Major Competitive Exams

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Major Competitive Exams

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Major Competitive Exams MCQ & Objective Questions

Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.

What You Will Practise Here

Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams

Exam Relevance

The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.

Common Mistakes Students Make

Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam

FAQs

Question: How can I improve my performance in Major Competitive Exams?
Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.

Question: What types of questions should I focus on for these exams?
Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.

Question: Are there specific strategies for tackling objective questions?
Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.

Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!

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Q. What is the gravitational potential energy of a 5 kg object at a height of 10 m?

A. 50 J
B. 100 J
C. 150 J
D. 200 J

Solution

Gravitational potential energy (PE) = m * g * h = 5 kg * 9.8 m/s² * 10 m = 490 J.

Correct Answer: B — 100 J

Q. What is the gravitational potential energy of a mass 'm' at height 'h' above the Earth's surface?

A. mgh
B. mg/h
C. gh/m
D. mgh^2

Solution

The gravitational potential energy U at height h is given by U = mgh.

Correct Answer: A — mgh

Q. What is the gravitational potential energy of a mass m at a height h above the Earth's surface?

A. U = mgh
B. U = mg/h
C. U = mgh²
D. U = gh/m

Solution

The gravitational potential energy is given by the formula U = mgh, where g is the acceleration due to gravity.

Correct Answer: A — U = mgh

Q. What is the gravitational potential energy of a mass of 10 kg at a height of 5 m above the ground? (g = 9.8 m/s²)

A. 490 J
B. 98 J
C. 588 J
D. 0 J

Solution

U = mgh = 10 * 9.8 * 5 = 490 J

Correct Answer: A — 490 J

Q. What is the gravitational potential energy of a mass of 10 kg at a height of 5 m in a gravitational field of strength 9.8 N/kg?

A. 490 J
B. 50 J
C. 98 J
D. 0 J

Solution

Gravitational potential energy U = mgh = 10 * 9.8 * 5 = 490 J.

Correct Answer: A — 490 J

Q. What is the gravitational potential energy of a mass of 10 kg at a height of 5 m above the ground? (2000)

A. 500 J
B. 1000 J
C. 1500 J
D. 2000 J

Solution

Gravitational potential energy U = mgh = 10 kg * 9.8 m/s² * 5 m = 490 J, approximately 500 J.

Correct Answer: B — 1000 J

Q. What is the gravitational potential energy of a mass of 2 kg at a height of 10 m above the ground? (g = 9.8 m/s^2)

A. 196 J
B. 98 J
C. 20 J
D. 10 J

Solution

Gravitational potential energy (U) = mgh = 2 kg * 9.8 m/s^2 * 10 m = 196 J.

Correct Answer: A — 196 J

Q. What is the gravitational potential energy of a mass of 2 kg at a height of 10 m? (g = 9.8 m/s²)

A. 19.6 J
B. 39.2 J
C. 78.4 J
D. 98 J

Solution

PE = mgh = 2 * 9.8 * 10 = 196 J

Correct Answer: B — 39.2 J

Q. What is the gravitational potential energy of a mass of 2 kg at a height of 10 m in a gravitational field of 9.8 m/s²?

A. 19.6 J
B. 39.2 J
C. 78.4 J
D. 98 J

Solution

Gravitational potential energy (U) = mgh = 2 kg * 9.8 m/s² * 10 m = 196 J.

Correct Answer: B — 39.2 J

Q. What is the gravitational potential energy of a satellite of mass m at a height h above the Earth's surface?

A. -GMm/R
B. -GMm/(R+h)
C. -GMm/(R-h)
D. -GMm/(R^2 + h^2)

Solution

The gravitational potential energy of a satellite at height h is given by U = -GMm/(R+h), where R is the radius of the Earth.

Correct Answer: B — -GMm/(R+h)

Q. What is the gravitational potential energy of an object of mass m at a height h above the Earth's surface?

A. mgh
B. gh/m
C. mg/h
D. mgh^2

Solution

The gravitational potential energy is given by the formula U = mgh.

Correct Answer: A — mgh

Q. What is the gravitational potential energy of two masses m1 and m2 separated by a distance r?

A. -G * (m1 * m2) / r
B. G * (m1 * m2) / r
C. G * (m1 + m2) / r
D. -G * (m1 + m2) / r

Solution

The gravitational potential energy is given by U = -G * (m1 * m2) / r.

Correct Answer: A — -G * (m1 * m2) / r

Q. What is the gravitational potential energy U of two masses m1 and m2 separated by a distance r?

A. U = -G * (m1 * m2) / r
B. U = G * (m1 * m2) / r
C. U = (m1 + m2) * r
D. U = G * (m1 - m2) / r

Solution

The gravitational potential energy is given by U = -G * (m1 * m2) / r.

