Major Competitive Exams

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Major Competitive Exams

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Major Competitive Exams MCQ & Objective Questions

Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.

What You Will Practise Here

Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams

Exam Relevance

The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.

Common Mistakes Students Make

Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam

FAQs

Question: How can I improve my performance in Major Competitive Exams?
Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.

Question: What types of questions should I focus on for these exams?
Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.

Question: Are there specific strategies for tackling objective questions?
Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.

Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!

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Q. What is the equivalent resistance of two resistors of 10 ohms and 20 ohms connected in series?

A. 30 ohms
B. 20 ohms
C. 10 ohms
D. 5 ohms

Solution

In series, the equivalent resistance R_eq = R1 + R2 = 10 ohms + 20 ohms = 30 ohms.

Correct Answer: A — 30 ohms

Q. What is the equivalent resistance of two resistors of 4 ohms and 6 ohms connected in series?

A. 10 ohms
B. 24 ohms
C. 2.4 ohms
D. 0.67 ohms

Solution

In series, the equivalent resistance is the sum: R_eq = R1 + R2 = 4 Ω + 6 Ω = 10 Ω.

Correct Answer: A — 10 ohms

Q. What is the equivalent resistance of two resistors of 4 ohms and 6 ohms in series?

A. 10 ohms
B. 24 ohms
C. 2.4 ohms
D. 0.67 ohms

Solution

In series, the equivalent resistance is the sum: R_eq = R1 + R2 = 4 Ω + 6 Ω = 10 Ω.

Correct Answer: A — 10 ohms

Q. What is the equivalent resistance of two resistors of 4Ω and 12Ω connected in parallel?

A. 3Ω
B. 4Ω
C. 6Ω
D. 8Ω

Solution

Using the formula for parallel resistors, 1/R_eq = 1/R1 + 1/R2 = 1/4 + 1/12 = 1/3. Therefore, R_eq = 3Ω.

Correct Answer: C — 6Ω

Q. What is the equivalent resistance of two resistors of 4Ω and 12Ω in parallel? (2022)

A. 3Ω
B. 4Ω
C. 2Ω
D. 6Ω

Solution

Using the formula 1/R_eq = 1/R1 + 1/R2, we get 1/R_eq = 1/4 + 1/12 = 1/3, so R_eq = 3Ω.

Correct Answer: A — 3Ω

Q. What is the equivalent resistance of two resistors of 5 ohms and 10 ohms connected in parallel?

A. 3.33 ohms
B. 15 ohms
C. 5 ohms
D. 7.5 ohms

Solution

Using the formula for resistors in parallel, 1/R_eq = 1/R1 + 1/R2, we find R_eq = 1 / (1/5 + 1/10) = 3.33 ohms.

Correct Answer: A — 3.33 ohms

Q. What is the equivalent resistance of two resistors of 5Ω and 10Ω connected in parallel?

A. 3.33Ω
B. 5Ω
C. 7.5Ω
D. 15Ω

Solution

1/Req = 1/R1 + 1/R2 = 1/5 + 1/10 = 2/10 + 1/10 = 3/10. Therefore, Req = 10/3 = 3.33Ω.

Correct Answer: A — 3.33Ω

Q. What is the equivalent resistance of two resistors of 8Ω and 12Ω connected in series? (2019)

A. 20Ω
B. 24Ω
C. 16Ω
D. 10Ω

Solution

In series, R_eq = R1 + R2 = 8Ω + 12Ω = 20Ω.

Correct Answer: A — 20Ω

Q. What is the equivalent resistance of two resistors of 8Ω and 4Ω connected in series? (2022)

A. 12Ω
B. 32Ω
C. 2Ω
D. 8Ω

Solution

In series, R_eq = R1 + R2 = 8Ω + 4Ω = 12Ω.

Correct Answer: A — 12Ω

Q. What is the equivalent resistance of two resistors, 6 ohms and 3 ohms, connected in series?

A. 2 ohms
B. 3 ohms
C. 9 ohms
D. 18 ohms

Solution

In series, the equivalent resistance is the sum: R_eq = R1 + R2 = 6Ω + 3Ω = 9Ω.

Correct Answer: C — 9 ohms

Q. What is the equivalent resistance of two resistors, 6Ω and 3Ω, connected in series?

A. 2Ω
B. 3Ω
C. 9Ω
D. 18Ω

Solution

In series, the equivalent resistance (R_eq) is the sum of the resistances: R_eq = 6Ω + 3Ω = 9Ω.

Correct Answer: C — 9Ω

Q. What is the equivalent resistance of two resistors, R1 = 4Ω and R2 = 6Ω, in parallel? (2022)

A. 2.4Ω
B. 10Ω
C. 24Ω
D. 1.5Ω

Solution

The formula for equivalent resistance in parallel is 1/R_eq = 1/R1 + 1/R2. Thus, 1/R_eq = 1/4 + 1/6 = 5/12, so R_eq = 12/5 = 2.4Ω.

Correct Answer: A — 2.4Ω

Q. What is the equivalent resistance of two resistors, R1 and R2, in parallel? (2022)

A. R1 + R2
B. R1 * R2 / (R1 + R2)
C. 1 / (1/R1 + 1/R2)
D. R1 - R2

Solution

The formula for equivalent resistance (R_eq) of two resistors in parallel is given by 1 / (1/R1 + 1/R2).

Correct Answer: C — 1 / (1/R1 + 1/R2)

Q. What is the equivalent weight of H2SO4 if its molar mass is 98 g/mol?

A. 49 g
B. 98 g
C. 196 g
D. 24.5 g

Solution

Equivalent weight = molar mass / number of equivalents = 98 g/mol / 2 = 49 g.

