Major Competitive Exams MCQ & Objective Questions
Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.
What You Will Practise Here
Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams
Exam Relevance
The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.
Common Mistakes Students Make
Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam
FAQs
Question: How can I improve my performance in Major Competitive Exams?Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.
Question: What types of questions should I focus on for these exams?Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.
Question: Are there specific strategies for tackling objective questions?Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.
Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!
Q. What is the gravitational field strength (g) at a distance r from the center of a planet of mass M? (2023)
A.
GM/r^2
B.
GM/r
C.
GMr^2
D.
G/Mr^2
Show solution
Solution
The gravitational field strength at a distance r from the center of a planet is given by g = GM/r^2.
Correct Answer:
A
— GM/r^2
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Q. What is the gravitational field strength at a distance 'R' from the center of a planet of radius 'R' and uniform density?
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Solution
Inside a uniform sphere, the gravitational field strength varies linearly with distance from the center, so at R/2 it is g/2.
Correct Answer:
C
— g/2
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Q. What is the gravitational field strength at a distance of 10 m from a mass of 100 kg? (G = 6.67 × 10^-11 N m²/kg²)
A.
6.67 × 10^-10 N/kg
B.
6.67 × 10^-9 N/kg
C.
6.67 × 10^-8 N/kg
D.
6.67 × 10^-7 N/kg
Show solution
Solution
g = G * M / r² = (6.67 × 10^-11) * (100) / (10²) = 6.67 × 10^-10 N/kg
Correct Answer:
A
— 6.67 × 10^-10 N/kg
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Q. What is the gravitational field strength at a distance of 3R from the center of a planet of mass M and radius R?
A.
G*M/R²
B.
G*M/(3R)²
C.
G*M/(9R²)
D.
G*M/(6R²)
Show solution
Solution
g = GM/r², at 3R, g = GM/(3R)² = GM/9R².
Correct Answer:
C
— G*M/(9R²)
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Q. What is the gravitational field strength at a distance of 3R from the center of the Earth? (R = radius of Earth)
A.
g/9
B.
g/3
C.
g/6
D.
g/12
Show solution
Solution
Gravitational field strength (g') = g / (distance^2) = g / (3R)^2 = g / 9.
Correct Answer:
A
— g/9
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Q. What is the gravitational field strength at a distance of 3R from the center of a planet of radius R?
Show solution
Solution
g = GM/r²; at 3R, g = GM/(3R)² = G/9.
Correct Answer:
A
— G/9
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Q. What is the gravitational field strength at a distance of 3R from the center of the Earth? (R = radius of the Earth) (2022)
A.
g/3
B.
g/9
C.
g/6
D.
g/12
Show solution
Solution
Gravitational field strength decreases with the square of the distance. At 3R, it is g/9.
Correct Answer:
B
— g/9
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Q. What is the gravitational field strength at a distance of 4R from the center of a planet of mass M and radius R?
A.
GM/R²
B.
GM/4R²
C.
GM/16R²
D.
GM/8R²
Show solution
Solution
g = GM/r²; at 4R, g = GM/(4R)² = GM/16R².
Correct Answer:
C
— GM/16R²
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Q. What is the gravitational field strength at a distance of 4R from the center of a planet of radius R?
A.
G/16
B.
G/4
C.
G/2
D.
G
Show solution
Solution
Gravitational field strength g = GM/r². At 4R, g = GM/(4R)² = GM/16R² = G/16.
Correct Answer:
A
— G/16
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Q. What is the gravitational field strength at a distance r from a mass M? (2022)
A.
GM/r
B.
GM/r^2
C.
Gm/r^2
D.
Gm/r
Show solution
Solution
The gravitational field strength (g) at a distance r from a mass M is given by g = GM/r^2.
Correct Answer:
B
— GM/r^2
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Q. What is the gravitational field strength at the surface of a planet of mass M and radius R?
A.
GM/R^2
B.
2GM/R^2
C.
GM/R
D.
