Circuit Theory for Competitive Exam Success

Circuit Theory

AC Fundamentals and Phasors AC Fundamentals and Phasors - Applications AC Fundamentals and Phasors - Case Studies AC Fundamentals and Phasors - Problem Set Network Theorems: Thevenin, Norton Network Theorems: Thevenin, Norton - Applications Network Theorems: Thevenin, Norton - Case Studies Network Theorems: Thevenin, Norton - Problem Set Resistors, Capacitors, Inductors Basics Resistors, Capacitors, Inductors Basics - Applications Resistors, Capacitors, Inductors Basics - Case Studies Resistors, Capacitors, Inductors Basics - Problem Set

Q. What is the total power consumed in a circuit with a 12V battery supplying a current of 2A?

A. 24W
B. 12W
C. 6W
D. 48W

Solution

Power can be calculated using P = V * I. Thus, P = 12V * 2A = 24W.

Correct Answer: A — 24W

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Q. What is the total power consumed in a circuit with a 24V source and a total resistance of 6Ω?

A. 48W
B. 72W
C. 36W
D. 60W

Solution

Power P = V^2 / R = 24V^2 / 6Ω = 96W.

Correct Answer: B — 72W

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Q. What is the total power delivered to a 6Ω resistor in a circuit with a 24V source?

A. 48W
B. 72W
C. 96W
D. 12W

Solution

Power P = V^2 / R = 24^2 / 6 = 576 / 6 = 96W.

Correct Answer: B — 72W

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Q. What is the total power dissipated in a circuit with a 24V source and a 4Ω resistor?

A. 6W
B. 12W
C. 24W
D. 48W

Solution

Power (P) = V^2 / R = 24V^2 / 4Ω = 576 / 4 = 144W.

Correct Answer: B — 12W

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Q. What is the total power dissipated in a circuit with a 24V source and a load of 6Ω?

A. 48W
B. 72W
C. 96W
D. 12W

Solution

Power is calculated using P = V^2 / R = 24^2 / 6 = 96W.

Correct Answer: B — 72W

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Q. What is the total power dissipated in a circuit with a 24V source and a total resistance of 8Ω?

A. 48W
B. 72W
C. 96W
D. 12W

Solution

Power P = V^2 / R = 24V^2 / 8Ω = 576 / 8 = 72W.

Correct Answer: A — 48W

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Q. What is the total power in a circuit with a 30V source and a 10Ω resistor?

A. 90W
B. 60W
C. 30W
D. 3W

Solution

Power is calculated using P = V^2 / R = 30^2 / 10 = 90W.

Correct Answer: B — 60W

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Q. What is the total resistance in a parallel circuit with two resistors of 4 ohms and 6 ohms?

A. 2.4 ohms
B. 10 ohms
C. 24 ohms
D. 12 ohms

Solution

The total resistance (R_total) in parallel is given by 1/R_total = 1/R1 + 1/R2. Thus, 1/R_total = 1/4 + 1/6 = 5/12, so R_total = 12/5 = 2.4 ohms.

Correct Answer: A — 2.4 ohms

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Q. What is the total resistance in a parallel circuit with two resistors, R1 and R2?

A. R1 + R2
B. 1 / (1/R1 + 1/R2)
C. R1 * R2 / (R1 + R2)
D. R1 - R2

Solution

The total resistance in a parallel circuit is given by the formula 1 / (1/R1 + 1/R2).

Correct Answer: B — 1 / (1/R1 + 1/R2)

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Q. What is the total voltage in a closed loop according to Kirchhoff's Voltage Law (KVL)?

A. Equal to the sum of the currents
B. Equal to zero
C. Equal to the sum of the resistances
D. Equal to the power consumed

Solution

KVL states that the sum of the electrical potential differences (voltage) around any closed network is zero.

Correct Answer: B — Equal to zero

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Q. What is the total voltage in a series circuit with a 12 V battery and two resistors of 4 ohms and 6 ohms?

A. 12 V
B. 10 V
C. 8 V
D. 6 V

Solution

In a series circuit, the total voltage is the sum of the individual voltages, which equals the battery voltage of 12 V.

Correct Answer: A — 12 V

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Q. What is the total voltage in a series circuit with a 12V battery and two resistors of 4 ohms and 6 ohms?

A. 12 V
B. 10 V
C. 8 V
D. 6 V

Solution

In a series circuit, the total voltage is equal to the source voltage, which is 12 V.

Correct Answer: A — 12 V

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Q. What is the unit of impedance?

A. Ohm
B. Volt
C. Ampere
D. Watt

Solution

The unit of impedance is the Ohm (Ω), which measures the opposition that a circuit presents to the flow of alternating current.

Correct Answer: A — Ohm

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Q. What is the voltage across a 10 ohm resistor carrying a current of 2 A?

A. 5 V
B. 10 V
C. 20 V
D. 15 V

Solution

Using Ohm's Law, V = I * R = 2 A * 10 ohms = 20 V.

Correct Answer: C — 20 V

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Circuit Theory

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