Correct Answer: A — 49 g

Q. What is the error called that occurs due to the limitations of the measuring instrument? (2023)

A. Random error
B. Systematic error
C. Instrumental error
D. Human error

Solution

Instrumental error occurs due to the limitations of the measuring instrument.

Correct Answer: C — Instrumental error

Q. What is the error in a measurement of 20.0 cm if the true value is 19.5 cm? (2023)

A. 0.5 cm
B. 0.5%
C. 2.5 cm
D. 2.5%

Solution

The error is the absolute difference between the measured value and the true value, which is |20.0 - 19.5| = 0.5 cm.

Correct Answer: A — 0.5 cm

Q. What is the error in measurement if the true value is 100 and the measured value is 95? (2023)

A. 5
B. 10
C. 15
D. 20

Solution

The error in measurement is the difference between the true value and the measured value, which is 100 - 95 = 5.

Correct Answer: A — 5

Q. What is the error in this sentence: 'Neither the manager nor the employees was happy with the decision.'?

A. Neither
B. nor
C. was
D. decision

Solution

'Was' should be 'were' because the subject is plural ('employees').

Correct Answer: C — was

Q. What is the escape velocity for a satellite to leave Earth's gravitational field?

A. 7.9 km/s
B. 11.2 km/s
C. 9.8 km/s
D. 5.0 km/s

Solution

The escape velocity from the Earth's surface is approximately 11.2 km/s.

Correct Answer: B — 11.2 km/s

Q. What is the escape velocity for a satellite to leave the Earth's gravitational field?

A. 7.9 km/s
B. 11.2 km/s
C. 9.8 km/s
D. 5.0 km/s

Solution

The escape velocity from the Earth's surface is approximately 11.2 km/s.

Correct Answer: B — 11.2 km/s

Q. What is the escape velocity for a satellite to leave the Earth's gravitational influence?

A. 11.2 km/s
B. 7.9 km/s
C. 9.8 km/s
D. 15.0 km/s

Solution

The escape velocity from the Earth's surface is approximately 11.2 km/s.

Correct Answer: A — 11.2 km/s

Q. What is the escape velocity from the surface of a planet with a radius of 3R and mass 4M?

A. √(8GM/R)
B. √(6GM/R)
C. √(4GM/R)
D. √(10GM/R)

Solution

Escape velocity v = √(2GM/R); here, v = √(2 * 4GM / 3R) = √(8GM/3R).

Correct Answer: A — √(8GM/R)

Q. What is the escape velocity from the surface of a planet with a radius of 4,000 km and a mass of 6 × 10^24 kg? (G = 6.67 × 10^-11 N m²/kg²)

A. 10,000 m/s
B. 11,200 m/s
C. 12,000 m/s
D. 13,000 m/s

Solution

Escape velocity = √(2GM/R) = √(2 * 6.67 × 10^-11 * 6 × 10^24 / 4 × 10^6) = 11,200 m/s

Correct Answer: B — 11,200 m/s

Q. What is the escape velocity from the surface of a planet with a radius of 4R and mass 2M?

A. 2√(GM/R)
B. √(8GM/R)
C. √(2GM/R)
D. 4√(GM/R)

Solution

Escape velocity v = √(2GM/R) = √(2 * 2M / 4R) = √(8GM/4R) = √(8GM/R)

Correct Answer: B — √(8GM/R)

Q. What is the escape velocity from the surface of a planet with mass M and radius R?

A. √(2GM/R)
B. √(GM/R)
C. √(2R/G)
D. √(G/R)

Solution

Escape velocity is given by v = √(2GM/R).

Correct Answer: A — √(2GM/R)

Q. What is the escape velocity from the surface of the Earth?

A. 7.9 km/s
B. 11.2 km/s
C. 9.8 km/s
D. 15 km/s

Solution

The escape velocity from the surface of the Earth is approximately 11.2 km/s.

Correct Answer: B — 11.2 km/s

Q. What is the escape velocity from the surface of the Earth? (g = 9.8 m/s^2, R = 6.4 x 10^6 m)

A. 7.9 km/s
B. 11.2 km/s
C. 9.8 km/s
D. 5.0 km/s

Solution

Escape velocity (v) = sqrt(2gR) = sqrt(2 * 9.8 * 6.4 x 10^6) ≈ 11.2 km/s.

Correct Answer: B — 11.2 km/s

Q. What is the escape velocity from the surface of the Earth? (g = 9.8 m/s², R = 6.4 × 10^6 m)

A. 11.2 km/s
B. 9.8 km/s
C. 7.9 km/s
D. 15 km/s

Solution

Escape velocity (v) = √(2gR) = √(2 * 9.8 * 6.4 × 10^6) ≈ 11.2 km/s

Correct Answer: A — 11.2 km/s

Q. What is the escape velocity from the surface of the Earth? (R = 6.4 × 10^6 m, g = 9.8 m/s²)

A. 11.2 km/s
B. 9.8 km/s
C. 7.9 km/s
D. 12.0 km/s

Solution

Escape velocity v = √(2gR) = √(2 * 9.8 * 6.4 × 10^6) ≈ 11.2 km/s.

Correct Answer: A — 11.2 km/s

Q. What is the estimated temperature at the Earth's inner core?

A. 4000°C
B. 5000°C
C. 6000°C
D. 7000°C

Solution

The temperature at the Earth's inner core is estimated to be around 6000°C.

Correct Answer: C — 6000°C

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