Factoring gives (x - 3)(x + 3) = 0. Thus, the solutions are x = 3 and x = -3.

Add 5 to both sides: 3x < 9. Divide by 3: x < 3.

Using the quadratic formula: a = 3, b = 12, c = 12. Discriminant = 12² - 4(3)(12) = 144 - 144 = 0. x = -b / 2a = -12 / 6 = -2.

Set y = 0: 0 = x^2 - 4. This factors to (x - 2)(x + 2) = 0, giving x = 2 and x = -2.

Step 1: Divide both sides by 2: x + 3 = 7. Step 2: Subtract 3 from both sides: x = 4.

Step 1: Divide both sides by 2: x + 3 = 8. Step 2: Subtract 3 from both sides: x = 5.

Step 1: Divide both sides by 2: x - 3 = 5. Step 2: Add 3 to both sides: x = 8.

Step 1: Subtract 2 from both sides: 7x = 21. Step 2: Divide both sides by 7: x = 3.

Step 1: Divide both sides by 2: x + 3 = 8. Step 2: Subtract 3 from both sides: x = 5.

Step 1: Divide both sides by 3: x - 2 = 4. Step 2: Add 2 to both sides: x = 6.

Step 1: Divide both sides by 4: x - 2 = 3. Step 2: Add 2 to both sides: x = 5.

Median is the middle value. The sorted data is 1, 2, 3, 4, 5. Median = 3.

Median = (30 + 40) / 2 = 35, since there are 5 numbers.

Median = 15, as the sorted data is 12, 12, 15, 18, 20.

Median is the average of 7 and 8, which is 7.5.

To find the median, arrange the numbers: 12, 15, 20, 22, 25. The median is the middle value, which is 20.

First, arrange the numbers in ascending order: 3, 4, 5, 6, 8. The median is the middle value, which is 5.

The median is the middle value, which is 9.

The period is calculated as 2π divided by the coefficient of x, which is 3, giving a period of 2π/3.

Mean = (3 + 3 + 4 + 5 + 5 + 5 + 6) / 7 = 31 / 7 ≈ 4.43.

Using tan(30) = height / 25, height = 25 * tan(30) = 25 * (1/√3) = 25/√3 meters.

Using tan(45) = height / 30, we have height = 30 * tan(45) = 30 * 1 = 30 meters.

Using tan(45°) = height/distance, distance = height/tan(45°) = 15/1 = 15 meters.

Using tan(45°) = height/50, height = 50 * tan(45°) = 50 meters.

The mode is the number that appears most frequently. Here, 7 appears twice, which is more than any other number.

The mode is the number that appears most frequently. Here, 7 appears twice.

Alternate exterior angles are equal when two parallel lines are cut by a transversal. Therefore, the other alternate exterior angle also measures 120 degrees.

Corresponding angles are equal when two parallel lines are cut by a transversal. Therefore, the corresponding angle also measures 40 degrees.

Same-side interior angles are supplementary. Therefore, if one angle is 40 degrees, the other must be 180 - 40 = 140 degrees.

Alternate exterior angles are equal when two parallel lines are cut by a transversal. Thus, the other alternate exterior angle also measures 120 degrees.