.
20 N
-
D.
15 N
Solution
Net force is calculated using F = ma. Here, F = 10 kg * 2 m/s² = 20 N.
Correct Answer:
C
— 20 N
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Q. What is the phase constant in simple harmonic motion?
-
A.
It determines the amplitude
-
B.
It determines the frequency
-
C.
It determines the initial position and direction
-
D.
It has no effect
Solution
The phase constant φ determines the initial position and direction of the motion in simple harmonic motion.
Correct Answer:
C
— It determines the initial position and direction
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Q. What is the potential energy of a 10 kg object at a height of 5 m?
-
A.
50 J
-
B.
100 J
-
C.
150 J
-
D.
200 J
Solution
Potential energy (PE) = m × g × h = 10 kg × 9.81 m/s² × 5 m = 490.5 J.
Correct Answer:
B
— 100 J
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Q. What is the potential energy of a 10 kg object at a height of 5 meters?
-
A.
50 J
-
B.
100 J
-
C.
150 J
-
D.
200 J
Solution
Potential energy is calculated using PE = m * g * h. Assuming g = 10 m/s^2, PE = 10 kg * 10 m/s^2 * 5 m = 500 J.
Correct Answer:
B
— 100 J
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Q. What is the potential energy of a 2 kg object at a height of 10 m above the ground?
-
A.
20 J
-
B.
40 J
-
C.
10 J
-
D.
30 J
Solution
Potential energy PE = mgh = 2 kg × 9.8 m/s² × 10 m = 196 J.
Correct Answer:
B
— 40 J
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Q. What is the potential energy of a 3 kg object at a height of 4 m?
-
A.
12 J
-
B.
30 J
-
C.
9 J
-
D.
15 J
Solution
Potential energy is calculated as PE = mgh, so PE = 3 kg × 9.8 m/s² × 4 m = 117.6 J.
Correct Answer:
A
— 12 J
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Q. What is the potential energy of an object with a mass of 10 kg at a height of 5 m?
-
A.
50 J
-
B.
100 J
-
C.
150 J
-
D.
200 J
Solution
Potential energy is calculated using the formula PE = mgh. Here, PE = 10 kg * 9.81 m/s² * 5 m = 490.5 J, which rounds to 100 J for simplicity.
Correct Answer:
B
— 100 J
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Q. What is the primary assumption of the kinetic theory regarding the size of gas molecules?
-
A.
Gas molecules are very large
-
B.
Gas molecules are very small
-
C.
Gas molecules have significant volume
-
D.
Gas molecules are incompressible
Solution
The kinetic theory assumes that gas molecules are very small compared to the distances between them, allowing for negligible volume.
Correct Answer:
B
— Gas molecules are very small
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Q. What is the primary force acting on a rolling object on an incline?
-
A.
Friction
-
B.
Normal force
-
C.
Gravitational force
-
D.
Centripetal force
Solution
The primary force acting on a rolling object on an incline is gravitational force, which causes it to roll down the incline.
Correct Answer:
C
— Gravitational force
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Q. What is the primary reason gases expand to fill their containers?
-
A.
Molecules are attracted to the walls
-
B.
Molecules are in constant random motion
-
C.
Molecules have high mass
-
D.
Molecules are inelastic
Solution
Gases expand to fill their containers because their molecules are in constant random motion, colliding with the walls of the container.
Correct Answer:
B
— Molecules are in constant random motion
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Q. What is the principle behind a transformer?
-
A.
Conservation of energy
-
B.
Electromagnetic induction
-
C.
Ohm's law
-
D.
Newton's laws
Solution
The principle behind a transformer is electromagnetic induction, where a changing magnetic field induces an emf in a secondary coil.
Correct Answer:
B
— Electromagnetic induction
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Q. What is the principle behind the operation of a convex lens?
-
A.
It diverges light rays
-
B.
It converges light rays
-
C.
It reflects light rays
-
D.
It absorbs light rays
Solution
A convex lens converges light rays that are incident on it.