G/R^2
Show solution
Solution
The gravitational field strength g at the surface of a planet is given by g = GM/R^2.
Correct Answer:
A
— GM/R^2
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Q. What is the gravitational field strength at the surface of a planet with mass 6 x 10^24 kg and radius 6.4 x 10^6 m?
A.
9.8 N/kg
B.
6.67 N/kg
C.
3.2 N/kg
D.
12.5 N/kg
Show solution
Solution
g = GM/R² = (6.67 x 10^-11 * 6 x 10^24) / (6.4 x 10^6)² = 9.8 N/kg
Correct Answer:
A
— 9.8 N/kg
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Q. What is the gravitational field strength at the surface of the Earth?
A.
9.8 N/kg
B.
10 N/kg
C.
11 N/kg
D.
12 N/kg
Show solution
Solution
The gravitational field strength at the surface of the Earth is approximately 9.8 N/kg.
Correct Answer:
A
— 9.8 N/kg
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Q. What is the gravitational force acting on a 1 kg mass at the surface of the Earth? (g = 9.8 m/s²)
A.
9.8 N
B.
19.6 N
C.
4.9 N
D.
0 N
Show solution
Solution
F = mg = 1 * 9.8 = 9.8 N.
Correct Answer:
A
— 9.8 N
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Q. What is the gravitational force acting on a 10 kg mass at the surface of the Earth?
A.
98 N
B.
10 N
C.
100 N
D.
9.8 N
Show solution
Solution
F = mg = 10 kg * 9.8 m/s^2 = 98 N.
Correct Answer:
A
— 98 N
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Q. What is the gravitational force acting on a 10 kg object at the surface of the Earth?
A.
98 N
B.
100 N
C.
10 N
D.
9.8 N
Show solution
Solution
Using F = mg, where m = 10 kg and g = 9.8 m/s², F = 10 * 9.8 = 98 N.
Correct Answer:
A
— 98 N
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Q. What is the gravitational force acting on a 10 kg object on the surface of the Earth? (g = 9.8 m/s²)
A.
9.8 N
B.
19.6 N
C.
29.4 N
D.
39.2 N
Show solution
Solution
F = mg = 10 * 9.8 = 98 N
Correct Answer:
B
— 19.6 N
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Q. What is the gravitational force acting on a 50 kg object at the surface of the Earth?
A.
490 N
B.
500 N
C.
510 N
D.
520 N
Show solution
Solution
Weight = mass * g = 50 kg * 9.8 m/s² = 490 N
Correct Answer:
A
— 490 N
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Q. What is the gravitational force acting on a 50 kg object on the surface of the Earth?
A.
490 N
B.
50 N
C.
5 N
D.
500 N
Show solution
Solution
Weight W = m * g = 50 kg * 9.8 m/s² = 490 N.
Correct Answer:
A
— 490 N
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Q. What is the gravitational force acting on a 70 kg person standing on the surface of the Earth? (g = 9.8 m/s²)
A.
686 N
B.
70 N
C.
9.8 N
D.
700 N
Show solution
Solution
Weight W = m * g = 70 kg * 9.8 m/s² = 686 N
Correct Answer:
A
— 686 N
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Q. What is the gravitational force acting on a satellite of mass m in orbit at a height h above the Earth's surface?
A.
GmM/(R+h)^2
B.
GmM/R^2
C.
GmM/(R-h)^2
D.
GmM/(R+h)
Show solution
Solution
The gravitational force acting on a satellite in orbit is given by F = GmM/(R+h)^2, where R is the radius of the Earth.
Correct Answer:
A
— GmM/(R+h)^2
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Q. What is the gravitational force between two 1 kg masses placed 1 m apart?
A.
6.67 × 10^-11 N
B.
6.67 × 10^-10 N
C.
6.67 × 10^-9 N
D.
