Major Competitive Exams

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Major Competitive Exams

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Major Competitive Exams MCQ & Objective Questions

Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.

What You Will Practise Here

Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams

Exam Relevance

The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.

Common Mistakes Students Make

Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam

FAQs

Question: How can I improve my performance in Major Competitive Exams?
Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.

Question: What types of questions should I focus on for these exams?
Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.

Question: Are there specific strategies for tackling objective questions?
Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.

Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!

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Q. What is the final temperature when 200 g of ice at 0°C is added to 100 g of water at 80°C? (Assume no heat loss to the surroundings) (2023)

A. 0°C
B. 20°C
C. 40°C
D. 80°C

Solution

Using heat balance: m_ice * L_f + m_water * c * (T_final - 80) = 0. Solving gives T_final = 20°C.

Correct Answer: B — 20°C

Q. What is the final temperature when 200 g of water at 90°C is mixed with 300 g of water at 30°C?

A. 50°C
B. 60°C
C. 70°C
D. 80°C

Solution

Using the formula m1*T1 + m2*T2 = (m1 + m2)*Tf, we find Tf = (200*90 + 300*30) / (200 + 300) = 70°C.

Correct Answer: C — 70°C

Q. What is the final volume when 100 mL of a 3 M solution is diluted to a concentration of 1 M? (2022) 2022

A. 300 mL
B. 200 mL
C. 100 mL
D. 150 mL

Solution

Using the dilution formula C1V1 = C2V2, we have 3 M * 100 mL = 1 M * V2. Thus, V2 = 300 mL.

Correct Answer: A — 300 mL

Q. What is the first derivative of f(x) = e^(2x)?

A. 2e^(2x)
B. e^(2x)
C. e^(x)
D. 2x*e^(2x)

Solution

Using the chain rule, f'(x) = 2e^(2x).

Correct Answer: A — 2e^(2x)

Q. What is the first derivative of f(x) = ln(x)? (2019)

A. 1/x
B. x
C. ln(x)
D. e^x

Solution

The derivative f'(x) = 1/x.

Correct Answer: A — 1/x

Q. What is the first derivative of f(x) = tan(x)? (2021)

A. sec^2(x)
B. cos^2(x)
C. sin^2(x)
D. csc^2(x)

Solution

The derivative of f(x) = tan(x) is f'(x) = sec^2(x).

Correct Answer: A — sec^2(x)

Q. What is the first law of thermodynamics?

A. Energy cannot be created or destroyed
B. Entropy of an isolated system always increases
C. Heat cannot spontaneously flow from a colder body to a hotter body
D. The total energy of a system is constant

Solution

The first law of thermodynamics states that energy cannot be created or destroyed, only transformed from one form to another.

Correct Answer: A — Energy cannot be created or destroyed

Q. What is the first step in effective reading comprehension?

A. Reading the questions first
B. Previewing the text
C. Highlighting key points
D. Taking notes

Solution

Previewing the text is the first step in effective reading comprehension as it provides an overview of the content.

Correct Answer: B — Previewing the text

Q. What is the first step in the reading comprehension process? (2021)

A. Reading the text
B. Identifying the main idea
C. Making predictions
D. Summarizing the text

Solution

The first step in the reading comprehension process is to read the text thoroughly to understand its content.

Correct Answer: A — Reading the text

Q. What is the focal length of a concave lens if it forms a virtual image at a distance of 20 cm from the lens?

A. -10 cm
B. -20 cm
C. 10 cm
D. 20 cm

Solution

For a concave lens, the focal length (f) is negative. The virtual image distance (v) is -20 cm. Using the lens formula 1/f = 1/v + 1/u, we can find f. Since v = -20 cm, we can assume u is at infinity, thus 1/f = 1/(-20) + 0, giving f = -20 cm.

Correct Answer: B — -20 cm

Q. What is the focal length of a concave lens with a focal point at -15 cm?

A. 15 cm
B. -15 cm
C. 30 cm
D. -30 cm

Solution

The focal length of a concave lens is negative, so it is -15 cm.

Correct Answer: B — -15 cm

Q. What is the focal length of a concave lens with a power of -2 diopters?

A. -0.5 m
B. 0.5 m
C. -2 m
D. 2 m

Solution

Power (P) = 1/focal length (f). Therefore, f = 1/P = 1/(-2) = -0.5 m.

Correct Answer: A — -0.5 m

Q. What is the focal length of a concave mirror if an object is placed at a distance of 30 cm from the mirror and the image is formed at a distance of 15 cm from the mirror?

A. 10 cm
B. 15 cm
C. 20 cm
D. 25 cm

Solution

Using the mirror formula, 1/f = 1/v + 1/u. Here, v = -15 cm (real image) and u = -30 cm (object distance). Thus, 1/f = 1/(-15) + 1/(-30) = -1/10, so f = -10 cm.

Correct Answer: A — 10 cm

Q. What is the focal length of a concave mirror if an object placed 30 cm in front of it produces an image at 10 cm in front of the mirror?

A. 5 cm
B. 10 cm
C. 15 cm
D. 20 cm

Solution

Using the mirror formula 1/f = 1/v + 1/u, where u = -30 cm and v = -10 cm, we find f = 15 cm.

Correct Answer: C — 15 cm

Q. What is the focal length of a concave mirror if an object placed at a distance of 30 cm produces an image at a distance of 15 cm?

A. 10 cm
B. 15 cm
C. 20 cm
D. 25 cm

Solution

Using the mirror formula, 1/f = 1/v + 1/u; here, v = -15 cm (real image) and u = -30 cm. Thus, 1/f = 1/(-15) + 1/(-30) = -1/10, so f = 10 cm.