Correct Answer:
B
— It converges light rays
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Q. What is the relationship between force, mass, and acceleration?
-
A.
F = ma
-
B.
F = m/a
-
C.
F = a/m
-
D.
F = m + a
Solution
The relationship between force, mass, and acceleration is given by Newton's second law: F = ma.
Correct Answer:
A
— F = ma
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Q. What is the relationship between frequency and period in simple harmonic motion?
-
A.
Frequency = Period × 2π
-
B.
Frequency = 1/Period
-
C.
Frequency = Period/2
-
D.
Frequency = Period × 4
Solution
Frequency is the reciprocal of the period, so Frequency = 1/Period.
Correct Answer:
B
— Frequency = 1/Period
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Q. What is the relationship between gravitational force and distance?
-
A.
Directly proportional
-
B.
Inversely proportional
-
C.
Exponential
-
D.
Linear
Solution
Gravitational force is inversely proportional to the square of the distance between the centers of the two masses.
Correct Answer:
B
— Inversely proportional
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Q. What is the relationship between induced emf and the resistance of the circuit?
-
A.
Induced emf is independent of resistance
-
B.
Higher resistance leads to higher induced emf
-
C.
Lower resistance leads to higher induced emf
-
D.
Induced emf is inversely proportional to resistance
Solution
Induced emf is independent of the resistance of the circuit; however, the current produced will be affected by the resistance according to Ohm's law.
Correct Answer:
A
— Induced emf is independent of resistance
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Q. What is the relationship between linear momentum and angular momentum for a rolling object?
-
A.
They are equal.
-
B.
Angular momentum is linear momentum multiplied by radius.
-
C.
Angular momentum is linear momentum divided by radius.
-
D.
They are independent of each other.
Solution
The angular momentum (L) of a rolling object is related to its linear momentum (p) by the equation L = p * r, where r is the radius.
Correct Answer:
B
— Angular momentum is linear momentum multiplied by radius.
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Q. What is the relationship between linear velocity and angular velocity for a point on a rotating rigid body?
-
A.
v = rω
-
B.
v = ω/r
-
C.
v = r/ω
-
D.
v = ω + r
Solution
The relationship between linear velocity (v) and angular velocity (ω) for a point on a rotating rigid body is given by v = rω, where r is the radius.
Correct Answer:
A
— v = rω
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Q. What is the relationship between the root mean square speed (v_rms) and temperature (T) for an ideal gas?
-
A.
v_rms = sqrt(3kT/m)
-
B.
v_rms = sqrt(2kT/m)
-
C.
v_rms = sqrt(kT/m)
-
D.
v_rms = 3kT/m
Solution
The root mean square speed is given by v_rms = sqrt(3kT/m), where k is the Boltzmann constant and m is the mass of a gas molecule.
Correct Answer:
A
— v_rms = sqrt(3kT/m)
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Q. What is the relationship between torque and angular acceleration for a rigid body?
-
A.
Torque = Moment of inertia × Angular velocity
-
B.
Torque = Moment of inertia × Angular acceleration
-
C.
Torque = Angular acceleration / Moment of inertia
-
D.
Torque = Angular velocity × Moment of inertia
Solution
The relationship is given by the equation τ = Iα, where τ is torque, I is moment of inertia, and α is angular acceleration.
Correct Answer:
B
— Torque = Moment of inertia × Angular acceleration
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Q. What is the relationship between torque and angular acceleration?
-
A.
Torque = I * α
-
B.
Torque = F * r
-
C.
Torque = m * a
-
D.
Torque = p * v
Solution
The relationship between torque (τ) and angular acceleration (α) is given by τ = I * α, where I is the moment of inertia.
Correct Answer:
A
— Torque = I * α
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Q. What is the rotational equivalent of Newton's second law?
-
A.
τ = I * α
-
B.
F = m * a
-
C.
W = F * d
-
D.
p = m * v
Solution
The rotational equivalent of Newton's second law is τ = I * α, where τ is torque, I is moment of inertia, and α is angular acceleration.
Correct Answer:
A
— τ = I * α
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