To find x, subtract 2 from both sides of the equation: x = 5 - 2, which gives x = 3.

To find x, subtract 3 from both sides: x = 7 - 3, which gives x = 4.

Substituting x and y gives us 2^(2+3) = 2^5 = 32.

Calculating, we find 2^3 + 3^2 = 8 + 9 = 17.

We have x = 8 and y = 4. Thus, x/y = 8/4 = 2.

x + y ≡ 2 + 1 ≡ 3 (mod 3), which is equivalent to 0, but since we are looking for the value, it is 0 mod 3.

Using the method of successive substitutions or the Chinese Remainder Theorem, the smallest solution is x = 26.

x can be expressed as 4 + 5k, where k is an integer. 19 is not congruent to 4 modulo 5.

10 mod 6 = 4, so x could be 10.

Using the method of successive substitutions or the Chinese Remainder Theorem, we find that the smallest positive integer solution is x = 25.

x + y ≡ 4 + 3 ≡ 7 (mod 7), which is equivalent to 0.

11 mod 7 = 4, so x could be 11.

Investing in Product A is recommended due to its consistent growth trend.

Based on the growth trend, a reasonable estimate for Product B's sales in Q5 would be 700 units.

Product B ranks the highest based on its average sales per quarter.

Product D would be last based on its Q4 sales figures.

Product D shows fluctuating sales across the quarters as per the table.

The decimal number 5 is represented as 12 in base 3 (1*3^1 + 2*3^0 = 3 + 2 = 5).

In base 3, the decimal number 5 is represented as '12' (1*3^1 + 2*3^0 = 3 + 2 = 5).

'54' in base 6 = 5*6^1 + 4*6^0 = 30 + 4 = 34.

'54' in base 6 is calculated as 5*6 + 4 = 30 + 4 = 34 in decimal.

To convert from base 6 to decimal, calculate: 2*6^2 + 4*6^1 + 5*6^0 = 2*36 + 4*6 + 5*1 = 72 + 24 + 5 = 101.

To convert from base 8 to decimal, calculate: 5*8^1 + 7*8^0 = 5*8 + 7*1 = 40 + 7 = 47.

'57' in base 8 is calculated as 5*8^1 + 7*8^0 = 40 + 7 = 47.

'10' in base 3 is 3 and '11' is 4. Their product is 12, which is '110' in base 3.

The decimal number 5 is represented as 21 in base-3 (2*3^1 + 1*3^0 = 5).

'210' in base-3 is 2*3^2 + 1*3^1 + 0*3^0 = 18 + 3 + 0 = 21 in decimal.

To add in base-3, convert to decimal: 12 (base-3) = 3 + 2 = 5 (decimal) and 21 (base-3) = 2 + 0 = 2 (decimal). The sum is 5 + 2 = 7 (decimal), which is 21 in base-3.

'132' in base 4 is calculated as 1*4^2 + 3*4^1 + 2*4^0 = 16 + 12 + 2 = 30.

The sum of '12' and '21' in base-4 is '30' in base-4.