Correct Answer: A — 10 cm

Q. What is the focal length of a concave mirror if an object placed at a distance of 30 cm produces an image at a distance of 10 cm? (2021)

A. 5 cm
B. 10 cm
C. 15 cm
D. 20 cm

Solution

Using the mirror formula, 1/f = 1/v + 1/u; here, v = -10 cm (real image) and u = -30 cm (object distance). Thus, 1/f = 1/(-10) + 1/(-30) = -1/6, so f = 5 cm.

Correct Answer: A — 5 cm

Q. What is the focal length of a concave mirror if the object distance is 30 cm and the image distance is 15 cm? (2021)

A. 10 cm
B. 15 cm
C. 20 cm
D. 25 cm

Solution

Using the mirror formula, 1/f = 1/v + 1/u. Here, v = -15 cm (real image) and u = -30 cm (object distance). Thus, 1/f = 1/(-15) + 1/(-30) = -1/10, so f = -10 cm.

Correct Answer: A — 10 cm

Q. What is the focal length of a concave mirror if the object is placed at a distance of 30 cm and the image is formed at a distance of 15 cm from the mirror? (2021)

A. 10 cm
B. 15 cm
C. 20 cm
D. 25 cm

Solution

Using the mirror formula, 1/f = 1/v + 1/u. Here, v = -15 cm (image distance is negative for concave mirror) and u = -30 cm. Therefore, 1/f = 1/(-15) + 1/(-30) = -1/10. Thus, f = 10 cm.

Correct Answer: A — 10 cm

Q. What is the focal length of a convex lens if it forms a real image at a distance of 30 cm when the object is placed at 15 cm from the lens?

A. 10 cm
B. 15 cm
C. 20 cm
D. 25 cm

Solution

Using the lens formula 1/f = 1/v - 1/u, where v = 30 cm and u = -15 cm, we find f = 20 cm.

Correct Answer: C — 20 cm

Q. What is the focal length of a diverging lens if the image distance is -15 cm and the object distance is -10 cm? (2023)

A. -30 cm
B. -20 cm
C. -15 cm
D. -10 cm

Solution

Using the lens formula 1/f = 1/v - 1/u, we find f = -20 cm.

Correct Answer: B — -20 cm

Q. What is the focal length of a lens if it forms a virtual image at a distance of 15 cm when the object is placed at 10 cm?

A. -30 cm
B. 30 cm
C. 15 cm
D. 10 cm

Solution

Using the lens formula 1/f = 1/v - 1/u, we have 1/f = 1/(-15) - 1/(-10) = -1/15 + 1/10 = -1/30, thus f = -30 cm.

Correct Answer: A — -30 cm

Q. What is the focal length of a lens if it forms a virtual image at a distance of 12 cm when the object is placed at 8 cm?

A. -24 cm
B. -12 cm
C. 12 cm
D. 24 cm

Solution

Using the lens formula, we find the focal length to be -12 cm.

Correct Answer: B — -12 cm

Q. What is the focal length of a lens if it forms an image at infinity when the object is placed at 30 cm?

A. 30 cm
B. 15 cm
C. 60 cm
D. 20 cm

Solution

For the image to be at infinity, the focal length must be equal to the object distance, hence f = 60 cm.

Correct Answer: C — 60 cm

Q. What is the focal length of a lens that forms a virtual image at a distance of 20 cm when the object is placed at 10 cm?

A. 5 cm
B. 10 cm
C. 15 cm
D. 20 cm

Solution

Using the lens formula, 1/f = 1/v - 1/u. Here, v = -20 cm (virtual image), u = -10 cm. Solving gives f = 5 cm.

Correct Answer: A — 5 cm

Q. What is the focal length of a plano-convex lens with a radius of curvature of 30 cm?

A. 15 cm
B. 30 cm
C. 45 cm
D. 60 cm

Solution

Using the lens maker's formula for a plano-convex lens, f = R/2 = 30 cm / 2 = 30 cm.

Correct Answer: B — 30 cm

Q. What is the focus of the Beti Bachao Beti Padhao scheme? (2015)

A. Promoting women's entrepreneurship
B. Saving the girl child and educating her
C. Providing healthcare to women
D. Increasing women's participation in politics

Solution

Beti Bachao Beti Padhao focuses on saving the girl child and ensuring her education.

Correct Answer: B — Saving the girl child and educating her

Q. What is the focus of the parabola defined by the equation y^2 = 20x?

A. (5, 0)
B. (0, 5)
C. (0, 10)
D. (10, 0)

Solution

In the equation y^2 = 4px, we have 4p = 20, thus p = 5. The focus is at (5, 0).

Correct Answer: A — (5, 0)

Q. What is the focus of the parabola given by the equation y^2 = 20x?

A. (5, 0)
B. (0, 5)
C. (0, -5)
D. (10, 0)

Solution

For the parabola y^2 = 4px, here 4p = 20, so p = 5. The focus is at (5, 0).

Correct Answer: A — (5, 0)

Q. What is the force between two charges of +2μC and -3μC separated by 0.5m? (2022)

A. 0.24 N
B. 0.12 N
C. 0.48 N
D. 0.36 N

Solution

Using Coulomb's law, F = k * |q1 * q2| / r^2 = (9 × 10^9) * (2 × 10^-6) * (3 × 10^-6) / (0.5)^2 = 0.24 N.

Correct Answer: A — 0.24 N

Q. What is the force between two point charges of +2 µC and -3 µC separated by a distance of 0.5 m in vacuum?

A. -24 N
B. -12 N
C. 12 N
D. 24 N

Solution

Using Coulomb's law, F = k * |q1 * q2| / r^2 = (9 × 10^9) * |2 × 10^-6 * -3 × 10^-6| / (0.5)^2 = -24 N.

Correct Answer: A — -24 N

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