6.67 × 10^-8 N
Show solution
Solution
F = G * (m1 * m2) / r² = (6.67 × 10^-11) * (1 * 1) / (1²) = 6.67 × 10^-11 N
Correct Answer:
A
— 6.67 × 10^-11 N
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Q. What is the gravitational force between two 1 kg masses placed 1 meter apart?
A.
6.67 x 10^-11 N
B.
6.67 x 10^-9 N
C.
6.67 x 10^-10 N
D.
6.67 x 10^-12 N
Show solution
Solution
Using F = G * (m1 * m2) / r², F = (6.67 x 10^-11) * (1 * 1) / (1²) = 6.67 x 10^-11 N.
Correct Answer:
A
— 6.67 x 10^-11 N
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Q. What is the gravitational force between two 1 kg masses placed 1 meter apart? (G = 6.67 × 10^-11 N m²/kg²)
A.
6.67 × 10^-11 N
B.
1.67 × 10^-10 N
C.
6.67 × 10^-10 N
D.
0 N
Show solution
Solution
F = G * (m1 * m2) / r² = (6.67 × 10^-11) * (1 * 1) / (1²) = 6.67 × 10^-11 N
Correct Answer:
A
— 6.67 × 10^-11 N
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Q. What is the gravitational force between two 1 kg masses separated by 1 meter?
A.
6.67 x 10^-11 N
B.
9.81 N
C.
1 N
D.
0 N
Show solution
Solution
Using F = G * (m1 * m2) / r^2, we find F = 6.67 x 10^-11 N for two 1 kg masses at 1 meter apart.
Correct Answer:
A
— 6.67 x 10^-11 N
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Q. What is the gravitational force between two 1 kg masses that are 1 m apart?
A.
6.67 x 10^-11 N
B.
6.67 x 10^-9 N
C.
6.67 x 10^-10 N
D.
6.67 x 10^-12 N
Show solution
Solution
Using F = G * (m1 * m2) / r^2, F = (6.67 x 10^-11) * (1 * 1) / (1^2) = 6.67 x 10^-11 N.
Correct Answer:
A
— 6.67 x 10^-11 N
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Q. What is the gravitational force between two 1 kg masses that are 1 meter apart?
A.
6.67 x 10^-11 N
B.
6.67 x 10^-9 N
C.
6.67 x 10^-10 N
D.
6.67 x 10^-12 N
Show solution
Solution
Using F = G * (m1 * m2) / r², F = (6.67 x 10^-11) * (1 * 1) / (1^2) = 6.67 x 10^-11 N.
Correct Answer:
A
— 6.67 x 10^-11 N
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Q. What is the gravitational force between two 10 kg masses separated by a distance of 2 m?
A.
0.25 N
B.
5 N
C.
10 N
D.
20 N
Show solution
Solution
Using Newton's law of gravitation: F = G(m1*m2)/r² = (6.674 × 10⁻¹¹)(10*10)/(2²) = 0.25 N.
Correct Answer:
A
— 0.25 N
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Q. What is the gravitational force between two 5 kg masses separated by 2 meters? (G = 6.67 x 10^-11 N m²/kg²)
A.
8.34 x 10^-11 N
B.
1.67 x 10^-10 N
C.
1.67 x 10^-11 N
D.
3.34 x 10^-11 N
Show solution
Solution
Using F = G(m1*m2)/r², F = (6.67 x 10^-11)(5)(5)/(2²) = 1.67 x 10^-10 N.
Correct Answer:
B
— 1.67 x 10^-10 N
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Q. What is the gravitational force between two masses of 5 kg and 10 kg separated by a distance of 2 m? (G = 6.67 x 10^-11 N m²/kg²)
A.
1.67 x 10^-10 N
B.
1.25 x 10^-10 N
C.
1.00 x 10^-10 N
D.
2.00 x 10^-10 N
Show solution
Solution
F = G * (m1 * m2) / r² = (6.67 x 10^-11) * (5 * 10) / (2²) = 1.67 x 10^-10 N
Correct Answer:
A
— 1.67 x 10^-10 N
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