Correct Answer: A — U = -G * (m1 * m2) / r

Q. What is the greatest common divisor (GCD) of 36 and 48?

A. 12
B. 18
C. 24
D. 6

Solution

GCD of 36 and 48 is 12.

Correct Answer: A — 12

Q. What is the greatest common divisor (GCD) of 48 and 64?

A. 8
B. 12
C. 16
D. 24

Solution

The GCD of 48 and 64 is 16.

Correct Answer: C — 16

Q. What is the ground state electron configuration of an oxygen atom? (2023)

A. 1s² 2s² 2p⁴
B. 1s² 2s² 2p²
C. 1s² 2s² 2p⁶
D. 1s² 2s¹ 2p⁵

Solution

Oxygen has 8 electrons, and its ground state electron configuration is 1s² 2s² 2p⁴.

Correct Answer: A — 1s² 2s² 2p⁴

Q. What is the group number of Alkali metals in the periodic table? (2023)

A. 1
B. 2
C. 3
D. 0

Solution

Alkali metals are located in group 1 of the periodic table.

Correct Answer: A — 1

Q. What is the group number of Halogens in the periodic table? (2021)

A. 16
B. 17
C. 18
D. 15

Solution

Halogens are located in group 17 of the periodic table.

Correct Answer: B — 17

Q. What is the growth rate from 2019 to 2020 as per the line graph?

A. 5%
B. 10%
C. 15%
D. 20%

Solution

The line graph shows a growth rate of 10% from 2019 to 2020.

Correct Answer: B — 10%

Q. What is the growth rate from Year 1 to Year 2 based on the table?

A. 5%
B. 10%
C. 15%
D. 20%

Solution

The growth rate is 15% calculated from the increase in values from Year 1 to Year 2.

Correct Answer: C — 15%

Q. What is the growth rate of sales from Q1 to Q2 for Product A?

A. 10%
B. 20%
C. 30%
D. 40%

Solution

Sales grew from 200 to 240, which is a growth rate of 20%.

Correct Answer: B — 20%

Q. What is the half-life of a radioactive isotope?

A. Time taken for half of the sample to decay
B. Time taken for the entire sample to decay
C. Time taken for the sample to double
D. None of the above

Solution

The half-life is defined as the time taken for half of the radioactive sample to decay.

Correct Answer: A — Time taken for half of the sample to decay

Q. What is the half-life of a radioactive substance if it takes 10 years for half of the substance to decay?

A. 5 years
B. 10 years
C. 20 years
D. 30 years

Solution

The half-life is defined as the time required for half of the radioactive substance to decay, which is given as 10 years.

Correct Answer: B — 10 years

Q. What is the half-life of a radioactive substance?

A. The time taken for half of the substance to decay
B. The time taken for the entire substance to decay
C. The time taken for the substance to double
D. The time taken for the substance to reach equilibrium

Solution

The half-life of a radioactive substance is defined as the time taken for half of the substance to decay.

Correct Answer: A — The time taken for half of the substance to decay

Q. What is the HCF of 36, 60, and 48?

A. 6
B. 12
C. 18
D. 24

Solution

The prime factorization gives: 36 = 2^2 * 3^2, 60 = 2^2 * 3 * 5, 48 = 2^4 * 3. The HCF is 2^2 * 3 = 12.

Correct Answer: B — 12

Q. What is the HCF of 45, 75, and 105?

A. 5
B. 15
C. 30
D. 45

Solution

The HCF of 45, 75, and 105 is 15, as it is the largest number that divides all three.

Correct Answer: B — 15

Q. What is the heat required to raise the temperature of 2 kg of aluminum from 25°C to 75°C? (Specific heat of aluminum = 0.9 J/g°C) (2022)

A. 9000 J
B. 18000 J
C. 36000 J
D. 4500 J

Solution

Heat required Q = mcΔT = (2000 g)(0.9 J/g°C)(50°C) = 90000 J.

Correct Answer: B — 18000 J

Q. What is the heat required to raise the temperature of 250 g of aluminum from 25°C to 75°C? (Specific heat of aluminum = 0.9 J/g°C)

A. 4500 J
B. 5000 J
C. 6000 J
D. 7000 J

Solution

Q = m*c*ΔT = 250 g * 0.9 J/g°C * (75°C - 25°C) = 4500 J.

Correct Answer: A — 4500 J

Q. What is the height of a building if it casts a shadow of 20 meters when the angle of elevation is 45°?

A. 10
B. 20
C. 20√2
D. 40

Solution

Height = shadow * tan(45°) = 20 * 1 = 20.

Correct Answer: B — 20

Q. What is the height of a building if the angle of elevation from a point 50 meters away is 45°?

A. 50
B. 25
C. 100
D. 75

Solution

Using tan(45°) = height/50, height = 50 * tan(45°) = 50.

Correct Answer: A — 50

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